λ = c : f
λ = 3 x 10⁸ : 1.05 x 10⁸
λ = 2.86 m
E = hf
h = Planck's constant (6.626.10⁻³⁴ Js)
E = 6.626.10⁻³⁴ x 2.86
E = 1.896 x 10⁻³³ J
λ = 3 x 10⁸ : 1.011 x 10⁸
λ = 2.97 m
E = hf
h = Planck's constant (6.626.10⁻³⁴ Js)
E = 6.626.10⁻³⁴ x 2.97
E = 1.97 x 10⁻³³ J
λ = 3 x 10⁸ : 1.05 x 10⁸
λ = 2.96 m
E = hf
h = Planck's constant (6.626.10⁻³⁴ Js)
E = 6.626.10⁻³⁴ x 2.96
E = 1.96 x 10⁻³³ J
what is the difference between 1 Newton/ metre² and 1 Pascal
Explain !!
Answer:
One pascal is equivalent to 1 newton (N) of force applied over an area of 1 square meter (m2). The pascal is also used to measure stress, specifically tectonic stress in the Earth's plates.
Explanation:
What is one way that trees can be like fossil fuels? A. They do not produce carbon dioxide when burned. B. They both grow. C. We can use our supply fa … ster than they can be replenished. D. They can not be replenished at all.
Answer:
Answer C. But don't be surprised if it isn't.
Explanation:
You can't use D. Trees can be replenished. Maybe not as well as God planted them in the first place, but we can replenish them.
A is incorrect. when burned, trees will produce CO2. In fact, trees produce more CO2 when burned that do fossil fuels do
Fossil fuels don't grow. Their rate of discovery might, but they themselves don't grow. Not B
C is your only choice. The problem is that it is not entirely true. We can replenish trees. Whether enough trees can be used as a clean fuel and be replaced in amounts we are used is the question.
Two differences between science activities carried out in a science laboratory and those carried out side of science laboratory.
Please answer quickly for brainliest
In a science lab, there is the adequate availability of raw materials for experiments such as chemicals while outside a science lab there isn't.
In a science lab, the availability of apparatuses and sources of heat is higher than outside a science lab.
What is science laboratory?The science lab is a place where the experiments related to the science background are performed with the use of apparatus.
The science lab has plenty of equipment to perform the experiment whether related to physics or chemistry or biology.
Thus, source of heat and availability of raw material and equipment are the differences between the science activities carried out in a science laboratory and those carried out side of science laboratory.
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A train moving west with an initial velocity of 20 m/s accelerates at 4 m/s' for 10 secon
moves a distance of
a
meters.
Answer:
Distance of 400m.
Explanation:
Use your kinematics equation to solve for distance (we can use kinematics b/c acceleration is constant).
d = (initial velocity x time) + 1/2 at^2
d = (20 x 10) + 1/2 (4) (10)^2
d = 200 + 200
d = 400 m
Spirderman’s nemesis Electro delivers 4kJ of electrical energy in half a second. How powerful is he?
How are u? I hope u doing well ااااااااااااااااا
Answer:
Hey
I'm alright and you
I also hope you're doing well
5 postulates of neil bohr atomic model
Answer:
What is Bohr’s Model of an Atom?
The Bohr model of the atom was proposed by Neil Bohr in 1915. It came into existence with the modification of Rutherford’s model of an atom. Rutherford’s model introduced the nuclear model of an atom, in which he explained that a nucleus (positively charged) is surrounded by negatively charged electrons.
Formulating an Investigative Question
In this lab, you will use a magnet and a simple circuit to
examine the concepts of electricity and magnetism. Think
about how these ideas can be shown experimentally.
In the space below, write a scientific question to address
by doing this experiment.
A magnet can be used to show electromagnetic forces by showing how negative charges can move a particular piece of metal.
What is a scientific question?A scientific question is a given question derived from observation of the real world and can be answered by applying the scientific method.
In this case, a plausible scientific question might be how electromagnetic forces can move a piece of metal and we need to develop an explanation (hypothesis) to understand it.
In conclusion, a magnet can be used to show electromagnetic forces by showing how negative charges can move a metal.
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Answer:
How can magnetic and electric fields be demonstrated?
Explanation:
How much work is done on the object as it moves from 6.0m to 9.0m
Answer:
W = 3F
Explanation:
Work is defined as the inner product between force and displacement. The inner product picks out the force components which point in the same direction as the displacement. The vertical components do not matter in the horizontal displacement. I am assuming you're dealing with 1-dimensional motion? Then the work would be:
[tex]W=Fd[/tex]
The displacement is 3 meters. Therefore, the work is:
[tex]W=3F[/tex]
You haven't gave the force being applied to the object, so I cannot give an explicit answer. Just multiply the force by 3 to get the work.
