Physics High School

Jen is conducting an experiment involving a device known as a pith-ball electroscope, shown below.

The plastic ball of the electroscope hangs in midair and is uncharged. Charges cannot move along the silk thread that holds the ball in the air.
Jen completes the following steps in her experiment:

1- She collects three identical, uncharged rubber tubes.
2-She holds a magnet to the first tube for 5 minutes.
3-She submerges the second tube in a tank of water for 5 minutes.
4- She rubs the third tube with animal fur for 5 minutes.

Jen's teacher tells her that she can use the pith-ball electroscope to see if any of the rubber tubes are surrounded by an electric field. What should Jen do to test for an electric field surrounding each tube?

Jen Is Conducting An Experiment Involving A Device Known As A Pith-ball Electroscope, Shown Below.The

Answers

Answer 1

Answer:

bring each tube close to the plastic ball and note any movement of the ball

Explanation:

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Answer 2

Answer:

bring each tube close to the plastic ball and note any movement of the ball

Explanation:

Electric fields can exert forces on objects, even if the objects involved are not touching. One way to demonstrate that electric fields exist around charged objects is to observe the effects of their forces at a distance.

Since the plastic ball of the electroscope is made of insulating plastic and is uncharged, it will be attracted to any charged object brought near it. So Jen can observe the effects of the tube's electric fields by bringing each tube close to the plastic ball and noting any movement of the ball. If the ball moves toward a tube, then the process that Jen used on the tube generated an electric field.

Related Questions

A mover pushes a 46.0kg crate 10.3m across a rough floor without acceleration. How much work did the mover do (horizontally) pushing the crate if the effective coefficient of friction was 0.50

Answers

Answer:

2,321.62Joules

Explanation:

The formula for calculating workdone is expressed as;

Workdone = Force * Distance

Get the force

F = nR

n is the coefficient of friction = 0.5

R is the reaction = mg

R = 46 ( 9.8)

R = 450.8N

F = 0.5 * 450.8

F = 225.4N

Distance = 10.3m

Get the workdone

Workdone = 225.4 * 10.3

Workdone  = 2,321.62Joules

Hence the amount of work done is 2,321.62Joules

Please select the word from the list that best fits the definition

family of elements that gain or share three electrons when they react

options: left, gas, semiconductor, halogen, right, solid, carbon, nitrogen

Answers

Answer:

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Explanation:

it maxed Imao

Answer:

false

Explanation:

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base your answer to this question on the information below and on your knowledge of physics. A toy launcher that is used to launch small plastic spheres horizontally contains a spring with a spring constant of 50. Newtons per meter. The spring is compressed a distance of 0.10 meter when the launcher is ready to launch a plastic sphere. The spring is released and a 0.10-kilogram plastic sphere is fired from the launcher. Calculate the maximum speed with which the plastic sphere will be launched.

Answers

Answer: v = 2.24 m/s

Explanation: The Law of Conservation of Energy states that total energy is constant in any process and, it cannot be created nor destroyed, only transformed.

So, in the toy launcher, the energy of the compressed spring, called Elastic Potential Energy (PE), transforms into the movement of the plastic sphere, called Kinetic Energy (KE). Since total energy must be constant:

[tex]KE_{i}+PE_{i}=KE_{f}+PE_{f}[/tex]

where the terms with subscript i are related to the initial of the process and the terms with subscript f relates to the final process.

The equation is calculated as:

[tex]\frac{1}{2}kx^{2}+0=0+\frac{1}{2}mv^{2}[/tex]

[tex]\frac{1}{2}kx^{2}=\frac{1}{2}mv^{2}[/tex]

[tex]\frac{1}{2}50(0.1)^{2}=\frac{1}{2}(0.1)v^{2}[/tex]

[tex]v^{2}=\frac{50(0.1)^{2}}{0.1}[/tex]

[tex]v=\sqrt{50(0.1)}[/tex]

[tex]v=\sqrt{5}[/tex]

v = 2.24

The maximum speed the plastic sphere will be launched is 2.24 m/s.

The maximum speed of plastic sphere is 2.236 m/s, when sphere is launched.

The maximum velocity of sphere can be calculated by,

[tex]V_{max}= x \sqrt {\dfrac km}[/tex]

Where,

[tex]V_{max}[/tex] - maximum velocity of the sphere

[tex]x[/tex] - length of stretch = 0.10 m

[tex]k[/tex]-  spring constant = 50 N

[tex]m[/tex]- mass of sphere =  0.10 kg

Put the values in the equation,

[tex]V_{max}= 0.1\sqrt {\dfrac {50}{0.1}}\\\\V_{max}= 0.1\times {22.36}\\\\V_{max}= 2.236\\[/tex]

Therefore,  the maximum speed of plastic sphere is 2.236 m/s, when sphere is launched.

To know more about maximum velocity of in spring,

https://brainly.com/question/24465541

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