please help me solve this

Please Help Me Solve This

Answers

Answer 1

Answer:

i actually don't know

Step-by-step explanation:


Related Questions

The daily cost of manufacturing x comic books at a small custom printing shop is C(x)=2x+325, and the number of comic books assembled in y hours is x(y)=35y. The composition function, C(x(y)), identifies the cost of assembled comic books in a y-hour day. Which mathematical expression represents C(x(y))?

A- 70y+11,375

B- 70y+325

C - 70x+325

D - 70x+11,375

Answers

The mathematical expression represents C(x(y)) will be C(x(y)) = 70y + 325. Then the correct option is B.

What is a function?

A function is a statement, rule, or law that establishes the connection between two variables. In mathematics, functions are everywhere and are necessary for constructing physical connections.

The daily cost of manufacturing x comic books at a small custom printing shop is C(x) = 2x + 325, and the number of comic books assembled in y hours is x(y) = 35y.

The composition function, C(x(y)), identifies the cost of assembling comic books in a y-hour day.

Then the mathematical expression represents C(x(y)) will be

C(x(y)) = 2(35y) + 325

C(x(y)) = 70y + 325

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Use f(x)=x^2+4x-12 Does the graph of a function open upward or downward?

Answers

Answer:

Upward

Step-by-step explanation:

Because of the positive leading coefficient, the graph of the function will open upwards, being a parabola.

answer upwards stepg by stepg explanition because the postivie leafingn coefficient the graph of rhe function will
open upwards and being a parabpla

PLSS HELP ASAP. Which of the follow box-and-whisker plots correctly displays this data set?

24, 32, 25, 27, 37, 29, 30, 30, 28, 31, 27, 23

Answers

Answer:  Choice D

The five number summary is

Min = 23Q1 = 26Median = 28.5Q3 = 30.5Max = 37

===========================================================

Further Explanation:

The original data set is {24, 32, 25, 27, 37, 29, 30, 30, 28, 31, 27, 23}

It sorts to {23, 24, 25, 27, 27, 28, 29, 30, 30, 31, 32, 37} when going from smallest to largest.

There are n = 12 items in this set. The median is found between slots 6 and 7 because n/2 = 12/2 = 6

Circle the items in slot 6 and slot 7 to highlight 28 and 29 in that order. The midpoint is (28+29)/2 = 57/2 = 28.5 which is the median.

Median = 28.5

---------------

Now break the set up into two pieces

L = {23, 24, 25, 27, 27, 28}

U = {29, 30, 30, 31, 32, 37}

L is the lower set below the median, U is the upper set above the median

The midpoint of L is (25+27)/2 = 26 and the midpoint of set U is (30+31)/2 = 30.5

This gives us Q1 = 26 and Q3 = 30.5 respectively

Q1 = first quartile

Q3 = third quartile

The min and max are simply the smallest and largest items of the set

min = 23

max = 37

------------------

We have this five number summary:

Min = 23Q1 = 26Median = 28.5Q3 = 30.5Max = 37

These five items directly determine the positioning of the box and whiskers. No extra info is needed.

The min and max handle the tips of the left and right whiskers if we don't have any outliers. In this case, we don't have outliers so we can ignore this aspect.

The Q1 and Q3 handle the left and right edges of the box

The median (aka Q2) is the vertical line inside the box. It doesn't have to be at the center of the box. It's simply anywhere inside.

With all this in mind, the best match is choice D

The tip of the left whisker is at 23The left edge of the box is at 26The vertical line inside the box is at 28.5The right edge of the box is at 30.5The tip of the right whisker is at 37

----------------------------------

In other words, we can eliminate the following

A) Because the right edge of the box for choice A is at 31 when it should be at 30.5B) The tip of the right whisker is at 35 when it should be at 37C) The tip of the left whisker is at 21 when it should be at 23

Since A, B, and C are eliminated, the only thing left is choice D which matches all aspects of the five number summary above.

Para preparar un pastel, se necesita: 1/3 de un paquete de 750
g de azúcar, 3/4 de un paquete de harina de kilo, 3/5 de una
barra de mantequilla de 200 g. Halla, en gramos, las
cantidades que se necesitan para preparar el pastel.

Answers

Considerando la multiplicando una fracción por un entero, las cantidades que se necesitan para preparar el pastel son 250 gramos de azúcar, 750 gramos de harina y 120 gramos de mantequilla.

