Let the numbers are x and y
According to the question
⇒x+y=1000.....eq1⇒x 2 −y 2
=256000∵x 2 −y 2
=(x+y)(x−y)
⇒1000∗(x−y)=256000
⇒x−y=256.....eq2
Adding eq1 and eq2
⇒2x=1256⇒x=628
Put the value of x in eq1
⇒628+y=1000⇒y=372
The numbers are 628 and 372
Hi I'm From PHILIPPINES
I'm here to help USA users like you
Laura, Scott, and Joe served a total of 104
orders Monday at the school cafeteria. Joe served 3
times as many orders as Scott. Laura served 9
more orders than Scott. How many orders did they each serve?
9514 1404 393
Answer:
Joe: 57Scott: 19Laura: 28Step-by-step explanation:
Let s represent the number of orders Scott served. Then we have Joe served 3s, and Laura served (s+9). The total of orders served is ...
3s +s +(s +9) = 104
5s = 95 . . . . . . . . . . . subtract 9 and collect terms
s = 19 . . . . . . . . . divide by 5
3s = 3×19 = 57
s+9 = 19+9 = 28
Joe served 57 orders, Scott served 19, and Laura served 28 orders.
A plane traveled 4425 miles with the wind in 7.5 hours and 3675 miles against the wind in the same amount of time. Find the speed of the plane in still air and the speed of the wind
Answer:
540 miles/hr and 50 miles/hr respectively
Step-by-step explanation:
Let the speed of plane in still air be x and the speed of wind be y.
ATQ, (x+y)*7.5=4425 and (x-y)*7.5=3675. Solving it, we get x=540 and y=50
Which of the following expressions is equal to tan205°?
tan55°
tan25°
tan25°
Answer:
the write answer to your question is tan 25 degree
The Laplace Transform of a function f(t), which is defined for all t > 0, is denoted by L{f(t)} and is defined by the improper integral L{f(t)}(s) = infinity 0 e-st.f(t)dt, as long as it converges. Laplace Transform is very useful in physics and engineering for solving certain linear ordinary differential equations. (Hint: think of as a fixed constant)
1. Find L{t}. (hint: remember integration by parts)
A. 1
B. -1/s2
C. 0
D. 1/s2
E. -s2
F. None of these
2. Find L{1}.
a.1/s
b. 1
c. 0
d. -s
e. -1/s
f. none of these
(1) D
[tex]L_s\left\{t\right\} = \displaystyle\int_0^\infty te^{-st}\,\mathrm dt[/tex]
Integrate by parts, taking
[tex]u = t \implies \mathrm du=\mathrm dt[/tex]
[tex]\mathrm dv = e^{-st}\,\mathrm dt \implies v=-\dfrac1se^{-st}[/tex]
Then
[tex]L_s\left\{t\right\} = \displaystyle \left[-\frac1ste^{-st}\right]\bigg|_{t=0}^{t\to\infty}+\frac1s\int_0^\infty e^{-st}\,\mathrm dt[/tex]
[tex]L_s\left\{t\right\} = \displaystyle \frac1s\int_0^\infty e^{-st}\,\mathrm dt[/tex]
[tex]L_s\left\{t\right\} = \displaystyle -\frac1{s^2}e^{-st}\bigg|_{t=0}^{t\to\infty}[/tex]
[tex]L_s\left\{t\right\} = \displaystyle \boxed{\frac1{s^2}}[/tex]
(2) A
[tex]L_s\left\{1\right\} = \displaystyle\int_0^\infty e^{-st}\,\mathrm dt[/tex]
[tex]L_s\left\{1\right\} = \displaystyle\left[-\frac1se^{-st}\right]\bigg|_{t=0}^{t\to\infty}[/tex]
[tex]L_s\left\{1\right\} = \displaystyle\boxed{\frac1s}[/tex]
Can I get some help
Please!!
Answer:
option D is the answer
Step-by-step explanation:
using the HH,ll,ha and la,
where h is the hypotenuse and l is the leg
If you have a volume of 366,514 cm, how many ft does that make? Round to 1 decimal.
Answer:
12024.7
Step-by-step explanation:
Searched it up.
then rounded
Sketch the region of integration and convert the polar integral to a Cartesian integral or sum of integrals. Do not evaluate the integral.
∫ ^π∫^2 r^3 sinθcosθdrd()
π/2 0
It looks like the integral in polar coordinates is given to be
[tex]\displaystyle\int_{\pi/2}^\pi \int_0^2 r^3\sin(\theta)\cos(\theta)\,\mathrm dr\,\mathrm d\theta[/tex]
Converting back to Cartesian, we take
x = r cos(θ)
y = r sin(θ)
dx dy = r dr dθ
so we can easily recover the integrand in Cartesian:
[tex]r^3\sin(\theta)\cos(\theta)\,\mathrm dr\,\mathrm d\theta = (r\sin(\theta))(r\cos(\theta))(r\,\mathrm dr\,\mathrm d\theta) = xy\,\mathrm dx\,\mathrm dy[/tex]
This leaves us with the limits:
• π/2 ≤ θ ≤ π corresponds to the second quadrant of the (x, y)-plane (that is, where x < 0 and y > 0)
• 0 ≤ r ≤ 2 correspond to the disk of radius 2 centered at the origin
Taken together, we see the region of integration is a quarter-disk of radius 2 in the second quadrant, which we can capture by the set
{(x, y) : -√2 ≤ x ≤ 0 and 0 ≤ y ≤ √(2 - x ²)}
So, in Cartesian coordinates, the integral would be
[tex]\displaystyle \boxed{\int_{-\sqrt2}^0 \int_0^{\sqrt{2-x^2}} xy\,\mathrm dy\,\mathrm dx}[/tex]
m∠AFD=90° . m∠AFB=31°. Find m∠DFE.
A. 87
B. 29.5
C. 31
D. 28
Answer:
D. 28
Step-by-step explanation:
Given:
m∠AFD = 90°
m∠AFB = 31°
Required:
m∠DFE
Solution:
m<AFB = m<CFD (both angles are marked as congruent angles)
Since m<AFB = 31°, therefore,
m<CFD = 31°
m<AFB + m<CFD + m<BFC = m<AFD
Plug in the known values
31° + 31° + m<BFC = 90°
62° + m<BFC = 90°
Subtract 62° from each side
m<BFC = 90° - 62°
m<BFC = 28°
m<BFC = m<DFE = 28° (both angles are marked congruent to each other)
Therefore,
m<DFE = 28°
Find the missing side round your answer to the nearest tenth
Answer:
x = 38.4
Step-by-step explanation:
tan(38) = 30/x
x = 30/tan(38)
x = 38.4
Answered by GAUTHMATH
A record store owner finds that 20% of customers entering her store make a purchase. One morning 180 people, who can be regarded as a random sample of all customers, enter the store.
a. What is the mean of the distribution of the sample proportion of customers making a purchase?
b) What is the variance of the sample proportion?
c) What is the standard error of the sample proportion?
d) What is the probability that the sample proportion is less than 0.15?
Answer:
a) 0.2
b) 0.0009
c) 0.0298
d) 0.0465 = 4.65% probability that the sample proportion is less than 0.15.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
20% of customers entering her store make a purchase.
This means that [tex]p = 0.2[/tex]
180 people
This means that [tex]n = 180[/tex]
a. What is the mean of the distribution of the sample proportion of customers making a purchase?
By the Central Limit Theorem, [tex]\mu = p = 0.2[/tex].
b) What is the variance of the sample proportion?
The standard deviation is:
[tex]s = \sqrt{\frac{0.2*0.8}{180}} = 0.0298[/tex]
Variance is the square of the standard deviation, so:
[tex]s^2 = (0.0298)^2 = 0.0009[/tex]
c) What is the standard error of the sample proportion?
As found in the previous item, 0.0298.
d) What is the probability that the sample proportion is less than 0.15?
This is the p-value of Z when X = 0.15. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.15 - 0.20}{0.0298}[/tex]
[tex]Z = -1.68[/tex]
[tex]Z = -1.68[/tex] has a p-value of 0.0465.
0.0465 = 4.65% probability that the sample proportion is less than 0.15.
Mary takes out a loan for $6,000 at a simple interest rate of 12% to be paid back in 36 monthly instalments. What is the amount of her monthly payments?
