Answer:
The maximum value of f(x) occurs at:
[tex]\displaystyle x = \frac{2a}{a+b}[/tex]
And is given by:
[tex]\displaystyle f_{\text{max}}(x) = \left(\frac{2a}{a+b}\right)^a\left(\frac{2b}{a+b}\right)^b[/tex]
Step-by-step explanation:
Answer:
Step-by-step explanation:
We are given the function:
[tex]\displaystyle f(x) = x^a (2-x)^b \text{ where } a, b >0[/tex]
And we want to find the maximum value of f(x) on the interval [0, 2].
First, let's evaluate the endpoints of the interval:
[tex]\displaystyle f(0) = (0)^a(2-(0))^b = 0[/tex]
And:
[tex]\displaystyle f(2) = (2)^a(2-(2))^b = 0[/tex]
Recall that extrema occurs at a function's critical points. The critical points of a function at the points where its derivative is either zero or undefined. Thus, find the derivative of the function:
[tex]\displaystyle f'(x) = \frac{d}{dx} \left[ x^a\left(2-x\right)^b\right][/tex]
By the Product Rule:
[tex]\displaystyle \begin{aligned} f'(x) &= \frac{d}{dx}\left[x^a\right] (2-x)^b + x^a\frac{d}{dx}\left[(2-x)^b\right]\\ \\ &=\left(ax^{a-1}\right)\left(2-x\right)^b + x^a\left(b(2-x)^{b-1}\cdot -1\right) \\ \\ &= x^a\left(2-x\right)^b \left[\frac{a}{x} - \frac{b}{2-x}\right] \end{aligned}[/tex]
Set the derivative equal to zero and solve for x:
[tex]\displaystyle 0= x^a\left(2-x\right)^b \left[\frac{a}{x} - \frac{b}{2-x}\right][/tex]
By the Zero Product Property:
[tex]\displaystyle x^a (2-x)^b = 0\text{ or } \frac{a}{x} - \frac{b}{2-x} = 0[/tex]
The solutions to the first equation are x = 0 and x = 2.
First, for the second equation, note that it is undefined when x = 0 and x = 2.
To solve for x, we can multiply both sides by the denominators.
[tex]\displaystyle\left( \frac{a}{x} - \frac{b}{2-x} \right)\left((x(2-x)\right) = 0(x(2-x))[/tex]
Simplify:
[tex]\displaystyle a(2-x) - b(x) = 0[/tex]
And solve for x:
[tex]\displaystyle \begin{aligned} 2a-ax-bx &= 0 \\ 2a &= ax+bx \\ 2a&= x(a+b) \\ \frac{2a}{a+b} &= x \end{aligned}[/tex]
So, our critical points are:
[tex]\displaystyle x = 0 , 2 , \text{ and } \frac{2a}{a+b}[/tex]
We already know that f(0) = f(2) = 0.
For the third point, we can see that:
[tex]\displaystyle f\left(\frac{2a}{a+b}\right) = \left(\frac{2a}{a+b}\right)^a\left(2- \frac{2a}{a+b}\right)^b[/tex]
This can be simplified to:
[tex]\displaystyle f\left(\frac{2a}{a+b}\right) = \left(\frac{2a}{a+b}\right)^a\left(\frac{2b}{a+b}\right)^b[/tex]
Since a and b > 0, both factors must be positive. Thus, f(2a / (a + b)) > 0. So, this must be the maximum value.
To confirm that this is indeed a maximum, we can select values to test. Let a = 2 and b = 3. Then:
[tex]\displaystyle f'(x) = x^2(2-x)^3\left(\frac{2}{x} - \frac{3}{2-x}\right)[/tex]
The critical point will be at:
[tex]\displaystyle x= \frac{2(2)}{(2)+(3)} = \frac{4}{5}=0.8[/tex]
Testing x = 0.5 and x = 1 yields that:
[tex]\displaystyle f'(0.5) >0\text{ and } f'(1) <0[/tex]
Since the derivative is positive and then negative, we can conclude that the point is indeed a maximum.
Therefore, the maximum value of f(x) occurs at:
[tex]\displaystyle x = \frac{2a}{a+b}[/tex]
And is given by:
[tex]\displaystyle f_{\text{max}}(x) = \left(\frac{2a}{a+b}\right)^a\left(\frac{2b}{a+b}\right)^b[/tex]
The Office of Student Services at a large western state university maintains information on the study habits of its full-time students. Their studies indicate that the mean amount of time undergraduate students study per week is 20 hours. The hours studied follows the normal distribution with a population standard deviation of seven hours. Suppose we select a random sample of 125 current students. What is the probability that the mean of this sample is between 19.25 hours and 21.0 hours
There is a probability of 77% that the mean of this sample is between 19.25 hours and 21.0 hours
Z score is used to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:
[tex]z=\frac{x-\mu}{\sigma/\sqrt{n} } \\\\where\ x=raw\ score,\mu=mean,\sigma=standard\ deviation,n=sample\ size[/tex]
Given that μ = 20, σ = 7, n = 125.
