Please help!!
I need it

Answer:

Answer is 18 degree as per the question

Answer: A. 18°

Step-by-step explanation:

Your formula is 108°+54°+X=180°
To find X, add 108° & 54°. The sum is 162°.
Next you need to subtract your sum from 180°.
180°-162°=18°
X=18°

Answer:

Step-by-step explanation:

Simplifying

x = 8 + 3y

Answer:

here u goooooooo

Step-by-step explanation:

x= 8-3y

Answer:

323

Step-by-step explanation:

Answer:

323 ;)

Step-by-step explanation:

Answer:

5/4

Step-by-step explanation:

m = y2-y2 / x2-x3

Answer:

Tiffany

Step-by-step explanation:

Ramon is 4 to 1 water to sugar

Tiffany is 3 to 1 water to sugar

The nectar that is more sugary is Tiffany's nectar.

A ratio shows us the number of times a number contains another number.

Given that Ramon makes nectar for a hummingbird feeder by mixing 8 cups of water with 2 cups of sugar. Therefore, the ratio of sugar to water can be written as,

Sugar / Water = 2 cups of sugar / 8 cups of water

Sugar / Water = 1/4

Sugar / Water = 0.25 cups of sugar per cup of water

Also, given that Tiffany makes nectar by mixing 9 cups of water with 3 cups of sugar. Therefore, the ratio of sugar to water can be written as,

Sugar / Water = 3 cups of sugar / 9 cups of water

Sugar / Water = 1/3

Sugar / Water = 0.33 cups of sugar per cup of water

Since the ratio of sugar to water is more in Tiffany's nectar (0.33 > 0.25). Therefore, Tiffany's nectar is more sugary.

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Answer:

Y=x+6

Step-by-step explanation:

Answer:

2 feet

Step-by-step explanation:

Answer:

0!

Step-by-step explanation:

If anything 0 is powered to a number, it will always be zero.

Answer:

SAS Axiom

QP=MN

Angle M = Angle P

NP=MQ

Answer:

As the x-values increase, the function increases towards positive infinity.

Step-by-step explanation:

I just did this on study island :D

For the exponential function as the x-values increase, the function increases towards positive infinity.

Exponential function is a function that involves exponents. Exponential function has a constant as its base and a variable as its exponent.

According to the given problem,

f(x) = [tex]3^{x}[/tex]

Let the value of x be -1,

⇒ f(x) = [tex]3^{-1}[/tex]

         = 0.33

Now, let the value of x be 1,

⇒ f(x) = [tex]3^{1}[/tex]

          = 3

Hence, we can conclude, as the x-values increase, the function increases towards positive infinity.

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Answer:

hello im good

Step-by-step explanation:

Answer:

10, 21, 36, 12, 24, 5, 33, 14

yes

Step-by-step explanation:

Answer:

You can. It's just a method used however.

Step-by-step explanation:

Answer:

D. The product of a constant factor 5 and a 2-term factor x+2

Step-by-step explanation:

Hope that helps

Answer:

5y + 30

Step-by-step explanation:

5(y+6)

5y + 30

Answer:

Simplify the radical expression.

Xx²−12Xx+35X−5x²+25x−30/((x−7)(x−5))

Step-by-step explanation:

Answer:

Yes it is a linear relation cause it has a common differences of +10.

Answer:

3x+2y

Step-by-step explanation:

Cost times quantity

Answer:

3x+2y

Step-by-step explanation:

You add the x and y to the end because you do not know how many pounds you buy.

Answer:

c=6

Step-by-step explanation:

In order to solve the original equation, we would have to square both sides of the equation:

\begin{aligned}\sqrt{29+4w}&=23-cw\\\\ \left(\sqrt{29+4w}\right)^2&=(23-cw)^2\\\\ 29+4w&=(23-cw)^2\end{aligned}  

29+4w

​  

(  

29+4w

​  

)  

2

29+4w

​  

=23−cw

=(23−cw)  

2

=(23−cw)  

2

​  

However, squaring both sides of an equation can create extraneous solutions! [Why?]