Multiplicando una fracción por un entero

Para multiplicar una fracción por un número entero, se debe tener en cuenta que cualquier entero n puede ser escrito como la fracción [tex]\frac{n}{1}[/tex].

Luego, se multiplican los denominadores para obtener el denominador final y se multiplican los numeradores para obtener el numerador final. Es decir, en la multiplicación de fracciones se multiplican los numeradores de las fracciones y aparte los denominadores.

Cantidades para preparar un pastel

Para preparar un pastel, se necesita 1/3 de un paquete de 750 g de azúcar, 3/4 de un paquete de harina de kilo (1000 g), 3/5 de una barra de mantequilla de 200 g. Esto es:

[tex]\frac{1}{3}[/tex]× 750 gramos [tex]\frac{3}{4}[/tex]× 1000 gramos[tex]\frac{3}{5}[/tex]× 200 gramos

Considerando la multiplicando de una fracción por un entero y resolviendo se obtiene:

[tex]\frac{1}{3}[/tex]× 750 gramos= [tex]\frac{1}{3}[/tex]× [tex]\frac{750}{1}[/tex]= [tex]\frac{750}{3}[/tex]= 250 gramos[tex]\frac{3}{4}[/tex]× 1000 gramos= [tex]\frac{3}{4}[/tex]× [tex]\frac{1000}{1}[/tex]= [tex]\frac{3000}{4}[/tex]= 750 gramos[tex]\frac{3}{5}[/tex]× 200 gramos= [tex]\frac{3}{5}[/tex]× [tex]\frac{200}{1}[/tex]= [tex]\frac{600}{5}[/tex]= 120 gramos

Finalmente, las cantidades que se necesitan para preparar el pastel son 250 gramos de azúcar, 750 gramos de harina y 120 gramos de mantequilla.

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Sydney is considering two jobs. One job pays $45,000 per year. The other job pays a
weekly salary of $950. Which job pays better?

Answers

Answer:

The first job pays more

Step-by-step explanation:

950 x 3 = One month pay = 2,850

2,859 x 12 = One year = 34,308 Per Year

Comparing them both

$45,000 One Year, First Job

$34,308 One Year, Second Job

The midpoint of AB is (3,2). If point is is located at(8,4) what are the coordinates of point B

Answers

Step-by-step explanation:

8-3 = 5,

3-5 = -2 = the x coordinate of B

-2-4 =-6,

-2-6 =-8 = the y coordinate of B

(-2,-8) is the point B

A is 5 to the right of the midpoint, so B is 5 to the left of the midpoint

A is 6 up from the midpoint so B is 6 down from the midpoint

somebody please help me​

Answers

Answer:

1/3

1/2

Step-by-step explanation:

Sum being greter than 8, means 9,10,11,12 (12 is max as 6+6)

You can get 9 in these ways, (6+3),(5+4),(4+5),(3+6)

For 10, (6+4),(5+5),(5+5),(4+6)

For 11, (6+5),(5+6)

For 12 (6+6),(6+6)

Each outcome has probability of 1/6 x 1/6 = 1/36

There are 12 outcomes hence 12(1/36) = 12/36 = 1/3

Part b is 1/2 because half of dice has odd numbers.

Beth took out a loan at an annual compound interest rate of 30%.After 2 years she owes a total of £8112.What was the original amount that Beth Borrowed.Give your answer to the nearest £1

Answers

now, we don't have a compounding period above, so we're assuming the amount is compounding annually.

[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill &\pounds 8112\\ P=\textit{original amount deposited}\\ r=rate\to 30\%\to \frac{30}{100}\dotfill &0.30\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}[/tex]

[tex]8112=P\left(1+\frac{0.30}{1}\right)^{1\cdot 2}\implies 8112=P(1.3)^2\implies \cfrac{8112}{1.3^2}=P\implies 4800=P[/tex]

plssss helppp meeeee​

Answers

Answer: s = 47°

Step-by-step explanation:

     This shape is a hexagon because it has 6 sides.

-> There are 720° total in a hexagon.

   Using this information, we will add together all the angles, set it equal to 720°, and solve for x.