Drag each label to the correct location on the image
Identify the particles and characteristics on this model of an atom
(Provide picture to explain more clearly)
A- Positively Charged
B- Electron
C- Proton
E- Neutron
D- Negatively Charged
Answer:
you cant really give any answers because i cant tell u were to drag
a simple generator has 200 loop square coil 10 cm on a side .how fast must it turn in a 0.25 T field to produce 24v peak out put
Hi there!
Recall Faraday's Law:
[tex]\epsilon = N\frac{d\Phi_B}{dt}[/tex]
ε = Emf (V)
N = Number of loops
ΦB = Magnetic Flux (Wb)
t = time (s)
Since the magnetic field is constant, we can take this out of the time derivative:
[tex]\frac{d\Phi_B}{dt} = B * \frac{dA}{dt}[/tex]
Therefore:
[tex]\epsilon = N B \frac{dA}{dt}[/tex]
We can express 'A', the area in which the magnetic field passes as:
[tex]A = Acos(\omega t)[/tex]
Taking the time derivative:
[tex]\frac{dA}{dt} = A\omega sin(\omega t)[/tex]
ω = angular speed of coil (rad/sec)
Now, combine with the above expression:
[tex]\epsilon = NBA\omega sin(\omega t)[/tex]
The maximum output will occur when the loop's area vector is PERPENDICULAR to the field, so sin(ωt) = 1.
Therefore:
[tex]\epsilon = NBA\omega \\\\[/tex]
Rearrange to solve for ω:
[tex]\omega = \frac{\epsilon}{NBA}\\\\\omega = \frac{24}{(200 * (.10^2) * 0.25} = \boxed{48 \frac{rad}{sec}}[/tex]
A diverging lens with f = -33.5 cm is placed 14 cm behind converging lens with f = 20cm. where will an object at infinity be focused?
Answer:
Explanation:
Focal length of diverging lens,
fd= -33.5 cm
focal length of converging lens,
fc = 20 cm
Now let s is object distance and s' is image distance.
Now using lens formula for conversing lens
\frac1{f_c}=\frac1{s}+\frac1{s'}
f
c
1
=
s
1
+
s
′
1
Putting all values(object is at s=infinity)
Then image distance
\frac1{s'}= \frac1{f_c}- \frac1{s}
s
′
1
=
f
c
1
−
s
1
=\frac1{20}- \frac1{\infin}=
20
1
−
∞
1
s'=20cms
′
=20cm
Now using lens formula for diversing lens
s''=14-20=-6cm
Using lens formula
\frac{1}{-33.5} = \frac{1}{-6 }+ \frac{1}{s''' }\\s'''=\frac{(6)\times(-33.5)}{(-33.5+6)}\\s'''=\frac{(-201) }{(-27.5) }
−33.5
1
=
−6
1
+
s
′′′
1
s
′′′
=
(−33.5+6)
(6)×(−33.5)
s
′′′
=
(−27.5)
(−201)
image distance for diverging lens
s''' = 7.3 cm (behind the diverging lens)
A diverging lens with f = -33.5 cm is placed 14 cm behind converging lens with f = 20cm. image distance for diverging lens, s''' = 7.3 cm (behind the diverging lens)
what are the type of lens ?When a lens in the path of a beam of parallel rays causes the rays to diverge after refraction, it is referred to as a diverging lens.
It always creates a virtual image and has a thinner core than its boundaries.
Concave lenses(diverging lenses) function as diverging lenses because they cause light rays to diverge as they pass through them.
Therefore, when used with air as the operating medium, a concave lens can be thought of as a diverging lens.
The concave lens has several applications, including in telescopes, cameras, lasers, glasses, binoculars, and other optical devices.
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The units of Work, Energy and power are________ ________units.
Answer:
the units of work and energy is joule and unit of power is Watt
Compute g at a height of 7 RE above the surface of Earth (RE=6.4E+6m, ME=6.0E+24kg).
The acceleration due to gravity g at height 7 times the radius of Earth above the surface of the Earth is 8.933 m/s².
What is acceleration due to gravity?It is the acceleration caused by any object when placed on the surface on the Earth due to its weight.
The acceleration due to gravity is related to the distance as
g =GM/R²
where G is the gravitational constant = 6.67 x 10⁻¹¹ N.m²/kg²
Given is the height R = 7 x 6.4 x 10⁶ m and mass of Earth M = 6 x 10²⁴ kg
Substitute the values into the expression to find the acceleration due to gravity.
g = ( 6.67 x 10⁻¹¹ x 6 x 10²⁴)/ ( 7 x 6.4 x 10⁶)²
g = 8.933 m/s²
Thus, the acceleration due to gravity g at height 7 times the radius of Earth above the surface of the Earth is 8.933 m/s².