Answer:
$199.29
Step-by-step explanation:
Total payments = $7,174.24
Total interest = $1,174.24
A particle moves along line segments from the origin to the points (3, 0, 0), (3, 4, 1), (0, 4, 1), and back to the origin under the influence of the force field F(x, y, z) = z^2i + 4xyj + 5y^2k. Use Stokes' Theorem to find the work done.
Answer:
the first option because I took the test
I need help guys thanks so much
Answer:
2
Step-by-step explanation:
8 ^ (5/3) ^ 1/5
We know a^b^c = a^(b*c)
8^ (5/3*1/5)
8^ 1/3
Rewriting 8 as 2^3
2^3 ^1/3
2 ^(3*1/3)
2^1
2
Answer:
2
Step-by-step explanation:
((2^3)^5/3)^1/5
= (2^5)^1/5
= 2
Answered by Gauthmath
Suppose that there are two internet service providers in Kabwe, Eyeconnect and Topconnect.
Currently, Eyeconnect has 180 000 customers and Topconnect has 120 000 customers.
Assume that, every year, 10% of the customer base of Eyeconnect switches to Topconnect
and 5% of the customer base of Topconnect switches to Eyeconnect. For the purposes of this
question, suppose no customer leaves a company without switching to the other one and no
company attracts customers that are not leaving the other (that is, the only changes in
customer base come from switching between the two companies).
a. Find the number of customers of Eyeconnect and Topconnect after one year.
b. Find the number of customers of Eyeconnect after many years.
Answer:
a. 168000 for Eyeconnect, 132000 for Topconnect
b. 100,000
Step-by-step explanation:
a.
Because the change in customers are only due to leaving companies, we can say that, after one year, Eyeconnect loses 10% of its customers to Topconnect and Topconnect loses 5% of its customers to Eyeconnect. This represents all changes in customers.
First, we can calculate how much Eyeconnect loses, which is 10% of 180,000 = 0.1 * 180,000 = 18,000 . They then have 180,000 - 18,000 = 162,000 employees
Next, Topconnect loses 120,000 * 5% = 120,000 * 0.05 = 6,000. They then have 120,000-6,000 = 114,000 employees
We can then add the customer amounts. Note that we are subtracting both sides before adding as both companies gain and lose customers simultaneously.
We can then add how much one company lost to the other company's customers.
Eyeconnect gains 6,000 customers, so they then have 162,000 + 6,000 = 168000 employees. Topconnect gains 18,000 customers so they then have 114,000 + 18,000 = 132,000 employees
b.
After many years, the number of customers Eyeconnect has will be less than the number of customers that Topconnect has. One way to find the end amount of customers that Eyeconnect has is to figure out when the customer bases even out, or when Eyeconnect loses the same amount of customers as Topconnect so the customer base stays the exact same. We know that no customers leave or join the companies except to leave/join the other, so the total amount of customers between the two companies stays the exact same. The amount of customers is 180,000 + 120,000 = 300,000. Therefore, at the end amount,
Eyeconnect customers (E) + Topconnect customers (T) =300,000
Furthermore, if the amount of customers that leave Eyeconnect is the same that leaves Topconnect, we can say
E * 0.1 = T * 0.05
divide both sides by 0.05 to isolate the T
E * 0.1 / 0.05 = T
2 * E = T
plug that into the first equation
E + 2 * E = 300,000
3 * E = 300,000
divide both sides by 3 to isolate E
E = 100,000 after many years
which ecpression is the simplest form of 3(3x-4)-5(x+3)
[tex]\boxed{ \sf{Answer}} [/tex]
[tex] \sf \: 3(3x - 4) - 5(x + 3) \\ \sf =( 3 \times 3x) - (3 \times 4) + ( - 5 \times x) +( - 5 \times 3 ) \\ \sf = 9x - 12 - 5x - 15 \\ \sf = 9x - 5x - 12 - 15 \\ = \underline{ \bf 4x - 27}[/tex]
ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ
꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐
[tex]\\ \sf\longmapsto 3(3x-4)-5(x+3)[/tex]
[tex]\\ \sf\longmapsto 9x-12-5x-15[/tex]
[tex]\\ \sf\longmapsto 9x-5x-15-12[/tex]
[tex]\\ \sf\longmapsto (9-5)x-27[/tex]
[tex]\\ \sf\longmapsto 4x-27[/tex]
Please how do I solve this.
Answer:
Horizontal Shift: Right 1
Vertical Shift: Down 5
Reflection: None
Explanation: To find the transformation, compare the function to the parent function (being in this case g(x)=1/x) and check to see if there is a horizontal or vertical shift or a reflection.
So, the answer would be Right 1, and down 5
Hope this helps you out :)
What is the distance between the following points?
WILL GIVE BRAINLIEST!!
Answer:
A. 5
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Reading a coordinate planeCoordinates (x, y)Algebra II
Distance Formula: [tex]\displaystyle d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]Step-by-step explanation:
Step 1: Define
Identify points from graph.
Point (8, 5)
Point (4, 2)
Step 2: Find distance d
Simply plug in the 2 coordinates into the distance formula to find distance d
Substitute in points [Distance Formula]: [tex]\displaystyle d = \sqrt{(8 - 4)^2 + (5 - 2)^2}[/tex][√Radical] (Parenthesis) Subtract: [tex]\displaystyle d = \sqrt{4^2 + 3^2}[/tex][√Radical] Evaluate exponents: [tex]\displaystyle d = \sqrt{16 + 9}[/tex][√Radical] Add: [tex]\displaystyle d = \sqrt{25}[/tex][√Radical] Evaluate: [tex]\displaystyle d = 5[/tex]An urn contains 5 blue marbles and 4 yellow marbles. One marble is removed, its color noted, and not replaced. A second marble is removed and its color is noted.
(a) What is the probability that both marbles are blue? yellow?
(b) What is the probability that exactly one marble is blue?
Answer:
(a)The probability that both marbles are blue=5/18
The probability that both marbles are yellow=1/6
(b)The probability that exactly one marble is blue=5/9
Step-by-step explanation:
Blue marbles=5
Yellow marbles=4
Total marbles=5+4=9
(a)
Probability of drawing first blue marble=5/9
Probability of drawing second blue marble without replacement=4/8
The probability that both marbles are blue
[tex]=\frac{5}{9}\times \frac{4}{8}=\frac{5}{18}[/tex]
Probability of drawing first yellow marble=4/9
Probability of drawing second yellow marble without replacement=3/8
The probability that both marbles are yellow
[tex]=\frac{4}{9}\times \frac{3}{8}=\frac{1}{6}[/tex]
(b)
The probability that exactly one marble is blue
=Probability of first blue marble (Probability of second yellow marble)+Probability of first yellow marble (Probability of second blue marble)
The probability that exactly one marble is blue
=[tex]\frac{5}{9}\times \frac{4}{8}+\frac{4}{9}\times \frac{5}{8}[/tex]
=[tex]\frac{5}{18}+\frac{5}{18}[/tex]
=[tex]\frac{10}{18}=\frac{5}{9}[/tex]
What is the solution to log (9x)-log, 3 - 3?
O X
col 00
8
X =
3
O x=3
OX=9
Answer:
x = 8/3
Step-by-step explanation:
Log₂(9x) – Log₂3 = 3
The value of x can be obtained as follow:
Log₂(9x) – Log₂3 = 3
Recall
Log M – Log N = Log (M/N)
Thus,
Log₂(9x) – Log₂3 = 3
Log₂(9x/3) = 3
Log₂3x = 3
3x = 2³
3x = 8
Divide both side by 3
x = 8/3
[tex]\sqrt{25}[/tex]=?
[tex]Hello[/tex] [tex]There[/tex]
The answer is...
[tex]5.[/tex]
[tex]HopeThisHelps!![/tex]
[tex]AnimeVines[/tex]
A group of 6 children and 6 adults are going to the zoo. Child tickets cost $10, and adult tickets cost $14. How much will the zoo tickets cost in all?
Answer:
i believe it'll cost 200 dollars
I need some help please!!!
9514 1404 393
Answer:
13 < √181 < 14
Step-by-step explanation:
Apparently, you're supposed to know that ...
13² = 169
14² = 196
so √181 will lie between 13 and 14.
13 < √181 < 14
Calculus II Question
Identify the function represented by the following power series.
[tex]\sum_{k = 0}^\infty (-1)^k \frac{x^{k + 2}}{4^k}[/tex]
With some rewriting, you get
[tex]\displaystyle \sum_{k=0}^\infty (-1)^k\frac{x^{k+2}}{4^k} = x^2 \sum_{k=0}^\infty \left(-\frac x4\right)^k[/tex]
Recall that for |x| < 1, you have
[tex]\displaystyle \frac1{1-x} = \sum_{k=0}^\infty x^k[/tex]
So as long as |-x/4| = |x/4| < 1, or |x| < 4, your series converges to
[tex]\displaystyle x^2 \sum_{k=0}^\infty \left(-\frac x4\right)^k = \frac{x^2}{1-\left(-\frac x4\right)} = \frac{x^2}{1+\frac x4} = \boxed{\frac{4x^2}{4+x}}[/tex]
Based on known expressions from Taylor series, the power series [tex]\sum \limits_{k = 0}^{\infty} (-1)^{k}\cdot \frac{x^{k+2}}{4^{k}}[/tex]Taylor series-derived formula of the rational function [tex]\frac{4\cdot x^{2}}{4+x}[/tex].
How to derive a function behind the approximated formula by Taylor seriesTaylor series are polynomic approximations used to estimate values both from trascendental and non-trascendental functions. It is commonly used in trigonometric, potential, logarithmic and even rational functions.
In this question we must use series properties and common Taylor series-derived formulas to infer the expression behind the given series. Now we proceed to find the expression:
[tex]\sum \limits_{k = 0}^{\infty} (-1)^{k}\cdot \frac{x^{k+2}}{4^{k}}[/tex]
[tex]x^{2}\cdot \sum\limits_{k = 0}^{\infty} \left(-\frac{x}{4} \right)^{k}[/tex]
[tex]x^{2}\cdot \left(\frac{1}{1+\frac{x}{4} } \right)[/tex]
[tex]\frac{4\cdot x^{2}}{4+x}[/tex]
Based on power and series properties and most common Taylor series- derived formulas, the power series [tex]\sum \limits_{k = 0}^{\infty} (-1)^{k}\cdot \frac{x^{k+2}}{4^{k}}[/tex] represents a Taylor series-derived formula of the rational function [tex]\frac{4\cdot x^{2}}{4+x}[/tex]. [tex]\blacksquare[/tex]
To learn more on Taylor series, we kindly invite to check this verified question: https://brainly.com/question/12800011
I need help on this 20 points
Answer:
4^15
Step-by-step explanation:
We know a^b^c = a^(b*c)
4^3^5
4^(3*5)
4^15
Please help please !!!
========================================================
Explanation:
You can use the AAS (angle angle side) theorem to prove that triangle ABD is congruent to triangle CBD.
From there, we can then say that AD and DC are the same length
AD = DC
3y+6 = 5y-18
3y-5y = -18-6
-2y = -24
y = (-24)/(-2)
y = 12
What is the solution of log3x + 4 4096 = 4?
Step-by-step explanation:
X= - 1
X=0
X=4/3
X=3
We solve for x by simplifying both sides of the equation, then isolate the variable.
Answer :
C (x=4/3)
Please answer and explain :)
Write an example for each of the following:
equation notation
set notation
interval notation
solution graph
Answer:
set notation _ A set is denoted or represented by a capital letter and enclosed in a curly bracket For example {A,B,P,Q}.
In 2018, Mike Krzyewski and John Calipari topped the list of highest paid college basketball coaches (Sports Illustrated website). The following sample shows the head basketball coach's salary for a sample of 10 schools playing NCAA Division I basketball. Salary data are in millions of dollars.
University Coach's Salary University Coach's Salary
North Carolina State 2.2 Miami (FL) 1.5
Iona 0.5 Creighton 1.3
Texas A&M 2.4 Texas Tech 1.5
Oregon 2.7 South Dakota State 0.3
Iowa State 2.0 New Mexico State 0.3
a. Use the sample mean for the 10 schools to estimate the population mean annual salary for head basketball coaches at colleges and universities playing NCAA Division I basketball.
b. Use the data to estimate the population standard deviation for the annual salary for head basketball coaches.
c. What is the 95% confidence interval for the population variance?
d. What is the 95% confidence interval for the population standard deviation?
From the data given, we estimate the population mean and population standard deviation. Then, we use this estimate to find a 95% confidence interval for the population variance and the population standard deviation.
Sample:
Salaries in millions of dollars: 2.2, 1.5, 0.5, 1.3, 2.4, 1.5, 2.7, 0.3, 2.0, 0.3
Question a:
The mean is the sum of all values divided by the number of values. So
[tex]\overline{x} = \frac{2.2 + 1.5 + 0.5 + 1.3 + 2.4 + 1.5 + 2.7 + 0.3 + 2.0 + 0.3}{10} = 1.42[/tex]
The sample mean salary is of 1.42 million.
Question b:
The standard deviation is the square root of the difference squared between each value and the mean, divided by one less than the number of values.
So
[tex]s = \sqrt{\frac{(2.2-1.42)^2 + (1.5-1.42)^2 + (0.5-1.42)^2 + (1.3-1.42)^2 + (2.4-1.42)^2 + (1.5-1.42)^2 + (2.7-1.42)^2 + ...}{9}} = 0.8772[/tex]
Thus, the estimate for the population standard deviation is of 0.8772 million.
Question c:
The sample size is [tex]n = 10[/tex]
The significance level is [tex]\alpha = 1 - 0.05 = 0.95[/tex]
The estimate, which is the sample standard deviation, is of [tex]s = 0.8772[/tex].
Now, we have to find the critical values for the Pearson distribution. They are:
[tex]\chi^2_{\frac{\alpha}{2},n-1} = \chi^2_{0.025,9} = 19.0228[/tex]
[tex]\chi^2_{1-\frac{\alpha}{2},n-1} = \chi^2_{0.975,9} = 2.7004[/tex]
The confidence interval for the population variance is:
[tex]\frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2},n-1}} < \sigma^2 < \frac{(n-1)s^2}{\chi^2_{1-\frac{\alpha}{2},n-1}}[/tex]
[tex]\frac{9*0.8772^2}{19.0228} < \sigma^2 < \frac{9*0.8772^2}{2.7004}[/tex]
[tex]0.3641 < \sigma^2 < 2.5646[/tex]
Thus, the 95% confidence interval for the population variance is (0.3641, 2.5646)
Question d:
Standard deviation is the square root of variance, so:
[tex]\sqrt{0.3641} = 0.6034[/tex]
[tex]\sqrt{2.5646} = 1.6014[/tex]
The 95% confidence interval for the population standard deviation is (0.6034, 1.6014).
For more on confidence intervals for population mean/standard deviation, you can check https://brainly.com/question/13807706
write the greatest and smallest four digit number by using 7,8,0,9 digit
A family has a day of 7 activities planned: shopping, picnic, hiking, swimming, bike ride, video games, and movie. To make it more adventurous they decide to randomly pick the order of the activities out of a hat. Find the probability that bike ride and movie are chosen consecutively, in either order.
Answer:
[tex]Pr= \frac{1}{21}[/tex]
Step-by-step explanation:
Given
[tex]n(S) = 7[/tex] --- number of games
Required
Probability of bike and movie in consecutive order
This probability is represented as:
[tex]Pr = P(Bike\ and\ Movie) \ or\ P(Movie\ or\ Bike)[/tex]
So, we have:
[tex]Pr = P(Bike\ and\ Movie) \ +\ P(Movie\ or\ Bike)[/tex]
The probability is an illustration of selection without replacement;
So, we have:
[tex]P(Bike\ and\ Movie) = P(Bike) * P(Movie)[/tex]
[tex]P(Bike\ and\ Movie) = \frac{n(Bike)}{n(S)} * \frac{n(Movie)}{n(S) - 1}[/tex] ---- without replacement
Bike and Movie appear in the game list 1 time.
So, the equation becomes
[tex]P(Bike\ and\ Movie) = \frac{1}{7} * \frac{1}{7 - 1}[/tex]
[tex]P(Bike\ and\ Movie) = \frac{1}{7} * \frac{1}{6}[/tex]
[tex]P(Bike\ and\ Movie) = \frac{1}{42}[/tex]
Similarly,
[tex]P(Movie\ and\ Bike) = \frac{1}{42}[/tex]
So, we have:
[tex]Pr = P(Bike\ and\ Movie) \ +\ P(Movie\ or\ Bike)[/tex]
[tex]Pr= \frac{1}{42}+\frac{1}{42}[/tex]
Take LCM
[tex]Pr= \frac{1+1}{42}[/tex]
[tex]Pr= \frac{2}{42}[/tex]
[tex]Pr= \frac{1}{21}[/tex]
