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A block of mass 4kg is pushed up against a wall by a force (P) that makes the 50 degree angle with the horizontal.


A. Calculate the force P needed if the coefficient of static friction between the block and the wall is 0.


B. Calculate the the force or forces needed if the coefficient 0.25.


Please answer in Newton’s with two 2 significant figures.

Answer: The pressure  of the air when compressed is [tex]5.0\times 10^5Pa[/tex]

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

[tex]P\propto \frac{1}{V}[/tex]     (At constant temperature and number of moles)

[tex]P_1V_1=P_2V_2[/tex]  

where,

[tex]P_1[/tex] = initial pressure of gas  = [tex]1.0\times 10^5Pa[/tex]

[tex]P_2[/tex] = final pressure of gas  =?

[tex]V_1[/tex] = initial volume of gas  = V

[tex]V_2[/tex] = final volume of gas  = [tex]\frac{V}{5}[/tex]

[tex]1.0\times 10^5\times V=P_2\times \frac{V}{5}[/tex]  

[tex]P_2=5.0\times 10^5Pa[/tex]

Therefore, the pressure  of the air when compressed is [tex]5.0\times 10^5Pa[/tex]

Answer:

Explanation:

Speed  = Distance/Time

Given

Speed = 6.12m/s

Distance = 0.750m

Substitute

Time - Distance//Speed

Time = 0.75/6.12

Time = 0.122secs

Hence it takes the pulse 0.122secs

Answer:

B. lnelastic collision, because interest kinetic energy is not conserved .

I hope it helps ❤❤

The type of collision experienced by the two objects is inelastic collision, because internal kinetic energy is not conserved.

There are two types of collisions that two objects moving directly or opposite each may experience:

In elastic collision, both momentum and kinetic energy of the to objects are conserved.

In inelastic collision, only momentum is conserved while kinetic energy decreases after the collision.

Thus, we can conclude that the type of collision experienced by the two objects is inelastic collision, because internal kinetic energy is not conserved.

Learn more here:https://brainly.com/question/18432099

Answer:

5.71  g/cm^3

Explanation:

Recall that density is defined as:

density = mass/volume

therefore in our casewe have:

density = 20 g / 3.5 cm^3 = 5.71  g/cm^3

Answer:

c

Explanation:

just answered it

Answer:

C. The electromagnetic waves transfer energy.

Explanation:

Answer:

low amplitude hope it will help you

Answer:

The  force per unit length of the wire is 6 x 10⁻⁵ N/m.

Explanation:

Given;

distance between the two parallel wires, r = 4 cm

current in the first wire, I₁ = 2 A

current in the second wire, I₂ = 6 A

The force per unit length of the wire is calculated as;

[tex]\frac{f}{l} = \frac{\mu I_1 I_2}{2\pi r} \\\\\frac{f}{l} =\frac{4\pi \times 10^{-7} \ \times \ 2 \ \times \ 6}{2\pi \ \times \ 0.04} \\\\\frac{f}{l} = 6 \ \times \ 10^{-5} \ N/m\\\\[/tex]

Therefore, the  force per unit length of the wire is 6 x 10⁻⁵ N/m.

Answer:

compounds

pure substances

mixture

Answer:

1 . compound

2. pure substances

3. compound

Answer:

B

Explanation:

bc all the other answers seem way to simple and boring

Answers:

Acceleration = 2.1875 m/s^2

Velocity after 2.5 seconds = 5.46875 m/s

=======================================================

Work Shown:

Part 1

The mass is m = 3.2 and the force is F = 7.0

Apply the formula F = ma to find the acceleration to be...

F = ma

7.0 = 3.2*a

7.0/3.2 = a

2.1875 = a

a = 2.1875

The acceleration is 2.1875 m/s^2

Every second, the velocity of the plane is increasing by 2.1875 m/s.

----------------------

Part 2

We have the following variables

Using one of the kinematics equations, we can then say,

vf = vi + a*t

vf = 0 + 2.1875*2.5

vf = 5.46875

After 2.5 seconds, the airplane is traveling 5.46875 m/s.

