log_c(A)=2
log_c(B)=5,
solve log_c(A^5B^3)

Answer:

k=4

Step-by-step explanation:

remove x:

10x.(-3) + ky.(-3)=-8.(-3)         (1)

-15x.2 - 6y.2 = 12.2               (2)

(1) - (2)  => -3ky+12y = 0

<=> (12-3k)y = 0

so that y has infinitely many solutions then

12-3k = 0 => k=4

9514 1404 393

Answer:

Step-by-step explanation:

The reflection over the x-axis is ...

  (x, y) ⇒ (x, -y)

The shift left 3 units is ...

  (x, y) ⇒ (x -3, y)

So, the two transformations together will be ...

  (x, y) ⇒ (x -3, -y)

  A(4, 2) ⇒ A"(1, -2)

  B(7,0) ⇒ B"(4, 0)

  C(9, 3) ⇒ C"(6, -3)

Answer:

x =7/ 3

Step-by-step explanation:

5x+  22=  2x+  29

⇔5x - 2x= 29 - 22

⇔3x = 7

⇔x = 7/3

Answer:

The answer is 5 units.

Step-by-step explanation:

Answer:

all of the above

Step-by-step explanation:

the ratio between the flour, the baking soda, and the salt would = 1:1:2 (disregarding tsp or cup measurements, since all the units stay the same in the choices)

so really, all the answers are correct

hope this helps!

Answer:

B. 1/2 teaspoon of salt per 1 teaspoon of baking soda.

Step-by-step explanation:

The ratio of cups of flour to tsp. of baking soda to tsp. of salt shown above is:

1/2 : 1/2 : 1/4

An equivalent rate to the ratio of tsp. of salt to tsp. of baking soda is 1/2 : 1 because:

Ratio of tsp. of salt to tsp. of baking soda is:

1/4 : 1/2

If we were to find an equivalent rate to this, it would be 1/2 teaspoon of salt per 1 teaspoon of baking soda for:

Multiply 2 to both terms in the ratio 1/4 : 1/2:

1/4 x 2 = 1/2 (simplified)

1/2 x 2 = 1 (simplified)

The new ratio is 1/2 : 1, which also represents the rate 1/2 teaspoon of salt per 1 teaspoon of baking soda.

Hope this helps!

Please comment back if this was correct.

Answer:

∠3z = 108 degrees

∠2z = 72 degrees

Step-by-step explanation:

First, we need to create an equation.

3z + 2z = 180

5z = 180

Divide both sides by 5:

z = 36

Now, substitute z for five for both angles.

3 x 36 = 108 degrees

2 x 36 = 72 degrees

Hope this helps!

If there is something wrong, please let me know.

Answer:

y2-y1/x2-x1

y2: 1050

y1:600

x2:75

x1:30

1050-600=450

75-30=45

450/45=10

slope is 10

Answer:

let:

A(30, 600)=(x1,y1)

B((75, 1050)=(x2,y2)

now,

[tex]slope(m) = \frac{y2 - y1}{x2 - x1} [/tex]

[tex] = \frac{1050 - 600}{75 - 30} [/tex]

[tex] = \frac{450}{ 45} [/tex]

[tex] = \frac{10}{1} [/tex]

Answer:

[tex]9\sqrt{3}[/tex]

Step-by-step explanation:

This is a 30-60-90 triangle.

It's good to remember this. The side length opposite to the 60 degree angle is always the base multiplied by [tex]\sqrt{3}[/tex]

Answer:

9√3.

Step-by-step explanation:

tan 60 = √3

So w/9 =√3

w = 9√3

I don't know what methods are available to you, so I'll just use one that I'm comfortable with: generating functions. It's a bit tedious, but it works! If you don't know it, there's no harm in learning about it.

Let U(x) be the generating function for the sequence u(n), i.e.

[tex]\displaystyle U(x) = \sum_{n=0}^\infty u(n)x^n[/tex]

In the recurrence equation, we multiply both sides by xⁿ (where |x| < 1, which will come into play later), then take the sums on both sides from n = 0 to ∞, thus recasting the equation as

[tex]\displaystyle \sum_{n=0}^\infty u(n+2) x^n = 8 \sum_{n=0}^\infty u(n+1) x^n - 16 \sum_{n=0}^\infty u(n) x^n[/tex]

Next, we rewrite each sum in terms of U(x). For instance,

[tex]\displaystyle \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2} \sum_{n=0}^\infty u(n+2) x^{n+2} \\\\ \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2} \bigg(u(2)x^2 + u(3)x^3 + u(4)x^4 + \cdots \bigg) \\\\ \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2} \sum_{n=2}^\infty u(n) x^n \\\\ \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2} \left(\sum_{n=0}^\infty u(n) x^n - u(1)x - u(0)\right) \\\\ \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2}(U(x) - 16x - 1) \\\\ \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2}U(x) - \frac{16}x - \frac1{x^2}[/tex]

After rewriting each sum in a similar way, we end up with a linear equation in U(x),

[tex]\displaystyle \frac1{x^2}U(x) - \frac{16}x - \frac1{x^2} = \frac8x U(x) - \frac8x - 16 U(x)[/tex]

Solve for U(x) :

[tex]\displaystyle \left(\frac1{x^2}-\frac8x+16\right) U(x) = \frac1{x^2} + \frac8x \\\\ \left(1-8x+16x^2\right) U(x) = 1 + 8x \\\\ (1-4x)^2 U(x) = 1 + 8x \\\\ U(x) = \dfrac{1+8x}{(1-4x)^2}[/tex]

The next step is to get the power series expansion of U(x) so that we can easily identity u(n) as the coefficient of the n-th term in the expansion.

Recall that for |x| < 1, we have

[tex]\displaystyle \frac1{1-x} = \sum_{n=0}^\infty x^n[/tex]

By differentiating both sides, we get

[tex]\displaystyle \frac1{(1-x)^2} = \sum_{n=0}^\infty nx^{n-1} = \sum_{n=1}^\infty nx^{n-1} = \sum_{n=0}^\infty (n+1)x^n[/tex]

It follows that

[tex]\displaystyle \frac1{(1-4x)^2} = \sum_{n=0}^\infty (n+1)(4x)^n[/tex]

and so

[tex]\displaystyle \frac{1+8x}{(1-4x)^2} = \sum_{n=0}^\infty (n+1)(4x)^n + 8x\sum_{n=0}^\infty (n+1)(4x)^n \\\\ \frac{1+8x}{(1-4x)^2} = \sum_{n=0}^\infty 4^n(n+1)x^n + 2\sum_{n=0}^\infty 4^{n+1}(n+1)x^{n+1} \\\\ \frac{1+8x}{(1-4x)^2} = \sum_{n=0}^\infty 4^n(n+1)x^n + 2\sum_{n=1}^\infty 4^nnx^n \\\\ \frac{1+8x}{(1-4x)^2} = \sum_{n=0}^\infty 4^n(n+1)x^n + 2\sum_{n=0}^\infty 4^nnx^n \\\\ \frac{1+8x}{(1-4x)^2} = \sum_{n=0}^\infty 4^n(3n+1)x^n[/tex]

which means

[tex]u(n) = \boxed{4^n(3n+1)}[/tex]

Complete Question

Complete Question is attached below

Answer:

[tex]M=160[/tex]

Step-by-step explanation:

From the question we are told that:

Standard models contribute $20

Deluxe  models contribute $30

Availability Average :

Stamping machine S= 30 minutes per hour

Motor installation Production M=60 minutes

Wiring is W=90 minutes per hour

Generally the formulation of the linear program is given as

[tex]Maximium (M)=20x + 30 y[/tex]

Where

For Stamping machine

[tex]S= 3x + 6y \leq 30.....Equ 1[/tex]

For Motor installation Production

[tex]10x + 10y \leq 60....Equ 2[/tex]

For Wiring

[tex]10x + 15y \leq 90....Equ3[/tex]

Therefore

Solving Equ...(1,2,3) simultaneously we have

[tex]x=2\\\\y=4[/tex]

Therefore

[tex]Maximium\ (M)=20x + 30 y[/tex]

[tex]M=20(2)+30(4)[/tex]

[tex]M=160[/tex]

Answer:

1,000,000

Step-by-step explanation:

length increased by 1000

width increased by 1000

1000 * 1000 = 1,000,000

Answer:

hlo buddy

can u msg me.......,.

