Object 1 and Object 2 have both the same mass. If object 1 moves twice as fast as Object 2, compare their kinetic energy.

A.) Object 1 has 1/4 the kinetic energy of object 2

B.) Object 1 has 1/2 the kinetic energy of object 2

C.) Object 1 has 2x the Kinetic energy of Object 2

D.) Object 1 has 4x the kinetic energy of object 2

Answer:

Their resultant force magnitude on the sleigh is approximately 583.095 N

Explanation:

The given parameters are;

The magnitude and direction in which the two reindeer-in-training pull on the sleigh are;

The force with which Connie pulls on the sleigh, F₁ = 200 N

The direction in which Connie pulls on the sleigh = 60° above the x-axis

The force with which Randolph pulls on the sleigh, F₂ = 800 N

The direction in which Connie pulls on the sleigh = 60° below the x-axis

The vector form of the force with which the two reindeer-in-training pulls the sleigh is given as follows;

[tex]\underset{F_1}{\rightarrow}[/tex] = 200 × cos(60°)·i + 200 × sin(60°)·j = 100·i + (100·√3)·j

[tex]\underset{F_2}{\rightarrow}[/tex] = 800 × cos(60°)·i - 800 × sin(60°)·j = 400·i - (400·√3)·j

The resultant force, R = [tex]\underset{F_1}{\rightarrow}[/tex] + [tex]\underset{F_2}{\rightarrow}[/tex]

∴ R = 100·i + (100·√3)·j + 400·i - (400·√3)·j = 500·i - (300·√3)·j

Their resultant force magnitude on the sleigh, [tex]\left | R \right |[/tex] = √(500² + (-300)²) ≈ 583.095 N

The direction of the resultant force = arctan(-300/500) = arctan(-0.6) ≈ -30.964 which is approximately 30.964° below the x-axis.

Answer:

710kg

Explanation:

Given parameters:

Weight of race car = 6958N

Unknown:

Mass of the race car  = ?

Solution:

The weight of a body is the force of gravity acting on that body. It is mathematically expressed as:

  Weight  = mass x acceleration due to gravity

Acceleration due to gravity  = 9.8m/s²

  6958 = mass x 9.8

        mass  = 710kg

Answer:

The gravitational force that an 81-kg person would experience while standing on the surface of Venus is approximately;

(A) 719 N

Explanation:

The question relates to gravity calculation for which we use the Newton's gravitational law which is presented as follows;

[tex]F=G \cdot \dfrac{M \cdot m}{r^{2}}[/tex]

Where;

G = The universal gravitational constant = 6.67408 × 10⁻¹¹ m³kg⁻¹s⁻²

F = The gravitational force between the two masses, "M" and "m"

r = The distance between the centers of the two masses

M = The mass of one body interacting in the gravitational force

m = The mass of the other body interacting in the gravitational force

The given parameters are;

The mass of Venus, M = 4.87 × 10²⁴ kg

The radius of the planet Venus, r (is corrected) = 6.05 × 10³ km  = 6.05 × 10⁶ km

The mass of the person standing on the surface of Venus, m = 81-kg

Therefore, by plugging in the values, we get;

[tex]F=6.67408 \times 10^{-11} \cdot \dfrac{4.87 \times 10^{24} \times 81}{(6.05 \times 10^6)^{2}} = 719.2744587391571613960795027662 \ N[/tex]

From Newton's third law of motion, the gravitational force that the 81-kg person experiences while standing on the surface of Venus = F ≈ 719 N.

Answer:

the answer is letter; C

Explanation:

Answer:

215000kgm/s

Explanation:

Given parameters:

Mass of the moving body  = 5000kg

Velocity  = 43m/s

Unknown:

Momentum  = ?

Solution:

The momentum of a body is the amount of motion a body possess.