For x = 19.25:
[tex]z=\frac{19.25-20}{7/\sqrt{125} } =-1.20\\\\\\For\ x=21:\\\\z=\frac{21-20}{7/\sqrt{125} } =0.62[/tex]
From the normal distribution table, P(-1.20 < z < 0.62) = P(z < 0.62) - P(z < -1.2) = 0.8849 - 0.1151 = 0.7698 = 77%
There is a probability of 77% that the mean of this sample is between 19.25 hours and 21.0 hours
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Every Thursday, Matt and Dave's Video Venture has “roll-the-dice" day. A customer may choose to roll two fair dice and rent a second movie for an
amount (in cents) equal to the numbers uppermost on the dice, with the larger number first. For example, if the customer rolls a two and a four, a
second movie may be rented for $0.42. If a two and two are rolled, a second movie may be rented for $0.22. Let X represent the amount paid for a
second movie on roll-the-dice day. The expected value of X is $0.47 and the standard deviation of X is $0.15.
If a customer rolls the dice and rents a second movie every Thursday for 30 consecutive weeks, what is the approximate probability that the total
amount paid for these second movies will exceed $15.00?
I saw other questions for this but why is the standard deviation 0.15*sqrt of 30 and not 0.15*30 because I thought this is a linear transformation
Using the normal distribution, it is found that there is a 0.1357 = 13.57% probability that the total amount paid for these second movies will exceed $15.00.
In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
It measures how many standard deviations the measure is from the mean. After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.For n instances of a normal variable, the mean is [tex]n\mu[/tex] and the standard error is [tex]s = \sigma\sqrt{n}[/tex]In this problem:
Mean of $0.47, standard deviation $0.15, hence [tex]\mu = 0.47, \sigma = 0.15[/tex]30 instances, hence [tex]n\mu = 30(0.47) = 14.1, s = 0.15\sqrt{30} = 0.8216[/tex]The probability is 1 subtracted by the p-value of Z when X = 15, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
Considering the n instances:
[tex]Z = \frac{X - n\mu}{s}[/tex]
[tex]Z = \frac{15 - 14.1}{0.8216}[/tex]
[tex]Z = 1.1[/tex]
[tex]Z = 1.1[/tex] has a p-value of 0.8643.
1 - 0.8643 = 0.1357.
0.1357 = 13.57% probability that the total amount paid for these second movies will exceed $15.00.
A similar problem is given at https://brainly.com/question/25769446
Need help fast worth 20 points
Select the correct answer.
Which set of absolute values is compared correctly
OA. 1-10] < |-5| < |17| < 151
OB. 1-5| > |-10| > |-12| > |17||
OC. |10| > |-15] > [-5| > 12||
OD. |-101 < [12] < |-15| < |17||
Answer:
i think its b.
Step-by-step explanation:
correct me if im wrong. and it was worth 10 points instead of 20.
Stuck on this, need help on this.
Answer:
Domain: (-∞ , ∞)
Range: y <= 8 [8 , -∞)
Step-by-step explanation:
x = 2
f(x) = 8
x<=2
f(x) <=8
At TGI Fridankay's you order a drink for $2.99, an appetizer for $9.99, the cajun chicken pasta for $11.50, and a dessert for $7.99. You had amazing service and know that you are going to tip your waiter 20%! The waiter also gave you a 10% coupon to use. There is also a 7% sales tax on the bill. What is your total bill after the tip, discount, and tax?
The total bill after the tip, discount, and tax is $37.76.
The total cost of the order is reduced by the coupon and increased by the tax paid and tip.
Total cost of the items bought = cost of the drink + appetizer + Cajun + dessert
$2.99 + $9.99 + $11.50 + $7.99 = $32.47
Value of the tip = 20% x $32.47 = $6.49
Cost of the items after the coupon: (100% - 10%) x $32.47
90% x $32.47
0.9 x $32.47 = $29.22
Cost of the items after the tax: (1.07) x $29.22 = $31.27
Total cost of the items = $31.27 +$6.49 = $37.76
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HELP! Due in 5 minutes
ANSWER:
the first one: 30x+48
The second one: x y^2(10 y + 15)
The third one: 30 x y - 5 x^2
Hope this helped!
sorry if im wrong. :)
GOOD LUCK!! <3
Approximately what portion of the box is shaded blue?
