percent composition for Na2S

Answer:

work can be the operation or function of something but it can also be the energy transfer that occurs when an object is moved or in everyday life it means to do something (specific thing). I don't know all of them by the way.

Explanation:

the differences in meaning sometimes makes it easier and sometimes makes it harder to learn science and technology. sometimes the everyday meaning might somehow be related to the science meaning which helps you grasp everything better while sometimes the meaning is so far fetched it makes it harder to know what you are learning. hope this helps

Answer:

b: Hot

a: Cold

c: Cold

d: Warm

e: Warm

f: Cold

g: Hot

Explanation:

:)

Answer:

The molar mass and molecular weight of Sn(CO3)2 is 238.728.

Explanation:

Molar mass of any molecule can be calculated by adding mass of all individual atoms  that comprises the compound. The Molar mass of [tex]Sn(CO_{3})_{2}[/tex] is 238.72g/mol.

Molar mass is defined as mass of one mole of a molecule or compound. It's SI unit is g/mole. The other term that is used for molar mass is molecular weight, formula unit mass. Molar mass is extensive property as it depends on the mass of individual atoms that constitutes the molecule.

Mass of tin= 118.71 g.mol

Mass of Carbon=12g/mol

mass of Oxygen= 16g/mole

Molar mass of [tex]Sn(CO_{3})_{2}[/tex] = 1×mass of tin+2×mass of carbon+6×mass of oxygen

substituting all the values we get

Molar mass of [tex]Sn(CO_{3})_{2}[/tex] = 1×118.71+2×12g/mol+6× 16g/mole

Molar mass of [tex]Sn(CO_{3})_{2}[/tex] =118.71 +24+66

Molar mass of [tex]Sn(CO_{3})_{2}[/tex]=238.72g/mol

Therefore the Molar mass of [tex]Sn(CO_{3})_{2}[/tex] is 238.72g/mol

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Answer:

Erm.......... can you clarify what "paper", you just said "paper" there's a lot.

Explanation:

Answer:

Explanation:

WHAT I AM

ONION

THANKS

IF MY ANSWER IS CORRECT THEN MARK ME AS BRAINLIST

Explanation:

Noble gases are odorless, colorless, nonflammable, and monotonic gases that have low chemical reactivity. The full valence electron shells of these atoms make noble gases extremely stable and unlikely to form chemical bonds because they have little tendency to gain or lose electrons. So, noble gases cannot participate in ionic bond formation.

Answer:

Because they can't!

Explanation:

For ionic bonds, ions are needed to be made which are made to form a stable outer shell octet of electrons of each atom to gain atomic stability. The noble gases don't need to form ions since they already have the octet of electrons in their outer shells. If they don't form ions, they don't form ionic bonds too.

This is one of the reasons why noble gases are unreactive.

#giveathanks

The density of a rectangle : ρ = 0.372 g/cm³

Given

The volume of rectangle : 395 cm³

Mass : 147 g

Required

The density

Solution

Density is a quantity derived from the mass and volume  

Density is the ratio of mass per unit volume  

Density formula:  

[tex]\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}[/tex]

ρ = density  

m = mass  

v = volume

Input the value :

ρ = 147 g : 395 cm³

ρ = 0.372 g/cm³

Answer:

yes light can move from a large space to another at a speed of 186,400 miles (300,000 km) per second.

Explanation:

lights does not need any material to carry its energy along which means I can move really fast

Answer:

yes light can move from a large space to another at a speed of 186,400 miles (300,000 km) per second.

Explanation:

lights does not need any material to carry its energy along which means I can move really fast

Explanation:that should help uuu

5 meters= 0.005

3 grams= 300millgrams

7 meters= 700 cm

60 milligrams=6e-5

2.5 meters=2500

4.5 centimeter= 4.5e-5km

Answer:

[tex]4.13[/tex] x [tex]10^{2}[/tex] = 413 kg

Explanation:

4.13 x 10 = 41.3 then we multiply 41.3 by 10 agian = 41.3 x 10 = 413

so, we multiplied ten two times that = [tex]10^{2}[/tex]

= 4.13 x [tex]10^{2}[/tex]= 413 kg

Given that 1 kilogram = 1000grams, the value of 413 kilograms in grams, using scientific notation is 4.13 × 10⁵g.

Note that;

1 kilogram = 1000grams

Given that;

Since, 1 kilogram = 1000grams

413 kilograms = ( 413 × 1000 )grams

413 kilograms = ( 413000 )grams

413 kilograms = 4.13 × 10⁵ g

Given that 1 kilogram = 1000grams, the value of 413 kilograms in grams, using scientific notation is 4.13 × 10⁵g.

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Answer:

both atoms are ions

Explanation:

Answer:

atom

cell

dust particle

ant

ping pong ball

Explanation:

:) hope this helps! :)

Answer:

Geologists commonly consider faults to be active if there has been movement observed or evidence of seismic activity during the last 10,000 years. Active faulting is considered to be a geologic hazard - one related to earthquakes as a cause.

Explanation:

Plz mark brainliest thanks

Answer:

Examples of longitudinal waves include: sound waves. ultrasound waves. seismic P-waves.

Explanation:

Answer:

When aluminum is placed in an acid it may initially appear not react. This is because a layer of aluminum oxide form on the surface of the aluminum due to prior reaction with the air and acts as a protective barrier ....Aluminum react with dilute acid to give aluminum chloride and hydrogen gas..

Answer:

oatmeal with raisins is a heterogeneous mixture. The raisins may be solid, but turn the bowl over and you will see the mixture as a whole most definitely acts like a liquid. Mud puddles are a heterogeneous mixture.