 It is mathematically expressed as:

  Momentum  = mass x velocity

 Now:

  Momentum  = 5000 x 43  = 215000kgm/s

Answer:

1 and 2 because atomic number is equal to the numbers of protons in the nucleus

Answer:

yes answer in 1 and 2 these is answer

Answer:

Significant figures are the number of digits in a value, often a measurement, that contribute to the degree of accuracy of the value. We start counting significant figures at the first non-zero digit. Calculate the number of significant figures for an assortment of numbers.

Explanation:

any of the digits of a number beginning with the digit farthest to the left that is not zero and ending with the last digit farthest to the right that is either not zero or that is a zero but is considered to be exact. — called also significant figure.

Answer:

Yes, it would be enough.

Explanation:

The volume of the tank (cylinder tank) is given by the following equation:

[tex]V_{initial}=\pi (\frac{D}{2})^{2}h[/tex]

Where:

D is the diameter of the tank

h is the height of the tank

Now, the engineer makes a tank 1.26 times as big in heigh and 1.41 times as large with respect to diameter, then the new volume of this tank will be:

[tex]V_{new}=\pi (\frac{1.41D}{2})^{2}1.26h[/tex]    

[tex]V_{new}=1.41^2*1.26\pi (\frac{D}{2})^{2}h[/tex]

[tex]V_{new}=2.51\pi (\frac{D}{2})^{2}h[/tex]

in terms of the initial volume:

[tex]V_{new}=2.51V_{initial}[/tex]

Which means that the volume of the water could be doubled.

I hope it helps you!

Answer:

quantity A is mass and quantity B is wright

Answer:

1200 kg?

Explanation:

Answer:

A

Explanation:

They Are Smoother and the other guy makes no sense.

Answer:

Fossil fuels have been used for centuries to generate power, but there are many disadvantages associated with their use:

Fossil fuels pollute the environment.

Fossil fuels are non-renewable and unsustainable.

Drilling for fossil fuels is a dangerous process.

Explanation:

can you help me please? https://brainly.com/question/21745542

Answer:

20 minutes

Explanation:

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Answer:

a. RT = 9 Ohms

b. RT = 0.5 Ohms

Explanation:

Let the two resistors be A and B.

Let RT be equivalent resistance.

Given the following data;

Resistor A = 6ohms

Resistor B = 3ohms

a. To find the equivalent series resistance;

RT = RA + RB

RT = 6 + 3

RT = 9 Ohms

b. To find the equivalent parallel resistance;

RT = 1/RA + 1/RB

Substituting into the equation, we have

RT = 1/6 + 1/3

RT = 3/6

RT = 0.5 Ohms

As here the 6 ohm and 3 ohm resistors are first connected in series and then parallel, so we can just find out the equivalent series resistance by the formula of it, which is the individual sum of all resistors (for series) and for parallel combination, the reciprocal of the total resistance is the individual reciprocal sum of all resistors, so if we apply same Formula here for series first, then we will be having :

[tex]{:\implies \quad \sf R_{s}=6+3}[/tex]

[tex]{:\implies \quad \boxed{\bf{R_{s}=9\Omega}}}[/tex]

Now, for parallel combination:

[tex]{:\implies \quad \sf \dfrac{1}{R_{p}}=\dfrac13 +\dfrac16}[/tex]

[tex]{:\implies \quad \sf \dfrac{1}{R_{p}}=\dfrac{2+1}{6}}[/tex]

[tex]{:\implies \quad \sf \dfrac{1}{R_{p}}=\dfrac36}[/tex]

[tex]{:\implies \quad \sf \dfrac{1}{R_{p}}=\dfrac12}[/tex]

[tex]{:\implies \quad \boxed{\bf{R_{p}=2\Omega}}}[/tex]

For more information related to Resistances, voltage and current, make sure to check the similar question from here :

Answer:

the relative speed should be 40mph

Explanation:

The approximate temperature at the South Pole is equal to -47.7 °C.

Fahrenheit to Celsius formula can be used to change the temperature from the scale Fahrenheit to Celsius. Both scales are utilized to determine the temperature and it offers a way to determine the object’s hotness and coldness. The symbol used to express Fahrenheit is °F. Similarly, the symbol used to represent Celsius is °C. The Celsius scale of temperature is also called centigrade scale.

