need help pleaseee!!!

Answer:

0.5%

Step-by-step explanation:

Answer:

√3/2 is the correct answer. I hope this helps ^^

Step-by-step explanation:

Answer:

  2 13/14 feet

Step-by-step explanation:

The remaining length is the difference between the starting length and the amount cut off:

  5 3/7 - 2 1/2 = (5 -2) +(3/7 -1/2) = 3 +((3·2-7·1)/(7·2)) = 3 -1/14

  = 2 13/14 . . . feet remaining

_____

Additional comment

Addition and subtraction of fractions can be accomplished using a formula that does not rely on finding a least common denominator. In this case, the denominators have no common factors, so their product is, in fact, the least common denominator.

  [tex]\dfrac{a}{b}-\dfrac{c}{d}=\dfrac{ad-bc}{bd}[/tex]

Answer:

3 and five fifthteenths or  3 and 4/9

Step-by-step explanation:

i think so.........

Answer:

3x5=15

5x3=15

Step-by-step explanation:

Answer:

option c.)

Step-by-step explanation:

m∠1 + m∠3 = 180°

Its 1/-2, or in other words it is -(1/2), so it would be the third option you have there.

Your welcome! :D

Answer:

Step-by-step explanation:

The area of each trapezoid can be found using the relevant formula:

  A = 1/2(b1 +b2)h . . . . b1, b2 are the base lengths; h is the height

For the top trapezoid, the height is 13 m-7 m = 6 m, so the area is ...

  A = 1/2(8 m +5 m)(6 m) = 39 m²

The area of the bottom trapezoid is ...

  A = 1/2(10 m +17 m)(7 m) = 94.5 m²

The area of the shape is the sum of the areas of the two trapezoids.

  area = 39 m² +94.5 m² = 133.5 m² . . . . area of the figure

__

The horizontal lengths are all marked, but the slant lengths are not. There are no angles or other information given that can help determine the slant lengths. In order to answer the question, we can assume that the trapezoids are isosceles. Then the base of the right triangle shown in the top trapezoid is (8 -5)/2 = 1.5 m. The height is 6 m. The Pythagorean theorem tells us the slant length is ...

  s1 = √(1.5² +6²) ≈ 6.1847 . . . . meters

Similarly, the base length of the right triangle shown next to the bottom trapezoid is (17 -10)/2 = 3.5 m. The height is 7 m. The slant length of that one is ...

  s2 = √(3.5² +7²) ≈ 7.8262 . . . . meters

__

The perimeter is the sum of the lengths of the sides. Note that the 17 m dimension includes 8 m that are not part of the boundary of the figure. The sum of lengths of the horizontal edges is ...

  10 m +(17 -8 m) +5 m = 24 m

The sum of the lengths of the slant edges is ...

  2·s1 +2·s2 = 2(6.1847 +7.8262) ≈ 28.02 . . . . meters

The perimeter of the figure is the sum of horizontal lengths and slant lengths:

  24 m + 28.02 m = 52.02 m . . . . perimeter of the figure

Answer:

y=7

Step-by-step explanation:

42/6=7

Answer:

y =7 iits divided

Step-by-step explanation:

y =6/42

y= 7

6/8

Step-by-step explanation:

1/2 = 0.5

6/8 = 0.75

therefore, 0.75 > 0.5

Answer:

2/45

Step-by-step explanation:

Answer:

Yes They Are Equivalent

Step-by-step explanation:

I checked by multiplying them.

Answer: yes, because they both equal x= -8

Step-by-step explanation:

m= -5 -3

calculate

= -8

m= -12+4

calculate

m= - 8

Applying the required rule or theorem, it can be concluded that the second biker is farther from the parking lot. The distance of the bikers to the parking lot are:

i. First biker = 17.0 km

ii. Second biker = 20.22 km

The path of travel of both bikers would form a triangle. Applying the Pythagoras theorem to the path of the first biker would give his distance from the starting point. While applying the cosine rule to the path of second rider would gives his distance to the starting point.

Thus,

a. To determine the distance of the first biker from the parking lot.

Let the required distance be represented by x. Applying the Pythagoras theorem, we have:

[tex]hyp^{2}[/tex] = [tex]adj 1^{2}[/tex] + [tex]adj 2^{2}[/tex]

[tex]x^{2}[/tex] = [tex]8^{2}[/tex] + [tex]15^{2}[/tex]

   = 64 + 225

   = 289

x = [tex]\sqrt{289}[/tex]

  = 17

x = 17 km

Thus, the first biker is 17.0 km from the starting point.

b. To determine the distance of the second biker from the parking lot.

Let the required distance be represented by x. So that applying the cosine rule, we have:

[tex]c^{2}[/tex] = [tex]a^{2}[/tex] + [tex]b^{2}[/tex] - 2ab Cos θ

[tex]x^{2}[/tex] = [tex]8^{2}[/tex] + [tex]15^{2}[/tex] - 2(15*8) Cos (180 - 20)

    = 64 + 225 - 240 Cos 160

    = 289 - 240 * -0.5

[tex]x^{2}[/tex] = 289 + 120

   = 409

x = [tex]\sqrt{409}[/tex]

 = 20.2237

x = 20.22 km

Thus, the second biker is 20.22 km from the starting point.

Therefore, the second biker is farther from the parking lot.

A sketch of the path of travel for the two bikers is attached for more clarifications.

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Using proportions, it is found that each of the pitchers for the Stingrays pitched for [tex]\mathbf{\frac{11}{3} = 3\frac{2}{3}}[/tex] innings.

The rule of three is:

3 pitchers - 11 innings

1 pitcher - x innings

Applying cross multiplication:

[tex]3x = 11[/tex]

[tex]x = \frac{11}{3}[/tex]

11 divided by 3 has result 3 with remainder 2, hence, also considering the answer as a mixed number:

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Answer:

EI = FI and EG is twice the length of EI. Try setting up algebraic equations 3x + 8 = 6x -4 to find the value of x. Then substitute it back into the equation to find the length.

Step-by-step explanation:

f(x+3)

[tex]\\ \sf\Rrightarrow 2(x+3-1)^2+3[/tex]

[tex]\\ \sf\Rrightarrow 2(x+2)^2+3[/tex]

[tex]\\ \sf\Rrightarrow 2(x^2+4x+4)+3[/tex]

[tex]\\ \sf\Rrightarrow 4x^2+8x+8+3[/tex]

[tex]\\ \sf\Rrightarrow 4x^2+8x+11[/tex]

Now

[tex]\\ \sf\Rrightarrow h(x)[/tex]

[tex]\\ \sf\Rrightarrow -f(x+3)-1[/tex]

[tex]\\ \sf\Rrightarrow -4x^2-8x-11-1[/tex]

[tex]\\ \sf\Rrightarrow -4x^2-8x-12[/tex]

[tex]\\ \sf\Rrightarrow 4(-x^2-2x-3)[/tex]

The speed of this car is equal to 1.6 km/min.

Given the following data:

To calculate the speed of this car:

Speed can be defined as the distance travelled by an object per unit time and it is usually measured in meter per seconds (m/s). Also, speed has magnitude but no direction and as such it is a scalar quantity.

Mathematically, speed is given by the formula;

[tex]Speed = \frac{distance}{time}[/tex]

Substituting the given parameters into the formula, we have;

[tex]Speed = \frac{50}{30}[/tex]

Speed = 1.6 km/min.

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Answer:

B

Step-by-step explanation:

Each tick = + or - 2 depending on which quadrant and axis

So the first line (the slanted one) intersects the y axis at (0,5) and continues until (2,5)

Then the line becomes straight (the y remains constant) from (2,5) (the points x value is 2) to (2,10) (the points x value is now 10)

Answer: -1/6

You can multiply 2/6 by 2 to get 4/12 which you can subtract from 6/12.

4/12 - 6/12 = -2/12 which you can simplify further to get -1/6

Answer:

1

Step-by-step explanation:

Answer:

the answer would be 3 bags of 6

Answer: There is no picture.

Step-by-step explanation:

Answer:

The value of [tex]f(2) - g(7)=-58[/tex]

Step-by-step explanation:

We have

[tex]f(x) = 3 ^ x - 7\\\\f(2) = 3 ^ 2 - 7\\\\=9-7\\\\=2\\\\g(x) = x ^ 2 + 11\\\\g(7) = 7 ^ 2 + 11\\\\=49+11\\\\=60\\\\f(2) - g(7)=2-60\\\\=-58[/tex]

Answer:

=35

Step-by-step explanation:

3(3) ^2 + 2(4)

= 3(9) + 8

= 35

Where you see a, substitute with 3 and where you see b, substitute with 4

Just follow the steps above.

[tex]\\ \sf\Rrightarrow 3a^2+2b[/tex]

[tex]\\ \sf\Rrightarrow 3(3)^2+2(4)[/tex]

[tex]\\ \sf\Rrightarrow 3(9)+8[/tex]

[tex]\\ \sf\Rrightarrow 27+8[/tex]

[tex]\\ \sf\Rrightarrow 35[/tex]

The answer is in the image attached. I hope it is helpful.

The least common denominator of two given rational expression are   4x, (x-3) and (x+3).

The factored denominator of two rational terms are called least common denominator of two rational numbers.

To find the least common denominator of two rational terms, we factor the expression and multiply all the distinct factors.

According to the given question

We have two rational expressions

[tex]\frac{9}{4x^{2} -12x}[/tex] and [tex]\frac{7x}{x^{2} -9}[/tex]

Now let's factorize the denominators

[tex]4x^{2} -12x =4x(x-3)[/tex]

and, [tex]x^{2} -9=(x+3)(x-3)[/tex]

Therefore,

[tex]\frac{9}{4x^{2} -12x}+\frac{7x}{x^{2} -9}[/tex]

⇒[tex]\frac{9}{4x(x-3)} +\frac{7x}{(x-3)(x+3)}[/tex]

⇒[tex]\frac{9(x+3)+7x(4x)}{4x(x-3)(x+3)}[/tex]

Therefore, the least common denominator of two given rational expression are   4x, (x-3) and (x+3).

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