Explanation:

Answer:

An oatmeal cookie is a heterogeneous mixture, which contains multiple distinct components

Answer: A mole ratio is a conversion factor that relates the amounts in moles of any two substances in a chemical reaction. The numbers in a conversion factor come from the coefficients of the balanced chemical equation

HOPE THIS HELPS

Answer:

Percent yield = 47.6 %

Explanation:

Given data:

Mass of K₂CrO₄ react = 25.0 g

Mass of PbCrO₄ produced = 20 g

Percent yield of PbCrO₄ = ?

Solution:

Chemical equation:

K₂CrO₄ + Pb(NO₃)₂   →    PbCrO₄ + 2KNO₃

Number of moles of K₂CrO₄:

Number of moles = mass/molar mass

Number of moles = 25.0 g/ 194.19 g/mol

Number of moles = 0.13 mol

Now we will compare the moles of K₂CrO₄ and PbCrO₄ .

                       K₂CrO₄       :            PbCrO₄

                            1               :               1

                           0.13           :             0.13

Mass of PbCrO₄: Theoretical yield

Mass = number of moles × molar mass

Mass = 0.13 mol × 323.2 g/mol

Mass = 42.0 g

Percent yield:

Percent yield = ( actual yield / theoretical yield )× 100

Percent yield = (20 g/ 42.0 g ) × 100

Percent yield = 47.6 %

Answer:

Fractional distillation (often shortened in high school to just distillation)

Explanation:

Some elements have different boiling points and can be separated by boiling one element out and condensing it. This is how sodium acetate is made, for example.

Hope this helped!

Answer:

Chemistry reactions are used in art for the following processes;

1) Analog photography

The photographic paper used in analog photography react when exposed to light such that the image on the film stains the photopaper

A series of chemicals are further used to develop the images now carried on the paper and water is used to rinse of the chemicals after the other chemical processes are complete

The photopaper, now bearing the developed photo is hung for it to be dried

2) Paint used for painting consists of several chemicals, including, minerals that serve as pigment, oils that serve as carrying agent, a thinner to prevent the paint from turning to solid

An artist therefore combines different chemicals for a given paint task

3) In the sculpting process

An original sculpture is produced by the artist with the aid of clay or plaster, from the original sculpture, on which wax coatings and chemicals are used to make a replica mold.

Copies of the sculpture can then be made by pouring material into the mold

Explanation:

Answer: A. 28.6 ml of the 0.7 M solution we need to start with.

B. There are 0.02 moles of solute were in the 0.7 M solution.

C. Amount of water to be added is 21.4 ml

D. The resulting solution will have concentration of 0.28 M

Explanation:

According to the dilution law,

[tex]M_1V_1=M_2V_2[/tex]

where,

[tex]M_1[/tex] = molarity of stock solution = 0.7 M

[tex]V_1[/tex] = volume of stock solution = ?

[tex]M_1[/tex] = molarity of diluted solution = 0.4 M

[tex]V_1[/tex] = volume of  diluted solution = 50 ml

Putting in the values we get:

[tex]0.7\times V_1=0.4\times 50[/tex]

[tex]V_1=28.6ml[/tex]

A. 28.6 ml of the 0.7 M solution we need to start with.

B. Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]

where,

n = moles of solute

[tex]V_s[/tex] = volume of solution in ml

[tex]0.7=\frac{n\times 1000}{28.6}[/tex]

[tex]n=0.02[/tex]

Thus there are 0.02 moles of solute were in the 0.7 M solution.

C. Amount of water to be added = (50-28.6 ) ml = 21.4 ml

D. If water added is [tex]2\times 21.4=42.8 ml[/tex]

[tex]0.7\times 28.6=M_2\times 71.4[/tex]

[tex]M_2=0.28M[/tex]

If volume of concentrated solution will be more , the resulting solution will have lesser concentration of 0.28 M

Answer:

things that are mixed together

Answer:

Subduction zone megathrust faults host Earth’s largest earthquakes, along with multitudes of smaller events that contribute to plate convergence. An understanding of the faulting behavior of megathrusts is central to seismic and tsunami hazard assessment around subduction zone margins. Cumulative sliding displacement across each megathrust, which extends from the trench to the downdip transition to interplate ductile deformation, is accommodated by a combination of rapid stick-slip earthquakes, episodic slow-slip events, and quasi-static creep. Megathrust faults have heterogeneous frictional properties that contribute to earthquake diversity, which is considered here in terms of regional variations in maximum recorded magnitudes, Gutenberg-Richter b values, earthquake productivity, and cumulative seismic moment depth distributions for the major subduction zones. Great earthquakes on megathrusts occur in irregular cycles of interseismic strain accumulation, foreshock activity, main-shock rupture, postseismic slip, viscoelastic relaxation, and fault healing, with all stages now being captured by geophysical monitoring. Observations of depth-dependent radiation characteristics, large earthquake slip distributions, variations in rupture velocities, radiated energy and stress drop, and relationships to aftershock distributions and afterslip are discussed. Seismic sequences for very large events have some degree of regularity within subduction zone segments, but this can be complicated by supercycles of intermittent huge ruptures that traverse segment boundaries. Factors influencing variability of large megathrust ruptures, such as large-scale plate structure and kinematics, presence of sediments and fluids, lower-plate bathymetric roughness, and upper-plate structure, are discussed. The diversity of megathrust failure processes presents a suite of natural hazards, including earthquake shaking, submarine slumping, and tsunami generation. Improved monitoring of the offshore environment is needed to better quantify and mitigate the threats posed by megathrust earthquakes globally.

Explanation: