JACKIE BROUGHT 3/4 OF A GALLON OF ICED TEA TO THE PARTY. BILL BROUGHT 7/8 OF A GALLON OF ICED TEA TO THE SAME PARTY. HOW MUCH ICED TEA DID JACKIE AND BILL BRING TO THE PARTY?

Answer:

im not sure but i do have a tip when you go to goo gle i want you to simplify your question (not what you asked on here) then copy your question as it is simple then search it on here because its slightly  for others to understand

Step-by-step explanation:

.

Answer:

Step-by-step explanation:

D={ 6  , -9  , 1 }

R={  0  ,-3 }

Step-by-step explanation:

ccxiddidificifificici i i ivi i i i i i i i iivvii iix9difi

Answer:

28°C

Step-by-step explanation:

First you do 3*19=57°C

-5+57= 52°C

then you do 4*6=24 °C

as its being cooled you takeaway

52-24=28°C

Answer:

Angle b is congruent to angle E

CA=FD

Step-by-step explanation:

If _______, then triangle ABC and triangle DEF are congruent by the ASA criterion.  ASA is angle side angle .  We know angle C= angle F and side CB = side FE We need to know angle B = angle E

If _______, then triangle ABC and triangle DEF are congruent by the SAS criterion.  SAS is side angle side,  we know side CB = side FE  and then angle C= angle F then we need side CA = side FD

If ∠ABC = ∠DEF, then ΔABC and ΔDEF are congruent by the ASA criterion.

If AC = DF, then ΔABC and ΔDEF are congruent by the SAS criterion.

Two figures are said to be congruent of they have the same shape and all the corresponding sides and angles are congruent.

The HL (hypotenuse leg) congruence theorem states that if the hypotenuse and one leg of a triangle is congruent to another triangle, then both triangles are congruent.

In triangle ABC and DEF;

BC = EF and ∠ACB ≅ ∠DFE

Hence:

If ∠ABC = ∠DEF, then ΔABC and ΔDEF are congruent by the ASA criterion.

If AC = DF, then ΔABC and ΔDEF are congruent by the SAS criterion.

Find out more on congruent figures at: https://brainly.com/question/1675117

Pressure is force per unit area. If the block is sitting at rest on the surface, it applies a pressure of mg/A, where mg is the block's weight and A is the area of the face that makes contact with the surface.

The smaller the value of A, the larger the pressure. So the highest pressure the block can exert is achieved when it's resting on the face with the smallest dimensions.

If the block is a cube with side length 95 cm, then the pressure exerted by each face is the same.

Answer:

a) 75

b) 4.33

c) 0.75

d) [tex]3.2 \times 10^{-13}[/tex] probability that no one in a simple random sample of 100 young adults owns a landline

e) [tex]6.2 \times 10^{-61}[/tex] probability that everyone in a simple random sample of 100 young adults owns a landline.

f) Binomial, with [tex]n = 100, p = 0.75[/tex]

g) [tex]4.5 \times 10^{-8}[/tex] probability that exactly half the young adults in a simple random sample of 100 do not own a landline.

Step-by-step explanation:

For each young adult, there are only two possible outcomes. Either they do not own a landline, or they do. The probability of an young adult not having a landline is independent of any other adult, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

75% of all young adults between the ages of 18-35 do not have a landline in their homes and only use a cell phone at home.

This means that [tex]p = 0.75[/tex]

(a) On average, how many young adults do not own a landline in a random sample of 100?

Sample of 100, so [tex]n = 100[/tex]

[tex]E(X) = np = 100(0.75) = 75[/tex]

(b) What is the standard deviation of probability of young adults who do not own a landline in a simple random sample of 100?

[tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100(0.75)(0.25)} = 4.33[/tex]

(c) What is the proportion of young adults who do not own a landline?

The estimation, of 75% = 0.75.

(d) What is the probability that no one in a simple random sample of 100 young adults owns a landline?

This is P(X = 100), that is, all do not own. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 100) = C_{100,100}.(0.75)^{100}.(0.25)^{0} = 3.2 \times 10^{-13}[/tex]

[tex]3.2 \times 10^{-13}[/tex] probability that no one in a simple random sample of 100 young adults owns a landline.

(e) What is the probability that everyone in a simple random sample of 100 young adults owns a landline?

This is P(X = 0), that is, all own. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{100,0}.(0.75)^{0}.(0.25)^{100} = 6.2 \times 10^{-61}[/tex]

[tex]6.2 \times 10^{-61}[/tex] probability that everyone in a simple random sample of 100 young adults owns a landline.

(f) What is the distribution of the number of young adults in a sample of 100 who do not own a landline?

Binomial, with [tex]n = 100, p = 0.75[/tex]

(g) What is the probability that exactly half the young adults in a simple random sample of 100 do not own a landline?

This is P(X = 50). So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 50) = C_{100,50}.(0.75)^{50}.(0.25)^{50} = 4.5 \times 10^{-8}[/tex]

[tex]4.5 \times 10^{-8}[/tex] probability that exactly half the young adults in a simple random sample of 100 do not own a landline.

DeMoivre's theorem says

(2 (cos(12°) + i sin(12°)))⁵ = 2⁵ (cos(5×12°) + i sin(5×12°))

… = 32 (cos(60°) + i sin(60°))

… = 32 (1/2 + √3/2 i )

… = 16 + 16√3 i

Answer:

It is E. radicand

Step-by-step explanation:

Answer:

Radicand

Step-by-step explanation:

Radicand is the number found inside the radicals

Example:

[tex]\sqrt[4]{5} ; 2\sqrt[4]{5}[/tex]  are like terms

5 -> radicand and 4 is the index

Answer:

A. If the side lengths are the same, then a triangle is not scalene.

Step-by-step explanation:

A triangle can be defined as a two-dimensional shape that comprises three (3) sides, three (3) vertices and three (3) angles.

Simply stated, any polygon with three (3) lengths of sides is a triangle.

In Geometry, a triangle is considered to be the most important shape.

Generally, there are three (3) main types of triangle based on the length of their sides and these include;

I. Equilateral triangle: it has all of its three (3) sides and interior angles equal.

II. Isosceles triangle: it has two (2) of its sides equal in length and two (2) equal angles.

III. Scalene triangle: it has all of its three (3) sides and interior angles different in length and size respectively.

First let's compute dx/dt

[tex]x = t - \frac{1}{t}\\\\x = t - t^{-1}\\\\\frac{dx}{dt} = \frac{d}{dt}\left(t - t^{-1}\right)\\\\\frac{dx}{dt} = 1-(-1)t^{-2}\\\\\frac{dx}{dt} = 1+\frac{1}{t^{2}}\\\\\frac{dx}{dt} = \frac{t^2}{t^{2}}+\frac{1}{t^{2}}\\\\\frac{dx}{dt} = \frac{t^2+1}{t^{2}}\\\\[/tex]

Now compute dy/dt

[tex]y = 2t + \frac{1}{t}\\\\y = 2t + t^{-1}\\\\\frac{dy}{dt} = \frac{d}{dt}\left(2t + t^{-1}\right)\\\\\frac{dy}{dt} = 2 - t^{-2}\\\\\frac{dy}{dt} = 2 - \frac{1}{t^2}\\\\\frac{dy}{dt} = \frac{2t^2}{t^2}-\frac{1}{t^2}\\\\\frac{dy}{dt} = \frac{2t^2-1}{t^2}\\\\[/tex]

From here, apply the chain rule to say

[tex]\frac{dy}{dx} = \frac{dy*dt}{dx*dt}\\\\\frac{dy}{dx} = \frac{dy}{dt} \times \frac{dt}{dx}\\\\\frac{dy}{dx} = \frac{dy}{dt} \div \frac{dx}{dt}\\\\\frac{dy}{dx} = \frac{2t^2-1}{t^2} \div \frac{t^2+1}{t^{2}}\\\\\frac{dy}{dx} = \frac{2t^2-1}{t^2} \times \frac{t^{2}}{t^2+1}\\\\\frac{dy}{dx} = \frac{2t^2-1}{t^2+1}\\\\[/tex]

We could use polynomial long division, or we could add 2 and subtract 2 from the numerator and do a bit of algebra like so

[tex]\frac{dy}{dx} = \frac{2t^2-1}{t^2+1}\\\\\frac{dy}{dx} = \frac{2t^2-1+2-2}{t^2+1}\\\\\frac{dy}{dx} = \frac{(2t^2+2)-1-2}{t^2+1}\\\\\frac{dy}{dx} = \frac{2(t^2+1)-3}{t^2+1}\\\\\frac{dy}{dx} = \frac{2(t^2+1)}{t^2+1}-\frac{3}{t^2+1}\\\\\frac{dy}{dx} = 2-\frac{3}{t^2+1}\\\\[/tex]

This concludes the first part of 4b

=======================================================

Now onto the second part.

Since t is nonzero, this means either t > 0 or t < 0.

If t > 0, then,

[tex]t > 0\\\\t^2 > 0\\\\t^2+1 > 1\\\\\frac{1}{t^2+1} < 1 \ \text{ ... inequality sign flip}\\\\\frac{3}{t^2+1} < 3\\\\-\frac{3}{t^2+1} > -3 \ \text{ ... inequality sign flip}\\\\-\frac{3}{t^2+1}+2 > -3 + 2\\\\2-\frac{3}{t^2+1} > -1\\\\-1 < 2-\frac{3}{t^2+1}\\\\-1 < \frac{dy}{dx}\\\\[/tex]

note the inequality signs flipping when we apply the reciprocal to both sides, and when we multiply both sides by a negative value.

You should find that the same conclusion happens when we consider t < 0. Why? Because t < 0 becomes t^2 > 0 after we square both sides. The steps are the same as shown above.

So both t > 0 and t < 0 lead to [tex]-1 < \frac{dy}{dx}[/tex]

We can say that -1 is the lower bound of dy/dx. It never reaches -1 itself because t = 0 is not allowed.

We could say that

[tex]\displaystyle \lim_{t\to0}\left(2-\frac{3}{t^2+1}\right)=-1\\\\[/tex]

---------------------------------------

To establish the upper bound, we consider what happens when t approaches either infinity.

If t approaches positive infinity, then,

[tex]\displaystyle L = \lim_{t\to\infty}\left(2-\frac{3}{t^2+1}\right)\\\\\\\displaystyle L = \lim_{t\to\infty}\left(\frac{2t^2-1}{t^2+1}\right)\\\\\\\displaystyle L = \lim_{t\to\infty}\left(\frac{2-\frac{1}{t^2}}{1+\frac{1}{t^2}}\right)\\\\\\\displaystyle L = \frac{2-0}{1+0}\\\\\\\displaystyle L = 2\\\\[/tex]

As t approaches infinity, the dy/dx value approaches L = 2 from below.

The same applies when t approaches negative infinity.

So we see that [tex]\frac{dy}{dx} < 2[/tex]

---------------------------------------

Since [tex]-1 < \frac{dy}{dx} \text{ and } \frac{dy}{dx} < 2[/tex], those two inequalities combine into the compound inequality [tex]-1 < \frac{dy}{dx} < 2[/tex]

So dy/dx is bounded between -1 and 2, exclusive of either endpoint.

