In a ∆ABC , angle A + Angle B = 125° and Angle B + Angle C = 150° . Find all the angles of ∆ABC.​

Answers

Answer 1

[tex]\large\underline{\sf{Solution-}}[/tex]

Given that,

In triangle ABC

[tex] \purple{\rm :\longmapsto\:\angle A + \angle B = 125 \degree \: - - - (1) }[/tex]

[tex] \purple{\rm :\longmapsto\:\angle B + \angle C = 150 \degree \: - - - (2)}[/tex]

We know,

Sum of all interior angles of a triangle is supplementary.

[tex] \purple{\rm :\longmapsto\:\angle A + \angle B + \angle C = 180\degree }[/tex]

On adding equation (1) and (2), we get

[tex] \purple{\rm :\longmapsto\:\angle A + \angle B + \angle B + \angle C = 125\degree + 150 \degree \:}[/tex]

[tex] \purple{\rm :\longmapsto\:\angle A + \angle B + \angle C + \angle B = 275\degree \:}[/tex]

[tex] \purple{\rm :\longmapsto\:180\degree + \angle B = 275\degree \:}[/tex]

[tex] \purple{\rm :\longmapsto\:\angle B = 275\degree - 180\degree \:}[/tex]

[tex] \purple{\rm :\longmapsto\:\angle B = 95\degree \:}[/tex]

On substituting the value in equation (1) and (2), we get

[tex] \purple{\rm :\longmapsto\:\angle A + 95\degree = 125\degree }[/tex]

[tex] \purple{\rm :\longmapsto\:\angle A = 125\degree - 95\degree }[/tex]

[tex] \purple{\rm :\longmapsto\:\angle A = 30\degree }[/tex]

Also, from equation (2), we get

[tex] \purple{\rm :\longmapsto\:95\degree + \angle C = 150\degree }[/tex]

[tex] \purple{\rm :\longmapsto\:\angle C = 150\degree - 95\degree }[/tex]

[tex] \purple{\rm :\longmapsto\:\angle C = 55\degree }[/tex]

Hence,

[tex]\begin{gathered}\begin{gathered}\bf\: \rm\implies \:\begin{cases} &\sf{\angle A = 30\degree } \\ \\ &\sf{\angle B = 95\degree } \\ \\ &\sf{\angle C = 55\degree } \end{cases}\end{gathered}\end{gathered}[/tex]

Answer 2

Answer:

angle A=30°

angle B=95°

angle C=55°


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Answers

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Answers

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Answers

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Answers

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Answers

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Hey there!

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~Amphitrite1040:)

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Answers

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Answers

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Answers

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