Luyando wants to have a bit of fun with her wagon. She puts her 12 baby sister, Waluse, on the wagon and pulls it across the floor using a rope at an angle of 22° above the floor. Using the spring balance that mum uses to weigh things in the kitchen, Luyando realises that the tension in the rope is constant and has a value of about 40 . Use the work-energy theorem to find Waluse’s speed after being pulled 4.0 across the living room. The coefficient of friction is 0.2 and the weight of the wagon is 3kg

Answer:

1. Absorption or Emission of the light

2. Light induced changes in the matter  

Explanation:

When an electromagnetic wave such as light interacts with solid, two consequences are for sure:

1. Absorption or Emission of the light

2. Light induced changes in the matter

When light travels through the solid, the intensity of light decreases as a result of addition of light energy to the body to which it interacts. If the medium or body to which light interacts is low in absorbing due to its atomic structure inside then light passing through it will show it. On the contrary, if a material is high in absorbing, very less intensive light will travel out.

Moreover, there will ionization of the atoms inside the medium to which light interacts. As light carries energy and when it interacts with atoms of the body, atoms gets energy and excited or de-excited accordingly.

Hence, above are the two primary consequences of this interaction.

Answer:

Right now I have three.

Explanation: Thanks for the points luv ^-^.

Answer:

I have two

Explanation:

Answer:

Because psychology helps you understand the mind of someone else. It can teach you about traits people may have based on what you see, or a likely personality of someone based on their history, and so many other things. Psychology helps you understand a whole other person, and understanding people is a big part in many things such as medicine, STEM, nursing, teaching, and many other things. Understanding people and the things around you is a necessary skill.

Answer:

Here:

Explanation:

These eight phases are, in order, new Moon, waxing crescent, first quarter, waxing gibbous, full Moon, waning gibbous, third quarter and waning crescent. The cycle repeats once a month (every 29.5 days).

Answer: the effective design stiffness required to limit the bumper maximum deflection during impact to 4 cm is 3906250 N/m

Explanation:

Given that;

mass of vehicle m = 1000 kg

for a low speed test; V = 2.5 m/s

bumper maximum deflection = 4 cm = 0.04 m

First we determine the energy of the vehicle just prior to impact;

W_v = 1/2mv²

we substitute

W_v = 1/2 × 1000 × (2.5)²

W_v = 3125 J

now, the the effective design stiffness k will be:

at the impact point, energy of the vehicle converts to elastic potential energy of the bumper;

hence;

W_v = 1/2kx²

we substitute

3125 = 1/2 × k (0.04)²

3125 = 0.0008k

k = 3125 / 0.0008

k = 3906250 N/m

Therefore, the effective design stiffness required to limit the bumper maximum deflection during impact to 4 cm is 3906250 N/m

Explanation:

Joule, unit of work or energy in the International System of Units (SI); it is equal to the work done by a force of one newton acting through one metre. ... In electrical terms, the joule equals one watt-second—i.e., the energy released in one second by a current of one ampere through a resistance of one ohm.

Answer:

Explanation:

As the car Started from rest means that Initial Velocity "Vi = 0 m/s" and final Velocity is given "Vf = 42m/s". Time is given "t = 6.2s"

Acceleration is required a =?

Use Formula;;    a = [tex]\frac{Vf-Vi}{t}[/tex]

a = [tex]\frac{42-0}{6.2}[/tex]

a = 6.7741 m/s² ≈ 6.8 m/s²

Mark me as brainliest if you got it...

Answer:

gravity pulls objects down to earth.

Explanation

Because Isaac Newton stated that. In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

Answer:

This is alpha decay

Explanation:

Answer:

[tex]\tau=20000\ Nm[/tex]

Explanation:

Given that,

The force the cable exerts on the bridge is 5000N

The length of the bridge is 8 m

We need to find the torque caused by the cable pulling horizontally on the inclined draw bridge. The torque acting on it is given by :

[tex]\tau=Fr[/tex]

Putting all the values,

[tex]\tau=5000\ N\times 8\ m\\\\=20000\ Nm[/tex]

So, the required torque is 20000 Nm.

Answer:

I think A not sure took this test 5  yrs ago

Explanation:

Answer:

The SI unit of thermal conductivity is watts per meter-kelvin (W/(m⋅K)).

Explanation:

hope this will help u

Answer:

positive

proton and neutron

electron

Answer:

c. 337

Explanation:

can someone answer my question

Answer:

[tex]v_f=4\:\mathrm{m/s\: in\:Biff's\:direction}[/tex]

Explanation:

Using the Law of Conservation of Momentum, we can set up the following equation:

[tex]m_2v_2-m_1v_1=m_fv_f[/tex], where [tex]m_1v_1[/tex] is Bruce's momentum and [tex]m_2v_2[/tex].

Plugging in given values, we get:

[tex]90\cdot7-45\cdot2=(90+45)v_f, \\v_f=\frac{540}{135}=\fbox{$4\:\mathrm{m/s}$}[/tex].

