Name two triangles that are congruent by the ASA Postulate.

ATC=DOG

ATC=NFI

PQR=INF

PQR=IFN

Answer:

Sale price = x - 0.45x

Step-by-step explanation:

Answer:

-4<-1 and -1<4

Step-by-step explanation:

Answer:

As shown in the attachment,

Step-by-step explanation:

Part 1

The snow melts at 2.5 inches per hour. After 2 hours, 2*2.5 = 5 inches has melted overall. We started with 15 inches, so there are 15-5 = 10 inches of snow left after 2 hours.

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Part 2

Let t be the number of hours that have elapsed. Because the snow melts at a rate of 2.5 inches per hour, this means after t hours, 2.5t inches of snow melts away. Subtract this from the 15 inches we start with to get 15-2.5t. This expression is the same as -2.5t+15

Answer:

80%

Step-by-step explanation:

800-160=640

640/800=.8

.8=80%

Answer:

4 hours

Step-by-step explanation:

It take them 1.5 h ÷ 0.5 h to chop down 1 tree, so it would take 0.5 h × 8 = 4 hours to chop down 8 trees

Answer: 5 : 12

Step-by-step explanation:

the total flower = 5 + 7 = 12

so tulips to total flowers = 5 : 12

please give me a brainliest answer

Answer:

the answer is D

Step-by-step explanation:

hopefully im right

Answer:

what is the question asking?

Answer:

Terms:4x, -2x

Coefficients:4, 2

Constant:3

Answer:

125000

Step-by-step explanation:

Answer:

0

Step-by-step explanation:

( x1, y1 ) = ( - 4, - 2 )

Here,

x1 = - 4

y1 = - 2

( x2, y2 ) = ( - 4, 22 )

Here,

x2 = - 4

y2 = 22

Formula : -

Slope = ( y2 - y1 ) / ( x2 - x1 )

Slope

= ( 22 - ( - 2 ) ) / ( - 4 - ( - 4 ) )

= ( 22 + 2 ) / ( - 4 + 4 )

= 24 / 0

= 0

Answer:

88 miles per hour

Step-by-step explanation:

12 + 122 = 134 minutes for the entire journey

The total distance was 197 miles.

The avarage speed is the total distance divided by the total time:

Convert the time from minutes to hours dividing it by 60:

134/60 = 2.24 hours

197/2.24 = 87.95 ≈ 88 miles per hour

Answer:

128 divided by 2 for 5 times is your answer enjoy my.kiddo

[tex]\tt5( x - 3 ) = 5x - 15 \\ \tt5x - 15 = 5x - 15 \\ \tt5x - 5x = - 15 + 15 \\ \tt\bcancel{5x} - \bcancel{5x} = \bcancel{- 15} + \bcancel{15} \\ \boxed{\tt0 = 0}[/tex]

Value of x (substitute 0 in the place of x).

[tex]\tt5( (0) - 3 ) = 5(0) - 15 \\ \tt0 - 15 = 0 - 15 \\ \tt \boxed{\tt -15 = -15}[/tex]

Answer:

it will take the certain particle 15/4 (unit of time) to reach 30 km/hr

Input 30 as for y and solve the equation.

Step-by-step explanation:

Since y is kilometers per hour and the question is asking for how long it takes for a certain particle to reach 30 km/hr, you input 30 for y and solve for x.

-4x + y = 15

-4x + (30) = 15

subtract 30 from both sides

-4x = -15

divide -4 from both sides

x = 15/4

it will take the certain particle 15/4 (unit of time) to reach 30 km/hr

Answer:

To overcome such type of real world problems we use union. Unlike structures union occupies single memory location to store all its members. So, unions are helpful when you want to store value in single member from a set of members. Size of union is defined according to size of largest member data type.

Step-by-step explanation:

In union, all members share the same memory location. For example in the following C program, both x and y share the same location. If we change x, we can see the changes being reflected in y. #include <stdio.h> // Declaration of union is same as structures.

Answer:

Yes, its true that 30 is 6 times as much as 5.

6×5=30.

Answer:

yes

Step-by-step explanation:

because 6x5=30

Answer:

I'll assume "position 7" refers to distance and not to the order of other people.  

Step-by-step explanation:

We want an equation of the form y=mx+b, where m is the slope and b is the y-intercept (the value of y when x=0).  We can assume that "claps" is a new measure of distance.  0 claps is the finish.

Let's express the information provided in point format.

"At 2 claps, Joe is in position 7"  is (2,7)  2 is the distance (claps) and 7 is the time (minutes)

And we can say the rate is also the slope of a line.  "rate of 3 claps per minute" is 3c/m, where c is claps and m is minutes.

We can start a line equation by stating y = 3x + b, where we're using the rate, 3 c/m, as the slope, m.

We need to determine the value of b.  We can use the given point (2,7) and solve for m:

y = 3x + b

7 = 3*(2) + b

b = 1

The equation becomes y = 3x + 1

y is the distance in claps and x is the time in minutes.

At a time of 2 claps he is at position of 7.  b = 1 means he started 1 clap further from the finish at 0 claps.

To find the time required to reach the finish, we need to know the total distance, in claps.

Answer:

forest, tundra, and grasslands

Answer:

Step-by-step explanation:

Area formula:

The height is:

Substitute the value for area and set equation:

Note the second root ignored as negative

Answer:

x = 3.08  (3 s.f.)

Step-by-step explanation:

Area of a Triangle (using sine)

 [tex]\sf Area=\dfrac{1}{2}ac \sin B[/tex]

where:

Given:

Substitute the given values into the formula:

[tex]\implies 4\sqrt{2}=\dfrac{1}{2}(2x-3)(x+2) \sin 45^{\circ}[/tex]

[tex]\implies 8\sqrt{2}=(2x-3)(x+2) \sin 45^{\circ}[/tex]

[tex]\implies 8\sqrt{2}=(2x-3)(x+2) \left(\dfrac{\sqrt{2}}{2}\right)[/tex]

[tex]\implies 8\sqrt{2}\left(\dfrac{2}{\sqrt{2}}\right)=(2x-3)(x+2)[/tex]

[tex]\implies (2x-3)(x+2) =16[/tex]

[tex]\implies 2x^2+4x-3x-6=16[/tex]

[tex]\implies 2x^2+x-22=0[/tex]

Use the Quadratic Formula to solve for x:

[tex]x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0[/tex]

[tex]\implies a=2, \quad b=1, \quad c=-22[/tex]

[tex]\implies x=\dfrac{-1 \pm \sqrt{1^2-4(2)(-22)} }{2(2)}[/tex]

[tex]\implies x=\dfrac{-1 \pm \sqrt{177}}{4}[/tex]

[tex]\implies x=3.08, -3.58\:\: \sf (3 \:s.f.)[/tex]

As distance is positive:

[tex]\implies x=3.08 \:\:(3 \sf \:s.f.) \:\textsf{only}[/tex]

Answer:

...probably

Step-by-step explanation:

since it's square units and this is a right triangle

area = (width * height) / 2

area = 6 * 3 / 2

area = 18 / 2

area = 9 square units²

Answer:

9 [tex]units^{2}[/tex]

Step-by-step explanation:

The formula to find the area of a triangle is [tex]A=\frac{1}{2}b*h[/tex] where b is the base or bottom of the triangle and h is the height of the triangle.

The base of the triangle in the picture is 6 units.

The height of the triangle in the picture is 3 units.

Substituting these values into the area formula:

[tex]A=\frac{1}{2}(6*3)=\frac{1}{2}(18)=9[/tex]

So the area of the triangle is 9 [tex]units^{2}[/tex]

Answer:

thank you :) for the points

Answer:

Thanks

Step-by-step explanation:

Answer:

y = 1/3x - 19/3

Step-by-step explanation:

3y = x -3

y = 1/3x -3

Slope = 1/3

Point= (1,-6)

y-intercept = -6 - (1/3)(1) = -6 - 1/3 = -19/3

Answer:

i think the answer is b Robert earned 10, which was less than twice what Eric earned

El área del paralelogramo con base de 13 centímetros y altura de 8 centímetros es 104 centímetros cuadrados.

El área del paralelogramo, en centímetros cuadrados, es igual al producto de su base por su altura, ambos en centímetros. En consecuencia, el área de la figura geométrica es la siguiente:

[tex]A = (13\,cm)\cdot (8\,cm)[/tex]

[tex]A = 104\,cm^{2}[/tex]

El área del paralelogramo con base de 13 centímetros y altura de 8 centímetros es 104 centímetros cuadrados.

Invitamos cordialmente a ver esta pregunta sobre paralelogramos: https://brainly.com/question/17205536

due to my knowledge its 75 because it is.

Step-by-step explanation:

first I thought the angles at Q and P are right angles (90 degrees). but the last part tells me they are not.

so, all the "perpendicular" answers are out.

answer 1 and 2 are all correct but I would pick 2, because it had the most detail that's true.

and since these 2 lines are parallel, the must have the same angles with the crossing line.

therefore, when the angle RQS is 75 degrees, then the angle TPU is also 75 degrees.