Answer:

2nd quadrant

Step-by-step explanation

if an angle is between 90 and 180 degrees, it is in the second quardrant. since 0<x<90, 90+x will be more than 90 but less than 180, hence it lies in the second quadrant

Answer:

1(16x²-9y²)

Step-by-step explanation:

1(16x²-9y²) there are no common factors or variables

Answer:

3c^2

Step-by-step explanation:

Answer:

4=x y=325

Step-by-step explanation:

60x + 20 = 65x

group the variables

20=5x

because you subtracted 60x from both

4=x

because you divided 5 from both

now substitute 5 for x

65×5 is 325

y=325

9514 1404 393

Answer:

  (d) 6√3

Step-by-step explanation:

There are several ways to work multiple-choice problems. One of the simplest is to choose the only answer that makes any sense. Here, that is 6√3.

y is the hypotenuse of the medium-sized right triangle, so will be longer than that triangle's longest leg. y > 9

The only answer choice that meets this requirement is ...

  y = 6√3

__

In this geometry, all of the right triangles are similar. This means corresponding sides have the same ratio. For y, we're interested in the ratio of long leg to hypotenuse.

  long leg/hypotenuse = y/(9+3) = 9/y

  y² = 9(9+3) = 9·4·3

  y = 3·2·√3 . . . . . . take the square root

  y = 6√3

__

Additional comments

You may notice that y is the root of the product of the longer hypotenuse segment (9) and the whole hypotenuse (9+3 = 12). We can say that y is the "geometric mean" of these segment lengths. Similarly (pun only partially intended), x will be the root of the product of the short segment (3) and the whole hypotenuse (12)

  x = √(3·12) = 6

This is another "geometric mean" relation.

Further, the altitude will be the geometric mean of the two segments of the hypotenuse:

  h = √(9·3) = 3√3

A way to summarize all of these relations is to say that the legs of the right triangle that are not the hypotenuse are equal to the geometric mean of the segments of the hypotenuse that the leg intercepts.

  x = √(3·12)

  y = √(9·12)

  h = √(3·9)

I hope that helped you

9514 1404 393

Answer:

Step-by-step explanation:

The first equation describes the total number of coins. It says the sum of the numbers of dimes and quarters is 44, the total number of coins.

__

The second equation describes the total value of the coins. It will say that 0.10 times the number of dimes plus 0.25 times the number of quarters is 8.30, the total dollar value of the coins.

The two equations are ...

  d + q = 44

  0.10d +0.25q = 8.30

__

Additional comment

The solution can be found by substituting for d:

  0.10(44 -q) +0.25q = 8.30

  0.15q = 3.90

  q = 26

  d = 44 -26 = 18

Vinnie has 18 dimes and 26 quarters in his bag.

Answer:

"D"

Step-by-step explanation:

just add the two functions

5x^2 - 8x^2 = -3x^2 etc

(a) You can parameterize C by the vector function

r(t) = (x(t), y(t) ) = P (1 - t ) + Q t = (2 - 2t, 7t )

where 0 ≤ t ≤ 1.

(b) From the above parameterization, we have

r'(t) = (-2, 7)   ==>   ||r'(t)|| = √((-2)² + 7²) = √53

Then

ds = √53 dt

and the line integral is

[tex]\displaystyle\int_C(9x(t)+5y(t))\,\mathrm ds = \boxed{\sqrt{53}\int_0^1(17t+18)\,\mathrm dt}[/tex]

(c) The remaining integral is pretty simple,

[tex]\displaystyle\sqrt{53}\int_0^1(17t+18)\,\mathrm dt = \sqrt{53}\left(\frac{17}2t^2+18t\right)\bigg|_{t=0}^{t=1} = \boxed{\frac{53^{3/2}}2}[/tex]

Answer:C

Step-by-step explanation:

Answer: Choice C. [tex]\frac{1}{x^{2}y^{5} }[/tex]and Choice E. [tex]x^{-2} y^{-5}[/tex]

Step-by-step explanation:

Algebraic exponents.

(y^-8)(y^3)(x^0)(x^-2)

(y^-8)(y^3)(x^-2)

(y^-5)(x^-2)

(1) / (y^5)(x^2)

Options 3 and 5 are correct

Hope this helps!

Answer:

Answer:

l = 15 feet

Step-by-step explanation:

l = 2w + 3

First you solve for the width(w)

(2w+15) (w-6) = 0

This means

2w+15=0 OR. w-6=0

First let’s solve 2w+15=0

2w = -15

w = -7.5

Width can’t be negative so that can’t be the answer. So we look at the second equation w-6=0

w= 6

Since we found the width now we can find the length by using the formula l = 2w + 3

= 2(6) + 3

= 12 + 3

= 15 feet

You can check this by using the given area which is 90.

A = lw = 15*6 = 90

Answer:

[tex] - 3(x + 4) {}^{2} - 4[/tex]

Step-by-step explanation:

Vertex form is

[tex]a(x - h) {}^{2} + k = f(x)[/tex]

We know that h and k are both -4. Let x be -2 and y be -16.

[tex]a( - 2 + 4) {}^{2} - 4 = - 16[/tex]

[tex]a(2) {}^{2} - 4 = - 16[/tex]

[tex]4a - 4 = - 16[/tex]

[tex]4a = - 12[/tex]

[tex]a = - 3[/tex]

So the equation in vertex form is

[tex] - 3(x + 4) {}^{2} - 4[/tex]

Answer:

THE ANSWER IS

Answer:

c.

Step-by-step explanation:

[tex]\frac{122}{10}*(-\frac{10}{61} )[/tex]Let's start by calculating their values one by one, and then we can match them.

Starting with [tex]-2\frac{2}{5} \div\frac{4}{5}[/tex], we can simplify this more by adding [tex]2*5[/tex] to the nominator. That gives us [tex]-\frac{12}{5} \div\frac{4}{5}[/tex]. Now we can apply the Keep-Change-Flip rule. Keep the first fraction as it is, change the division sign into multiplication, flip the second fraction. [tex]-\frac{12}{5} *\frac{5}{4}[/tex]. We apply fraction multiplication which is simply multiplying the first nominator by the first nominator and the same for the dominator.  and the result is [tex]-\frac{60}{20}[/tex] or simply -3.

[tex]-2\frac{2}{5} \div\frac{4}{5} = -3[/tex]

Now, we calculate the second one, [tex]-12.2\div(-6.1)[/tex]. This can be re-written as [tex]-\frac{122}{10}\div(-\frac{61}{10} )[/tex]. As we did in the previous part we apply the  Keep-Change-Flip, this will give us [tex]-\frac{122}{10}*(-\frac{10}{61} )[/tex]. Do the multiplication and the result will be [tex]\frac{1220}{610}[/tex], we can divide both the nominator and dominator by 10 which will result [tex]\frac{122}{61}[/tex] and finally we know that [tex]61*2=122[/tex] and we can divide both of them again by 61 which will result [tex]\frac{2}{1} =2[/tex]

[tex]-12.2\div(-6.1)=2[/tex]

You can try solving the rest by yourself but here's is the final answer for them both:

[tex]16\div(-8)=-2\\3\frac{3}{7} \div1\frac{1}{7} =3[/tex]

The statement that odd degree polynomials have a u-shaped graph and even degree polynomials have an s-shaped graph is FALSE.

Odd degree polynomials have branches that go in opposing directions which means that they will form an s-shaped graph.

Even degree polynomials on the other hand, have graphs that go in the same direction which is why they form u-shaped graphs.

In conclusion, the above statement is false.

Find out more on polynomials at https://brainly.com/question/9696642.