Answer:

Explanation:

Displacement ( downwards ) = 50 m , initial speed = - u (upwards ) ,

time = 5 s .

acceleration due to gravity( downwards)  = 9.8 m /s² .

s = ut + 1/2 g t²

50 = - 5 u + .5 x 9.8 x 5²

50 = -5u + 122.5

5u = 122.5 - 50

u = 14.5 m /s

2 )

final velocity v = 0 , height upto which it rises = h

v² = u² - 2 g h

0 = 14.5² - 2 x 9.8 h

h = 10.72 m

3 )

At the highest point velocity = 0

4 )

At the highest point acceleration = 9.8 m /s² downwards .

Complete Question:

What force (in N) must be exerted on the master cylinder of a hydraulic lift to support the weight of a 2100 kg car (a large car) resting on the slave cylinder ? The master cylinder has a 2.00-cm diameter and the slave has a 24.0-cm diameter

Answer:

[tex]F_1 = 142.92N[/tex]

Explanation:

Given

[tex]m = 2100kg[/tex] --- mass

[tex]D_1 = 2.00\ cm[/tex] --- diameter of the large cylinder

[tex]D_2 = 24.0\ cm[/tex] --- diameter of the slave cylinder

To do this, we apply Archimedes' principle of buoyancy which implies that:

[tex]P = \frac{F_1}{A_1} = \frac{F_2}{A_2}[/tex]

Where

[tex]F_1 = Force\ on\ the\ master\ cylinder[/tex]

[tex]F_2 = Force\ on\ the\ slave\ cylinder[/tex]

[tex]A_1 = Area\ of\ the\ master\ cylinder[/tex]

[tex]F_2 = Area\ of\ the\ small\ cylinder[/tex]

Calculating the area of the master cylinder.

[tex]A_1 = \pi r_1^2[/tex]

[tex]r_1 = \frac{1}{2}D_1 = \frac{1}{2} * 2.00cm = 1.00cm[/tex]

[tex]A_1 = \pi* 1^2[/tex]

[tex]A_1 = \pi * 1[/tex]

[tex]A_1 = \pi[/tex]

Calculating the area of the slave cylinder.

[tex]A_2 = \pi r_2^2[/tex]

[tex]r_2 = \frac{1}{2}D_2 = \frac{1}{2} * 24.00cm = 12.00cm[/tex]

[tex]A_2 = \pi* 12^2[/tex]

[tex]A_2 = \pi* 144[/tex]

[tex]A_2 = 144\pi[/tex]

Substitute these values in:

[tex]P = \frac{F_1}{A_1} = \frac{F_2}{A_2}[/tex]

[tex]\frac{F_1}{\pi} = \frac{F_2}{144\pi}[/tex]

Multiply both sides by [tex]\pi[/tex]

[tex]\pi * \frac{F_1}{\pi} = \frac{F_2}{144\pi} * \pi[/tex]

[tex]F_1 = \frac{F_2}{144}[/tex]

The force exerted on the slave cylinder (F2) is calculated as:

[tex]F_2 = mg[/tex]

[tex]F_2 = 2100 * 9.8[/tex]

[tex]F_2 = 20580[/tex]

Substitute 20580 for F2 in [tex]F_1 = \frac{F_2}{144}[/tex]

[tex]F_1 = \frac{20580}{144}[/tex]

[tex]F_1 = 142.92N[/tex]

Hence, the force exerted on the master cylinder is approximately 142.92N

Answer:

The International Astronomical Union (IAU) downgraded the status of Pluto to that of a dwarf planet because it did not meet the three criteria the IAU uses to define a full-sized planet. Essentially Pluto meets all the criteria except one—it “has not cleared its neighboring region of other objects

Explanation:

Answer:

Explanation:

Sample Response: Sound travels faster in a warm room because temperature affects the speed of a wave. In a warm room, the particles of air move faster and have higher chances of bumping into each other, which then increases the instances of energy transfer.

By Newton's second law, the net vertical force acting on the object is 0, so that

n - w = 0

where n = magnitude of the normal force of the surface pushing up on the object, and w = weight of the object. Hence n = w = mg = 196 N, where m = 20 kg and g = 9.80 m/s².

The force of static friction exerts up to 80 N on the object, since that's the minimum required force needed to get it moving, which means the coefficient of static friction µ is such that

80 N = µ (196 N)   →   µ = (80 N)/(196 N) ≈ 0.408

Moving at constant speed, there is a kinetic friction force of 40 N opposing the object's motion, so that the coefficient of kinetic friction ν is

40 N = ν (196 N)   →   ν = (40 N)/(196 N) ≈ 0.204

And so the closest answer is C.

(Note: µ and ν are the Greek letters mu and nu)

Answer:

[tex]a=368.97\ m/s^2[/tex]

Explanation:

Given that,

Initial angular velocity, [tex]\omega=0[/tex]

Acceleration of the wheel, [tex]\alpha =7\ rad/s^2[/tex]

Rotation, [tex]\theta=14\ rotation=14\times 2\pi =87.96\ rad[/tex]

Let t is the time. Using second equation of kinematics can be calculated using time.

[tex]\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\\t=\sqrt{\dfrac{2\theta}{\alpha }} \\\\t=\sqrt{\dfrac{2\times 87.96}{7}} \\\\t=5.01\ s[/tex]

Let [tex]\omega_f[/tex] is the final angular velocity and a is the radial component of acceleration.

[tex]\omega_f=\omega_i+\alpha t\\\\\omega_f=0+7\times 5.01\\\\\omega_f=35.07\ rad/s[/tex]

Radial component of acceleration,

[tex]a=\omega_f^2r\\\\a=(35.07)^2\times 0.3\\\\a=368.97\ m/s^2[/tex]

So, the required acceleration on the edge of the wheel is [tex]368.97\ m/s^2[/tex].

The radial component of the acceleration (in m/s2) on the edge the wheel is 369.45 m/s²

Using ω² = ω₀² + 2αθ, we find the final angular speed after 14 revolutions, ω where

So, substituting the values of the variables into the equation, we have

ω² = ω₀² + 2αθ,

ω² = (0 rad/s)² + 2 × 7 rad/s² × 87.965 rad.

ω² = 0 rad²/s² + 1231.504 rad²/s²

ω² = 1231.504 rad²/s²

ω = √(1231.504 rad²/s²)

ω = 35.09 rad/s

We know that the radial acceleration a = rω² where

So, substituting the values of the variables into the equation, we have

a = rω²

a = 0.30 m × (35.09 rad/s)²

a = 0.30 m × 1231.504 rad²/s²

a = 369.45 m/s²

So, the radial component of the acceleration (in m/s2) on the edge the wheel is 369.45 m/s².

Learn more about radial acceleration here:

https://brainly.com/question/25243603

Answer:

see that for the same pressure the displaced height in each cylinder is different because its diameter is different.   Pascal's principle

Explanation:

The pressure on a system is given by the relations

         P = ρ g h

         P = F / A

where ρ is the density of the liquid, h the height and A the area

The expressions above we see that if for the same height the pressure is the same regardless of the shape of the cylinder.

With the second expression we see that if the system has a different area, the pressure is

         P = [tex]\frac{F_{1} }{A_{1} } = \frac{F_{2} }{A_{2} }[/tex]

where we use subscript 1 for one body and subscript 2 for the other body

         F₁ = [tex]\frac{A_{1} }{A_{2} } F_{2}[/tex]

The cylinder displacement is

         V = A h

where V is the volume and h the height, in general the liquids are incompressible therefore the displaced volume is constant in the two bodies

         V = A₁ h₁ = A₂ h₂

         [tex]\frac{A_{1} }{A_2} = \frac{h_2}{h_1}[/tex]

we substitute

        F₁ = [tex]\frac{h_2}{h_1}[/tex] F2

From here we see that for the same pressure the displaced height in each cylinder is different because its diameter is different.

If the diameter is the same, the offset height is the same

Answer:

Follows are the solution to the given question:

Explanation:

The rectangular part has a length of [tex]14 \ mm[/tex] and its rectangular part has a width of [tex]4.98 \ mm[/tex].

In option A

Calculating the area of the rectangular throgh the given piece:

[tex]\to A_R = WL=(14 mm) (4.98 mm) =69.72 \ mm^2[/tex]

In option B

Calculating the ratio of rectangle's width which is rectangle's length:

[tex]\to R_{WL}=\frac{W}{L}= \frac{4.98 \ mm}{14 \ mm} = 0.3557[/tex]

So, the ratio of rectangle's width to rectangle's length is 0.3557  .

In option C

Calculating the Perimeter of the rectangle:

[tex]\to P_R=2(W+L)=2(14 \ mm+ 4.98 \ mm)= 2(18.98) = 37.96 \ mm[/tex]  

In option D

Calculating the difference between length and width:  

[tex]\to D_{LW} = L- W = 14\ mm -4.98 \ mm =9.02 \ mm[/tex]

In option E

Calculating the ratio of length to width:

[tex]\to R_{LW}=\frac{L}{W} =\frac{14\ mm}{4.98 \ mm} = 2.811[/tex]

Answer:

1: E

2: A

3: C

4: B

5: D

Explanation:

Answer:

  58.9 N [W24.8°N]

Explanation:

The vectors are at right angles, so the magnitude of their sum is ...

  √(38² +45²) ≈ 58.9 . . . . newtons

The angle Fc makes with Fa can be found using the arctangent:

  angle between Fa and Fc = arctan(45/38) ≈ 49.8°

The direction required for the sum of the vectors to be zero is the opposite of [E(49.8° -25°)S], so is [W24.8°N]

The vector that makes the sum zero is 58.9 N [W24.8°N].

Answer:

16÷8=2

Explanation:

if you run 8 mi an hour than in 16 mi you would have run 2 hours

Answer:

The energy possessed by a body because of its motion, equal to one half the mass of the body times the square of its speed is called its kinetic energy. Hence, when velocity is doubled, kinetic energy becomes 4 times.

Explanation: