The centrifugal force C = mv^2/r = kq^2/r^2 = P centripetal force. m is the electron mass, q are the proton and electron charges (opposites), and r is the Bohr radius.
Thus 1/2 mv^2/r = 1/2 kq^2/r^2 and KE = 1/2 mv^2 = 1/2 kq^2/r = 1/2 PE
Therefore KE/PE = 1/2, no matter what state the electron is in.
I need help with this physics question
Answer:
its B hope you have a good Day
Explain how the potential energy is changed to kinetic energy in the Hoover Dam
The water behind a hydroelectric dam stores gravitational potential energy since it is at a higher level than the water on the other side of the dam. As the water falls, this potential energy is converted into kinetic energy, which turns turbines to generate electricity. Often, the water comes from behind a dam built across a river valley. The water high up behind the dam contains gravitational potential energy . This is transferred to kinetic energy as the water rushes down through tubes inside the dam. The moving water drives electrical generators , which may be built inside the dam.
Find the gravitational force between Earth (5.97 x 1024 kg) and the Sun (1.99 x 1030 kg) knowing they are 1.48 x 1011 m apart.
Using the gravitational force of F= G(m1*m2/r^2)
m1= 5.97 x 10^24 kg (Earth)
m2= 1.99 x 10^30 kg (Sun)
r= 1.48 x 10^11 m
G is a known value, it is 6.672 x 10^-11
All units are proper. Therefore plug in the values and you get 3.16 x 10^22 N.
Let me know if I calculated this wrong and it is something else so I can delete this. Thank you. I don't want to make other students put down the wrong answer.
Answer:
[tex]\boxed {\boxed {\sf F_g \approx 3.62 *10^{22} \ N}}[/tex]
Explanation:
We are asked to find the gravitational force between Earth and the Sun. Use the following formula:
[tex]F_g= \frac{Gm_1m_2}{r^2}[/tex]
G is the universal gravitational constant. One mass (m₁) is the Earth and the other (m₂) is the Sun. r is the distance between the planets.
G= 6.67 * 10⁻¹¹ N*m²/kg²m₁ = 5.97 * 10²⁴ kg m₂= 1.99 * 10³⁰ kg r= 1.48 *10¹¹ mSubstitute the values into the formula.
[tex]F_g = \frac{ (6.67*10^{-11} N*m^2/kg^2)(5.97*10^{24} \ kg)(1.99*10^{30} \ kg) }{ (1.48 *10^{11} \ m)^2}}[/tex]
Multiply the numerator. The units of kilograms cancel.
[tex]F_g = \frac {7.9241601 *10^{44} \ N*m^2}{ (1.48 *10^{11} \ m)^2 }[/tex]
Solve the exponent in the denominator.
[tex]F_g= \frac {7.9241601 *10^{44} \ N*m^2}{ 2.1904*10^{22} \ m^2}[/tex]
Divide. The units of meters squared cancel.
[tex]F_g=3.61767718 *10^{22} \ N[/tex]
The original values all have 3 significant figures, so our answer must have the same. For the number we found, that is the hundredth place. The 7 in the thousandth place tells us to round the 1 up to a 2.
[tex]F_g \approx 3.62 *10^{22} \ N[/tex]
The gravitational force between Earth and the Sun is approximately 3.62 *10²² Newtons.
If you were to mix 10 grams of salt into 100 grams of water, how much will the total mass of the solution be?
Group of answer choices
90 grams
100 grams
110 grams
10 grams
110 grams
mass of salt + mass of water
10 + 100
110g
Answer:
110 grams
Explanation:
If you were to mix 7 grams of sugar into 100 grams of water, how much will the total mass of the solution be?
No mass was gained or lost, so the mass would be 107 grams.
100 grams
107 grams
93 grams
95 grams
No mass was gained or lost, so the mass would be 107 grams.
(For your problem it would be 10+ 100= 110g)
moving east with a constant velocity of 30 m/s for 5 seconds. What is the object's
acceleration?
a. O m/s/s
C. 30 m/s/s
b. 6 m/s/s
d. 150 m/s/s
An open train car rolls along a track while it is being filled with sand. There is negligible friction. As a result of
the accumulating sand, what happens to the speed of the train car? (Assume negligible friction and the cart is
just rolling along, not receiving any additional force to regulate its speed.)
Answer:
Explanation:
that`s a the train car, that you asked the meaning, of that if the train car rolls it`s doing it`s speed, and it`s not ganna fall off the the trail of the train, car.An open train car rolls along a track while it is being filled with sand. There is negligible friction. The speed of the train car will be slowed down.
What is friction?Between two surfaces that are sliding or attempting to slide over one another, there is a force called friction. For instance, friction makes it challenging to push a book down the floor.
Friction always moves an object in a direction that is counter to the direction that it is traveling or attempting to move.
Speed indicates the rate of movement of something or someone. If you know how far something has traveled and how long it took to get there, you can calculate its average speed. Speed is calculated as follows: speed = distance x time.
Therefore, an open railway car is packed with sand and is rolling along a track. Very little friction exists. The railway car's speed will be slowed down.
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I was walking with Ruby in a garden from rest in a straight line with uniform acceleration so that we covered 0.25 m in the fifth second of our motion. Calculate our acceleration.
Answer:
0.02m/s^2
Explanation:
Dan is working as a family resources coordinator. Which of these statements are true about him?
Dan is responsible for overseeing the administrative functions and daily operations of a childcare center. He also helps families with children
who have special needs to uphold the rights of the children. He assists daycare teachers in carrying out their everyday duties. He also helps
families make use of early intervention services.
Reset
Next
rights reserved
The true statement about Dan is that "he also helps families make use of early intervention services."
Family resource coordinators are experts whose job it is to help families to ensure that children get along in early intervention services. They always work with families and school age children.
If Dan is working as a family resources coordinator, then a true statement about him is that "he also helps families make use of early intervention services."
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Answer:
-He also helps families make use of early intervention services.
-He also helps families with children who have special needs to uphold the rights of the children
Explanation:
Got it right on plato.
Hi, please help! •_•
One workman is measured as having a power of 528W. His weight is 800N. He can develop the same power climbing a ladder, whose rungs are 30cm apart. How many rungs can he climb in 5s?
Answer:
He can climb 11 rungs
Explanation:
Power = 528W, Force = 800N, Time= 5s Total Distance moved = 30x cm or 0.3x m, where x is the number of rungs he climbed
Power = Work done/time
Work done = Power × time
= 528 × 5
= 2640Joules
Also Work done = Force × total distance moved
Total Distance moved = Work done/force
0.3x = 2640/800
0.3x = 33
x = 3.3/0.3
x = 11
what happens to light when it travels from air into water
Answer:
Water is more dense than air. When water goes through a denser thing, the light is "bent" more towards the "normal" which is a straight, vertical line.
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Iron, Nickel, Copper, Zinc... These are all what kind of metals?
Answer:
there very old
Explanation:
what is the unit of measurement for expressing the intensity of sound
Someone answer? Please
How to do this question plz
Answer:
C
Explanation:
Most discussions of refraction will have a diagram similar to that of C.
The angle of incidence is measured from the normal to the boundary, as is the angle of refraction. The product of the sine of the angle and the index of refraction is the same for the media on either side of the boundary.
n₁·sin(θ₁) = n₂·sin(θ₂)
For media, such as optical fiber, that has an index of refraction greater than 1, the angle of refraction will be smaller in that media than the angle of incidence coming from air.
Figure C applies.
If an input force of 202N is applied to the handles of the wheelbarrow in the sample problem how large is the output force that just lifts the load?
For this case, the relationship between the two forces is given by:
F1 = nF2
Where,
F1: output strengthF2: input forcen: mechanical advantageThen, replacing the values we have:
F1 = (2.2)(202)
Having the calculations we have:
F1 = 444.4N
Answer: The output force that only lifts the load is F1 = 444.4N.
Help please!
3. A 75 kg linebacker moving at 6 m/s is running towards an 80 kg tackle moving 4 m/s. If they collide and stick together, how fast will they be moving after the collision?
5. A 6 kg bowling ball and a 4 kg bowling ball are rolled toward each other. The 6 kg ball is initially moving at 5.1 m/s and the 4 kg ball is moving in the opposite direction at 1.3 m/s. If the 6 kg ball slows to 1.5 m/s, what is the final speed of the 4 kg ball?
3. The sum of the players' momenta is equal to the momentum of the players when they're stuck together:
(75 kg) (6 m/s) + (80 kg) (-4 m/s) = (75 kg + 80 kg) v
where v is the velocity of the combined players. Solve for v :
450 kg•m/s - 320 kg•m/s = (155 kg) v
v = (130 kg•m/s) / (155 kg)
v ≈ 0.84 m/s
4. The total momentum of the bowling balls prior to collision is conserved and is the same after their collision, so that
(6 kg) (5.1 m/s) + (4 kg) (-1.3 m/s) = (6 kg) (1.5 m/s) + (4 kg) v
where v is the new velocity of the 4-kg ball. Solve for v :
30.6 kg•m/s - 5.2 kg•m/s = 9 kg•m/s + (4 kg) v
v = (16.4 kg•m/s) / (4 kg)
v = 4.1 m/s
Simplicity of conducting the study is to ________ as ability to test large numbers of participants is to ________.
Simplicity of conducting the study is to archival research as ability to test large numbers of participants is to surveys.
What is Archival research?Archival research is a type of research which involves seeking out and extracting the evidence from archival records. These archival records may be held together either in the collection of institutions, such as libraries and museums, or in the custody of the organization that originally generated or accumulated them, or in that of a successor object.
Archival research can be contrasted with the secondary research, which involves identification and consulting the secondary sources related to the topic of enquiry; and with the other types of primary research and empirical investigation such as fieldwork and experiment.
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How many volts would it take to push 1 amp through a resistance of 1 ohm?
Answer:
[tex]1\; \rm V[/tex].
Explanation:
Ohm's Law give the following relationship between the potential [tex]V[/tex] across a conductor, the electrical resistance [tex]R[/tex] of that conductor, and the current [tex]I[/tex] through that conductor:
[tex]V = I \, R[/tex].
It is given that the current through this conductor is [tex]I = 1\; {\rm A}[/tex], and that the electrical resistance of this conductor is [tex]R = 1\; \rm \Omega[/tex].
Note, that the unit of electrical resistance Ohm is a composite unit; [tex]1\; {\rm \Omega} = 1\; {\rm V \cdot A^{-1}}[/tex] (volts per ampere.)
Substitute the value of [tex]I[/tex] and [tex]R[/tex] into the equation [tex]V = I \, R[/tex] from Ohm's Law to find the potential across this conductor:
[tex]\begin{aligned}V &= I \, R \\ &= 1\; {\rm A} \times 1\; {\rm \Omega} \\ &= 1\; {\rm A} \times 1\; {\rm V \cdot A^{-1}} \\ &= 1\; {\rm V}\end{aligned}[/tex].
Convert 8 m/s to miles per hour
Answer:
17.8954903 or 17.9 mph
Explanation:
m/s is meters per second. 1609.344 meters is one mile. There are 3,600 seconds in an hour. 8 meters *3600 seconds= 28,800. 28,800/1609.344 = 17.8954903. Simplify to 17.9
In a car engine, fuel is ignited within a cylinder to cause an explosion that moves a piston. If the explosion exerts 300 Pa of pressure on a piston with a surface area of 80 cm^2?
The force exerted by the explosion on the piston is 2.4 N.
The given parameters:
Pressure of the explosion on piston, P = 300 Pa (N/m²)Surface area of the piston, A = 80 cm²The force exerted on the piston by the explosion is calculated as follows;
F = PA
where;
A is the area of the piston in m²
The surface area of the piston in square meter is calculated as follows;
[tex]A = 80 \ cm^2 \times \frac{(1m)^2}{(100 \ cm)^2} \\\\A = 0.008 \ m^2[/tex]
The force exerted by the explosion on the piston is calculated as follows;
[tex]F = 300 \ (N/m^2)\ \times \ 0.008 \ (m^2)\\\\F = 2.4 \ N[/tex]
The complete question is here:
In a car engine, fuel is ignited within a cylinder to cause an explosion that moves a piston. If the explosion exerts 300 Pa of pressure on a piston with a surface area of 80 cm^2, what is the force exerted on the piston?
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please help
Which color will a red rose appear to be if only a blue light reached it?
red
white
black
purple
Answer:
Black
Explanation:
Why do you call that flower a "red" rose? Could it be because it appears red in a typical 'wideband' solar or household light? That must mean that when the light of many colors shines on it, the rose absorbs everything except red, and red is the only light left to bounce off of it toward your eyes. If that's the case, and you illuminate it with the light of any single color other than red, then the rose will absorb that light and appear black.
