It takes you 0.8 of a minute to read each page of your health book. It takes you 5.5 minutes to take the test at the end. How long will it take you to read 6.25 pages and also take the test?

Answer:

12-n

Step-by-step explanation:

im confused but sure

Answer:

9/16

Step-by-step explanation:

;)

Answer:

-0.5625

Step-by-step explanation:

-0.75 x 0.75 = -0.5625

Answer:

y-3 = -4 (x-1)

Step-by-step explanation:

y= -4x - 5

In slope-intercept form, they give us the slope, -4, and the y-intercept, -5 (we don't need for point-slope form).

Use the point (1,3) and substitute it into the equation.

Point-slope form: y-y1 = m(x-x1)

y-3 = -4 (x-1)

Answer:

I am not the person to answer this question but the answer is B or74/3

10 Miles Because 25-15=10

Answer:

1+4+7

2+4+6

3+4+5

Step-by-step explanation:

Answer:

6+4+2=12     5+4+3 =12

Step-by-step explanation:

Answer:

x=95

Step-by-step explanation:

They are vertical angles

Answer:

[tex]y = \frac{2}{3} + 7[/tex]

Answer:

4

Step-by-step explanation:

4² = 16

Answer:

ggggmd

hsmhdmvx.hffyfylltet

Answer:

Neither, why... for it to be direct or inverse variation, the model has to fit either y=k/x or y=kx, it may not have a y-intercept at all if it is inverse variation and it must have a y-intercept of 0 for it to be direct variation.

Step-by-step explanation:

The statement y=2 is quite specific. Because k is positive, y increases as x increases. So as x increases by 1, y increases by 1.5. Inverse Variation: Because k is positive, y decreases as x increases.  yx is a constant number -8. The constant of variation, k , is 23 . Inverse Variation

An inverse variation can be represented by the equation xy=k or y=kx .

That is, y varies inversely as x if there is some nonzero constant k such that, xy=k or y=kx where x≠0,y≠0 .

Suppose y varies inversely as x such that xy=3 or y=3x . That graph of this equation shown.

Answer:

5

Step-by-step explanation:

good luck

Answer: $54 / 3 = $27 for each girl

Step-by-step explanation:

Answer:

33 : 15 : 6

Step-by-step explanation:

Answer:

the answer would be about 28.60 km

Answer:

28 KM

Step-by-step explanation:

As an estimation we are told 5 miles is 8 km

mathematically , 5 miles = 8 KM

So , therefore 1 miles = 8/5 KM

now just , multiply 17.8 with 8/5

Answer:

$1.28 per liter

Step-by-step explanation:

750ml/1 L = .75

.96/.75 = 1.28

Answer:

g) 2 h) 4

Step-by-step explanation:

g) The time t when the instantaneous velocity of the positron is zero is;

t = 2

h) The location of the positron at the time of t = 2 is;

p = 4.

g) We are told that the function that models the position of the sub atomic particles is;

p(t) = t²/(t - 1)

Instantaneous velocity is simply the derivative of the distance with respect to time.

Thus, Instantaneous velocity is gotten by using online differentiation calculator to get; dp/dt = [2t/(t - 1)] - [t²/(t - 1)²]

When Instantaneous velocity is zero, we have;

[2t/(t - 1)] - [t²/(t - 1)²] = 0

Rearranging to get;

[2t/(t - 1)] = [t²/(t - 1)²]

Cross multiply to get;

2t(t - 1)² = t²(t - 1)

divide both sides by t to get;

2(t - 1)² = t(t - 1)

Expand the bracket to get;

2(t² - 2t + 1) = t² - t

2t² - 4t + 2 = t² - t

Rearrange to get;

t² - 3t + 2 = 0

Using online quadratic equation solver gives;

t = 1 or 2

We are told that t > 1

Thus, we will adopt t = 2

h) At t = 2 seconds gotten in g above, the positron is located at;

p(2) = 2²/(2 - 1)

p(2) = 4

Read more at; https://brainly.com/question/2020753

Answer:

a. Sketch is given in the attachment

b. [tex]V_{p}[/tex] = (0,-525)

c. [tex]V_{w}[/tex] = ([tex]\sqrt{2}[/tex],[tex]\sqrt{2}[/tex])  

d. [tex]V_{g}[/tex] = (60[tex]\sqrt{2}[/tex], 60[tex]\sqrt{2}[/tex]  - 525)

e. Actual Speed = |[tex]V_{g}[/tex]| = 448.3 MPH

Direction = Ф = - 79.1°

Direction = Ф = 280.9° with respect to x - axis.

Step-by-step explanation:

a. Sketch the scenario on the x-y axis.

Where,

Velocity of the plane relative to air = [tex]V_{p}[/tex]

Velocity of the jet stream = [tex]V_{w}[/tex]

Velocity of the plane relative to ground = [tex]V_{g}[/tex]

Solution:

Note: Solution is given in the attachment. Please refer to the attachment for the sketch.

b. Express the velocity of the plane relative to the air as a vector.