(3s - 41)° + (3s - 12)° + (3s - 38)° + (3s)° + (125)° + (3s-19)° = 720°

3s° - 41° + 3s° - 12° + 3s° - 38° + 3s° + 125° + 3s° - 19° = 720°

3s° + 3s° + 3s° + 3s°+ 3s° - 12° - 38° - 41° + 125° - 19° = 720°

15s° + 15° = 720°

15s° = 705°

s = 47°

Triplets Peter, Reeta and Nikita have two ways for getting home from school each day: cycle on a tandem bike or walk. The bike can carry either one or two riders at a time. Regardless of the number of people pedalling, cycling speed is 5 times walking speed. The triplets always leave school at the same time and always use the same path between school and home, whether walking or cycling. The school is 5km from home and their walking speed is 4 kilometres per hour.

d) On Thursday, it is Reeta's turn to walk. Peter drops Nikita off at a certain point leaving her to walk home, Meanwhile he returns to pick up Reeta and they cycle home together. If all three arrive home at the same time, how far from school are the drop-off ad pick up points.

Answers

Answer:

Pick up point  is 1.43 km from the school and drop point is 3.57 km from the school  ( to the nearest hundredth).

Step-by-step explanation:

School <----------- 5 km ---------------> Home

_______ P _______ D _______        

      x  km          y km        5-x-y km

                     _______

                           y      

                     _________________

                                  5-x km

D is the point where Peter drops off N and P is the pick point x km from the school  where  Peter picks up R. He travels back y km to pick up R.

We work in times:

Time = distance / speed

The time that  R walks from the school to point P is the same  as Peter travels the distance  (x + 2y) km, so we have

x/5 =  (x + 2y)/20

20x = 5x + 10y

15x - 10y = 0     A

The time that N walks home equals the time that Peter travels y + 5 - x km.

So (y + 5 - x)/20 = (5 - x - y)/5

5y + 25 - 5x = 100 - 20x - 20y

15x  + 25y = 75

3x + 5y = 15   B

Solving equation A and B

15x - 10y = 0

3x + 5y = 15

Multiply the second equation by 2:

6x + 10y = 30

Adding this to the first equation

21x = 30

x = 30/21 = 1.4285

So  3(1.4285) + 5y = 15

y = 2.1428

Pick up x  = 1.43 km

and the drop is 1.43 + 2.14 = 3,57 km from the school

What is the slope of the graph?

Answers

Answer:

-x

The slope-intercept equation is y = -x + 1

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

The slope is 1 because it goes 2 units down and then 2 units right. So 2 divided by 2 = 1 as slope.

Area of triangle = 24

Answers

Answer:

[tex]x=-2\pm2\sqrt13[/tex]

Step-by-step explanation:

The area of the triangle is;

[tex]A=\frac{1}{2} \times b\times h[/tex]

[tex]b=x+4[/tex]

[tex]h=x[/tex]

[tex]Area=A=24[/tex]

[tex]A=\frac{1}{2}\times[(x+4)\times x] \\24=\frac{x^{2} +4x}{2} \\24\times2=x^{2} +4x\\48=x^{2} +4x\\x^{2} +4x-48=0\\[/tex]

This can only be solved by the quadratic formula.

[tex]x=\frac{-b\pm\sqrt {b^{2}-4ac }}{2a}[/tex]

where;

[tex]a=1\\b=4\\c=-48[/tex]

and we get,

[tex]x=-2\pm2\sqrt13[/tex]

Estimate
754÷13
Hurry up please

Answers

Answer:

754 divided by 13= 58

I hope this Helps! ;)

I believe it's 58 my friend! :)

A plane flies from Dubbo on a bearing of 139° for 852 km, then turns and flies on a bearing of 285° until it is due west of Dubbo. How far from Dubbo is the plane, to the nearest km?

Answers

Answer:

Step-by-step explanation:

So first you add them together which gives you infinity and then you divide infinity by (139+285) then keep doing it until you realise this is a scam

A straight line whose equation is 3y-2x=-2 meets the x-axis at R determine the coordinates of R

Answers

Answer:

3y-2x=-2

The straight line meets the X-axis when y = 0

Hence, 3(0) - 2(x) = -2

2x = 2

x = 1

Therefore, the coordinates of R is (1,0)

Can you simplify 10/24

Answers

Answer: 5/12

Step-by-step explanation: basically divide each number (10 &24) by 2

Select the correct answer.

Which function is represented by this graph?

Answers

The correct answer is the 2nd one

What is the area of the trapezoid? a trapezoid has a base of 10 meters, a height of 7 inches, and a top side length of 6 inches. 49 in.2 56 in.2 67 in.2 74 in.2

Answers

The formula for calculating the area of a trapezoid is expressed as A = 0.5(a+b)h. The given area of the trapezoid is 1398.9 square inches

Area of a trapezoid

The formula for calculating the area of a trapezoid is expressed as:

A = 0.5(a+b)h

Given the following parameters

a = 10m = 393.7in

b = 6in

h = 7in

Substitute

A = 0.5(393.7 + 6) * 7
A = 0.5 * 399.7 7
A = 1398.9 square inches

Hence the given area of the trapezoid is 1398.9 square inches

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Answer:

The correct answer is 56. This is correct on e d g e .

Step-by-step explanation:

We add together the two bases, divide by two, and then multiply by the height, getting 56. I hope this helps anyone on the exam

PLEASE HELP 100 POINTS AND BRAINLIEST

Answers

Answer:

I did the work and uploaded the answers i hope it helped!!

19. Solve for the angle x.
sin²(2x) = 1

Answers

Answer: Е

Step-by-step explanation:

▪︎ a^2 - b^2 = (a-b)(a+b)

sin^2(2x) = 1

sin^2(2x) - 1 = 0

(sin2x - 1)(sin2x + 1) = 0

sin2x - 1 = 0 or sin2x + 1 = 0

sin2x - 1 = 0

sin2x = 1

2x = 90° + 360°n

x = 45° + 180°n

▪︎180° means half of the unit circle, therefore,

x = 45° + 360°n and

x = 45° + 180° + 360°n = 225° + 360°n

sin2x + 1 = 0

sin2x = -1

2x = 270° + 360°n

x = 135° + 180°n

therefore,

x = 135° + 360°n and

x = 135° + 180° + 360°n = 315° + 360°n

n is an integer

The volume of a sphere with radius r
is given by the formula V=4/3 π r^3.
Find the volume of a sphere with radius 10 cm is?

Answers

Answer:

4186.6 cm³

[tex] \: [/tex]

Step-by-step explanation:

In the question, it is given that a sphere has a radius of 10 cm and we have to find the volume of the sphere.

To Find the volume of the cone, we must know this formula :

[tex]\\{\longrightarrow{ \qquad{\underline{\boxed {\pmb{\frak { Volume_{(sphere) }= \dfrac{4}{3} \: \pi {r}^{3}}}}}}}} \\ \\[/tex]

Now, we will substitute the values in the formula :

[tex]\\{\longrightarrow{ \qquad{ {\pmb{\sf { Volume_{(sphere) }= \dfrac{4}{3} \: \times 3.14 \times {(10)}^{3}}}}}}} \\ \\[/tex]

[tex]\\{\longrightarrow{ \qquad{ {\pmb{\sf { Volume_{(sphere) }= \dfrac{4}{3} \: \times 3.14 \times 1000}}}}}} \\ \\[/tex]

[tex]\\{\longrightarrow{ \qquad{ {\pmb{\sf { Volume_{(sphere) }= \dfrac{4}{3} \: \times 3140}}}}}} \\ \\[/tex]

[tex]\\{\longrightarrow{ \qquad{ {\pmb{\sf { Volume_{(sphere) }= \dfrac{4 \times 3140}{3} }}}}}} \\ \\[/tex]

[tex]\\{\longrightarrow{ \qquad{ {\pmb{\sf { Volume_{(sphere) }= \dfrac{12560}{3} }}}}}} \\ \\[/tex]

[tex]\\{\longrightarrow{ \qquad{ {\pmb{\sf { Volume_{(sphere) }= 4186.6 }}}}}} \\ \\[/tex]

Therefore,

The volume of the sphere is 4186.6 cm³

Given :

Radius of sphere is 10 cm.

To Find :

Volume of sphere.

Solution :

As we know that volume of sphere is calculated by the formula :

V = 4/3 πr³

Here,

V is volume r is radius Value of π is 22/7

Putting the values in the formula,

>> V = (4 / 3) × (22 / 7) × (10)³

>> V = (4 / 3) × (22 / 7) × (10 × 10 × 10)

>> V = (4 / 3) × (22 / 7) × (10 × 100)

>> V = (4 / 3) × (22 / 7) × 1000

>> V = 4 × 22 × 1000 / 3 × 7

>> V = 88 × 1000 / 3 × 7

>> V = 88000 / 3 × 7

>> V = 88000 / 21

>> V = 4190.47 cm³

Expand to write an equivalent expression
-1/4 (-8x + 12y)

Answers

The equivalent expression on expanding -1/4 (-8x + 12y) is 2x - 3y

Expansion of expression

Expansion of expression can be carried out using the distributive rule a shown:

A(B + C) = AB + AC

Note that A is distributed over B and C
Given the expression

-1/4 (-8x + 12y)

-1/4(-8x) - 1/4(12y)

2x - 3y

Hence the equivalent expression on expanding -1/4 (-8x + 12y) is 2x - 3y

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30 points!! What is the equation of this line?

Answers

Answer:

y = - 2x

Step-by-step explanation:

the equation of a line passing through the origin is

y = mx ( m is the slope )

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (- 1, 2) ← 2 points on the line

m = [tex]\frac{2-0}{-1-0}[/tex] = [tex]\frac{2}{-1}[/tex] = - 2 , then

y = - 2x ← equation of line

How do the average rates of change for f(x) = -0.5x² and g(x) = -1.5x² over the interval -5 ≤ x ≤ -2 compare?​

Answers

Pick an x-value between the interval givens. I’ll choose “1”. If you sub in one for both f(x) and g(x) you get that f(1) = -1.5 and g(1) = -0.5. Now you can divide f(1) by g(1) to get average rate of change. -1.5/-0.5 = 3.

=
Given that f(x) = 2x – 2 and
g(x) = 3x, evaluate
,
f(g(-1))

Answers

Hope this is not confusing.

If , the ratio of the length of to the length of is .

Answers

Given the ratio of 5 : 3, the length of the rectangle is 45 units

How to determine the length?

The ratio is given as:

Length : Width = 5 : 3

The perimeter is given as:

Perimeter = 144

The perimeter of a rectangle is:

Perimeter = 2 * (Length + Width)

So, we have:

2 * (Length + Width) = 144

Divide both sides by 2

Length + Width = 72

Recall that:

Length : Width = 5 : 3

Express as fraction

Length/Width = 5/3

Make Width the subject

Width = 3Length/5

Substitute Width = 3Length/5 in Length + Width = 72

Length + 3Length/5  = 72

Multiply through by 5

5Length + 3Length  = 360

This gives

8Length  = 360

Divide both sides by 8

Length  = 45

Hence, the length of the rectangle is 45 units

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What is the value of x in this figure?
O x=85
O x= 90
O x= 95

Answers

35° + 60° + x° = 180°

95° + x° = 180°

x° = 180° - 95°

x° = 85°

In any triangle, the sum of its interior angles measures 180º.

HELPPP. DO TODAY SO PLEASE HELP!!!!!!!!!!

Answers

Answer:

47/6cm or [tex]7\frac{5}{6}[/tex]cm

Step-by-step explanation:

FE= [tex]2\frac{2}{3}[/tex]

FA= 5/12

AB= 2/3

CD=2

ED=[tex]1\frac{1}{4}[/tex]

BC= 5/6

All=47/6 or [tex]7\frac{5}{6}[/tex]

WILL GIVE 100 POINTS TO WHO ANSWERS THESE!!! Questions in Pictures.
Polynomials and Factoring

Answers

Assuming that you want the product of the two factors given in each problem:

 ⇒ we solve this problem by timing each unit of a factor to every unit

     of the other factor

   ⇒then add each one of them who shares a common like-term

      ⇒to get the answer

Let's solve:

Question 9:

            [tex](4m+n)(m-2n)=4m*m+(-2n)*4m+n*m+n(-2n)\\=4m^2-7nm-2n^2[/tex]

Question 12

            [tex](2a-4b)(7a-2b)=2a*7a+(-2b)(2a)+(-4b)7a+(-4b)(-2b)\\=14a^2-4ab-28ab+8b^2\\=14a^2-32ab+8b^2[/tex]

Question 15

            [tex](4m+1)^2=(4m+1)(4m+1)=4m*4m+4m*1+1*4m+1\\=16m^2+4m+4m+1\\=16m^2+8m+1[/tex]

Question 18

            [tex](2w+1)(2w-1)=2w*2w+2w(-1)+1*(2w)+1(-1)\\=4w^2-1[/tex]

Question 21:

            [tex](m+3)(m^2+4m+7)\\=m*m^2+m*4m+m*7+3m^2+3*4m+3*7\\=m^3+4m^2+7m+3m^2+12m+21\\=m^3+7m^2+19m+21[/tex]

Question 24:

           [tex](3x+2)(5x^2-12x-2)\\=3x*5x^2+3x(-12x)+3x(-2)+2(5x^2)+2(-12x)+2(-2)\\=15x^3-36x^2-6x+10x^2-24x-4\\=15x^3-26x^2-30x-4[/tex]

Hope that helps!

Did I solve this problem correctly?

Answers

Answer:

yes

Step-by-step explanation:

yeah i think you did
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