If IN = 2x + 10 and AT = 26, find x. Group of answer choices 10 8 12 6

Pi, or π, is a number that is used to represent the ratio between a circle's circumference and its diameter.

Step-by-step explanation:

Answer: dude idek how to do this

Step-by-step explanation:

not lying still dont know

Answer:

-1/3

Step-by-step explanation:

because it is a negative number and closer to zero than -3 is making it greater, becuase it is closer to a positive number.

Answer:

-1/3 is greater than -3

-3 < -1/3

Answer:

The probability scale for this question is not 100% sure to buy shoes so the scale is given to be even chance(1/2).

Step-by-step explanation:

Answer:

my best estimate would be 15,116,600

Step-by-step explanation:

,

Answer:

A. evaluate progress

Step-by-step explanation:

common sense

The age of Nina and sam are 15years and 10 years respectively now

They consists of equations and unknown variables

Let their current age be x and y

If five years ago, Nina was twice as old as Sam then;

x - 5 = 2(y-5)

If in five years she will be 1.5 times as old as Sam, then;

x = 1.5y

Substitute

1.5y - 5 = 2y -10

-0.5y  = -5

y =5/0.5

y = 10

Since x = 1.5y

x = 15years

Hence the age of Nina and sam are 15years and 10 years respectively now

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The total balance in Raul's account after 40 years when he retires is $65,714.90.

The formula that can be used to determine the balance of the accout is: monthly amount saved x annuity factor.

Annuity factor = {[(1+r)^n] - 1} / r

Where:

$100 x [(1.00125^480) - 1 ] / 0.00125 = $65,714.90

Here is the complete question:

Raul is a saver. He sets aside $100 per month during his career of 40 years to prepare for retirement. He does not like the idea of investing because he prefers to minimize his risk as much as possible, so he puts his money in a savings account which earns 1.5% interest per year. What is the balance in the account after 40 years?

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Answer:

See below for answers and explanations

Step-by-step explanation:

Problem 1

Recall that the projection of a vector [tex]u[/tex] onto [tex]v[/tex] is [tex]\displaystyle proj_vu=\biggr(\frac{u\cdot v}{||v||^2}\biggr)v[/tex].

Identify the vectors:

[tex]u=\langle-10,-7\rangle[/tex]

[tex]v=\langle-8,4\rangle[/tex]

Compute the dot product:

[tex]u\cdot v=(-10*-8)+(-7*4)=80+(-28)=52[/tex]

Find the square of the magnitude of vector v:

[tex]||v||^2=\sqrt{(-8)^2+(4)^2}^2=64+16=80[/tex]

Find the projection of vector u onto v:

[tex]\displaystyle proj_vu=\biggr(\frac{u\cdot v}{||v||^2}\biggr)v\\\\proj_vu=\biggr(\frac{52}{80}\biggr)\langle-8,4\rangle\\\\proj_vu=\biggr\langle\frac{-416}{80} ,\frac{208}{80}\biggr\rangle\\\\proj_vu=\biggr\langle\frac{-26}{5} ,\frac{13}{5}\biggr\rangle\\\\proj_vu=\langle-5.2,2.6\rangle[/tex]

Thus, B is the correct answer

Problem 2

Treat the football and wind as vectors:

Football: [tex]u=\langle42\cos172^\circ,42\sin172^\circ\rangle[/tex]

Wind: [tex]v=\langle13\cos345^\circ,13\sin345^\circ\rangle[/tex]

Add the vectors: [tex]u+v=\langle42\cos172^\circ+13\cos345^\circ,42\sin172^\circ+13\sin345^\circ\rangle\approx\langle-29.034,2.481\rangle[/tex]

Find the magnitude of the resultant vector:

[tex]||u+v||=\sqrt{(-29.034)^2+(2.481)^2}\approx29.14[/tex]

Find the direction of the resultant vector:

[tex]\displaystyle \theta=tan^{-1}\biggr(\frac{2.841}{-29.034}\biggr)\approx -5^\circ[/tex]

Because our resultant vector is in Quadrant II, the true direction angle is 6° clockwise from the negative axis. This means that our true direction angle is [tex]180^\circ-5^\circ=175^\circ[/tex]

Thus, C is the correct answer

Problem 3

We identify the initial point to be [tex]R(-2,12)[/tex] and the terminal point to be [tex]S(-7,6)[/tex]. The vector in component form can be found by subtracting the initial point from the terminal point:

[tex]v=\langle-7-(-2),6-12\rangle=\langle-7+2,-6\rangle=\langle-5,-6\rangle[/tex]

Next, we find the magnitude of the vector:

[tex]||v||=\sqrt{(-5)^2+(-6)^2}=\sqrt{25+36}=\sqrt{61}\approx7.81[/tex]

And finally, we find the direction of the vector:

[tex]\displaystyle \theta=tan^{-1}\biggr(\frac{6}{5}\biggr)\approx50.194^\circ[/tex]

Keep in mind that since our vector is in Quadrant III, our direction angle also needs to be in Quadrant III, so the true direction angle is [tex]180^\circ+50.194^\circ=230.194^\circ[/tex].

Thus, A is the correct answer

Problem 4

Add the vectors:

[tex]v_1+v_2=\langle-60,3\rangle+\langle4,14\rangle=\langle-60+4,3+14\rangle=\langle-56,17\rangle[/tex]

Determine the magnitude of the vector:

[tex]||v_1+v_2||=\sqrt{(-56)^2+(17)^2}=\sqrt{3136+289}=\sqrt{3425}\approx58.524[/tex]

Find the direction of the vector:

[tex]\displaystyle\theta=tan^{-1}\biggr(\frac{17}{-56} \biggr)\approx-17^\circ[/tex]

Because our vector is in Quadrant II, then the direction angle we found is a reference angle, telling us the true direction angle is 17° clockwise from the negative x-axis, so the true direction angle is [tex]180^\circ-17^\circ=163^\circ[/tex]

Thus, A is the correct answer

Problem 5

A vector in trigonometric form is represented as [tex]w=||w||(\cos\theta i+\sin\theta i)[/tex] where [tex]||w||[/tex] is the magnitude of vector [tex]w[/tex] and [tex]\theta[/tex] is the direction of vector [tex]w[/tex].

Magnitude: [tex]||w||=\sqrt{(-16)^2+(-63)^2}=\sqrt{256+3969}=\sqrt{4225}=65[/tex]

Direction: [tex]\displaystyle \theta=tan^{-1}\biggr(\frac{-63}{-16}\biggr)\approx75.75^\circ[/tex]

As our vector is in Quadrant III, our true direction angle will be 75.75° counterclockwise from the negative x-axis, so our true direction angle will be [tex]180^\circ+75.75^\circ=255.75^\circ[/tex].

This means that our vector in trigonometric form is [tex]w=65(\cos255.75^\circ i+\sin255.75^\circ j)[/tex]

Thus, C is the correct answer

Problem 6

Write the vectors in trigonometric form:

[tex]u=\langle40\cos30^\circ,40\sin30^\circ\rangle\\v=\langle50\cos140^\circ,50\sin140^\circ\rangle[/tex]

Add the vectors:

[tex]u+v=\langle40\cos30^\circ+50\cos140^\circ,40\sin30^\circ+50\sin140^\circ\rangle\approx\langle-3.661,52.139\rangle[/tex]

Find the magnitude of the resultant vector:

[tex]||u+v||=\sqrt{3.661^2+52.139^2}\approx52.268[/tex]

Find the direction of the resultant vector:

[tex]\displaystyle\theta=tan^{-1}\biggr(\frac{52.139}{-3.661} \biggr)\approx-86^\circ[/tex]

Because our resultant vector is in Quadrant II, then our true direction angle will be 86° clockwise from the negative x-axis. So, our true direction angle is [tex]180^\circ-86^\circ=94^\circ[/tex].

Thus, B is the correct answer

Yes, I guess so.

Hope this helps!

Answer:

yea actually what if she turned?- but yea its 0 so D

Step-by-step explanation:

Answer:

carbon (C), hydrogen (H), nitrogen (N), and oxygen (O)—make up 96.5% of an organism's weight.

Step-by-step explanation:

hope this helps.

[tex]x^2+y^2=r^2~\hfill x=rcos(\theta )~\hfill y=rsin(\theta ) \\\\[-0.35em] ~\dotfill\\\\ r=3sin(A)\implies \stackrel{\textit{multiplying both sides by "r"}}{r^2~~ = ~~3~rsin(A)}\implies x^2+y^2=3y[/tex]

r = 3sinA is written in rectangular form as[tex]x^2+y^2 = 3y.[/tex]

Any complex number z = a + ib can be written in polar form as:

[tex]z = r(\cos(\theta) + i\sin(\theta))[/tex]

Complex numbers are those numbers that contain the imaginary and the real part.

Raising this to nth power (n being an integer), we get:

[tex]z ^n = r^n (\cos(n\theta) + i\sin(n\theta))[/tex]

We need to find r = 3sinA is written in rectangular form as[tex]x^2+y^2[/tex].

We know that

x = r cosA

y = r sin A

We have been given ;

r = 3sinA

Multiply by r on both sides;

[tex]r^2 = 3r sin A\\\\r^2 = 3 y[/tex]

therefore,

[tex]x^2+y^2 = 3y[/tex]

Hence, r = 3sinA is written in rectangular form as [tex]x^2+y^2 = 3y[/tex].

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Answer:

A. both the interest and fees on a loan.

Step-by-step explanation:

An annual percentage rate (APR) includes both the interest and fees on a loan.

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Answer:

x= -2

x= -3

x= 5

Step-by-step explanation:

The expression is rewritten as the greatest common factor multiplied by the sum of two numbers is: 6*(8 + 11)

First, we need to find the greatest common factor between 48 and 66.

To find it, we can write both of these as a product of its prime factors, we get:

48 = 2*24 = 2*2*12 = 2*2*2*6 = 2*2*2*2*3

66 = 2*33 = 2*3*11

The greatest common factor that we can make is 2*3 = 6

Then we rewrite the numbers as:

48 = 6*8

66 = 6*11

Now we can rewrite our expression:

48 + 66 = 6*(8 + 11)

So the correct option is C

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Answer:

hopefully this helps :] 16th line down I think

Answer:

A

Step-by-step explanation:

Close to 0 means there isn't a certain number, and there also isn't a certain answer for what the probability. While all of the others are alreaady stated, this is the only one that is not.

Linear equations are usually organized in slope-intercept form, which looks like this:

[tex]y=mx+b[/tex]

To find the equation of a line in slope-intercept form:

We're given:

First, plug the given slope into the slope-intercept form equation:

[tex]y=mx+b\\\\y=\dfrac{1}{2}x+b[/tex]

Now, determine the y-intercept.

[tex]y=\dfrac{1}{2}x+b[/tex]

⇒ Plug in the given point (4,1) and solve for b:

[tex]1=\dfrac{1}{2}(4)+b\\1=2+b\\b=-1[/tex]

⇒ Therefore, the y-intercept is -1. Plug this back into our original equation:

[tex]y=\dfrac{1}{2}x-1[/tex]

[tex]y=\dfrac{1}{2}x-1[/tex]

Answer:

Right angle

Step-by-step explanation:

It is because ANGLE QMS from the given figure denote 90 ° and right angle means 90°.

Step-by-step explanation:

x > 5, both terms are positive

x < - 5, both terms are negative

This is not clear

If x>5

Hence..

If x<-5 terms are negative

If x=-5

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Explanation:

Refer to the figure below.

Focus on triangle ABF. Angle AFB = 40 is marked in red. Angle BAF = 90 is marked in blue. The missing angle is 180-90-40 = 50 which is angle ABF.

Inscribed angle ABF = 50 doubles to arc AC since this inscribed angle subtends the arc in question. I'm using the inscribed angle theorem.

arc AC = 2*(angle ABF) = 2*50 = 100 degrees

Note: We don't need the fact that angle AGD = 86

The value of x, y and z from the system of equation are -1, -8 and 5 respectively.

Data;

To solve this problem, we have to solve the system of equation using substitution method.

From equation (iii)

[tex]2z = 10\\z = 5[/tex]

let us substitute the value of z into equation (ii)

[tex]-3y + 7z = 59\\z = 5\\-3y + 7(5) = 59\\-3y + 35 = 59\\-3y = 59 - 35\\-3y = 24\\y = -8[/tex]

Let's substitute the value of x and y into equation (i)

[tex]-2x + 6y + 3z = -31\\y = -8, z = 5\\-2x + 6(-8) + 3(5) = -31\\-2x - 48 + 15 = -31\\-2x - 33 = -31\\-2x = -31 + 33\\-2x = 2\\x = -1[/tex]

From the calculation above, the value of x, y and z are -1, -8 and 5 respectively.

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Answer:

F= -4t+61

T= -1/4f + 61/4

Answer:

  30°

Step-by-step explanation:

The angle sum theorem tells you the sum of angles in any triangle is 180°. A right triangle has one angle that is 90°, so the sum of the remaining two acute angles is 180° -90° = 90°. That is, the acute angles in a right triangle are complementary.

__

The other acute angle is ...

  90° -60° = 30°

Answer:

Step-by-step explanation:

2x + 3y = -7

7x + 9y = -14

-3(2x+3y= -7) = -6x - 9y = 21

-6x - 9y = 21

7x + 9y = -14

add columns (y values cancel)

1x + 0y = 7

x = 7

plug 7 into the x value in either equation to find y

2(7) + 3y = -7

14 + 3y = -7

3y = -21

y = -7

(x,y) = (7,-7)

Answer:

a) m problems, d days to complete.

m/d

b) m/15d

c)-if 15 was connected; 15d

if 15 WAS NOT connected, m problems

Answer:

13 pints

Step-by-step explanation:

6 1/2 (6.50) quarts is equal to 13 pints

Answer:

13pt

to go from quarts to pints multiply the value by 2

Answer:

[tex]m=\frac{6}{7}[/tex]

Step-by-step explanation:

[tex]m=\frac{10-4}{9-2}=\frac{6}{7}[/tex]

Answer:  [tex]\frac{6}{7}[/tex]

Explanation:

In the numerator we have [tex]y_2 - y_1 = 10-4 = 6[/tex] to represent the change in y, aka the rise. This is the vertical change. It's how much we go up.

The denominator has [tex]x_2 - x_1 = 9-2 = 7[/tex] to represent the run. It is the horizontal change, or how much we go to the right.

We go up 6 and to the right 7 to have a slope of [tex]m = \frac{\text{rise}}{\tex{run}} = \frac{6}{7}[/tex]

Here's how you can show the steps

[tex]m = \frac{y_2-y_1}{x_2-x_1}\\\\m = \frac{10-4}{9-2}\\\\m = \frac{6}{7}\\\\[/tex]

Note: To write [tex]\frac{6}{7}[/tex] on the keyboard, you can type 6/7