Hint #22 / 4

Let's plug \blueD w=\blueD{5}w=5start color #11accd, w, end color #11accd, equals, start color #11accd, 5, end color #11accd into the last equation we obtained:

\begin{aligned}29+4\blueD w&=(23-c\blueD{w})^2\\\\ 29+4(\blueD 5)&=(23-c(\blueD{5}))^2\\\\ 49&=(23-5c)^2\end{aligned}  

29+4w

29+4(5)

49

​  

=(23−cw)  

2

=(23−c(5))  

2

=(23−5c)  

2

​  

This equation is correct, both when 23-5c=723−5c=723, minus, 5, c, equals, 7 and when 23-5c=-723−5c=−723, minus, 5, c, equals, minus, 7.

However, the original equation is not correct for 23-5c=-723−5c=−723, minus, 5, c, equals, minus, 7, since this way we obtain \sqrt{49}=-7  

49

​  

=−7square root of, 49, end square root, equals, minus, 7.

Hint #33 / 4

Therefore, an extraneous solution is obtained for the ccc-value that makes 23-5c23−5c23, minus, 5, c equal -7−7minus, 7, which is c=6c=6c, equals, 6.

Substituting this back into the original equation gives \sqrt{29+4w}=23-6w  

29+4w

​  

=23−6wsquare root of, 29, plus, 4, w, end square root, equals, 23, minus, 6, w. You can now solve this for www and see for yourselves that w=5w=5w, equals, 5 is indeed extraneous.

Hint #44 / 4

The answer is:

c=6c=6

c = 6, makes w = 5 an extraneous solution of the equation √(29 + 4w) = 23 - cw.

A root of a transformed equation that is not a root of the original equation because it was omitted from the domain of the original equation is referred to as an extraneous solution.

In the question, we are asked to find the value for the constant c, that makes w = 5, an extraneous solution in the equation:

√(29 + 4w) = 23 - cw.

We first try to solve this equation, by squaring both sides,

29 + 4w = (23 - cw)²,

or, 29 + 4w = 23² - 2(23)(cw) + (cw)²,

or, 29 + 4w = 529 - 46cw + c²w²,

Now, we substitute w = 5, in the above equation to get:

29 + 4(5) = 529 - 46c(5) + c²(5)²,

or, 29 + 20 = 529 - 230c + 25c²,

or, 25c² - 230c + 480 = 0.

Solving this by the quadratic formula, we get:

[tex]c = \frac{-(-230)\pm \sqrt{(-230)^{2}-4(25)(480)}}{2(25)}[/tex] ,

or, [tex]c = \frac{230\pm \sqrt{52900-48000}}{50}[/tex] ,

or, [tex]c = \frac{230\pm \sqrt{4900}}{50}[/tex] ,

or, [tex]c = \frac{230\pm 70}{50}[/tex] ,

or, c = 300/50 or 160/50,

or, c = 6 or c = 3.2.

Now, we will check these values in the original equation by keeping w = 5.

When c = 6:

√(29 + 4w) = 23 - cw,

or, √(29 + 4(5)) = 23 - (6)(5),

or, √(29 + 20) = 23 - 30,

or, √49 = -7,

or, 7 = -7, which is not true.

Hence, c = 6 makes w = 5 an extraneous solution.

When c = 3.2,

√(29 + 4w) = 23 - cw,

or, √(29 + 4(5)) = 23 - (3.2)(5),

or, √(29 + 20) = 23 - 16,

or, √49 = 7,

or, 7 = 7, which is true.

Hence, c = 3.2 makes w = 5 a proper solution.

Therefore, c = 6, makes w = 5 an extraneous solution of the equation √(29 + 4w) = 23 - cw.

The question mentioned is not understandable. For proper question, refer to the attachment.

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Answer:

b i think

Step-by-step explanation:

Answer: 210/1000

Step-by-step explanation:

80+ 60+30+40= 210/100

Answer:

1,100 ounces because 20 × 30 + 10 × 50 = 1,100

Step-by-step explanation:

Answer:

Step-by-step explanation:

y=15x+65

Answer:

5/12

Step-by-step explanation:

8/12 + -3/12

Answer:

2/3 - 1/4 =

8/12 - 3/12 = 5/12

:)

Answer:

The answer to this is 3(2n-9)