PLEASE HELP 100 POINTS! Please fill in the scale distance from sun and diversion factor, listing off the numbers works

Answer:

10.75 m/s

Explanation:

let  velocity of Dodgems b  be y

law of conservation of momentum

120 x 10 + 160 x 7=120x5+ 160 x y

1200+1120 = 600 + 160 x y

160y = 1720

y = 10.75 m/s

The distance traveled by the object in the first 1 second is determined as 0.98 m.

The distance traveled by the object is calculated as follows;

F - μkmgcosθ = ma

0 - μkmgcosθ = ma

- μkgcosθ = a

-(0.4)(9.8)cos60 = a

- 1.96 m/s² = a

s = ut + ¹/₂at²

s = 0(1) + ¹/₂(-1.96)(1)²

s = -0.98 m

|s| = 0.98 m

Thus, the distance traveled by the object in the first 1 second is determined as 0.98 m.

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The net force on the block is 20.678 N. Force is defined as the product of mass and acceleration. Its unit is Newton.

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Anujan rope pulls with a force of 35 N [35° N of W]. The force is resolved in x and y direction as;

[tex]\rm F_{1x}= 35 cos 35^0 \\\\ F_{1y}=35 sin 35^0[/tex]

Piragavy pulls with a force of 11 N [41° S of E]. The force is resolved in x and y direction as;

[tex]\rm F_{2x}= 11 cos 41^0 \\\\ F_{2y}=11 sin 41^0[/tex]

The net force on the block is;

[tex]\rm F_{net}=F_{1x}-F_{2x}\\\\\ F_{net}=35 \ cos 35^0- 11 \cos 41^0 \\\\ F_{net}=20.678 \ N[/tex]

Hence,the net force on the block is 20.678 N.

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Sonar is used to determine the speed of an object. The object is moving at 8.4146 m/s.

The frequency of any wave is defined as the number of cycles per second.

The frequency of the sound received is

f' = f x [(V+Vo /V-Vo)]

where f = 40kHz, f' = 42kHz, V =345 m/s, then the velocity of the observer will be

(V+Vo /V-Vo) = 42/40 =1.05

On rearranging the doppler shift formula, we have

Vo = 0.05 x 345 /2.05

Vo = 8.4146 m/s.

Thus, the object is moving at 8.4146 m/s.

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The centripetal acceleration of the aeroplane is determined as 7.03 m/s².

The centripetal acceleration of the aeroplane is calculated as follows;

ac = v²/r

where;'

ac = (75²)/(800)

ac = 7.03 m/s²

Thus, the centripetal acceleration of the aeroplane is determined as 7.03 m/s².

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Answer:

Q = c M ΔT      where c is the heat capacity and M the mass present

Q2 / Q1 = M2 / M1    since the other factors are the same

M = ρ V     where ρ is the density

M = ρ Π (d / 2)^2           where d is the diameter of the sphere

M2 / M1 = (2 D/2)^2 / (D/2)^2 = 4

It will take 4Q heat to heat the second sphere

The distance between the aliens traveling in group and their launchpad in kilometers is 40.23km.

Given that data in the question;

Note that;

1 miles = 1.609 kilometers

Now, the distance in kilometers will be;

distance = 25 miles

distance = ( 25 × 1.609 )kilometers

distance = 40.23km

Therefore, the distance between the aliens traveling in group and their launchpad in kilometers is 40.23km.

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The kind of atoms or molecules are present and their relative abundance can be determined by observing wavelengths.

Wavelength is the distance between adjacent crest or trough of the wave.

The light travels in the form of wave and particle. It behaves like both. Light ray consist energy of the photons. The kind of atoms or molecules present behave like particle and they have particular wavelength.

Thus, by observing wavelength , we can determine the kind of atoms or  molecules are present and their relative abundance.

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If the current is held constant, an increase in voltage will result in an increase in resistance.

hope it helps...!!!

Answer:

[tex]\huge\boxed{\sf f=0.55 \ Hz}[/tex]

Explanation:

Given Data:

Length = l = 820 mm = 0.82 m

Acceleration due to gravity = g = 9.8 ms⁻²

Required:

Frequency = f = ?

Formula:

[tex]\displaystyle f =\frac{1}{2 \pi} \sqrt{\frac{g}{l} }[/tex]

Solution:

[tex]\displaystyle f =\frac{1}{2 \pi} \sqrt{\frac{g}{l} } \\\\Put\ the\ givens\\\\f=\frac{1}{2 \pi} \sqrt{\frac{9.8}{0.82} }\\\\ f = 0.159 \times \sqrt{11.95} \\\\f=0.159 \times 3.457\\\\f=0.55 \ Hz\\\\\rule[225]{225}{2}[/tex]

Answer:

What is the interaction between two different species in an ecosystem called?

Interactions between different species in a community are called interspecific interactions—inter- means "between." Different types of interspecific interactions have different effects on the two participants, which may be positive (+), negative (-), or neutral (0).

Explanation:

When q₂ is place between q₁ and q₃, the net force on q₂ is 0.486N.

The electrostatic force of attraction or repulsion is proportional to the product of magnitude of charges and inversely proportional to the square of distance between them.

Force on q₂ due to q₁

F₁₂ = kq₁q₂ / r₁₂²

Substitute the values provided , we get

F₁₂ = 9 x 10⁹ x 5 x 10⁻⁶ x 2.5 x 10⁻⁶ / (0.5)²

F₁₂ = 0.414 N

Force on q₂ due to q₃ placed at distance 0.25m

F₂₃ =kq₂q₃ / r₂₃²

Substitute the values, we get

F₂₃ =  9 x 10⁹ x 2.5 x 10⁻⁶ x 2.5 x 10⁻⁶ / (0.25)²

F₂₃ = 0.9N

The net force F =F₂₃ -F₁₂

F =0.9 - 0.414 = 0.486 N

Thus, the net force of q₂ is 0.486 N.

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Answer:

0.45

Explanation:

trust me

Answer:

Gravitational force is an attraction between masses. The greater the size of the masses, the greater the size of the gravitational force (also called the gravity force). The gravitational force weakens rapidly with increasing distance between masses

Answer:

gravity

Explanation:

as the earth rotates on an axis, it causes an effect known as centripetal acceleration with is an acceleration that pulls objects towards the center of the object. in planets, we call this Gravity

Answer:

See below

Explanation:

The initial downward velocity, the acceleration of gravity and air friction all play a part

Answer:

The correct answer is - C.  Increasing the concentration increases the reaction rate.

Explanation:

Answer:

B. Increasing the temperature increases the reaction rate.

Explanation:

The reaction time column displays how long the reaction ran for. If a reaction rate was fast then time taken for reaction to run would be slow right?

Therefore, original condition had reaction time of 10 second, but increaseing temperature lowered the time to 5 second, which must mean that reaction rate increased.

v² = u² + 2as

v² = 4² + 2 × 1.2 × 20

v² = 16 + 2 × 12/10 × 20

v² = 16 + 48

v² = 64

v = 8 ms - 1

ii)

V = u + at

8 = 4 + 1.2 × t

8 - 4 = 1.2t

4 = 12/10 t

4 × 10 /12 = t

3.33 = t

Average velocity = Displacement/Time

20/3.33

6.006 ms - 1

F=m.a

a = F/m

a = 90/65

a = 1.385 m/s²

Answer:

solution

here,

Explanation:

weight = 90N

mass=65kg

acceleration due to gravity (g)=??

Now,

w=m×g

90=65×g

90/65=g

:g=1.38m/s^2

The coefficient of linear expansion of the metal at the given length is determined as  3.75 x 10⁻⁴/⁰C.