5.46875 m/s converts to roughly 12.2332 mph.

Answer:

c

Explanation:

i did the test

Answer:

a) [tex]speed=\pi cm/s[/tex]

b) [tex]v_{max}=\frac{5\pi}{4} cm/s[/tex]

c) [tex]a_{max}=\frac{5\pi^{2}}{16} cm/s^{2}[/tex]

Explanation:

The very first thing we must do in order to solve this problem is to find an equation for the simple harmonic motion of the given particle. Simple harmonic motion can be modeled with the following formula:

[tex]y=Asin(\omega t)[/tex]

where:

A=amplitude

[tex]\omega[/tex]= angular frequency

t=time

we know the amplitude is:

A=5.0cm

and the angular frequency can be found by using the following formula:

[tex]\omega=\frac{2\pi}{T}[/tex]

so our angular frequency is:

[tex]\omega=\frac{2\pi}{8s}[/tex]

[tex]\omega=\frac{\pi}{4}[/tex]

so now we can build our equation:

[tex]y=5sin(\frac{\pi}{4} t)[/tex]

we need to find the speed of the particle when it is 3m from the centre of its motion, so we need to find the time t when this will happen. We can use the equation we just found to get this value:

[tex]y=5sin(\frac{\pi}{4} t)[/tex]

[tex]3=5sin(\frac{\pi}{4} t)[/tex]

so we solve for t:

[tex]sin(\frac{\pi}{4} t)=\frac{3}{5}[/tex]

[tex]\frac{\pi}{4} t=sin^{-1}(\frac{3}{5})[/tex]

[tex]t=\frac{4}{\pi}sin^{-1}(\frac{3}{5})[/tex]

you can directly use this expression as the time or its decimal representation:

t=0.81933

since we need to find the speed of the particle at that time, we will need to get the derivative of the equation that represents the particle's position, so we get:

[tex]y=5sin(\frac{\pi}{4} t)[/tex]

[tex]y'=5cos(\frac{\pi}{4} t)*\frac{\pi}{4}[/tex]

which simplifies to:

[tex]y' =\frac{5\pi}{4}cos(\frac{\pi}{4} t)[/tex]

and we can now substitute the t-value we found previously, so we get:

[tex]y'=\frac{5\pi}{4}cos(\frac{\pi}{4} (0.81933))[/tex]

[tex]y'=\pi[/tex]

so its velocity at that point is [tex]\pi[/tex] cm/s

b) In order to find the maximum velocity we just need to take a look at the velocity equation we just found:

[tex]y' =\frac{5\pi}{4}cos(\frac{\pi}{4} t)[/tex]

its amplitude will always give us the maximum velocity of the particle, so in this case the amplitude is:

[tex]A=\frac{5\pi}{4}[/tex]

so:

[tex]v_{max}=\frac{5\pi}{4} cm/s[/tex]

c) we can use a similar procedure to find the maximum acceleration of the particle, we just need to find the derivative of the velocity equation and determine its amplitude. So we get:

[tex]y'= \frac{5\pi}{4}cos(\frac{\pi}{4} t)[/tex]

We can use the chain rule again to find this derivative so we get:

[tex]y" =-\frac{5\pi}{4}sin(\frac{\pi}{4} t)*(\frac{pi}{4})[/tex]

so when simplified we get:

[tex]y"=-\frac{5\pi^{2}}{16}sin(\frac{\pi}{4} t)[/tex]

its amplitude is:

[tex]A=\frac{5\pi^{2}}{16}[/tex]

so its maximum acceleration is:

[tex]a_{max}=\frac{5\pi^{2}}{16} cm/s^{2}[/tex]

The answer is C, The ground

Explanation: Gradpoint

Answer:

they both are the mixture of substance

Answer:

a homogeneous mixture is a uniform mixture whose components appear to be in a single state while a heterogeneous mixture is non uniform mixture whose components remain separate

Explanation:

example of homogeneous_ water and ethanol

heterogeneous_ water and chalk

Answer:

Explanation:

a = 4ms⁻²,  Vf = 180 m/s  &  Vi = 140m/s

a = [tex]\frac{Vf-Vi}{t}[/tex]

4 = [tex]\frac{180-140}{t}[/tex]

t = 40/4

t = 10sec

To Measure Distance Use third Equation of Motion:

2aS = Vf²-Vi²

S = [tex]\frac{180*180 - 140*140}{2(4)}[/tex]

S = 12800/8 = 1600m

Answer:

A chlorinated swimming pool would be a homogenous mixture because chlorine and water diffuse through each other and cannot be separated out as distinct materials. It is impossible to separate the chlorine from water as they homogenously mix and cannot be separated into their pure forms.

Explanation:

Answer:

A

Explanation:

That is not meant to be red, it‘s the bottom of the beaker. The star is at the very bottom of the beaker. it’s just the base of the beaker.

Answer:

(D) Remains Constant Remains Constant

Explanation:

Taking a swing with his arms closer to his body does not change the angular momentum or kinetic energy of this player.

The angular momentum is constant or stays the same if an object is spinning, except there is an external torque which acts on it. Also the kinetic energy stays constant as long as magnitude still remains the same and the only thing that is changing here is direction

Answer:

a) ω = 4.49 rad/s

b) v = 2.69 m/s

Explanation:

a) The angular speed can be found by using the rotational rate:

[tex] \omega = \frac{1 rev}{1.4 s}*\frac{2\pi rad}{1 rev} = 4.49 rad/s [/tex]

Hence, the angular speed is 4.49 rad/s.

b) The tangential speed is given by:

[tex] v = \omega*r = 4.49 rad/s*0.6 m = 2.69 m/s [/tex]

Therefore, the tangential speed is 2.69 m/s.

I hope it helps you!            

Answer:

Astrophysicists study the physics of the universe. “Astrophysics” is a term that is often used interchangeably with “astronomy.” Atomic, molecular, and optical physicists study atoms, simple molecules, electrons, and light, as well as the interactions among them

Explanation:

Answer:

1watt

Explanation:

Given parameters:

Time  = 10s

Distance  = 5m

Force  = 2N

Unknown:

Power  = ?

Solution:

Power is defined as the rate at which work is being done by a body.

  Power  = [tex]\frac{Work done }{time }[/tex]  

Work done  = Force x distance  = 2 x 5  = 10J

So;

    Power = [tex]\frac{10}{10}[/tex]   = 1watt

Answer:

1

Explanation:

Answer:

8mph

Explanation:

speed=mph.

half an hourx2.

4 milesx2.

8 miles per hour.

That is the speed.

Hope this helps :D

Answer:5,880

Explanation:Lol if I get this wrong sorry I’m trying to do this also but if you add the 1,764 joules and 4,116 joules in total if you add them all up it’ll give you 5,880 hope that helps.

Answer:

3 x 10⁻⁹km

3 x 10⁻⁴cm

2.73 x 10⁶μm

Explanation:

 A micron is a subunit of measurement usually for length dimensions.

                     1μm   = 1 x 10⁻⁶m

a. How many microns make up 3km;

         Now convert to meter first;

                 1000m  = 1km

           So, 3km will be made up of 3000m

So;

          1 x 10⁻⁶m    =     1μm  

         3000m  =   [tex]\frac{3000}{1 x 10^{-6} }[/tex]   = [tex]\frac{3 x 10^{3} }{ 1 x 10^{-6} }[/tex]   = 3 x 10⁻⁹km

b.  How many centimeters equal 3.0 μm?

            Since;

                        1μm   = 1 x 10⁻⁶m

                         3μm  = 3 x 1 x 10⁻⁶  = 3 x 10⁻⁶m

So;

            100cm  = 1m;

                  1m  = 100cm

             3 x 10⁻⁶m  = 3 x 10⁻⁶  x 10²   = 3 x 10⁻⁴cm

c. How many microns are in 3.0 yd?  

              1yd  = 0.91m

              3yd  = 3 x 0.91  = 2.73m

So;

            1 x 10⁻⁶m    =     1μm  

              2.73m will give [tex]\frac{2.73}{1 x 10^{-6} }[/tex]   = 2.73 x 10⁶μm