A.2/3. B.9/10
C.3/5
Write 0.511 as a fraction.
Answer:
511 / 1000
Step-by-step explanation:
0.511 = 511 / 1000
Answer:
511/1000Step-by-step explanation:
Steps to convert 0.511 into a fraction:
Write 0.511 as 0.511/1
For each digit following the decimal point, multiply both the numerator and denominator by ten:
0.511/1
= 0.511 * 1000/ 1 * 1000 = 511/1000As an aside, the entire number-integral section is: blank.
The decimal component is as follows: 0.511 = 511/1000
The following is the complete breakdown of simple fractions: 511/1000
Please help me prove that RST is congruent to RUT!
Answer:
See image
Step-by-step explanation:
On line 3, the reason is filled in that "All right angles are congruent" so kind of working backwards, the statement must say that two right angles are congruent. Use the angles in the previous two statements. Line 4 has the statement completely filled in, the reason is bc it is given in the list of given statements beside the diagram. Line 5 says that RT is congruent to itself. That is reflexive property, like a reflection in a mirror. Same ~= same.
You can see from the markings on the image that you have Angle-Side-Angle, which is one of several ways that we can show that triangles are congruent. ASA is what is shown in statements 1-5. See image.
What is the possible degree of a polynomial if it has a root of -3 with multiplicity of 2 and, a root of 4 with a multiplicity of 1?
Answer:
3rd degree
Step-by-step explanation:
factors are
a(x + 3)(x + 3)(x - 4)
polynomial is
a(x² + 6x + 9)(x - 4)
a(x³ + 2x² - 15x - 36)
where (a) could be any real number
Please help me in this 4th grader question, its a homework and i was sick over the weekend
Answer:
what is your question ask then I shall answer you
Can you identify a parallel or perpendicular equation and type the correct code? Please remember to type in ALL CAPS with no spaces.
The equation of the line that is parallel to [tex]2\cdot x + 5\cdot y = 10[/tex] is [tex]y = -\frac{2}{5} \cdot x + 3[/tex] and the equation of the line that is perpendicular to [tex]4\cdot x + 3\cdot y =12[/tex] is [tex]y =\frac{3}{4}\cdot x - 1[/tex].
Let be a line whose equation is:
[tex]a\cdot x + b\cdot y = c[/tex] (1)
Whose explicit form is:
[tex]y = -\frac{a}{b} \cdot x +\frac{c}{b}[/tex] (2)
Where:
[tex]x[/tex] - Independent variable.[tex]y[/tex] - Dependent variable.The slope and x-intercept of the line are [tex]-\frac{a}{b}[/tex] and [tex]\frac{c}{b}[/tex], respectively.
There are two facts:
A line is parallel to other line when the former has the same slope of the latter.A line is perpendicular to other line when the former has a slope described the following form ([tex]m_{\perp} = -\frac{1}{m}[/tex]), where [tex]m[/tex] is the slope of the former.Then, the equation of the line that is parallel to [tex]2\cdot x + 5\cdot y = 10[/tex] is [tex]y = -\frac{2}{5} \cdot x + 3[/tex] and the equation of the line that is perpendicular to [tex]4\cdot x + 3\cdot y =12[/tex] is [tex]y =\frac{3}{4}\cdot x - 1[/tex].
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The value of the digit 2 in 425.3 is *
Answer:
20 which is twenty
Step-by-step explanation:
searched it up on chrome
Can someone help me with both questions I will mark u brilliant
1. First, he will be climbing 10,000 feet from where he is right now. 10,000 / 1,000 = 10.
-3.6 x 10 = 36 degree decrease.
25 - 36 = -11
At 12,000 feet, the temperature will be -11.
2. First, we need to do 8.80 x 7 = 61.6
61.6 / 4 = 15.4
61.6 - 15.4 = 46.2
He has $26.20 left.
Hope this helps!
The teen club had a cupcake sale.
They sold 2/3 of their cupcakes in the morning. They sold 1/6 of their cupcakes in the afternoon. They sold 200 cupcakes altogether.
How many cupcakes were left to sell?
40. Let C be the total number of cupcakes. Then 2/3 x C + 1/6 x C = 200.
Combining , 5/6 x C = 200. So C = 240.