What is the magnitude of the resultant of
a 3.0-
meter displacement and a 4.0-meter
displacement as shown in the diagram?
A. 1.0 meter
4.0 meters
B. 5.0 meters
3.0 meters
C. 7.0 meters
D. 12 meters
Answer:b. 5.0 meters
Explanation: d² = 3²+4²
d² = 9+16
d² = 25
d = √25
d = 5m
The magnitude of the displacement is 5 m as shown in the diagram. Option B is correct.
What is displacement?
Displacement can be defined as the total change in the position of the object. It is a vector quantity.
From the Pythagorean theorem,
[tex]d =\sqrt { 3^2 +4^2}\\\\d = \sqrt {25}\\\\d = 5[/tex]
Therefore, the magnitude of the displacement is 5 m.
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if the wave velocity and frequency of a wave are both doubled, the wavelength is
If the wave velocity and frequency of a wave are both doubled, the wavelength will remain the same.
The wavelength of a wave shows the spatial orientation of distance between two successive crest in a wave medium.
The wavelength λ is expressed by using the relation:
[tex]\mathbf{\lambda = \dfrac{v}{f}}[/tex]
Now, if velocity and frequency of wave is both doubled, the wavelength will remain the same.
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Which of the following is the goal of physical fitness test? *
a. to determine the level of fitness.
b. to identify the area of development/improvement.
c. all of the above
d. to identify strengths and weaknesses.
Answer
C
hope this helps!!
*please mark brainliest if correct!! Trying to level up!!
I need help!
A car has a mass of 1,200 kg and the road can provide a maximum force of 24 kN on the car what is the maximum acceleration?
Answer:
The acceleration of the car with the mass of 1200kg and a force of 11 × 10³N is 9.17m/s²
Explanation:
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What was the evidence that Earth was round before there were photos from space?
Answer:
?????
Explanation:
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Which statement regarding characteristics of electromagnetic radiation is correct?
Longer wavelengths of light have higher energies.
Lower frequencies of light have higher energies.
Higher frequencies of light have shorter wavelengths.
Shorter wavelengths of light have lower energies.
Answer:
Higher frequencies of light have shorter wavelengths.
if clarisses mass on earth is 52kg what would be her weight on venus if the acceleration due to gravity on that planet is 8.87 m/s^2
Answer:
Weight=F=MA=52*8.87=461.24
Tom pulls a muscle. He has to stop working to get an ice pack. Claudia continues to work and soon finishes her pile.
Power is the rate of doing work. It's calculated by dividing work by time (power = work = time). Who had more power in
this scenario? Why?
Answer:
Tom
Explanation:
if for example both their work is 40 and Tom stops working after 2 hours but Claudia continues and stops after 3 hours when you divide their work by their time Claudia will get a lower number of power.
(in your explanation maybe use different numbers based on you book or notes)
Answer:
Claudia had more power. She did more work than Tom, and she did it in less time.
Explanation:
sample answer on edmentum. maybe change it up. hope this helps:)
A seashell is suspended in the air at rest by two strands of spider silk. Each strand of silk makes an angle of 75 degrees above the horizontal, and experiences a tension of 1.42 N.
What is the mass of the seashell?
The mass of the seashell suspended by the two strands of spider silk is 0.28 kg.
The given parameters:
Tension on each strand of silk, T = 1.42 NAngle of inclination of each strand, θ = 75⁰The mass of the seashell at equilibrium is calculated by applying Newton's second law of motion;
[tex]\Sigma F = 0\\\\T_1 sin(\theta) + T_2 sin(\theta) - W = 0[/tex]
where;
W is the weight of the seashellThe weight of the seashell is calculated as;
[tex]1.42 \times sin(75) \ + \ 1.42 \times sin(75) \ - W = 0\\\\2.743 - W = 0\\\\W = 2.743 \ N[/tex]
The mass of the seashell is calculated as follows;
[tex]W = mg\\\\m = \frac{W}{g} \\\\m = \frac{2.743}{9.8} \\\\m = 0.28 \ kg[/tex]
Thus, the mass of the seashell suspended by the two strands of spider silk is 0.28 kg.
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