Answer:

x=5

Step-by-step explanation:

im so bad at explaining things but i hope this helped

Answer:

the answer would be 100,000,000

Greatest 8 Digit Number: 99,999,999

Adding 1 = 99999999+1

= 100,000,000

Must click thanks and mark brainliest

Answer:

−3x + y = −7       y - 9 = 5 (x - 1)

Step-by-step explanation:

y2 - y1 / x2 - x1

5 - (-1) / 4 - 2

6/2

= 3

slope intercept: −3x + y = −7

y - 9 = 5 (x - 1)

Answer:

the probability of taking a clear picture of a California candor is .24

Answer:

63

Step-by-step explanation:

50+10=60 60+3=63 dollars

he spends 63$ on variable expenses

Answer:

24780

Step-by-step explanation:

might not be right but 24780 because 23600*5% is 1180 and add that to the original 23600 to get 24780

5% more is 105% in total, including the the 100% we start with, so:

23,600 * 1.05 = 24780

Answer:

C

Step-by-step explanation:

the fibrin definition tells us that the first term of the sequence a1 = 6

so, B is out.

and for every following term we always add 7 to every previous term to create the next one.

so, when I add 7 to 6, what is my second term in the sequence ? 7+6 = 13

not 42, not -7

therefore, only C is correct.

and 13+7 = 20

and 20+7 = 27

it all fits

Answer:

The total lateral surface of this cube is 4*e^2

Step-by-step explanation:

A cube is a figure with all the sides of the same length, so each face of a cube is a square.

Remember that the area of a square of sidelength L is:

A = L^2

Now, when we want to find the lateral surface of a figure, we ignore the bases of the figure.

So, if a cube has 6 faces, if we ignore the two bases, we are left with 4 square faces.

And if the edge length is e, then each one of these four faces has an area:

A = e^2

So the total lateral surface is 4 times that:

S = 4*e^2

The total lateral surface of this cube is 4*e^2

Answer:

4e2

Step-by-step explanation:

I got it correct on founders edtell

If θ lies in the fourth quadrant, then sin(θ) < 0 and cos(θ) > 0. So we have from the Pythagorean identity,

sin²(θ) + cos²(θ) = 1   ==>   cos(θ) = +√(1 - sin²(θ)) = √21/5

Then

sec(θ) = 1/cos(θ) = 5/√21

and

tan(θ) = sin(θ)/cos(θ) = (-2/5)/(√21/5) = -2/√21

Answer:

f(x) = 6 when -5 < x ≤ -1

Step-by-step explanation:

Answer:

Step-by-step explanation:

New median:40100

New mode:385100

[tex]\sf\huge\underline\color{pink}{༄Answer:}[/tex]

What is the solution of the equation x^2 - 14x + 67 = 0?

[tex]\color{pink}{==========================}[/tex]

#CarryOnLearning

[tex]\sf\color{pink}{༄⁂✰Bae \: Yoonah}[/tex]

Respuesta:

3650

Explicación paso a paso:

Dado que :

Principal, P = capital prestado

Tasa anual, r = 10% * 6 = 60%

Interés = 1140

Periodo = 6 meses y 10 días = (6 * 30) +10 = 190 días

Conversión a años:

Periodo = 190/365

Usando la relación:

Interés = principal * tasa * tiempo

1140 = P * 60% * (190/365)

1140 = 0.3123287P

P = 1140 / 0,3123287

P = 3650

Answer:

MUST BE IN HLA, NOT FROM C TO ASSEMBLY.

PROGRAM 6: Same

Write an HLA Assembly language program that implements a function which correctly identifies when all four parameters are the same and returns a boolean value in AL (1 when all four values are equal; 0 otherwise). This function should have the following signature:

procedure theSam

Answer:

- 16

Step-by-step explanation:

The way this is given, you have to find the second term before you can fine the third.

a2 = d(n - 1) * (-2)^2

a2 = 2 * (-2)^2

a2 = 2 * 4

a2 = 8

a3 = d(3 - 1) * (-2)^3

a3 = 2 * (-2)^3

a3 = 2 * - 8

a3 = - 16

Answer:

Z -0.879173965

Step-by-step explanation:

Z -0.879173965

ρ  0.5

π 0.54

n 120

The value of the test statistic is the z-score z = -0.88

The relationship between a value and the mean of a set of values is expressed numerically by a Z-score. The Z-score is computed using the standard deviations from the mean. A Z-score of zero indicates that the data point's score and the mean score are identical.

The Z-score is calculated using the formula:

z = (x - μ)/σ

where z: standard score

x: observed value

μ: mean of the sample

σ: standard deviation of the sample

Given data ,

Let the test statistic value be represented as z

Now , the probability of emergency room visitors are insured is q = 0.54

The total number of patients n = 120

The number of patients that were insured = 60

So , the percentage of people that were insured p = 60/120 = 0.5

Now , test statistic value z = ( p - q ) / [ √ ( q ( 1 - q )/n² ]

The value of z score is

z = [ 0.5 - 0.54 ] / √ 0.54 ( 1 - 0.54 ) / 120²

On simplifying the equation , we get

The value of z score is z = -0.88

Hence , the test statistic is z = -0.88

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Answer:

Step-by-step explanation:

a) Probability-Above 30 min = 5.72% = .0572

b) Probability-Above 15 min =  99.11% = .9911

c) *Probability-Between  1 - 59.49% = .4051

d) 19.136 minutes  z = -1.28

a) The probability that trip will take at least 1/2 hour will be 0.0606.

b) The percentage of time the lawyer is late for work will be 99.18%.

c) The probability that lawyer misses coffee will be 0.3659.

d) The length of time above which we find the slowest 10​% of trips will be 0.5438.

e) The probability that exactly 2 out of 3 trips will take at least one half

1/2 hour is 0.0103.

What do you mean by normal distribution ?

A probability distribution known as a "normal distribution" shows that data are more likely to occur when they are close to the mean than when they are far from the mean.

Let assume the time taken for a one way trip be x .

x ⇒ N( μ , σ ²)

x  ⇒ N( 24 , 3.8 ²)

a)

The probability that trip will take at least 1/2 hour or 30 minutes will be :

P ( x ≥ 30)

= P [ (x - μ) / σ ≥ (30 - μ) / σ ]

We know that , (x - μ) / σ = z.

= P [ z ≥ (30 - 24) / 3.8)]

= P [ z ≥ 1.578 ]

= 1 - P [  z ≤ 1.578 ]

Now , using the standard normal table :

P ( x ≥ 30)

= 1 - 0.9394

= 0.0606

b)

The percentage of the time the lawyer is late for work will be :

P ( x  ≥ 15)

= P [ z ≥ -2.368 ]

= P [  z ≤ 2.368]

= 0.9918

or

99.18%

c)

The probability that lawyer misses coffee :

P ( 15 < x < 25 ) = P ( x < 25 ) - P ( x < 15)

= P [  z < 0.263] - P ( z < -2.368)

or

= 0.3659

d)

The length of time above which we find the slowest 10​% of trips :

P( x ≥ X ) ≤ 0.10

=  0.5438

e)

Let's assume that y represents the number of trips that takes at least half hour.

y ⇒ B ( n , p)

y ⇒ B ( 3 , 0.0606)

So , the probability that exactly 2 out of 3 trips will take at least one half

1/2 hour is :

P ( Y = 2 )

= 3C2 × (0.0606)² × ( 1 - 0.0606)

= 0.0103

Therefore , the answers are :

a) The probability that trip will take at least 1/2 hour will be 0.0606.

b) The percentage of time the lawyer is late for work will be 99.18%.

c) The probability that lawyer misses coffee will be 0.3659.

d) The length of time above which we find the slowest 10​% of trips will be 0.5438.

e) The probability that exactly 2 out of 3 trips will take at least one half

1/2 hour is 0.0103.

Learn more about normal distribution here :

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