The coeffcient of linear expansion of the metal is calculated as follows;

ΔL = αLΔT

α = ΔL/LΔT

Where;

α = (1.5)/(20 x 200)

α = 3.75 x 10⁻⁴/⁰C

The complete question is below:

A metallic axle with a diameter of 20mm has to be fitted into a wheel which has a circular hole at its center with diameter of 18.5mm. To fit the axle into the hole, the axle is dipped into liquid nitrogen at a temperature of -200°C. Calculate the coefficient of linear expansion of the metal.

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Answer:

real depth / apparent depth = R.I.

Real depth = 1.5 x 1 = 1.5 m

f = μk.N (N = m.g)

f = 0.29 x 95 x 10

f = 275.5 N

Answer:

option C...

resistance training is the correct answer

The rate at which energy is lost from the whale's core from the core/blubber interface through the blubber to the skin is 3,162.5 W.

The rate of conduction of core/blubber interface is calculated as follows;

[tex]\frac{Q}{t} = \frac{kA\Delta T}{d}[/tex]

where;

[tex]\frac{Q}{t} = \frac{kA\Delta T}{d} = \frac{kA}{d} (\Delta Ta \ +\Delta Tb)\\\\\frac{Q}{t} = \frac{kA}{d} ((T_1- T_2 \ +\ T_2-T_3)\\\\\frac{Q}{t} = \frac{0.25 \times 22}{0.04} ( 35 - 29 \ + \ 29 - 12)\\\\\frac{Q}{t} = 137.5( 6 + 17)\\\\\frac{Q}{t} = 3,162.5 \ W[/tex]

Thus, the rate at which energy is lost from the whale's core from the core/blubber interface through the blubber to the skin is 3,162.5 W.

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[tex] \large \sf \underline{Question:}[/tex]

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[tex] \large \sf \underline{Answer:}[/tex]

[tex] \qquad \qquad \huge \bold{Option \: D}[/tex]

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[tex] \large \sf \underline{Explanation:}[/tex]

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Explanation:

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Answer:

P V = N R T     ideal gas equation

P2 / P1 = T2 / T1       where the other variables are constant

P2 = (T2 / T1) * P1 = (313 / 293) * 40 psi = 42.7 psi

Hi there!

We can begin by deriving the magnetic field strength for a circular loop at its center.

Using Biot-Savart's Law:
[tex]dB = \frac{\mu_0}{4\pi }\frac{idl \times \^r}{r^2}[/tex]

μ₀ = Permeability of free space (Tm/A)

dl = Differential length element

r = radius (m)

We can rather use 'ds' to represent a differential arc length since we are finding the magnetic field for a circular loop.

We must begin by dealing with the cross-product. Luckily, this derivation is simple since the radius vector is ALWAYS perpendicular to the path of integration along the loop's circumference. (ONLY if we are finding the field for the direct center.) Thus, since sin(90) = 1, we can get rid of the cross-product.

Therefore:

[tex]dB = \frac{\mu_0}{4\pi }\frac{ids}{r^2}[/tex]

Now, we can integrate with respect to ds.

[tex]= \frac{\mu_0}{4\pi }\int\limits^{2\pi r}_0 {\frac{i}{r^2}} \, ds\\\\ = \frac{\mu_0}{4\pi }{\frac{i * 2\pi r}{r^2}} \, ds[/tex]

Simplify:

[tex]B = \frac{\mu_0 i_{circle}}{2r}\\[/tex]

Now, for a straight conductor (assuming of infinite length), we know the magnetic field strength equation to be:

[tex]B = \frac{\mu_0 i_{rod}}{2\pi r}[/tex]

Set the two equal.

[tex]\frac{\mu_0 i_{circle}}{2r}= \frac{\mu_0 i_{rod}}{2\pi r}[/tex]

Cancel out '2', μ₀, and 'r':
[tex]i_{circle}}= \frac{ i_{rod}}{\pi }[/tex]

Plug in the given values and solve.

[tex]40\pi = i_{rod}\\\\i_{rod} = \boxed{125.663 A}[/tex]