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Answer:

a Penicillin is produced by fungal fermentation.

Explanation:

The industrial production of penicillin (PEN) occurs via fermentation using the filamentous fungus Penicillium chrysogenum

Penicillin G (benzylpenicillin) was first produced from a penicillium fungus that occurs in nature. The strain of fungus used today for the manufacture of penicillin G was created by genetic engineering to improve the yield in the manufacturing process.

Answer:

The brain is a part of the body that is particularly sensitive to high temperature. Hence some ungulates, like the Thomson's gazelle, use a counter-current heat exchanging structure known as the carotid rete to keep the brain cooler than the body.The cooled arterial blood then continues toward the brain.

El análisis de un grafico de velocidad versus tiempo permite encontrar los resultados para las preguntas son:

a) La velocidad es v= 0,6 m/s

b) La distancia recorrida  dₐ = 1,5 m

c) La distancia recorrida entre t= 5 y 10 s es  [tex]d_b[/tex] = 3,0 m

d) La aceleración   a = -0,4 m/s²

e) La distancia total recorrida  es [tex]d_{total}[/tex] = 5,3 m

f) La velocidad media es  [tex]v_{media}[/tex] = 0,44 m/s

La cinemática estudia el movimiento de los cuerpos, buscando relaciones entre la posición, la velocidad y la aceleración de los cuerpos.

La velocidad es definida como el cambio de la posición en función del tiempo y la aceleración es el cambio de la velocidad en el intervalo de tiempo.

           .[tex]v= \frac{\Delta x}{t} \\a = \frac{\Delta v}{t}[/tex]

Donde v y a son la velocidad y aceleración, respectivamente, t es el tiempo y Δx y Δv son la variación de la posición y la velocidad, respectivamente.  

En el adjunto muestran un grafico de la velocidad en función del tiempo, donde del área bajo la curva obtenemos la distancia recorrida y la pendiente corresponde a la aceleración del cuerpo.

Respondamos las preguntas:

a)  La velocidad de la bola a los 5 s.

Como es un grafico de velocidad versus tiempo, la velocidad puede ser leída directamente, en el grafico tenemos un valor de

          v= 0,6 m/s  

b) La distancia recorrida corresponde al área bajo la curva.

         [tex]d_a = \frac{v_f - v_o}{2} t \\d_a = \frac{0.6-0}{ 2}\ 5[/tex]  

         d = 1,5 m

c) La distancia en el intervalo de 5 a 10 s.

En este intervalo la velocidad es constante, el área es

        [tex]d_b = v \Delta t\\d_b = 0.6 \ 5\\[/tex]  

        d =  3 m

d) La aceleración en el intervalo  10 a 12 s.

La aceleracion es la pendiente del grafico

        a = [tex]\frac{\Delta v}{\Delta t}[/tex]  

        a = [tex]\frac{-0.2 - 0.6}{12-10}[/tex]

        a = -0,4 m/s²

El signo negativo indica que la aceleración se opone a la velocidad del cuerpo.

e) La distancia total recorrida  

       [tex]d_{total} = d_a + d_b + d_c[/tex]

      dₐ = 1,5 m

      [tex]d_b[/tex] = 3,0 m

Busquemos la distancia en el ultimo intervalo

         [tex]d_c = \frac{0.6 + 0.2}{2} ( 12-10)[/tex]

       [tex]d_c[/tex] = 0,8 m

Substituimos

     [tex]d_{total}[/tex] = 1,5 + 3,0 + 0,8

     [tex]d_{total}[/tex]  =  5,3 m

f) La rapidez  de la bola

La rapidez prmedio es la relación entre la distancia recorrida en el tiempo.

         [tex]v_{avg} = \frac{\Delta x}{\Delta t }[/tex]  

         [tex]v_{avg} = \frac{5.3}{12}[/tex]

         [tex]v_{avg}[/tex]  =0,44 m/s

En conclusión usando el análisis de un grafico de velocidad versus tiempo podemos encontrar los resultados para las preguntas son:

         a) La velocidad es v= 0,6 m/s

         b) La distancia recorrida  da = 1,5 m

         c) La distancia recorrida entre t= 5 y 10 s es  db = 3,0 m

         d) La aceleración   a = -0,4 m/s²

         e)  La distancia total recorrida  es [tex]d_{total}[/tex] = 5,3 m

          f) La velocidad media es  [tex]v_{avg}[/tex] = 0,44 m/s

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Answer:

reduce passive stiffness and increase range of movement during exercise.

