Answer:
Joe can only use 3GB of Data. Bill is 21 .
[tex]21 + 9 + 30[/tex]
[tex]1gb \: \: = 3[/tex]
3*9 = 93 ( 3 ) + 21 = 30Step-by-step explanation:
Hope this helps !!Plz help me to find the answer to 4th question..plz help me
Answer:
I got that AE^2 = 8EC^2
Step-by-step explanation:
Here's what I did. I probably did this wrong, but this might give you an idea on how to solve it.
First, create equations:
AB = BC = AC = DE = 2EC
BD= BC = EC
Then, I used pythagorean theorem (since AD is perpendicular to BC): AD^2 + DE^2 = AE^2
Substitute: (2EC)^2 + (2EC)^2 = AE^2
Simplify: 4EC^2 + 4EC^2 = AE^2
AE^2 = 8CE^2
Find the derivative of f(x) = 6/x at x = -2. (2 points)
Using the definition of the derivative,
[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{f(x) - f(-2)}{x - (-2)}[/tex]
[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{\dfrac6x + 3}{x + 2}[/tex]
[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{\dfrac{6+3x}x}{x + 2}[/tex]
[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{6+3x}{x(x + 2)}[/tex]
[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{3(x+2)}{x(x + 2)}[/tex]
[tex]\displaystyle f'(-2) = \lim_{x\to-2}\frac{3}{x} = \boxed{-\dfrac32}[/tex]
Which math expression means "the product of 16 and 26"?
16 +26
O 16.26
15 - 26
26-16
Answer:
The product of 16 and 26 would be 16 * 26
Step-by-step explanation:
This is because "the product of" means multiplication so *. Making it 16 * 26.
Sam wants to write an equation to represent a proportional relationship with a constant of proportionality of 6 he write y = 6 + x
Answer:
y = 6x
Step-by-step explanation:
The equation representing a proportional relationship is
y = kx ← k is the constant pf proportionality
Here k = 6 , then
y = 6x ← equation of proportion
Answer:
She is not correct, she would need to have something before the y to know the answer
Step-by-step explanation:
hope this helps :)
A Triangular Park ABC has sides 120 m, 80m and 50m. a gardener has to put a fence all around it and also plant grass inside. How much area does she need to plant? Find the cost of fencing it with barbed wire at the rate of of Rs. 20 per metre leaving a space 3m wide for a gate on one side?
The perimeter = sum of all sides
= 120 + 80 + 50
= 250
So 250 - 3
247
Left space for gate
Now cost of fencing = Rs 20/per meter
= 247 × 20
= Rs 4,940
Now the area of the triangular park can be found using heron's formula
S = (a+b+c)/2
S = (120+80+50)/2
S = 250/2
S = 125
Now
Herons formula = √s(s-a)(s-b)(s-c)
√125(125-120)(125-80)(120-50)
√125(5)(45)(70)
√5×5×5×5×5×3×3×5×14
After Making pairs
5×5×5×3√14
375√14
Therefore 375√14m is the area of the triangular park
Must click thanks and mark brainliest
$\sf\underline\bold{Answer:}$
$\sf\small\underline{\underline{Area\: planted\: by\: the\: gardener : 1452.36m^2}}$$\sf\small\underline{\underline{The\:cost\:of\:fencing\:the\:park:Rs.4940}}$$\space$
$\sf\underline\bold{Step-by-Step:}$
$\space$
$\sf\bold{Given(In \:the\:Q):}$
Sides of the triangular park are 120m,80m and 50m.$\space$
$\sf\bold{To \: find:}$
How much area of the park does she need to plant?The cost of fencing the park ?$\space$
$\sf\small{☆Area\:to\:be\:planted=Area \: of \: ∆ABC}$
$\space$
$\sf\underline\bold{Calculating\:area\:of\:∆ABC:}$
$\space$
Use heron's formula to find the area of the triangle.
$\space$
$\mapsto$ $\sf\small{Heron's\:formula=}$
[tex]\sf\sqrt{s(s-a)(s-b)(s-c)}[/tex]
$\sf{Where\:s=semi\:perimeter}$$\sf{a,b,c\: = side\:of\:the\:∆}$$\sf\small{Here\:a=120,b=80 \:and\: c=50}$$\space$
$\sf\bold{Now,find\:semi\:parameter:-}$
$\sf\small{Perimeter\:of\:the\:∆=120+80+50=250}$
$\sf\small{Semi-Perimeter:}$ $\sf\dfrac{250}{2}$ $\sf\small{=125m}$
$\space$
$\sf\small{Substitute \: the\:values\:in\:heron's\:formula:}$
$\sf{Area\:of\:the\:∆:-}$
$\mapsto$ [tex]\sf\sqrt{125(125-120)(125-80)(125-50)}[/tex]
$\space$
$\mapsto$ $\sf\sqrt{125\times(5)\times(45)\times(75)}$
$\space$
$\mapsto$ $\sf\small\sqrt{2109375}$ $\sf\small{=375}$ $\sf\small\sqrt{15}$
$\space$
$\longmapsto$ $\sf\underline\bold\purple{1452.56m^2}$
______________________________
$\sf\underline\bold{Now,find\:the\:cost\:of\:fencing:}$
$\sf{Cost\:of\:fencing-}$
$\sf{Rate = Rs.20 per \:meter}$ $\sf{Left\:space=3m}$$\space$
$\sf\underline{Hence,the\:gardener\:has\:to\:fence:}$
$\sf{= 250-3=247m.}$$\space$
So,total cost of fencing at the rate of Rs.20 per m:-
$\sf\underline\bold\purple{=247\times20=4940}$___________________________________
If the area of a rectangular field is x2 – 3x + 4 units and the width is 2x – 3, then find the length of the rectangular field.
Answer:x²-3 x+4/ 2x-3 units
Step-by-step explanation:
Area = Length * Width sq. units
x^2 - 3x + 4 = Length * 2x - 3
=>Length = x^2- 3 x + 4/ 2 x − 3 units
Courtney needs to wrap this gift box, which is 412 inches wide, 6 inches long, and 3 inches tall. What is the surface area of the box?
Help pls will give brainliest
Answer:
hello,
answer C
Step-by-step explanation:
area of the rectangle=2b*b=2b²
area of the half cercle= [tex]\\\dfrac{\pi*(\frac{c}{2})^2}{2} =\dfrac{\pi*c^2}{8} \\[/tex]
Area in blue= 2b²-πc²/8
The seating capacity at a movie theater is 400. For a Monday
afternoon movie, 68% of the seats are filled. About how many
seats are empty?
-.- sorta need this answer quickly, thanks
6 year ago, a mans age was six times the age of his son,4year hence,thrice age will be equal to eight times his son age.find their age. Ans is 36 years and 11 years
Answer:
jsjzbdjwbxjdbwisjsobs9fbe
Step-by-step explanation:
hfkdowwhdbhdvsjsh2ivdusvqvduzvqidv
Answer:
Yeeeeaaahhhh its correct.
The number of days ahead travelers purchase their airline tickets can be modeled by an exponential distribution with the average amount of time equal to 15 days. Find the probability that a traveler will purchase a ticket fewer than ten days in advance. How many days do half of all travelers wait
Answer:
The right answer is:
(a) 0.4866
(b) 10.3972
Step-by-step explanation:
Let X be the number of days,
X is [tex]exp(\lambda)[/tex],
⇒ [tex]\lambda =\frac{1}{15}[/tex]
now,
⇒ [tex]F_x(x) = P(X \leq x)[/tex]
[tex]=1-e^{-\lambda x}[/tex]
[tex]=1-e^{-\frac{x}{15} }[/tex]
or,
[tex]x>0[/tex]
(a)
⇒ [tex]P(X<10)=F_x(10)[/tex]
[tex]=1-e^{\frac{10}{15} }[/tex]
[tex]=1-e^{\frac{2}{3} }[/tex]
[tex]=0.4866[/tex]
(b)
If the medium be m, then
[tex]P(X=m) = \frac{1}{2}[/tex]
[tex]=2^{-1}[/tex]
⇒[tex]1-e^{-\frac{m}{15} } = \frac{1}{2}[/tex]
[tex]e^{-\frac{m}{15} } = 2^{-1}[/tex]
[tex]m= 15\ ln2[/tex]
[tex]=10.3972[/tex]
Which transformation gives the same result as a reflection over the x-axis followed b
a reflection over the y-axis?
Answer:
filtration system is not working
filtration
ILL GIVE POINTS!! PLS HELP !!!
Which set of polar coordinates describes the same location as the
rectangular coordinates (1. - 1)?
A. (sqrt2,315°)
B. (-1,135°) C. (sqrt2,225°)
D. (1,45°)
Answer:
The polar coordinates appear in the form (r, θ), where r is the the radius from the center and θ is the angle. To get the radius, do the following.
[tex]r = \sqrt{x^2 + y^2} = \sqrt{1^2 + (-1)^2} = \sqrt{2}\\[/tex]
You can get the angle visually by drawing a point (1, -1) on a graph and seeing that it is 45 degrees from the top right quadrant (you can tell its 45 because both x and y have the same magnitude). Since there are 360 degrees, 360 - 45 = 315.
If you would like to find it mathematically, this is the way to do it
[tex]\theta = atan(y/x) = -45[/tex]
Notice that -45 degrees is just 360 - 45 = 315
Your answer would be
[tex](\sqrt{2}, 315)[/tex]
three different are rung at intervals of 36 minutes 40 minutes and 48 minutes if they were rung together at 9 a.m. at what time would they be rung together again?
To find the time in which all the bells ring together, we need to find the LCM of 36,40,48.
Prime factorization of 36=2×2×3×3
Prime factorization of 40=2×2×2×5
Prime factorization of 48=2×2×2×2×3
Hence, LCM of 36,40,48=2×2×2×2×3×3×5=720 seconds.
720seconds=
60
720
minutes=12minutes
Hence, all the bells will ring together after 12 mi
Answer:
9pm or 12 hours from 9am.
Find the distance between the two points.
(-5,1)
(0,0)
[?]
Enter the number that
goes beneath the
radical symbol.
Answer:
[tex]{26}[/tex]
Step-by-step explanation:
[tex] \sqrt{(0 - ( - 5) ){}^{2} + (0 - 1) {}^{2} } [/tex]
[tex] = \sqrt{ {(5)}^{2} + {( - 1)}^{2} } [/tex]
[tex] = \sqrt{25 + 1} [/tex]
[tex] = \sqrt{26} [/tex]
Answered by GAUTHMATH
Answer:
26
Step-by-step explanation:
(-5, 1) (0, 0)
sqrt(5^2 + (-1^2))
sqrt(25 + 1)
sqrt(26)
So, 26 goes under the radical.
a student walks 50m on a bearing 0.25 degrees and then 200m due east how far is she from her starting point.
Answer:
Step-by-step explanation:
I'm going to use Physics here for this concept of vectors. Here are some stipulations I have set for the problem (aka rules I set and then followed throughout the problem):
** I am counting the 50 m as 2 significant digits even though it is only 1, and I am counting 200 as 3 significant digits even though it is only 1. 1 sig dig doesn't really give us enough accuracy, in my opinion.
** A bearing of .25 degrees is measured from the North and goes clockwise; that means that measured from the x axis, the angle is 89.75 degrees. This is the angle that is used in place of the bearing of .25 degrees.
** Due east has an angle measure of 0 degrees
Now let's begin.
We need to find the x and y components of both of these vectors. I am going to call the first vector A and the second B, while the resultant vector will be C. Starting with the x components of A and B:
[tex]A_x=50cos(89.75)[/tex] so
[tex]A_x=.22[/tex]
[tex]B_x=200cos(0)[/tex] so
[tex]B_x=200[/tex] and we need to add those results together. Due to the rules for adding significant digits properly, the answer is
[tex]C_x=200[/tex] (and remember I am counting that as 3 sig fig's even though it's only 1).
Now for the y components:
[tex]A_y=50sin(89.75)[/tex] so
[tex]A_y=50[/tex] (which I'm counting as 2 sig fig's)
[tex]B_y=200sin(0)[/tex] so
[tex]B_y=0[/tex] and we need to add those results together.
[tex]C_y=50[/tex]
Now for the resultant magnitude:
[tex]C_{mag}=\sqrt{(200)^2+(50)^2}[/tex] and that gives us a final magnitude of
[tex]C_{mag}=206[/tex] m
Now for the angle:
Since both the x and y components of the resultant vector are in quadrant 1, we don't need to add anything to the angle to get it right, so
[tex]tan^{-1}(\frac{50}{200})=14[/tex]
The girl is 206 meters from her starting point at an angle of 14 degrees
HELP ME SOLVE THIS PLEASE
Solve the equation for all values of x.
(22 – 16)(2x2 + 49) = 0
Help please
Answer:
7i/sqrt(2)
Step-by-step explanation:
so, if I understand correctly, the equation is
(22-16)(2x² + 49) = 0
6(2x² + 49) = 0
that automatically means
2x² + 49 = 0
2x² = -49
x² = -49/2
x = sqrt(-49/2)
a square root of a negative number has no real solution. the solution is in the world of complex and imaginary numbers, which bases on the sqrt(-1) = i.
so, we get
x = sqrt(49/2 × -1) = (7/sqrt(2)) × I = 7i/sqrt(2)
please help meeeeeeeeeeeeee
Answer:
a)-2x(x+4x²)+3(x²+2x)
-2x²-8x³+3x²+6x
-2x²+3x²+6x-8x³
x²-8x³+6x
in descending order
-8x³+x²+6x
b)(4x-3)(4x+3)
4x(4x+3)-3(4x+3)
16x²+12x-12x-9
16x²-9
I hope this helps and sorry if it's wrong
pls help !! :// <333
Answer:
Its that squiglly one on top
Step-by-step explanation:
cuh cuh cuh cuh cuhc
Số hạng đầu và số hạng thứ 2 của một cấp số nhân lần lượt là x+2 và x^2 -4 số hạng thứ 3 của cấp số nhân này là
Answer:
x³-2x²-4x+8
Step-by-step explanation:
a1=x+2
a2=x²-4⇒q=a2/a1=x-2
⇒a3=q.a2=(x-2).(x²-4)=x³-2x²-4x+8
Which rules define the function graphed below? (15 points cuz I'm stumped)
y=2x+3; y=-1/3x+3
y=2x; y=-1/3x
y=3x+2; y=3x-1
y=-3x+3; y=x+3
Answer: Choice A
y=2x+3; y=-1/3x+3
==================================================
Explanation:
The left portion of the blue curve is y = 2x+3 but it is only graphed when x < 0 (we could argue that [tex]x \le 0[/tex] but I'll set that aside for the other portion).
The right portion is the line y = -1/3x + 3 and it's only graphed when [tex]x \ge 0[/tex]
So we could have this piecewise function
[tex]f(x) = \begin{cases}2x+3 \ \text{ if } x < 0\\-\frac{1}{3}x+3 \ \text{ if } x \ge 0\\\end{cases}[/tex]
Or we could easily swap the "or equal to" portion to move to the first part instead like this
[tex]f(x) = \begin{cases}2x+3 \ \text{ if } x \le 0\\-\frac{1}{3}x+3 \ \text{ if } x > 0\\\end{cases}[/tex]
Either way, we're involving the equations mentioned in choice A
Just need to know if I answered this correctly please!
Answer:
yes, your answers are correct
can you help me to do this
Answer:
keep the pic clearly
Step-by-step explanation:
keep the pic clearly
Rodney and their roommates are making homemade pizza for dinner. Rodney tells his roommates that he would like for his slice to be cut at a 100 degree angle. The pizza has a diameter of 20 inches. To the nearest tenth of an inch, find the area of Rodney's slice of pizza. Approximate pi at 3.14.
Answer:
Area of pizza slice = 87 inches² (Approx.)
Step-by-step explanation:
Given:
Angle cut of pizza = 100°
Diameter of pizza = 20 inches
Find:
Area of pizza slice
Computation:
Area of sector = [Ф / 360][π][r²]
Area of pizza slice = [100/360][3.14][(20/2)²]
Area of pizza slice = [100/360][3.14][(10)²]
Area of pizza slice = [100/360][3.14][100]
Area of pizza slice = [0.2778][3.14][100]
Area of pizza slice = 87.2292
Area of pizza slice = 87 inches² (Approx.)
Can you help me please please correct my
Answer:
a = m/c
~~~~~~~~~~~~~~~~~~~~~~~
m=ca
divide both sides by c
you get a = m/c
Step-by-step explanation:
Answer:
a = m/c
Step-by-step explanation:
m = ca
divide both sides by c
m/c = ca/c
m/c = a
:.a = m/c
Find the length of the third side. If necessary, write in simplest radical form
Answer:
5
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean theorem
a^2+b^2 = c^2 where a and b are the legs and c is the hypotenuse
a^2 + 10^2 = (5 sqrt(5))^2
a^2 +100 = 25(5)
a^2 +100 = 125
a^2 = 125-100
a^2 = 25
Taking the square root of each side
sqrt(a^2) = sqrt(25)
a = 5
pls I'll mark u BRAINLIEST
(B−A)∪C=(B∪C)−(A−C)
Answer:
(I don't have the complement sign of sets, so I've used "©" to denote compliment)
L.H.S.
(B-A)∪C
= (B∩A©)∪C
= (B∪C)∩(A©∪C)
= (B∪C)∩(A-C)©
= (B∪C)-(A-C) = R.H.S.
(Proved)
HELPPPPPPPPPPPPPPPP:))))))
Answer:
Step-by-step explanation:
Since T is in Quadrant II, sinT > 0 and cosT < 0.
cotT = -5/12
You would like to know how effective a diet program is at helping people lose weight. 18 over-weight people are randomly selected to participate in the program. They are weighed before and after the program and the results are listed below. Do these results give evidence that the diet program is effective at the 1% significance level?
Answer:
There is not enough evidence to support the claim that drug is effective at 1%
Step-by-step explanation:
For this we use the pored test as we have dependent test;
Difference :
10,5,-5,3,-3,4,2,-3,0,10,8,-2,3,-2,5,5,4,0
Hypothesis :
H0 : μd = 0
H0 : μd ≠ 0
The mean of d, dbar = Σd / n = 44 / 18 = 2.44
The standard deviation, Sd = 4.45 (using calculator)
The test statistic, T : dbar / (Sd/√n)
T = 2.44 / (4.45/√18)
T = 2.44 / 1.0488750
T = 2.326
Degree of freedom, df = n - 1 ; 18 - 1 = 17
The Pvalue = 0.0326
α = 0.01
Since Pvalue < α ; we fail to reject H0
