Which graph represents the solution set of this inequality? -2x + 7 < 23
Answer:
-2x < 23-7
-2x < 16
-2x÷-2 < 16 ÷ -2
x > -8
Find the circumference of a circle whose area is 25π. Leave the answer in terms of π.
[tex]\text{Given that,}\\\\~~~~~~~\text{Area} = 25\pi\\\\\implies \pi r^2 = 25 \pi\\\\\implies r^2 = 25\\\\\implies r= 5\\\\\text{Now,}\\\\\text{Circumference}= 2\pi r\\\\~~~~~~~~~~~~~~~~~~~~=2\pi \cdot 5\\ \\~~~~~~~~~~~~~~~~~~~~=10\pi[/tex]
The radius of a circle is 4 feet. what is the angle measure of an arc pi feet long?
Answer:
Step-by-step explanation:
Im honestly so confused and need help with it because i just want to go on to the next question♀️
Answer:
1.05 (0.2x + 1/2y + 0.75z)
Step-by-step explanation:
Finding the cost of each item :
1 Sweatshirt
Cost = $xDiscount = 80% offPrice = (100% - 80%)(x)Price = 0.2x2 T-shirts
Cost = $yDiscount = Buy one, get one 50% offPrice = (50%)(y)Price = 1/2y1 Pair of Pants
Cost = $zDiscount = 25% offPrice = (100% - 25%)(z)Price = 0.75zNow, the final cost (after applying sales tax) is :
1.05 (0.2x + 1/2y + 0.75z)Option #1Select the correct answer from each drop-down menu. a container holds 50 electronic components, of which 10 are defective. if 6 components are drawn at random from the container, the probability that at least 4 are not defective is . if 8 components are drawn at random from the container, the probability that exactly 3 of them are defective is .
The probability of exactly 3 of the containers being defective is given as 0.1468
How to solve for the probabilityWe have to set p as the probability of container being non- defective
We have p as the probability of container being defective 50 - 10 = 40
p = 40/50
= 0.8
q = 10/50
= 0.2
P(3) = 8c3 * 0.2² * 0.8⁵
= 0.1468
Hence the probability that the container has exactly 3 defective containers is 0.1468
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Express sin(-184) as a function of a positive acute angle.
The sin(-184) can be expressed as cos 86° as a function of a positive acute angle.
How do you express a trigonometry function as a positive acute angle?
To express a trigonometry identity as a function of a positive acute angle, we need to find the quadrant in which that given identity is located.
Here, we have a negative trigonometry identity: Sin (-184)
Recall that:
the sine is negative in the third quadrant(III)So, to turn that to a positive sign, we add 360
=sin(-184 + 360)
= sin(176)
To find the positive acute angle, we have:
x = cos(176 - 90)
x = cos 86°
Therefore, we can conclude that the sin(-184) can be expressed as cos 86° as a function of a positive acute angle.
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Find the volume of the sphere. Round your answer to the nearest tenth. A sphere is shown with a diameter of 12 yards. The volume is about cubic yards.
We know:
[tex]{{ \diamond\diamond \quad{ \boxed{ \pink{ \sf{Volume \: of \: Sphere ={ \large{ \frac{4}{3} \pi {r}^{3} }}}}}}} \quad \diamond \diamond}[/tex]
where,
Radius (r) = Diameter/2 = 12/2 = 6 yards. Pi (π) = 22/7[tex] \: [/tex]
[tex]{\longrightarrow {\sf{Volume \: of \: Sphere \: = \: { \large {\frac{4}{3} \times \frac{22}{7} \times {6}^{3} }}}}}[/tex]
[tex] {\longrightarrow {\sf{Volume \: of \: Sphere \: = \: { \large{ \frac{88}{21} \times 6 \times 6 \times 6 }}}}}[/tex]
[tex] {\longrightarrow {\sf{Volume \: of \: Sphere \: = \: { \large{ \frac{88}{21} \times 216 }}}}} [/tex]
[tex] {\longrightarrow {\sf{Volume \: of \: Sphere \: = \: { \large{ \frac{19008}{21} }}}}} [/tex]
[tex] {\longrightarrow {\sf{Volume \: of \: Sphere \: = \: { \large{ { \boxed{ \red{ \sf{905.14 {yards}^{3} }}}}}}}}} [/tex]
Thus, The volume of Sphere is 905.14yards³. (Approx.)
what property is illustrated by the statement 3+z=z+3???
Answer: Commutative Property of Addition
Explanation:
This is the rule which says that we can add two numbers in any order.