Fahrenheit to Celsius formula is commonly used to convert the given temperature in Fahrenheit to Celsius.

[tex]^oC =(^oF-32)\times \frac{5}{9}[/tex]

Where F is the temperature in Fahrenheit and C is the temperature in Celsius.

Given, the temperature in Fahrenheit = -54 °F

The temperature in Celcius at the South Pole can be calculated as:
T (°C) = (-54 -32) × (5/9)

T (°C) = -47.7 °C

Learn more about temperature conversion, here:

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Answer:

Clouds form when below the dew point

Clouds form when the air is cooled below the dew point. The dew point is the temperature at which the air becomes saturated, meaning it can no longer hold all the water vapor it contains. The correct answer is the dew point.

When the air cools below this temperature, the excess water vapor condenses into tiny water droplets or ice crystals, forming clouds.

The dew point is an important concept in meteorology and refers to the temperature at which the air becomes saturated, leading to the formation of dew, fog, or clouds. It is the temperature at which the air can no longer hold all the water vapor it contains, resulting in the condensation of water vapor into liquid water droplets.

When air is cooled, its capacity to hold water vapor decreases. As the temperature drops, the air reaches a point where it becomes saturated, meaning the air is holding the maximum amount of water vapor it can at that specific temperature and pressure. This temperature is known as the dew point.

Therefore, while relative humidity, water content, and percent saturation are relevant factors in understanding the moisture content of the air, clouds specifically form when the air is cooled below the dew point. The correct answer is the dew point.

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Answer:

-3m+7m =  4m

Explanation:

As he walks south, he is going down 3m (-3m). Then he walks up 7m (+7m).

You subtract the final position from the initial position to get displacement.

7m - 3m = 4m

Answer:

The atom is now a negative charge

Explanation:

Adding electrons makes things negative.

Answer:

1. Cart Y has a larger magnitude of momentum.

2. Because the mass of cart Y is larger than the mass of cart A.

Explanation:

The following data were obtained from the question:

Mass of cart A (mₐ) = 2 Kg

Velocity of cart A (vₐ) = 4 m/s

Mass of cart Y (mᵧ) = 8 Kg

Velocity of cart Y (vᵧ) = 2 m/s

1. Determination of which of the cart has a larger magnitude of momentum.

For Cart A:

Mass (mₐ) = 2 Kg

Velocity (vₐ) = 4 m/s

Momentum of cart A (pₐ) =?

Momentum = mass × velocity

pₐ = mₐ × vₐ

pₐ = 2 × 4

pₐ = 8 Kgm/s

Thus, the momentum of cart A is 8 Kgm/s

For Cart Y:

Mass (mᵧ) = 8 Kg

Velocity (vᵧ) = 2 m/s

Momentum of cart Y (pᵧ) =?

Momentum = mass × velocity

pᵧ = mᵧ × vᵧ

pᵧ = 8 × 2

pᵧ = 16 Kgm/s

Thus the momentum of cart Y is 16 Kgm/s

SUMMARY:

The momentum of cart A is 8 Kgm/s

The momentum of cart Y is 16 Kgm/s

Therefore, cart Y has a larger magnitude of momentum.

2. Determination of the reason why cart Y has a larger magnitude of momentum.

Momentum is simply defined as the product of mass and velocity i.e

Momentum = mass × velocity

Thus, an increase in either mass or velocity will increase the momentum.

Considering the question given and the solution obtained:

Cart A:

Mass (mₐ) = 2 Kg

Velocity (vₐ) = 4 m/s

Momentum of cart A (pₐ) = 8 Kgm/s

Cart Y:

Mass (mᵧ) = 8 Kg

Velocity (vᵧ) = 2 m/s

Momentum of cart Y (pᵧ) = 16 Kgm/s

From the above data, we can see that the mass of cart Y (i.e 8 Kg) is larger than the mass of cart A (i.e 2 Kg).

Thus, we can conclude that the magnitude of the momentum of cart Y is larger than that of cart A irrespective of their velocities because the mass of cart Y is larger than the mass of cart A.

Answer:

The car is 72.75 miles away from its starting position.

Explanation:

First, remember the relation:

distance = time*speed.

Also, the distance between two points (a, b) and (c, d) is:

D = √( (a - c)^2 + (b - d)^2)

For this problem, we can assume:

The North is equivalent to the y-axis, and the East is equivalent to the x-axis.

We also assume that the initial position of the car is (0mi, 0mi)

Now the car moves to the East at a speed of 52mi/h for one hour, then the new position of the car is:

(0mi, 0mi) + (52mi/h*1h, 0mi) = (52mi, 0mi)

Now the car travels 30 mins (or 0.5 hours) to the northeast at a speed of 52mi/h.

We can assume that it moves at an exact angle of 45° from East to North, then the components of the speed can be written as:

Sx = speed in the x-axis = 52mi/h*cos(45°) = 36.77 mi/h

Sy = speed in the y-axis = 52mi/h*sin(45°) =  36.77 mi/h

Then the new position of the car is:

(52mi, 0mi) + (36.77 mi/h*0.5h, 36.77 mi/h*0.5h) = (70.385 mi, 18.385 mi)

Now we know the final position of the car.

The distance between the final position (70.385 mi, 18.385 mi) and the initial position (0mi, 0mi) is:

D = √( (70.385 mi - 0mi)^2 + (18.385 mi - 0mi)^2) = 72.75 mi

The car is 72.75 miles away from its starting position.

Answer:

We begin by solving the equation P = hρg for depth h: h=Pρg h = P ρ g . Then we take P to be 1.00 atm and ρ to be the density of the water that creates the pressure.

Explanation:

if it helps problem doesn't sorry

Answer:

A velocity

B acceleration

C ms^-2

Answer:

Newton first law

Explanation:

Newton's first law states that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force. The hockey puck moved because you hit it. ( tell me if I helped I hope you do good)

Answer:

o The result of a chemical change is a different  composition; in a physical change, the composition  remains the same.

Explanation:

In a chemical change, new kinds of matter are produced although the atoms are the same.

For physical changes, no new kinds of matter formed. Only the state of substances changes.

Answer:

8165.138kg/cubic meter

Explanation:

Pressure= 80100 Pascal.= 1N/m^2

Height=10.2 meters

density of the fluid in kg/cubic meter= ?

g=acceleration due to gravity= 9.81m/s^2

The pressure of a system can be calculated using the expression below

P = ρ g h

Where

p =pressure,

h =depth of the liquid,

ρ = density of the liquid,

g = acceleration due to gravity.

If we substitute those values we have

80100 1N/m^2= ρ × 9.81m/s^2

ρ= 80100/9.81

ρ=8165.138kg/cubic meter

Hence, the density of the fluid in kg/cubic meter is 8165.138kg/cubic meter

Answer:

No.

Explanation:

Answer:

[tex]9\ m/s^2[/tex]

Explanation:

Net Force

The Second Newton's law states that an object acquires acceleration when an external unbalanced net force is applied to it.

The acceleration is proportional to the net force and inversely proportional to the mass of the object.

It can be expressed with the formula:

[tex]\displaystyle a=\frac{F_n}{m}[/tex]

Where

Fn = Net force

m  = mass

An object has an acceleration of [tex]18\ m/s^2[/tex], thus:

[tex]\displaystyle \frac{F_n}{m}=18\ m/s^2[/tex]

If the new force is halved:

F' = F_n/2, the new acceleration will be:

[tex]\displaystyle a'=\frac{F_n/2}{m}[/tex]

[tex]\displaystyle a'=\frac{1}{2}\cdot\frac{F_n}{m}[/tex]

Substituting the given acceleration:

[tex]\displaystyle a'=\frac{1}{2}\cdot 18\ m/s^2[/tex]

[tex]\displaystyle a'=9\ m/s^2[/tex]

The new acceleration is [tex]9\ m/s^2[/tex]