If you complete the square in the quadratic equation ​, you get the quadratic formula for the solutions x ​_______.

Answer:

4

Step-by-step explanation:

It is 4 because the point rises 4 units up from the graph and runs 1 unit to the right which is 4/1 = 4.

Answer:

B

Step-by-step explanation:

2.

what is the middle between 2 numbers (any numbers, really) ?

you add both numbers and divide the result by 2.

the same here :

(-3 + 24) / 2 = 21/2 = 10 1/2

proof :

what is the distance from -3 to 10 1/2 ? it is 10 1/2 from 0 to 10 1/2 plus 3 from -3 to 0 = 10 1/2 + 3 = 13 1/2.

what is the distance from 10 1/2 to 24 ? it is 13 from 11 to 24, and another half from 10 1/2 to 11. so, in total 13 1/2.

both distances are equal, so it is proven for 10 1/2 to be the midpoint.

Step-by-step explanation:

[tex] \frac{a}{b} c = \frac{a}{ \frac{b}{c} } [/tex]

[tex] \frac{a}{b} c = a \times \frac{c}{b} [/tex]

Answer:

Step-by-step explanation: change A/B/C to A÷B/C then change the division sign into a multiplicmultiplication sign so that you will have A×C/Bwhich will make your left equation = to your right equation

Answer:

Step-by-step explanation:

{2, 3, 5, 7, 11, 13, 17, 19}

The probability of correctly guessing at random exactly one correct answer will be 15%. Then the correct option is A.

Its simple notion is that something will most likely occur. The favorable event's proportion to the overall number of occurrences.

A five-question multiple-choice quiz has five choices for each answer.

Use the random number table provided, with 0’s representing incorrect answers and 1’s representing correct answers, to answer the following question.

Then the probability of correctly guessing at random exactly one correct answer will be

P (X = x) = ⁿCₓ × pˣ × (1 - p)⁽ⁿ⁻ˣ⁾

The probability of success will be 0.5. Then we have

P (X = 1) = ⁵C₁ × p¹ × (1 - p)⁽⁵ ⁻ ¹⁾

P (X = 1) = 0.15625

P (X = 1) = 15.625%

P (X = 1) ≅ 15%

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Answer:

Lateral surface area = [tex]18\sqrt{91}[/tex] units²

                                 = 171.71 units²

Step-by-step explanation:

Lateral area:  total surface area excluding its base

Find the radius (circumradius) of the regular hexagonal base.  Use this to find the slant edge of the pyramid, then use the slant edge to find the slant height and thus the area of each face.

Radius of a regular polygon: distance from its center to its vertices.

[tex]\textsf{Radius of a regular polygon}=\dfrac{s}{2 \sin \left(\dfrac{180^{\circ}}{n}\right)}[/tex]

where:

Given:

[tex]\implies \textsf{Radius}=\dfrac{6}{2 \sin \left(\dfrac{180^{\circ}}{6}\right)}=6\:\sf units[/tex]

Use Pythagoras' Theorem to find the slant edge:

[tex]\begin{aligned}\textsf{Slant edge} & =\sf \sqrt{r^2+h^2}\\& = \sqrt{6^2+8^2}\\ & = 10\:\sf units\end{aligned}[/tex]

Use Pythagoras' Theorem to find the slant height:

[tex]\begin{aligned}\textsf{Slant height} & = \sqrt{\textsf{slant edge}^2-\left(\dfrac{s}{2}\right)^2}\\& =\sqrt{10^2-3^2}\\ & =\sqrt{91}\: \sf units\end{aligned}[/tex]

[tex]\begin{aligned}\textsf{Area of one face} & = \dfrac{1}{2} \times s \times \textsf{slant height}\\\\ & = \dfrac{1}{2} \cdot 6 \cdot \sqrt{91}\\\\ & = 3\sqrt{91}\: \sf units^2\end{aligned}[/tex]

[tex]\begin{aligned}\textsf{Lateral Surface Area}& = 6 \times \textsf{area of one face}\\ & = 6 \cdot 3\sqrt{91}\\ & = 18\sqrt{91}\\ & =171.71\: \sf units^2\:(nearest\:hundredth)\end{aligned}[/tex]

Answer:

sorrry i forget you man ..... or bro .....

The width of the path when the length of the outer rectangle is 26+2x and width of it is 18+2x is 4 meters.

Area of a rectangle is the product of the length of the rectangle and the width of the rectangle. It can be given as,

A=a×b

Here, (a)is the length of the rectangle and (b) is the width of the rectangle

The length of the outer rectangle is 26+2x and width of it is 18+2x. The area of this rectangle is 884² m. Thus,

A=a×b

884=(26+2x)×(18+2x)

884=468+52x+36x+4x²

4x²+88x-416=0

Divide both side with 4,

x²+22x-104=0

x²+26x-4x-104=0

x(x+26)-4(x+26)=0

(x+26)(x-4)=0

x=-26,4

Take the positive value 4. The width of the path is equal to x which is 4 meters.

Hence, the width of the path when the length of the outer rectangle is 26+2x and width of it is 18+2x is 4 meters.

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Answer:

its b actually jack had 5 numbers for each button

Answer:

then

x2-4x+3=x-5

or,x2-4x-x= -5-3

or,x2-5x+8=0

Answer:

Step-by-step explanation:

Two legs of a right triangle measure 3 inches and 4 inches. Which of the following choice for the length of the third side will make the triangle a right triangle?

x = √(3²+4²)

x = √(9 + 16)

x = √25

Answer:

The answer is Graph C.

Step-by-step explanation:

Both the equation of each other are the same in Graph C..

Answer:

B. Graph C

The lines are together, so every point they pass is a solution

Answer:

5.9 C

Step-by-step explanation:

Plug in 16°C for the initial amount, 0.06 for the rate of decrease, and 16 minutes for the time elapsed.

y= a(1–r)t

y= 16(1–0.06)16 Plug in values

y= 16(0.94)16 Subtract

y= 16(0.37157…) Simplify

y= 5.94518… Multiply

Round to the nearest tenth.

5.94518… → 5.9

To the nearest tenth, the difference in temperature will be 5.9°C.

    If your options are:

A. x(12-3)

B. 8x

C. 3 (3x-x)

D. 9

      Then the following is true.

Answer: (A) x(12-3)

   First, we will simplify the given expressions;

A. x(12-3)     = 12x - 3x

B. 8x           = 8x

C. 3 (3x-x)   = 9x - 3x

D. 9             =9

   This means the answer to your question is;

          A. x(12-3)

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Answer:

each notebook costs $2

Step-by-step explanation:

21-5=16/8=$2

Step-by-step explanation:

all the pink area above the blue line (above means ">", and the blue line is -1/2 x), and not including the line.

Answer:

Minimum: 0

Quartile Q1: 22.5

Median: 50

Quartile Q3: 77.5

Maximum: 100

Step-by-step explanation:

Answer:

hope it helps you

Step-by-step explanation:

To make such a frequency distribution table, first, write the class intervals in one column. Next, tally the numbers in each category based on the number of times it appears. Finally, write the frequency in the final column. A frequency distribution table drawn above is called a grouped frequency distribution table.

The equation of the ellipse will be (x - 5)² / 16 + (y + 7)² / 64 = 1 and the equation of the hyperbola will be (x + 1)² / 4 - (y)² / 64 = 1.

Ellipse is a locus of a point that moves in a plane such that the sum of its distances from the two points called foci adds up to a constant. It is taken from the cone by cutting it at an angle.

The hyperbola is the locus of a point such that the difference of distance from point P to two non-movable points. These two points are called foci of hyperbola.

Conic sections provide a format that makes them fairly uncomplicated to draw manually.

Then the equation of the ellipse will be

(x - 5)² / 16 + (y + 7)² / 64 = 1

Then the equation of the hyperbola will be

(x + 1)² / 4 - (y)² / 64 = 1

The graphs are given below.

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Answer:

the length of the line is 7

Step-by-step explanation:

it is b. 7

Answer:

1440 cubic inches

V = [tex]l[/tex] × [tex]w[/tex] × [tex]h[/tex]

V = 12 × 10 × 12 = 1,440 cubic inches

There are a total of  180 seats in the theater

The theatre illustrates an arithmetic sequence, with the following parameters:

Number of rows = 18

Let the number of seats per row be n.

So, we have:

Total = 18n

When there are 3 fewer rows, the total number of seats is:

Total = (18 - 3) * (n + 6)

This gives

Total = 15* (n + 6)

Substitute Total = 18n in Total = 15* (n + 6)

18n = 15* (n + 6)

Open the bracket

18n = 15n + 90

Subtract 15n from both sides

3n = 30

Divide both sides by 3

n = 10

Substitute n = 10 in Total = 18n

Total = 18 *10

This gives

Total = 180

Hence, there are 180 seats in the theater

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Answer:

y = 1/3 x + 4

Step-by-step explanation:

y = 1/3 x + 4

The y intercept is 4 (when x = 0 from the graph) and the slope is rise (1) and run (3).

The cost of each department A, B, C, and D of the Marketing Department would take up is $8,391.17, $4,914.83, $3,356.47, and $2,337.53, respectively.

A fraction is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25.

Given the cost of operating the marketing Department for March is $19,000. The total area of operation is,

Total Area = Department A + Department B + Department C + Department D

Total Area = 1400 m² + 820 m² + 560 m² + 390 m² = 3,170 m²

Now, the cost of operating a unit area can be determined as,

Cost of operating = $19,000/3,170m² = $5.99369 per m²

Further the cost of operating the different departments are,

Department A = 1400m²×$5.99 = $8,391.17

Department B = 820m²×$5.99 = $4,914.83

Department C = 560m²×$5.99 = $3,356.47

Department D = 390m² × $5.99 = $2,337.53

Hence, the cost of each department A, B, C, and D of the Marketing Department would take up is $8,391.17, $4,914.83, $3,356.47, and $2,337.53, respectively.

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Answer:

I'd say the order from youngest to oldest, would be B A C.

Step-by-step explanation:

My reason is that, A is younger than C or in other words C is older than A. Also B is NOT older than A, so therefore B must be younger than A.

So from youngest to oldest, B is younger than A, A is younger than C, and that means C is the absolute oldest out of the three children.

Hope this helps you :)

Sorry if it didn't though.

Since the isotope is initially 154 mg, the amount of radioactive isotope left after 64 hours is 9.625 mg

To answer the question, we need to know what radioactive decay is.

Radioactive decay is the spontaneous disintegration of a larger atom to a smaller one

Half-life of a radioactive isotope is the time it takes for the isotope to decay to half its initial value.

The amount left after n half lives is N = (1/2)ⁿN₀ where N₀ = initial mass of isotope.

Given that the half-life of the isotope is 16 hours, and we desire the amount present after 64 hours.

The number of half-lives after 64 hours is n = time/half-life

= 64 h/16 h

= 4

Since we have 154 mg of isotope present, N₀ = 154 mg

Given that

Substituting the values of the variables into N, we have

N = (1/2)ⁿN₀

N = (1/2)⁴ × 154 mg

N = 154 mg/16

N = 9.625 mg

So, the amount of radioactive isotope left after 64 hours is 9.625 mg

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