For example, 3+2 = 2+3 since both sides result in 5. The rule can be extended to involve variables, because variables are placeholders for actual numbers. Also, the rule can be extended to any number of terms and not just two.
A more generalized form of the rule could be something like x+y = y+x
Given the data below which set of numbers contains the lower quartile median and upper quartile help fast please !!
Answer:
{27.5, 29, 34}.
Step-by-step explanation:
In order they are
24 27 28 28 29 31 32 36 38
The Median = middle value = 29.
Lower quartile = mean of 27 and 28 = 27.5.
Upper quartile = mean of 32 and 36 = 34.
Answer:
{27.5, 29, 34}
Step-by-step explanation:
Arrange in increasing order :
24, 27, 28, 28, 29, 31, 32, 36, 38Lower Quartile :
24 + 27 + 28 + 28 / 4107/426.75 ≈ 27.5 (closest based on options)Median :
5th term29Upper Quartile :
31 + 32 + 36 + 38 / 4137/434.25 ≈ 34A cone has a volume of 37.68cm3. If the height of the cone is 9cm what is the radius of the cone's
base?
cm
Radius:
(Use 3.14)
Answer:
[tex]2cm[/tex]
Step-by-step explanation:
Volume of a cone= [tex]\pi r^2\frac{h}{3}[/tex]
Substitute: [tex]37.68cm^3=\pi r^2(\frac{9}{3})[/tex]
[tex]37.68cm^3=\pi r^2(3)[/tex]
[tex]37.68cm^3=\pi r^2(3)[/tex] Divide by 3
[tex]12.56cm=\pi r^2[/tex] Divide by pi
[tex]4cm=r^2[/tex]
[tex]r=\sqrt{4}[/tex]
[tex]r=2[/tex]
The following data points represent the total weight loss
(in kilograms) for each member of omar's final fitness
team. 61,90, 31, 35, 69, 37, 78
The histogram shows that the majority of Omar's Final Fitness Team had weight loss between 30 to 49 kg, with only a few members achieving higher weight loss of 60 to 69 kg.
To create a histogram from the given data, follow these steps:
Step 1: Determine the range of the data (largest value - smallest value): Range = 90 - 31 = 59
Step 2: Choose a number of classes for the histogram. A convenient number of classes is usually between 5 and 15. For this data set, we can choose 6 classes.
Step 3: Determine the width of each class by dividing the range by the number of classes:
Class width = Range / Number of classes
Class width = 59 / 6 = 9.83
Round the class width up to 10 to make it a convenient number.
Therefore, the class width is 10.
Step 4: Determine the lower limit of the first class. Choose a value that is equal to or less than the smallest data point.
Lower limit of first class = 30
Step 5: Create the frequency distribution table by counting how many data points are in each class:
| Class Interval | Frequency |
|:----:|:----:|
| 30 - 39 | 2 |
| 40 - 49 | 2 |
| 50 - 59 | 0 |
| 60 - 69 | 2 |
| 70 - 79 | 1 |
| 80 - 89 | 1 |
Step 6: Draw the histogram. On a horizontal axis, mark the class intervals. On the vertical axis, mark the frequency for each class. Draw vertical bars to represent the frequency in each class. Make the bars touch each other so that it shows a continuous distribution.
Here's the histogram of the given data:
```
Frequency
|
| x
| x
--------|----|----|----|----|---|---
30 40 50 60 70 80 90
| Class intervals |
```
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I need help with this asap .. i have to get it done before morning
Answer:
Can you please tell me what you need done?
Step-by-step explanation:
I would love to help you but it seems you haven't put any information.
Each of 4 ladies randomly chooses a woolen overcoat from 15 different styles. What is the probability that at least 2 ladies choose the same type of overcoat?
Answer:
1/2
total No-4
required number-2
=No of required outcome
No of Normal outcome
=2/4
=2
Which of the following is a true proportion of the figure based on the triangle proportionality theorem?
A. j / k = j / i
B. i / j = h / k
C. h / i = h / k
D. k / i = j / i
Based on the triangle proportionality theorem, the true proportion regarding the figure is: B. i/j = h/k
What is the Triangle Proportionality Theorem?The triangle proportionality theorem states that when two sides of a triangle is intersected by a line that is parallel to the third side of a triangle, the two sides intersected are therefore divided in the same ratio.
TU is parallel to QR. Therefore, based on the triangle proportionality theorem, TU will divide QS and RS in the following ratio: B. i/j = h/k
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Which inequality has an open circle when it is graphed on a number line?
x greater-than three-fifths
StartFraction 4 over 7 EndFraction greater-than-or-equal-to x
x less-than-or-equal-to 12
x greater-than-or-equal-to negative 6
Answer:
A.) X greater than 3/5
Open circles are used for numbers that are less than or greater than (< or >). Closed circles are used for numbers that are less than or equal to and greater than or equal to (≤ or ≥).
