Jane is participating in a
charity run. For each 5 miles
she runs, she will raise $30.

Answer:

V = 76 ft³

Step-by-step explanation:

We can find the volume of the figure by finding the sum of volume of the small rectangular prism and big rectangular prism.

V of a rectangular prism = length*hight* width

V = V (big rectangular prism) + V (small rectangular prism)

V = (8·4·2) +(3·2·2)

V = 64 + 12

V = 76 ft³

Answer:

  82 2/9 square meters

Step-by-step explanation:

The problem statement gives us two relations between length and width. We can write those using equations and the variables L and W for length and widh, in meters.

  P = 2(L +W) . . . . . . formula for the perimeter of a rectangle

  38 = 2(L +W) . . . . . the perimeter is 38 meters

  (L -3) = 2(W -2) . . . . length less 3 is twice the difference of wdith and 2.

__

Dividing the first equation by 2 gives ...

  19 = L +W

Solving this for L gives ...

  L = 19 -W

Substituting for L in the second equation, we have ...

  (19 -W) -3 = 2(W -2)

  16 -W = 2W -4 . . . . . . . simplify

  20 = 3W . . . . . . . . . . . add W+4

  W = 20/3 . . . . . . . . . divide by 3

  L = 19 -20/3 = 37/3 . . . . find L from W

__

The area of the farm is the product of length and width:

  A = LW = (37/3 m)(20/3 m) = 740/9 m²

  A = 82 2/9 m²

The area of the farm is 82 2/9 square meters.

Answer:

c= 30

Step-by-step explanation:

To find the value of c, start by forming an equation using the ∠ sum of ∆ property.

c° +60° +90°= 180° (∠ sum of ∆)

Simplify:

c° + 150°= 180°

c°= 180° -150°

c°= 30°

c= 30

Notes:

Answer:

Step-by-step explanation:

1) Given

2) <Q is congruent to <Q by reflexive prop of congruence

3) <QBA is congruent to <QSR by alternate interior angles theorem

4) Triangle QBA is similar to triangle QSR by AA theorem

5) QA/QR=QB/QS by CPSP (corresponding parts of similar polygons are proportional)

Answer:

37

Step-by-step explanation:

it just it

Answer:

Step-by-step explanation:

Remarks.

This can be solved as a proportion. A proportion is 2 ratios making a total of 4 parts. If we know 3 of the parts, we can solve for the 4th.

63/(8x - 2) = 49 /42

Notice that the given parts of the top triangle are the numerators of the ratios. The 2 parts of the bottom triangle are the denominators of the proportions

Proportion

63/(8x - 2) = 49 /42

Solution

63/(8x - 2) = 49 /42                        Cross Multiply

(8x - 2)*49 = 63 * 42                       Combine the right.

(8x - 2)*49 = 2646                           Divide by 49

8x - 2 = 54                                        Add 2 to both sides

8x -2+2=54+2                                   Combine

8x = 56                                              Divide by 8

8x/8 = 56/8                                        

Answer: x = 7

Answer:

208m^2

Step-by-step explanation:

area of hexagon = 93.53 using its equation

area of single triangle = 0.5(6*6)

area of all triangles = 6(0.5(6*6))

total area = 207.53

NWN = 208

Answer:

Bill go the better deal

Step-by-step explanation:

43.35/15=2.89

61.82/32=2.81

Step-by-step explanation:

a square has 4 identical sides.

so, when you have to "walk" around the perimeter of a square you have to go 4 times the same distance.

therefore

20 = 4×side length

side length = 20/4 = 5 in

it is a 5 in × 5 in square.

FYI a rectangle has 2 pairs of sides that are equally long inside their pair.

and so you have in this case a perimeter of

2×6 + 2×4 = 12 + 8 = 20 in

Answer:

37

Step-by-step explanation:

Pythagorean theorem: a^2 + b^2 = c^2

Lets put the values in now :)

35^2 + 12^2 = c^2

1225 + 144 = c^2

1369 = c^2

Now we need to find the square root!

[tex]\sqrt{1369}[/tex] = 37

Have a great day!!

Please rate and mark brainliest!!

Hey Buddy !

For the following right triangle , find the side length x .

We have to find the value of x .

The concept of this question belongs to Pythagoras theorem . We have to find the value of x by using Pythagoras Theorem .

According to Pythagoras Theorem , in a right angle triangle the sum of square of perpendicular and base is equal to square of hypotenuse .

[tex] \longmapsto \: \pink{ \boxed{{H {}^{2} = P {}^{2} + B {}^{2} }}}[/tex]

Where ,

Substituting the values in formula :

[tex] \blue{ \boxed{ \sf{Therefore , \: value \: of \: x \: is \: 37 }}}[/tex]

Answer:

The answer is 1

Step-by-step explanation:

5w² – 5w = 0

Add 5w both side

5w² – 5w + 5w = 5w – 5w

5w² = 5w

Now, Divide both side by 5w we get,

5w²/5w = 5w/5w

w = 1

Thus, The value of w is 1

Answer:

w = 1

Step-by-step explanation:

Given :

Bring 5w to the other side.

Answer:

2/15

Step-by-step explanation:

3/9*2/5=

1/3*2/5=

2/15

Answer:

282 Hours after 6 weeks

Step-by-step explanation:

Multiply the 6 weeks and the 48 hour a week adverage and theres your answer!

The universal set contains all possible elements in the set

The sets are given as:

Where the universal set is:

U = {all integers}

The set B is the set of all even integers.

So, its complement would be the set of all odd integers i.e. set D

Hence, the complement of set B is the set D.

From the set definition, we have:

C = {x | x ∈ U and 2x is an odd integer}

This means that the set C contains elements 2x, where 2x is an odd number.

The element x is an integer, and twice an integer (i.e. 2x) is an even number.

This means that 2x cannot be an odd number;

Hence, the empty set is the set C;

The subset E = {1, 3, 5, 7} contains odd integers.

From the set definition, set D represents the set of odd integers

Hence, the set D contains the subset E = {1, 3, 5, 7}

Read more about sets at:

https://brainly.com/question/10057967

Answer:

D,C,D

Step-by-step explanation:

On edge 2023

Answer:1.4*10^-9

Step-by-step explanation:

Answer:

1.4×10−x^-{9}

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 10.

If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

Hopefully this helps you!

- Matthew

There are two different ways to find surface area of square pyramid

1st

[tex]\sf surface \ area \ = \ a^2 + 2(a)(l)[/tex]

2nd

[tex]\sf surface \ area = a^2+2a\sqrt{\dfrac{a^2}{4}+h^2 }[/tex]

Answer:

sample response

Step-by-step explanation: :)

You would first calculate the area of the base, which is length times width. You would then calculate the area of the faces, which is 1 2 (base times height) and multiply the result by 4 for the 4 faces. Finally, add the area of the base and the areas of the faces.

The approximate surface area of the balloon is 199 cm².

The approximate volume of the balloon is 262 cm³

Radius of the balloon = circumference / 6.2832

25 / 6.2832 = 3.98cm

Surface area = 4πr²

4 x 22/7 x 3.97² = 199 cm²

Volume =  4/3πr³

4/3 x 22/7 x 3.97³ = 262.20 cm³

To learn more about the volume of a sphere, please check: https://brainly.com/question/13705125

Answer:

[tex]3\cdot \frac{1}{2},\:\frac{21}{7},\:\pi ,\:4.1[/tex]

Step-by-step explanation:

convert the number to all decimals or fraction and compare.

Answer:

Distributive Property

Step-by-step explanation:

You can distribute the 5 to the 6 and 9 in the parenthesis.

Answer:

distributive

is the letter A

In order to see whether or not a point lies on the line, we need to plug in the x-coordinate (instead of x) and plug the y-coordinate instead of y.

In this case, the x-coordinate is:-

[tex]\mathrm{1}[/tex]

and the y-coordinate is:-

[tex]\mathrm{-1}[/tex]

Plug in the values:-

[tex]\mathbf{-10(1)+5(-1)=-8}[/tex]

[tex]\mathbf{-10-5=-8}[/tex]

[tex]\mathbf{-15=-8}[/tex]

Huh?!

As you can see, we ended up with a false statement.

Hence, the answer is:-

[tex]\bigstar{\boxed{\pmb{The~point~(1,-1)~doesn't~lie~on~the~line}}}[/tex]

Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I'll comment and/or edit my answer :)

Answer:

the point (1, -1) doesn’t  lie on the line (-10x + 5y = -8)

Step-by-step explanation:

Generaly , a point A(x₀ , y₀)  lies on the line of equation ax + by = c

If its coordinates verify the equation which means

When we replace x by x₀ and y by y₀ in our equation we get ax₀ + by₀ = c

Then

just replace x by 1 and y by -1 in the equation: -10x + 5y = -8

We get , -10(1) + 5(-1) = -10 - 5 = -15

Since -15 ≠ -8 then (1 , -1) don’t verify the equation

Hence ,  the point (1, -1) doesn’t  lie on the line (-10x + 5y = -8)

Answer: B

Step-by-step explanation:

Answer:

(3,2)

Step-by-step explanation:

Setting up equation so we can use substitution method

x - y = 1 , x + 3y = 9

step 1 set first equation equal to x by adding y to both sides so we can use the substitution method to solve the system of equations.

x = y + 1 , x + 3y = 9

now we can plug in ( or substitute hence substitution method ) the first equation into the second

Solving for y using the substitution method

x + 3y = 9

plug in x = y + 1

y + 1 + 3y = 9

combine like terms

4y + 1 = 9

subtract 1 from both sides

4y = 8

divide both sides by 4

y = 2

Now to find the value of x we plug in the value of y into one of the equations and solve for x.

Solving for x

x - y = 1

y = 2

x - 2 = 1

add 2 to both sides

x = 3

The solution would be (3,2)

Answer:

x = 3 and y = 2 or (3,2) in coordinate form

Step-by-step explanation:

Given:

[tex]\displaystyle \large{\begin{cases} x-y=1 \\ x+3y=9 \end{cases}}[/tex]

Solve by elimination of x-terms by multiplying either one of equations with -1:

For this, I choose to multiply -1 in first equation:

[tex]\displaystyle \large{\begin{cases} -1(x-y=1) \\ x+3y=9 \end{cases}}\\\displaystyle \large{\begin{cases} -x+y=-1 \\ x+3y=9 \end{cases}}[/tex]

Then add both equations:

[tex]\displaystyle \large{-x+x+y+3y=-1+9}\\\displaystyle \large{4y=8}[/tex]

Divide both sides:

[tex]\displaystyle \large{\dfrac{4y}{4} = \dfrac{8}{4}}\\\displaystyle \large{y=2}[/tex]

Next, substitute y = 2 in one of equations to solve for x:

For this, I choose to substitute y = 2 in the first equation:

[tex]\displaystyle \large{x-y=1}[/tex]

Substitute y = 2 in:

[tex]\displaystyle \large{x-2=1}[/tex]

Add both sides by 2:

[tex]\displaystyle \large{x-2+2=1+2}\\\displaystyle \large{x=3}[/tex]

Hence, the solution is x = 3 and y = 2 or you can write as in coordinate form (3,2)

__________________________________________________________

First method is elimination method, I’ll demonstrate another method which is by using matrices to find the solutions.

Given:

[tex]\displaystyle \large{\begin{cases} x-y=1 \\ x+3y=9 \end{cases}}[/tex]

Write the system of equations in matrices form:

[tex]\displaystyle \large{\left[\begin{array}{ccc}1&-1\\1&3\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] =\left[\begin{array}{ccc}1\\9\end{array}\right]}[/tex]

Let:

[tex]\displaystyle \large{A=\left[\begin{array}{ccc}1&-1\\1&3\end{array}\right] }\\\displaystyle \large{X=\left[\begin{array}{ccc}x\\y\end{array}\right] \\\displaystyle \large{B = \left[\begin{array}{ccc}1\\9\end{array}\right] }[/tex]

From [tex]\displaystyle \large{AX=B \to X=A^{-1}B}[/tex] where:

[tex]\displaystyle \large{A^{-1}=\dfrac{1}{\det A} \left[\begin{array}{ccc}d&-b\\-c&a\end{array}\right] = \dfrac{1}{ad-bc} \left[\begin{array}{ccc}d&-b\\-c&a\end{array}\right] }[/tex]

Find [tex]\displaystyle \large{\det A}[/tex]:

[tex]\displaystyle \large{\det A = ad-bc = 3+1=4}[/tex]

Therefore:

[tex]\displaystyle \large{A^{-1} = \dfrac{1}{4}\left[\begin{array}{ccc}3&1\\-1&1\end{array}\right]}\\\therefore \displaystyle \large{X = \dfrac{1}{4}\left[\begin{array}{ccc}3&1\\-1&1\end{array}\right] \left[\begin{array}{ccc}1\\9\end{array}\right]}[/tex]

Evaluate the matrices:

[tex]\displaystyle \large{X= \dfrac{1}{4}\left[\begin{array}{ccc}3(1)+1(9)\\-1(1)+1(9)\end{array}\right] }\\\displaystyle \large{X= \dfrac{1}{4}\left[\begin{array}{ccc}3+9\\-1+9\end{array}\right] }\\\displaystyle \large{X= \dfrac{1}{4}\left[\begin{array}{ccc}12\\8\end{array}\right]}\\\displaystyle \large{X= \left[\begin{array}{ccc}3\\2\end{array}\right] }\\\therefore \displaystyle \large{\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}3\\2\end{array}\right]}[/tex]

Therefore, the solution is x = 3 and y = 2

Answer:

B

Step-by-step explanation:

Add the value of the dots

0 + 3/8 + 3/8 + 4/8 + 5/8 + 7/8 =   22/8 = 2 6/8

Answer:

x = 45, y = 24.

Step-by-step explanation:

If the 2 numbers are x and y:

x + y = 69...........(1)

x = 2y - 3

x - 2y = -3...........(2)

Subtract: (1) - (2):

x - x + y - (-2y) = 69 - (-3)

y + 2y = 72

3y = 72

y = 24.

From equation 1:-

x + 24 = 69

x = 45.

Answer:

one number would be 63 and the other would be 6

Step-by-step explanation:

69/2=34.5

it says 3 less which means minus 3, so you would:

34.5-3=31.5

then it says twice the smaller number, so you would:

31.5*2

The lunch menu is an illustration of permutation and combination

To answer this question, the following set of lunch menu would be used:

Since the event organizers can repeat lunch menu, then each of the 5 lunch menus can be selected each of the 3 times.

So, the number of selection is:

n = 5³

Evaluate

n = 125

Possible selections are:

Since the event organizers cannot repeat lunch menu, then each of the 5 lunch menus can be selected once of the 3 times.

So, the number of selection is:

n = ⁵C₃

Evaluate

n = 10

Possible selections are:

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The value of the cox will be equal to Cosx=[tex]\pm[/tex]0.95

It is given that

The value of Sinx=0.3

Now we know that

[tex]Sin^2x+Cos^2x=1\\\\0.3^2+Cos^2=1\\\\Cos^2=1-0.3^2\\\\Cos^2x=1-0.9\\\\Cos^x=0.91\\\\Cos=\sqrt{0.91}\\\\Cosx=\pm 0.95[/tex]

Hence the value of  Cosx=[tex]\pm[/tex]0.95

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Answer:

Step-by-step explanation:

Pyramid height should be 14

Base area should be 14*14(196)

So, Base area is 196

1. Multiply the Base area by the height of the pyramid:

196*14=2744

2. Divide the number above by 3:

2744/3=914.7

Answer:

Step-by-step explanation:

Let the cost be A.

a) Cost to run ad for one week:

b) Cost to run ad for four weeks:

Answer:

See below ↓↓

Step-by-step explanation:

Cost to run one week

Cost to run four weeks