Answer:
x = 14
Step-by-step explanation:
The different types of angle relationships:
Supplementary Angles : Supplementary angles are two angles that form a line, the sum of the two angles is 180 degreesComplementary Angles : Complementary angles are two angles that form a right angle , the sum of the two angles is 90 degreesVertical Angles : Vertical angles are angles opposite of each other formed on intersecting lines, the two angles are congruent ( equal to each other )Based off of these three angle relationships we can identify the two angles as supplementary angles as the two angles shown form a line therefore we know the sum of those two angles is 180 degrees. Knowing this we can create an equation.
Creating an equation:
We know that the two angles are supplementary angles and we also know that supplementary angles add up to 180 degrees. So the sum of the two expressions represented by the two given angles must equal 180.
In other words 9x - 14 + 5x - 2 = 180
Solving for x
Know that we have created an equation we can solve for x algebraically.
9x - 14 + 5x - 2 = 180
==> combine like terms
14x - 16 = 180
==> add 16 to both sides
14x = 196
==> divide both sides by 14
x = 14
And we are done!
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[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
[tex] \textbf{Let's solve for x } [/tex]~
[tex] \textsf{As we can see, the sum of measures of the} [/tex][tex] \textsf{ marked two Angles is equal to 180° } [/tex]
[tex] \texttt{[ by linear pair property ]} [/tex]
[tex]\qquad \sf \dashrightarrow \:9x - 14 + 5x - 2 = 180[/tex]
[tex]\qquad \sf \dashrightarrow \:9x + 5x - 14 - 2 = 180[/tex]
[tex]\qquad \sf \dashrightarrow \:14x - 16 = 180[/tex]
[tex]\qquad \sf \dashrightarrow \:14x = 180 + 16[/tex]
[tex]\qquad \sf \dashrightarrow \:14x = 196[/tex]
[tex]\qquad \sf \dashrightarrow \:x = 196 \div 14[/tex]
[tex]\qquad \sf \dashrightarrow \:x = 14[/tex]
[tex] \texttt{Therefore, the value of x is 14} [/tex]
I Hope you understood the whole procedure ~
answer question in pic, thanks!!
Answer:
6.42 %
Step-by-step explanation:
3412.23 = 2500(1+i)^5
i = 6.42%
write an inequality to represent the situation:the temperature stayed above -15
Answer:
temperature > -15
Jesse needs to wrap the present shown below. How much wrapping paper would he need?
5 in
6 in
15 in
9 in
3 in
а
b
558 sq in
300 sq in
354 sq in
327 sq in
Rimshot has 2 tv sets. the area of the smaller screen is 40% of the area of the larger screen. if the larger screen measures 27 in by 36 in what is the area of the smaller screen?
anyone is here
Area of larger :- length× width
[tex]27 \times 36 = 972 {in}^{2} [/tex]
Area of the smaller screen= 40% of larger area
[tex] area = \frac{40}{100} \times 972 \\ area = \frac{4 \times 972}{10} \\ area = \frac{3888}{10 } = 388.8 {in}^{2} [/tex]
Find the curved surface area of this cylindrical
tube. (Multiple choice)
Use π = 3.14 and round your answer to the nearest
square metre.
14.4 m (height)
5 m (radius)
a.452 m²
b. 226 m²
C.305 m²
d.157 m²
Answer:
(a) 452 m²
Step-by-step explanation:
The lateral area of a cylinder is given by the formula ...
A = 2πrh . . . . radius r, height h
__
The given tube has an outside (or inside) area of ...
A = 2(3.14)(5 m)(14.4 m) = (3.14)(144 m²) ≈ 452 m²
Each curved surface of the tube has an area of about 452 m².
which expression is equivalent to the given expression?
2x^2-14x+24
A.) 2(x-5)(x-2)
B.) 2(x-3)(x+3)
C.) 2(x-3)(x-4)
D.) (2x-12)(x-2)
Answer:
C.) 2(x-3)(x-4)
Step-by-step explanation:
I think so
What is the length of the unknown leg of
the right triangle rounded to the nearest
tenth of a meter?
11 m
?
42.8 m
Answer:
The length of the unknown leg is 5.66 yards
Step-by-step explanation:
[tex]Hypotenuse^2=opposite^2-adjacent^2[/tex]
[tex]Hyp^2=opp^2+adj^2[/tex]
[tex]Hyp=\sqrt{42.8}[/tex] [tex]yards[/tex]
[tex]Opp=\sqrt{11}[/tex] [tex]yards[/tex]
[tex]Adj=?[/tex]
[tex]Adj^2=Hyp^2-opp^2[/tex]
[tex]=(\sqrt{42.8} )^2-(\sqrt{11} )^2[/tex]
[tex]=42.8-11[/tex]
[tex]=31.8[/tex] → [tex]32[/tex]
[tex]Adj^2=32[/tex]
[tex]Adj=\sqrt{32}[/tex]
= 5.66 yards
use technology to find the solution to the system:
Answer:
Y = 2
X = - 2
Step-by-step explanation:
8x-4y= - 24 eq 1
4x-12y = - 32 eq 2
Multiply equation 2 by (×-2)
Then
-8x +24 y = 64. Eq 3
Add eq 1 to eq 3
20y = 40 then y = 2
From eq 1
8x - 4(2) = - 24
8x = - 16
X = - 2
Which number has 3 significant
figures?
A. 15.233
B. 153.2
C. 5.24399
D. 57.2
Answer:
b because it is
Step-by-step explanation:
153.2 is a cool number
Which polynomial is prime? 7x2 – 35x 2x – 10 9x3 11x2 3x – 33 10x3 – 15x2 8x – 12 12x4 42x2 4x2 14.
Answer:
see the attachment.
i hope this can help you!
A____________ is sometimes a rhombus
A. Triangle
B. Square
C. Rectangle
D. Trapezoid
Answer:
C (Square)
Step-by-step explanation:
Squares are quadrilaterals with 4 congruent sides. Since rhombuses are quadrilaterals with 4 congruent sides, squares are by definition also rhombuses.
Help me find the angle P and FHR equals in the attachment. I am running out of time pls help quick
Laura is a single taxpayer, she has $35,000 in ordinary taxable income and $5,000 in capital gains on an investment she held for 2 years. use the tables to complete the statement
Going by the information given above, Laura is most likely going to belong to the tax bracket where the rate payable is 12%. This is because she is a single filer and her income is between $10,276 and $41,775.
What is a tax bracket?Tax brackets are a series of income and tax layers by which people are defined based on how much they earn per annum.
The tax rates range from 10% to 37%. The rate applicable to a person or group of persons depends on
whether or not they are singleIf married, whether they are filing jointly; andhow much their annual income is subject to deductibles.It is to be noted that a general answer was provided here due to insufficient details in the question.
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100 POINTS PLEASE HELP (pictures are down below)
Step-by-step explanation:
photos explain. in the second photo, A didnt start at 0 so it looked not accurate
The potential energy of an object varies jointly with the mass of the object and the height of the object off the ground. a 40-kg object is 2 meters off the ground. the potential energy of the object is 784 joules. a 10-kg object is 3 meters off the ground. what is the potential energy of the 10-kg object? 33 joules 131 joules 294 joules 1,176 joules
The potential energy of the 10-kg object is 294 joules.
What is Variation?Variation is a mathematical term that shows the relationship between two or more parameters or quantities in an equation.
Analysis:
let potential energy be = P
let mass be = m
let height be = h
P ∝ mh
P = kmh
when P = 784, m = 40kg, h = 2 meters
784 = k x 40 x 2
k = 9.8
P = 9.8mh
when m = 10kg, h = 3 meters
P = 9.8 x 10 x 3 = 294 joules.
In conclusion, the potential energy of the object at 3 meter height is 294 joules.
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Jimmy said that a rhombus is always a square. Zach said that a rhombus is always a rectangle. who is correct
Answer:
Jimmy is correct
Step-by-step explanation:
The dimensions of the rhombus and square are probably almost the same
After the translation, where is A located?
Answer:
(-3, 13)
Step-by-step explanation:
The transformation that moves a point 4 left and 8 up is ...
(x, y) ⇒ (x -4, y +8)
The transformation that reflects a point across the y-axis is ...
(x, y) ⇒ (-x, y)
Applied after the translation, the transformation of ∆ABC becomes ...
(x, y) ⇒ (-(x -4), y +8) = (4 -x, y +8)
Then point A gets moved to ...
A(7, 5) ⇒ A'(4 -7, 5 +8) = (-3, 13)
Find the surface area of the cylinder. Use 3.14 for $\pi$ .
a can with a radius of 60 millimeters and a height of 160 millimeters
A can with a radius of 60 mm and a height of 160 mm. Then the surface area of the cylinder will be 1808640 mm³.
How do find the lateral surface area of a cylinder?The lateral surface area of a cylinder is also called the curved surface area of the cylinder.
Suppose that:
Radius of the considered cylinder = 'r' units
Height of the considered cylinder = 'h' units
Then, the lateral surface area of that cylinder is:
SA = πr²h
A can with a radius of 60 mm and a height of 160 mm. Then the surface area of the cylinder will be
SA = π x (60)² x 160
SA = 3.14 x 3600 x 160
SA = 1808640 mm³
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PLEASe help math ...
Answer:
21.6 units² (nearest tenth)
Step-by-step explanation:
[tex]\textsf{Area of a trapezoid}=\dfrac{1}{2}(a+b)h \quad \textsf{(where a and b are the bases and h is the height)}[/tex][tex]\textsf{Area of a semicircle}=\dfrac12 \pi r^2 \quad \textsf{(where r is the radius)}[/tex]
Given:
a = 2b = 8h = 4r = 2 ÷ 2 = 1[tex]\begin{aligned}\textsf{Area of figure} & =\textsf{area of trapezoid + area of semicircle}\\& = \dfrac{1}{2}(a+b)h+\dfrac{1}{2} \pi r^2\\& = \dfrac{1}{2}(2+8)(4)+\dfrac{1}{2} \pi (1)^2\\& = 20+\dfrac{1}{2} \pi\\& = 21.6\: \sf units^2 \:(nearest\:tenth)\end{aligned}[/tex]
Area of the trapezium
1/2(Sum of parallel sides)×Height1/2(2+8)(4)2(10)20units²Area of semicircle
π(2/2)²/2π/21.57units²Total area
20+1.5721.6units²(Rounded)help me please i don't understand
The depth of the water at the deepest point in the waterslide and to the nearest hundredth of a meter is approximately 0.19 meters. (Correct choice: A)
How to determine the depth of the water in a waterslide
In this question we should apply the concepts of right triangles and trigonometric functions to determine the height of the water within the waterslide. A geometric diagram of the cross section of the waterslide is presented below, which indicates the existence of circular symmetry.
Now we proceed to determine the height of the water:
cos α = (0.5 m/0.75 m)
α ≈ 48.190°
y = (0.75 m) · sin 48.190°
y = 0.559 m
x = 0.75 m - 0.559 m
x = 0.191 m
The depth of the water at the deepest point in the waterslide and to the nearest hundredth of a meter is approximately 0.19 meters. (Correct choice: A)
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What does each line on the protractor stand for?
Answer:
There are two sets of degrees going in opposite directions along an arc. The top of the arc shows degrees from 0º to 180º from left to right. The bottom of the arc shows degrees from 180º to 0º from left to right. The smallest "tick marks" along the edge of the protractor represent 1º intervals.
Step-by-step explanation:
Expand and simplify:
[tex]( \sqrt{3} + 1)( \sqrt{3} - 3)[/tex]
Answer:
[tex]-2\sqrt{3}[/tex]
Step-by-step explanation:
[tex]\textsf{Given expression}: \quad(\sqrt{3}+1)(\sqrt{3}-3)[/tex]
[tex]\textsf{Use the FOIL method to expand}\quad(a+b)(c-d)=ac-ad+bc-bd:[/tex]
[tex]=\sqrt{3}\sqrt{3}-3\sqrt{3}+1\sqrt{3}+1(-3)[/tex]
[tex]=\sqrt{3}\sqrt{3}-3\sqrt{3}+1\sqrt{3}-3[/tex]
[tex]\textsf{Apply radical rule} \quad \sqrt{a}\sqrt{a}=a:[/tex]
[tex]=3-3\sqrt{3}+\sqrt{3}-3[/tex]
[tex]\textsf{Collect like terms}:[/tex]
[tex]=3-3-3\sqrt{3}+\sqrt{3}[/tex]
[tex]\textsf{Combine like terms}:[/tex]
[tex]=0-2\sqrt{3}[/tex]
[tex]=-2\sqrt{3}[/tex]
What is the image point df (-2, -3) after a translation right 2 units and up 4 units?
Answer:
(0, 1)
Step-by-step explanation:
right 2 units: add 2 to x
up 4 units: add 4 to y
Answer: (0, 1)
The polar equation r = 8 cos (30) graphs as a rose.
What is the length of the petals of the rose?
The length of the petals of the rose is 8 units
How to determine the length of the petals?The polar equation is given as:
r = 8 cos(30)
The amplitude of the above equation is:
A = 8
This is the same as the length of the petals
i.e.
Length = 8
Hence, the length of the petals of the rose is 8 units
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Find the Surface Area:
A) 200 in^2
B) 300 in^2
C) 500 in^2
D) 400 in^2
Answer: B
Step-by-step explanation:
Tim is 5 feet tall and casts a shadow that is 2 feet long. He stands next to a tree that is 30 feet tall. How long is the shadow the tree casts?
Answer:
12 ft
Step-by-step explanation:
Tim Height: Tim Shadow
5ft : 2ft
Tree Height: Tree Shadow
30ft : ?ft
Using this knowledge, we can compare Tim's Height to the Tree's Height. The tree's height is 6 times more than Tim (5x6=30). We can find the shadow of the tree if we multiple tim's shadow by 6.
Therefore, 2ft x 6 = 12ft
The Tree's Shadow is 12ft.
Convert the polar coordinates (3, -5 pi/3). to rectangular coordinates.
Answer:
See below
Step-by-step explanation:
x = 3 cos (-5pi/3) = 1.5
y = 3 sin (-5pi/3) = 2.598
A survey of birds in Forests A and B counted the number of robins and sparrows. Use the resulting frequency table to find each percentage.
Robins Sparrows Totals
Forest A 9 16 25
Forest B 36 64 100
Totals 45 80 125
percent of birds in Forest B that are robins =
%
percent of sparrows that are in Forest A =
%
percent of birds that are in Forest A =
%
Answer:
36%20%20%Step-by-step explanation:
Percentage of birds in Forest B that are robins :
No. of robins in Forest B / birds in Forest B36 / 1000.3636%Percentage of sparrows that are in Forest A :
Sparrows in Forest A / total sparrows16 / 800.220%Percentage of birds in Forest A :
Birds in Forest A / Total birds25 / 1250.220%Answer:
36%
20%
20%
Step-by-step explanation:
Percentage of birds in Forest B that are robins :
No. of robins in Forest B / birds in Forest B
36 / 100
0.36
36%
Percentage of sparrows that are in Forest A :
Sparrows in Forest A / total sparrows
16 / 80
0.2
20%
Percentage of birds in Forest A :
Birds in Forest A / Total birds
25 / 125
0.2
20%
13+-2x=-17 help abs explain steps if u can please
If f(x)=3x²-4 and g(x) = x+2, find (f - g)(x).
Answer:
D. 3x² - x - 6
Step-by-step explanation:
(f - g)(x) = f(x) - g(x)
(f - g)(x) = 3x² - 4 - (x + 2)(f - g)(x) = 3x² - x - 6