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Define the concept of heat. What is heat?
Answer:
In a simplest terms,
temperature is how hot or cold an object is, while heat is the energy that flows from a hotter object to cooler one
Suppose you were to make a three-dimensional model of magnetic force
using magnetic field lines and a magnet. Which two characteristics might
your model have?
A. The field lines exist only at the top and the bottom of the magnet.
B. Arrows on the field lines point from the magnet's north pole to its
south pole.
C. The field lines near the magnet are far apart.
D. The field lines do not cross paths as they go from one pole of the
magnet to the other.
दा
Answer:
D. Po cguro pero I will study hard to get the correct answer and I will share to you pero I try mo Lang po Yan kac halos kami dito Yan po Yung nilagay namin na answer baka kac Tama po e Kaya tau mag aral po tau ng mabuti Para MAtopad natin Yung mga pangarap natin at making tau sa mga pamilya at guro Yung Lang po good bless
A 6.20-kg steel ball at 27.7°C is dropped from a height of 21.7 m into an insulated container with 4.50 L of water at 10.1°C. If no water splashes, what is the final temperature of the water and steel? The specific heat of steel and water is 450J / (kg - K) and 4186J / (kg - K) respectively.
The final temperature of the water and steel mixture after the steel is dropped is determined as 7.12 ⁰C.
Conservation of energy
From the principle of conservation of energy, the energy lost by the steel ball is equal to the energy gained by the water.
P.E(steel) - Thermal(steel) = Thermal(water)
mgh - mcΔθ = mcΔθ
where;
mass of water = density x volume = 1 kg/L x 4.5 L = 4.5 kg(6.2)(9.8)(21.7) - (6.2)(450)(27.7 - T) = (4.5)(4186)(T - 10.1)
1,318.492 - 77,283 + 2790T = 18,837T - 190,253.7
114,289.192 = 16,047T
T = 7.12 ⁰C
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You are walking through the woods and cone acroos an old well thats 15 meters deep if the speed of sound and air is 340 m/s then how long would it take to hear echo
Answer:
.0882 s
Explanation:
Sound has to travel to the bottom (15 m) then back up (15m ) to hear the echo
(15 + 15 m) / 340 m/s = .0882 s
Two identical pucks of equal but unknown mass head straight towards each other with velocities
of 8.0 m/s and -6.0 m/s. They collide and stick together. What is their resulting velocity?
inelastic collision
m.8 - m.6 = 2mv'
2m = 2mv'
v' = 1 m/s
Answer:
1 m/s
Explanation:
According to the Law of Conservation of Momentum, (for inelastic collisions)
v = m₁v₁ + m₂v₂ / m₁ + m₂v = 8m - 6m / 2mv = 2m/2mv = 1 m/sWhat is the de-Broglie wavelength of a 70kg person jogging at the rate of 2.70m/s. the mass of an electron is 9.11 x 10-28g, the speed of light is 3.00 x 108m/s, planks constant is 6.63 x 10-34js.
The de-Broglie wavelength of a person jogging at the rate of 2.70m/s is 3.5 x 10⁻³² m.
What is de-Broglie wavelength?De-Broglie wavelength is the ratio of Planck's constant h to the momentum of the electron p.
Momentum p = mass m x velocity v
Given is the mass of a person = 70kg, the speed of person 2.70m/s, Planck's constant h= 6.63 x 10⁻³⁴J.s
De- Broglie wavelength λ= h/mv
λ = 6.63 x 10⁻³⁴/ ( 70 x 2.70)
λ = 3.5 x 10⁻³² m
Thus the wavelength is 3.5 x 10⁻³² m.
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an ldeal gas with internal energy U at 202°C is heated to 410°C.its internal energy then will be?
Internal energy is directly proportional to temperature
U1T2=U2T1U(273+410)=U2(273+202)683U=475U_2U_2=1.44U A object moving in 3m radius circular path,
when it reaches the beginning point again, then
the displacement in m equals:
Answer:
0
Explanation:
Physically:
Beginning point means initial point so you're basically going into circles which means a displacement of zero.
Mathematically:
[tex]d = x _{f} - x _{i}[/tex]
We know
[tex]x _{f} =x _{i}[/tex]
So we get
[tex]d = x _{f} - x _{f}[/tex]
[tex]d = 0[/tex]
Assume the roller coaster experiences no friction. What would be the speed of the roller
coaster at point F? Defend your answer in 1-2 sentences.