Explanation:

stretching performed as part of a warm up prior to exercise is thought to reduce passive stiffness and increase range of movement during exercise. in general it appears that is static stretching is most beneficial for athletes requiring flexibility for their sports.

Answer:   6.605

Explanation:

Answer:

Explanation:

This is an application of Newton's second Law.

Formula

F = m * a

F = 300 N

m = 100 kg

a = ?

F = m * a

300N = 100 kg * a            Divide by 100

300N/100kg = a

a = 3 m/sec^2

Answer:

0.4 g/cm

Explanation:

density (g cm ³) = mass (g)

÷

volume (cm³)

Answer:

C. 4 g/cm

Explanation:

Use the formula:

density = mass ÷ volume

Sub in the values:

density = 36 ÷ 9 = 4 g/cm

Answer = 4 g/cm

Answer:

hi im from canada so can we be friends

Explanation: Solution

1.

Gravitational potential energy

U=mgh=500*9.8*50

U=245000 J

2.

Kinetic energy is present at bottom of the hill

K=(1/2)mV2=(1/2)*500*27.82

K=193210 J

3.

Work done by friction

W=193210-245000=-51790 J

The mechanical energy at the top and bottom of the hill is equal to 352800 J and 163840 J respectively.

Kinetic energy (KE) can be described as the energy possessed by a moving object due to its motion. Work by a body will be done to change the kinetic energy. The kinetic energy is represented as K.E = ½mv².

Potential energy (P.E) can be described as the energy that is stored by an object due to its position and is represented in the equation as P.E = mgh, where ‘m’ is the mass, ‘g’ is the acceleration due to gravity and ‘h’ is the height.

The mechanical energy = Kinetic energy + potential energy

Given, the mass of the car, m = 500 Kg

The height of the hill, h = 72 m

The velocity of the car, v = 25.6 m/s

At the top of the hill, the mechanical energy = potential energy

The potential energy at the top of the hill, = mgh

P. E. = 500 × 9.8 ×72

P.E. = 352800 J

At the bottom of the hill, the mechanical energy = kinetic energy

The kinetic energy of the car at the bottom of the hill,

K.E. =  ½ × 500 (25.6)²

K.E. = 163840 J

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Answer:

the correct answer is sugar

Answer:

Explanation:

a) I = ½mR² = ½(19)(0.15²) = 0.21375 kg•m²

b) τ = Fnet(r) = (25 - 12)(0.15) = 1.95 N•m

c) CCW

d) a = τ/I = 1.95 / 0.21375 = 9.12280701... = 9.1 rad/s²

e) CCW

If its is a frozen hockey puck, it bounce off the ground after collision to a height of 0.3m.

Given the data in the question;

Since the hockey puck was initially in the referee's hands

First we will find the velocity of the Puck when it hits the ground

From the Third Equation of Motion:

[tex]v^2 = u^2 + 2as[/tex]

Where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity and s is the distance.

Since the pluck is under gravity, we will have:

[tex]v^2 = u^2 + 2gh[/tex]

We substitute in our value and find "v"

[tex]v^2 = 0 + (2 \ *\ 9.8m/s^2\ *\ 2.5m )\\\\v^2 = 47.04m^2/s^2\\\\v= \sqrt{47.04m^2/s^2}\\\\v = 6.85857m/s[/tex]

Now, Velocity of the hock puck after it hits the ground and bounce back;

We know that; Coefficient of restitution [tex]= \frac{Relative\ velocity\ after\ collision}{Relative\ velocity\ before\ collision}[/tex]

Hence, Relative Velocity after collision = Coefficient of restitution × Relative Velocity before collision

we substitute in our values;

Relative Velocity after collision [tex]= 0.35 \ *\ 6.85857m/s[/tex]

Relative Velocity after collision [tex]= 2.4 m/s[/tex]

Now, to determine how high should the puck bounced back

We use the Third Equation of Motion:

[tex]v^2 = u^2 + 2as[/tex]

Where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity and s is the distance.

Since the pluck is under gravity, we will have:

[tex]v^2 = u^2 + 2gh[/tex]

Now, since the hockey puck bounces back, it is experiencing a negative acceleration

Hence, the equation becomes

[tex]v^2 = u^2 - 2gh[/tex]

We substitute our values into the equation and find "h"

[tex](0m/s)^2 = (2.4m/s)^2 - ( 2*9.8m/s^2*h)\\\\0 = 5.76m^2/s^2 - (19.6m/s^2*h)\\\\(19.6m/s*h) = 5.76m^2/s^2 \\\\h= \frac{ 5.76m^2/s^2 }{19.6m/s^2}\\\\h = 0.3m[/tex]

Therefore, If its is a frozen hockey puck, it bounce off the ground after collision to a height of 0.3m.

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Answer:

Explanation:

The engine should create the same force

1) F = ma

  F = M(½a)

therefore

ma = ½Ma

 m = ½M

 M = 2m

 M = 2(0.8)

 M = 1.6 kg

2) Unbalanced forces

 a. Two people pulling on the same side of a wheelbarrow

 c. Two people of opposite sides of a big tire. One pushes the tire and one pulls it with equal force

3) b. The force of friction on the object is different if it is stationary or not

2.34 A

Explanation:

[tex]V = IR \Rightarrow I = \dfrac{V}{R} = \dfrac{117\:\text{V}}{50\:Ω} = 2.34\:\text{A}[/tex]

Answer:

31

Explanation:

No need

Answer: I think it’s craters

Explanation:

Answer:

MOUNTAINS

CRATERS

PLATEAUS

Explanation:

The Moon has many familiar landforms like mountains, plains, and dark patches that look like seas. We now know that these areas are not seas filled with water. They are deep dry plains.

Answer:

D) 19.8 lbs

Explanation:

1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.

1kg is also equal to 2.205 lbs. 9*2.205=19.8416

9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system

a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.

This leaves us with 19.8 lbs

Answer: 1.646 m/s²

Explanation:

The distance that is traveled by the astronaut given that the motion is free-fall can be calculated through the equation,

   d = Vot + 0.5at²

where d is the distance, Vo is the initial velocity, t is the time, and a is the acceleration. Substituting the known,

  6 = (0 m/s)(2.7 s) + 0.5(a)(2.7 s)²

Determining the value of a,

   a = 1.646 m/s²

What ever games your playing it wont work you cant defeat me hahhahha oh I know :O but he can AHHHH :D D: NOOOO IMPOSSIBLE.

The statement shows a case of rotational motion, in which the disc decelerates at constant rate.

i) The angular acceleration of the disc ([tex]\alpha[/tex]), in revolutions per square second, is found by the following kinematic formula:

[tex]\alpha = \frac{\omega_{f}-\omega_{o}}{t}[/tex] (1)

Where:

If we know that [tex]\omega_{o} = \frac{5}{12}\,\frac{rev}{s}[/tex], [tex]\omega_{f} = 0\,\frac{rev}{s}[/tex] y [tex]t = 15\,s[/tex], then the angular acceleration of the disc is:

[tex]\alpha = \frac{0\,\frac{rev}{s}-\frac{5}{12}\,\frac{rev}{s}}{15\,s}[/tex]

[tex]\alpha = -\frac{1}{36}\,\frac{rev}{s^{2}}[/tex]

The angular acceleration of the disc is [tex]\frac{1}{36}[/tex] radians per square second.

ii) The number of rotations that the disk makes before it stops ([tex]\Delta \theta[/tex]), in revolutions, is determined by the following formula:

[tex]\Delta \theta = \frac{\omega_{f}^{2}-\omega_{o}^{2}}{2\cdot \alpha}[/tex] (2)

If we know that [tex]\omega_{o} = \frac{5}{12}\,\frac{rev}{s}[/tex], [tex]\omega_{f} = 0\,\frac{rev}{s}[/tex] y [tex]\alpha = -\frac{1}{36}\,\frac{rev}{s^{2}}[/tex], then the number of rotations done by the disc is:

[tex]\Delta \theta = 3.125\,rev[/tex]

The disc makes 3.125 revolutions before it stops.

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Answer:

The equation for speed is simple: distance divided by time. You take the distance traveled (for example 3 meters), and divide it by the time (three seconds) to get the speed (one meter per second).

Explanation:

Answer:

True statements a, b, and c

Explanation:

Answer d is false because in any collision, each object receives the same impulse. Also the momentum of car 1 is mv, while the momentum of car 2 is 0.5m(1.5v) = 0.75mv

The impulse of collision of cars depends on the mass and velocity of the cars. The statements which are true about the car collisions are option a, b, c.

Impulse is a physical quantity expressed as the product of force and time. The change in momentum mΔV is numerically equals to the impulse F t.

If two identical cars with identical speeds collide head on, the magnitude of the impulse received by each car and each driver is the same as if one car at the same speed had collided head on with a concrete wall. Because they have equal mass and velocity.

The bigger acceleration is experienced by the one which have lighter mass thus car 1 with lower mass experience higher acceleration .

The essential safety benefit of crumple zones (parts of the front of a car designed to receive maximum deformation during a head-on collision) is due to their absorbing kinetic energy.

Converting this energy into deformation, and lengthening the effective collision time, thus reducing the average force experienced by the driver.

The momentum change is proportional to the velocity. The one which have higher velocity is having the higher momentum. Thus car 2 have higher velocity. Thus option d is false.

Therefore, the statements which are true are a, b and c.

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Answer:

Explanation:

Time needed for a balloon to drop from vertical rest a distance of 11.6 m

t = √(2h/g) = √(2(11.6)/9.8) = 1.538618

d = vt = 4.2(1.538618) = 6.462197...

d = 6.5 m

Horizontal distance x = 6.5 m from the bridge he should be when the youth drops the balloon with velocity 4.2 m/s.

When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.

Uniform motion an object is said to have uniform motion when object cover equal distance in equal interval of time within exact fixed direction. For a body in uniform motion, the magnitude of its velocity remains constant over time.

Given in the question time needed for a balloon to drop from vertical rest a distance of 11.6 m

t = √(2h/g) = √(2(11.6)/9.8) = 1.538618

d = vt = 4.2(1.538618) = 6.462197...

d = 6.5 m

Horizontal distance x = 6.5 m from the bridge he should  be when the youth drops the balloon with velocity 4.2 m/s.

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Answer:

Explanation:

High levels of air pollution can cause an increased risk of heart attack, wheezing, coughing, and breathing problems, and irritation of the eyes, nose, and throat. Air pollution can also cause worsening of existing heart problems, asthma, and other lung complications.

Ambient air pollution accounts for an estimated 4.2 million deaths per year due to stroke, heart disease, lung cancer and chronic respiratory diseases. Around 91% of the world's population lives in places where air quality levels exceed WHO limits.

Serious Effects of Pollution on Our Humans and Environment

Environment Degradation. The environment is the first casualty for the increase in pollution weather in air or water. ...

Human Health. ...

Global Warming. ...

Ozone Layer Depletion. ...

Infertile Land.

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Answer:

3q

Explanation:

Answer:

4th answer

Explanation:

The gradient of a distance-time graph gives the speed.

gradient = distance / time = speed

Here, the gradient is a constant till 30s. So it has travelled at a constant speed. It means it had not accelarated till 30s. and has stopped moving at 30s.

Answer:

If two masses 5.2 kg and 4.8 kg are attached to the ends of inextensible strings passed over a frictionless pulley then the acceleration of system is 0.4 ms-2.

Explanation:

The force that will move the box at constant velocity must be a little more than 64 N.

The coefficient of sliding friction is obtained from the formula;

μ= F/R

Where;

F = frictional force

μ = coefficient of sliding friction

R = Normal reaction

It is necessary to note that the force that will move the body must be greater than the frictional force acting between the body and the surface in order to move the body. Hence, the force that will move the box at constant velocity must be a little more than 64 N.

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Answer:

Explanation:

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