Pls help I’ll give 30 points

Answer:

2(3-√13) is the answer

Step-by-step explanation:

Given that,

x = \frac{3 - \sqrt{13} }{2}

or, \frac{1}{x} = \frac{2}{3 - \sqrt{13} } (Taking reciprocal on both sides)

We know that,

(a + b)² = a² + b² + 2ab

or, (x \ + \frac{1} {x})^{2} = {x}^{2} + \frac{1}{x {}^{2} } + 2

or, {x}^{2} + \frac{1}{x {}^{2} } = (x \ + \frac{1}{x })^{2} - 2

Now,

or, {x}+ \frac{1}{x } = \frac{3 - \sqrt{13} }{2} + \frac{2}{3 - \sqrt{13} }

or, (3 - \sqrt{13 {})^{2} } + 4

2(3-√13) is the answer

If you didn't understand the frac etc... then I'll attach the f ans file.

Step-by-step explanation:

The outer angle at the top C of the ABC is 112 °. If the bisector of the side AB intersects the side AC at point Q and the segment BQ is perpendicular to AC, find the magnitude of ABC

Answer:

0, 1, 2, 3, 4

Step-by-step explanation:

Multiply each x value by 1/3 then add 2. Since the numerator is 1, you would multipy by one and divide by the denominator of 3, so you really need to divide each x value by 3 then add 2.

-6:

-6/3 = -2

-2 + 2 = 0

-3:

-3/3 = -1

-1 + 2 = 1

0:

0/3 = 0

0 + 2 = 2

3:

3/3 = 1

1 +2 = 3

6:

6/3 = 2

2 + 2 =4

Answer:

5

Step-by-step explanation:

54÷8 x 4 ÷2 means that your answer would be 12

Answer:

x = 3 and y = 0

Step-by-step explanation:

To find the solution where you have two equations is called a System of Equations.

What you do is you notice there are two equations and the let both equations equal each other. We can do this because both equations start with a y. These "y" work like puzzles and you can connect the "x+3" and "2x + 6" together. Then solve for it. Here's what i mean,

y = x+3

y = 2x+6

Now connecting them,

x+3 = 2x+6

Subtract x from both sides

3 = x + 6

Subtract 6 from both sides,

x = -3

Now solve for y,

y = -3 + 3 = 0

So our solution is x = 3 and y = 0.

Answer:

  (x, y) = (-3, 0)

Step-by-step explanation:

Substitution or elimination work well for solving this system of equations.

__

Subtract the first equation from the second.

  (y) -(y) = (2x +6) -(x +3)

  0 = x +3

  -3 = x . . . . . . . subtract 3

  y = (-3) +3 = 0 . . . . use the first equation to find y

  (x, y) = (-3, 0)

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Use the second equation to substitute for y in the first.

  2x +6 = x +3

  x = -3 . . . . . . . . . subtract x+6 from both sides

  y = (-3) +3 = 0 . . . . find y using the first equation

  (x, y) = (-3, 0)

__

A graphing calculator answers these quickly.

Answer:

The equation is 4 1/3(2/5+1)

Step-by-step explanation:

So, it's 4 1/3+1 11/15=

65/15+26/15=91/15

6 1/15

2/5x4 1/3

Which is 2/5 x 13/3

Which is 26/15

Which is 1 11/5

Answer:

The equation would be 5000(1.02)^x with x representing the amount of years, as the values keep multiplying.

Answer:

X = 20

Y = 10√3 or 17.32 or 17.3

Steps given below in the image,

I hope my answer helps you.

Answer:

x = 20

y = 17.32

Step-by-step explanation:

[tex]10 = x \cos 60 \degree \\ \\ \implies \: 10 = x \times \frac{1}{2} \\ \\ \implies \: 10 \times 2= x \\ \\ \implies \: \huge{ \boxed{x = 20}} \\ \\ y = 10 \tan \: 60 \degree \\ \\ \implies \: y = 10 \times \sqrt{3} \\ \\\implies \: y = 10 \times 1.732 \\ \\\implies \: \huge{ \boxed{ y = 17.32}}[/tex]

[tex]\text{L.H.S}\\\\=\dfrac{1}{\sin^2 A} - \dfrac1{\tan^2 A}\\\\\\=\dfrac{1}{\sin^2 A}- \dfrac{1}{\tfrac{\sin^2 A}{\cos^2 A}}\\\\\\=\dfrac{1}{\sin^2 A} - \dfrac{\cos^2 A}{\sin^2 A}\\\\\\=\dfrac{1 - \cos^2 A}{\sin^2 A}\\\\\\=\dfrac{\sin^2 A}{\sin^2 A}\\\\\\=1\\\\=\text{R.H.S}\\\\\text{Proved.}[/tex]

Answer:

the amount of space a 3-dimensional object takes up

Step-by-step explanation:

Of the four definition options, the first is the only only that incorporates a three dimension explanation.  The others only describe a two dimension object.  Units for the first would be unit^3.  The other three would only be one-dimensional "units."

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