The roller coaster experiences no friction, the speed of the roller
coaster at point F is mathematically given as
v= 65.72 m/s
What would be the speed of the roller coaster at point F?Generally, the equation for the Mechanical enegy is is mathematically given as
ME = mgh + 1/2mv^2
Therefore
ME= 80*9.8*200 + 1/2*80*20^2
ME= 172800 J
In conclusion, the speed of the roller coaster at point F is
ME=1/2*m*V^2
172800 = 1/2*80*V^2
v= 65.72 m/s
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Sana loved swimming.She joined a new smimmimg club .When she looked at the floor of the pool to estimate its depth she found that it was shallow .But when she dived in the pool she found out that the pool was quiet deep.Write down the scientific reason for this situation?
Answer:
Refraction
Explanation:
When light passes from a rarer medium into a denser medium, it bends in the medium away from the normal. This creates the phenomenon of "apparent depth" as given in the question.
A satellite with a mass of 150 kg fires its engines to increase velocity, thereby
increasing the size of its orbit about Earth. As a result, it moves from a
circular orbit of radius 7.5 x 106 m to an orbit of radius 7.7 x 106 m. What is
the approximate change in gravitational force from Earth as a result of this
change in the satellite's orbit? (Recall that Earth has a mass of 5.97 x 1024 kg
and G = 6.67 x 10-11 N-m²/kg².)
OA. -113 N
OB. -148 N
O C. -216 N
D. -54 N
The approximate change in gravitational force from Earth as a result of the change in radius of the satellite's orbit is 5. 35N
What is the universal law of gravitation?The universal law of gravitation states that the particle of matter in the universe attracts another particle with a force directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
It is written thus;
F = G MIM2÷ r∧2
Where
F = Gravitational force
G = Gravitational constant
M1 and M2 are the masses of the object
r = radius
How to calculate the gravitational forceFormula:
F = G MIM2 ÷ r∧2
Given M1 = 150kg, M2 = 5.97 x 1024 kg, r = 7.5 x 106 m, G = 6.67 x 10-11 N-m²/kg²
For the first orbit, substitute the values
F = 6.67 x 10∧-11 × 150 × 5.97 x 10∧24 ÷ (7.5 x 10∧6)²
F = 5.95 × 10∧16 ÷ 56.25 × 10∧12 = 105.77 N
For the second orbit of radius 7.7 x 106 m
F = 6.67 x 10∧-11 × 150 × 5.97 x 10∧24 ÷ (7.7 x 10∧6)²
F = 5.95 × 10∧16 ÷ 59.25 × 10∧12 = 100. 42 N
The approximate change = 105. 77 - 100.42 = 5. 35N
Hence, the approximate change in gravitational force from Earth as a result of the change in radius of the satellite's orbit is 5. 35N
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if the initial velocity of body is 2 metre per second and final velocity is four metre per second calculate average velocity
Answer:
3 m/s
Explanation:
Average velocity = Initial velocity + Final velocity / 2
Solving :
⇒ Average velocity = 2 + 4 / 2
⇒ Average velocity = 6/2
⇒ Average velocity = 3 m/s
if the initial velocity of body is 2 metre per second and final velocity is four metre per second calculate average velocity
Solution:AV = 2 + 4 / 2AV = 6/2AV = 6 ÷ 2AV = 3m/sSo the average velocity is 3ms.
What is the mass of a ball that has 29j of potential energy and is lifted 2.0m?
Answer:
1.48kg
Explanation:
Here,
potential energy (P.E) = 29j
height (h) = 2m
acceleration due to gravity(g) =
[tex]9.8m {s}^{ - 2} [/tex]
mass(m) = ?
we know,
P.E = mgh
or, 29 = m×9.8×2
or, 29/19.6 = m
or,m = 1.48kg
A 50.0-N bowling ball is held in a person’s hand with the forearm horizontal. The biceps muscle is attached 0.030 0 m from the joint, and the ball is 0.350 m from the joint. Find the upward force F exerted by the biceps on the forearm (the ulna) and the downward force R exerted by the humerus on the forearm, acting at the joint.
The upward force F exerted by the biceps on the forearm will be 583 N.
What is force?Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size of the body.
Force is defined as the product of mass and acceleration. Its unit is Newton.
The torque balancing equation is found as;
[tex]\rm \tau_i=\tau_R+\tau_F+\tau_{BB}=0\\\\ R(0)+F(0.0300)-(50.0)(0.350)\\\\ F=583 \ N[/tex]
Hence,the upward force F exerted by the biceps on the forearm will be 583 N.
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2.25 A car's speed is 30m/s, then it slows down in rate 6m/s2, after 4 seconds its speed will be ..... m/s
Answer:
A
Explanation:
Applying the First Equation of Motion :
⇒ v = u + at
⇒ v = 30 + (-6)(4)
⇒ v = 30 - 24
⇒ v = 6 m/s
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