Solution:

[tex]V_{p}[/tex] = |[tex]V_{p}[/tex]| cosФi + |[tex]V_{p}[/tex]| sinФj

where,

|[tex]V_{p}[/tex]| = magnitude of the vector.

|[tex]V_{p}[/tex]| =  525 MPH

Ф = 270° w.r.t to x - axis. (See the sketch in the attachment)

[tex]V_{p}[/tex] = |[tex]V_{p}[/tex]| cosФi + |[tex]V_{p}[/tex]| sinФj

Plug in the values into this equation to express it in the vector form as required.

[tex]V_{p}[/tex] = (525) cos270i + (525) sin270j

As, Cos270 = 0

and

Sin270 = -1

So,

[tex]V_{p}[/tex] = (525) (0)i + (525) (-1)j

[tex]V_{p}[/tex] = 0i -525j    

[tex]V_{p}[/tex] = (0,-525)  

c. Express the velocity of the jet stream as a vector.

Solution:

Velocity of the jet stream as a vector.

[tex]V_{w}[/tex] = |[tex]V_{w}[/tex]| cosФi + |[tex]V_{w}[/tex]| sinФj

where,

|[tex]V_{w}[/tex]| = magnitude of the vector.

|[tex]V_{p}[/tex]| =  120 MPH

Ф = 45°  (See the sketch in the attachment)

[tex]V_{w}[/tex] = |[tex]V_{w}[/tex]| cosФi + |[tex]V_{w}[/tex]| sinФj

Plug in the values into this equation to express it in the vector form as required.

[tex]V_{w}[/tex] = (120) cos45i + (120) sin45j

As, Cos45 = [tex]\frac{1}{\sqrt{2} }[/tex]

and

Sin45 =  [tex]\frac{1}{\sqrt{2} }[/tex]

So,

[tex]V_{w}[/tex] = (120) ([tex]\frac{1}{\sqrt{2} }[/tex])i + (120) ([tex]\frac{1}{\sqrt{2} }[/tex])j

[tex]V_{w}[/tex] = 60[tex]\sqrt{2}[/tex]i +60[tex]\sqrt{2}[/tex]j    

[tex]V_{w}[/tex] = ([tex]\sqrt{2}[/tex],[tex]\sqrt{2}[/tex])  

d. Find the velocity of the plane relative to the ground.

Solution:

Velocity of the plane relative to the ground = Sum of velocity of plane relative to the air and velocity of the jet stream

[tex]V_{g}[/tex] = [tex]V_{p}[/tex] + [tex]V_{w}[/tex]

[tex]V_{g}[/tex] = 0i -525j    +  60[tex]\sqrt{2}[/tex]i +60[tex]\sqrt{2}[/tex]j    

[tex]V_{g}[/tex] = 60[tex]\sqrt{2}[/tex]i + 60[tex]\sqrt{2}[/tex]  - 525j

[tex]V_{g}[/tex] = (60[tex]\sqrt{2}[/tex], 60[tex]\sqrt{2}[/tex]  - 525)

e. Find the actual speed and direction of the plane relative to the ground. Round to the  tenths.

Solution:

Actual Speed = |[tex]V_{g}[/tex]|  = magnitude of the velocity of the plane relative to the ground.

Actual Speed = |[tex]V_{g}[/tex]| = [tex]\sqrt{(60\sqrt{2}) ^{2} + (60\sqrt{2}-525) ^{2} }[/tex]

Actual Speed = |[tex]V_{g}[/tex]| = 448.3 MPH

Direction = Ф = [tex]tan^{-1}[/tex] ([tex]\frac{60\sqrt{2}-525 }{60\sqrt{2} }[/tex])

Direction = Ф = - 79.1°

To find out the direction with respect to x - axis.

Direction = Ф = 360 - 79.1

Direction = Ф = 280.9°

Answer:

1

Step-by-step explanation:

Answer:

It would be 58 degrees

Step-by-step explanation:

Hope it helps :)

Answer:           x(2x=1)(x+1)-3(2x+1)(x+1)

Step-by-step explanation:

Answer:

water has be taken to separate and has been take the Kyon bag and tricks to win their water to bag and separate the tube and water the

Answer:

39 in³

Step-by-step explanation:

Pyramid volume: v = 1/3Bh    b=13 h=9

volume; 1/3 * 13 * 9 = 39

Answer:

k = 11

Step-by-step explanation:

Expand brackets

2k - 10 = 12

add 10 on both sides

2k = 22

divide both sides by 2

k = 11

Answer:

The Population is 865000

Step-by-step explanation:

0.7 Million is equal to 700,000

700,000 + 165,000=865000

3/4 of 80 = 60.

First off let's start with 1/4 of 80.

80/4 = 20.

But the question asks for 3/4 and that’s three times more than 1/4 so you multiply 3 to 20.

20*3 = 60.

So your answer is 60.

Answer:

650,000,000

Step-by-step explanation:

6.5x10^8