Step-by-step explanation:
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The correct inequality that has an open circle when it is graphed on a number line is,
1) x greater-than three-fifths
We have to given that,
All the expressions are,
1) x greater-than three-fifths
2) Start Fraction 4 over 7 End Fraction greater-than-or-equal-to x
3) x less-than-or-equal-to 12
4) x greater-than-or-equal-to negative 6.
We can write all the inequality as,
1) x greater-than three-fifths
⇒ x > 3/5
Since, it has symbol '>' which represent open circle.
Hence, It is true.
2) Start Fraction 4 over 7 End Fraction greater-than-or-equal-to x.
4/7 ≥ x
Since, it has symbol '≥' which represent closed circle.
Hence, It is not true.
3) x less-than-or-equal-to 12
x ≤ 12
Since, it has symbol '≥' which represent closed circle.
Hence, It is not true.
4) x greater-than-or-equal-to negative 6.
x ≥ - 6
Since, it has symbol '≥' which represent closed circle.
Hence, It is not true.
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For the function f(x) = x2
Find f(5) =
Find f(-5) =
Answer:
25
Step-by-step explanation:
..............
Match the transformation with the description.
Answer:
Translation = Slide
Reflection = Flip
Rotation = Turn
Step-by-step explanation:
Answer all.
a)Name two angles that are complementary.
_______________________
b)Name the angle supplementary to BOA
_______________________
c)AOE and DOE are supplementary.Find mAOE
_______________________
d)Name the angels adjacent to BOC
_______________________
PLEASE ANSWER AND SHOW WORK FOR ALL!!
Answer:
see attached picture for details
a = BOA + COD
b = BOD
c = 150
d = BOA + COD
Step-by-step explanation:
see attached picture with color coded answers
Question 4 (Essay Worth 10 points)
(04.05 MC)
The graph represents the journey of a bus from the bus stop to different locations:
Bus Journey
Distance
(miles)
Time (hours)
Part A: Use complete sentences to describe the motion of the bus in parts 1, 2, 3, 4, and 5 of the journey. (4 points)
Part B: In which parts of the graph is the function increasing, decreasing, and constant? (4 points)
Part C: Is the graph linear or non-linear? Explain your answer. (2 points)
5
1 and 3 are increasing, 2 and 4 are constant, and 5 is decreasing. And the graph is non-linear.
What is a function?A function is a statement, rule, or law that establishes the connection between two variables. In mathematics, functions are everywhere and are necessary for constructing physical connections.
The graph represents the journey of a bus from the bus stop to different locations:
Complete sentences to describe the motion of the bus in parts 1, 2, 3, 4, and 5 of the journey.
1 and 3 show that the bus is going to the last station, 2 and 4 show the holding time of the bus at a station, and 5 shows that the bus is returning.
1 and 3 are increasing, 2 and 4 are constant, and 5 is decreasing.
The graph is non-linear.
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Select the correct answer. In which of the scenarios can you reverse the dependent and independent variables while keeping the interpretation of the slope meaningful? A. As the number of cigarettes smoked in a day increases, the risk for lung cancer increases. B. As the age of an infant increases, the height of the infant increases. C. As the number of vehicles in a city increases, the amount of pollution in the city increases. D. As the concentration of salt in water increases, the density of water increases. E. As the number of calls made by a cell phone increases, the cell phone bill amount increases. Reset Next
Answer:
In Option A, we can see that the reverse may not be true as the increase in the risk for lung cancer may not necessarily mean an increase in cigarette smoked in a day. For example, high risk of lung cancer may be due to high exposure to asbestos dust too.
In Option B, again we can see that the reverse may not be true as an increase in the height of an infant does not necessarily mean that the age of the infant is increasing too. For example the infant may have a rapid gain in height even if the age is not increasing as rapidly.
In Option C, too, that an increase in the amount of pollution in a city does necessarily mean that the number of vehicles in the city has increased. For example, this increase in pollution may be due to the establishment of a high pollution causing industry in the city or in it's vicinity.
Likewise, in Option D, an increase in the density of water does not necessarily mean that the concentration of salt in the water has increased.
Only in Option E do we see a possible reverse dependence happening because an increase in the phone bill amount does usually mean an increase in the number of calls made by the cell phone.
So, in the given list of Options only in Option E can we reverse the dependent and independent variables while keeping the interpretation of the slope meaningful.
Step-by-step explanation:
I NEED HELP IN THIS PLSSS
Answer:
1. A
2. i think c not sure
Step-by-step explanation:
(1 - cot theta) ^ 2 + (1 + cot theta) ^ 2 = 2cosec ^ 2 theta
[tex]\text{L.H.S}\\\\=(1 - \cot \theta )^2 + (1 + \cot \theta)^2 \\\\=(1-\cot \theta + 1 + \cot \theta)^2 - 2(1 -\cot \theta)(1 + \cot \theta)\\\\=2^2 - 2(1 - \cot^2 \theta)\\\\=4-2+2 \cot ^2 \theta\\\\=2+2 \cot^2 \theta\\\\=2(1 + \cot^2 \theta)\\\\=2 \csc^2 \theta\\\\=\text{R.H.S}\\\\\text{Proved.}[/tex]
Which of the follow box-and-whisker plots correctly displays this data set?
24, 32, 25, 27, 37, 29, 30, 30, 28, 31, 27, 23
Answer:
Since there isn't any of the following attached, I made my wn attached below
Step-by-step explanation:
Population size: 12
Median: 28.5
Minimum: 23
Maximum: 37
First quartile: 25.5
Third quartile: 30.75
Interquartile Range: 5.25
Outliers: none
Hope this helps you a little more for your last day of finishing hmw :)
Let me know if you need anymore help !
OR have questions
Fatima wants to find the value of sine theta, given cotangent theta = four-sevenths. which identity would be best for fatima to use?
By using trigonometric relations, we will find that:
sin(θ) = (√33)/7 = √(33/49)
How to find the value of the sine?Remember that for a right triangle, we have the relations:
cos(a) = (adjacent cathetus)/(hypotenuse)
sin(a) = (opposite cathetus)/(hypotenuse).
Here we know that:
cos(θ) = 4/7
Then we can say that we have a triangle with an adjacent cathetus of 4 units and a hypotenuse of 7 units. Now we need to find the other cathetus.
opposite cathetus = √(7^2 - 4^2) = √33
Then we can write:
sin(θ) = (√33)/7 = √(33/49)
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Answer:
The answer is D.
Step-by-step explanation:
Edge 2022
Help me Please!!!!! I need it!!!!
Answer:
-3125
Hope this helps!!
Evaluate the expression.
7^0
Answer:
Heyyy!!!!
The answer is 1.
Please read explanation it will definitely help you....
Step-by-step explanation:
Okay... Here it goes...
Basically, there is an exponent rule that says that anything to the power of 0 is 1.
I hope this helps!
Answer:
7^0 = 1
Step-by-step explanation:
Anything that has an exponent of 0 is 1.
best estimate for 6 3/4 divided by 1 2/3
Answer:
4.05
Step-by-step explanation:
PLS HELP ME IT IS DUE TODAY
For each value of , determine whether it is a solution to
-28 < 4w - 8.
Step-by-step explanation:
reduce -28<4w-8
-7<w-2
add +2
-7+2<w-2+2
-5<w
w>-5
Answer:
See below ~
Step-by-step explanation:
Solving the inequality :
-28 < 4w - 84w > -20w > -5Evaluating the given numbers :
-5
-5 > -5No5
5 > -5Yes-9
-9 > -5No-1
-1 > -5YesTwo classes of students took an exam.
Here is a list of the scores in Class A:
65, 70, 70, 80, 80, 85, 85, 85, 90, 90, 100
Here is a box plot that shows the scores in Class B:
Box plot from 55 to 100 by 5’s. Whisker from 60 to 70. Box from 70 to 80 with vertical line at 75. Whisker from 80 to 90.
1. Which class had better overall results on the exam?
2. Which class had greater variability in the results?
The class that had better overall results on the exam is class A.
The class with greater variablity in results is class B.
Which class performed better?The statistics of students in class A:
Maximum score = 100
Minimum score = 65
Median = 85
First quartile = 1/4(n + 1) = 1/4 x 12 = 3rd term = 70
Third quartile = 3/4 x (n + 1) = 3/4 x 12 = 9th term = 90
The statistics of students in class B:
Maximum score = 100
Minimum score = 55
Median = 75
First quartile = 70
Third quartile = 80
Which class had greater variability in the results?The range would be used to determine which class has greater variability.
Range = highest score - lowest score
Class a = 100 - 65 = 35
Class B = 100 - 55 = 45
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Anyone please help me this I can't solve so I need help.༎ຶ‿༎ຶ waaaaaahhhhhh
This is your answer. I keep hope it will help you
which grade are you studying