240–200= 40
A farmer has 220 bushels of apples to sell at roadside stand. She sells an average of 14 3/5 each day. Represent the total change in the number of bushels has for sale after 6 days.The total change in the number of bushels has for sale is ???, please answer as a fraction
Answer:
Step-by-step explanation:
He has sold (16+1/4) bushels/day x 5 days = (16 x 5) + (1/4 x 5) = 80 + 5/4 = 81 + 1/4 = 81.25
The change in the number of bushels is 140 - 81.25 = 58.75 or 58 and 3/4 bushels
In other words, he has 58.75 (or 18 and 3/4) bushels remaining and has sold 81.25 (or 81 and 1/4) bushels
Joe lost his part-time job, which reduced the net family income by 20%. His wife Janice decided to work overtime to compensate for the lost income. Other things being equal, by what percentage must her net salary increase in order to arrive at the same net family income as they had before Joe lost his job?
The percentage by which Janice's net salary must be increased in order to arrive at the same net family income as they had before Joe lost his job is 25%.
What are Percentages?A percentage is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25 which is equal to 25%.
To convert a fraction to a percentage, convert the fraction to decimal form and then multiply by 100 with the '%' symbol.
Let the salary of Joe be represented by x, while the salary of Janice is represented by y.
Since the sum of the salary of Joe and Janice is the net income of the family. Therefore, the net salary when Joe had a job will be,
x + y₁ = 100%
Now, it is known that Joe lost his job, which reduced the net family income by 20%. Therefore, the net salary now will be only 80% which will be equal to the salary of Janice. Thus, we can write,
y₁ = 80%
Further, Janice decided to work overtime to compensate for the lost income. Therefore, we can write,
y₂ = 100%
Furthermore, the percentage change in salary of Janice can be written as,
Percentage Change = [(100% - 80%)/80% ] × 100%
= 20/80 × 100%
= 25%
Hence, the percentage by which Janice's net salary must be increased in order to arrive at the same net family income as they had before Joe lost his job is 25%.
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Explain the step by step process of finding a function for a hyperbola given the center (1,4), vertices (-7,4) and (9,4), and a point on the hyperbola at (-11, -6). Make sure to include the location of the foci.
NO LINKS!!
Answer:
(x -1)²/64 -(y -4)²/80 = 1foci (-11, 4) and (13, 4)Step-by-step explanation:
The standard form of a hyperbola whose transverse axis is horizontal is ...
(x -h)²/a² -(y -k)²/b² = 1 . . . . center (h, k); transverse axis 2a; conjugate axis 2b
The distance between the two vertices is given as (9 -(-7)) = 16 = 2a, so the value of a is 8 and we have the partial equation ...
(x -1)²/8² -(y -4)²/b² = 1
Filling in the given point value gives us an equation for b².
(-11 -1)²/8² -(-6 -4)²/b² = 1
9/4 -100/b² = 1
5/4 = 100/b²
b² = 80
So, the equation is ...
(x -1)²/64 +(y -4)²/80 = 1
__
The distance between the foci is 2c, where c² = a² +b².
c² = 64 +80 = 144 = 12²
c = 12, so the foci are at ...
(x, y) = (1 ±12, 4) . . . . . . . 12 units either side of the center
The foci are (-11, 4) and (13, 4).
_____
Additional comment
The steps are ...
use the given information to fill in as much of the equation as you can.use any given points or additional information to find the unknown values in the equationdetermine any additional information asked for (foci, asymptotes, ...)The relevant relations are ...
2a = length of transverse axis (distance between vertices)
2b = length of conjugate axis (distance between co-vertices)
±b/a = slope of asymptotes, which are lines through the center
2c = distance between foci, where c² = a² +b²
The equation is (x -h)²/a² -(y -k)²/b² = 1 for a hyperbola that opens horizontally with center (h, k). Swapping variables x and y will give a hyperbola that opens vertically. If the figure opens vertically, the asymptotes will have slope ±a/b.
The distances from a point to the foci have a constant difference of 2a.
Solve for g. Make sure to use scrap paper to show your work.
( 144 + 6 x 8 ) ÷ 3 = g
192
64
48
NO NOT PUT THIS IN A FILE
Answer:
64
Step-by-step explanation:
P E D M A S
() ² ÷ × + -
6 x 8 = 48
114 + 48 = 192
(192) ÷ 3 = g
192 / 3 = 64
g = 64
y=1/4x−2y=−2x+3 help solve problem.
Answer:
(x, y) = (2 2/9, -1 4/9)
Step-by-step explanation:
Equate the values of y and solve for x.
1/4x -2 = -2x +3
(2 1/4)x = 5 . . . . . . . . add 2+2x to both sides
x = 20/9 = 2 2/9 . . . multiply by 4/9
y = -2(2 2/9) +3 = -4 4/9 +3 . . . . substitute for x in the second equation
y = -1 4/9
The solution is x = 2 2/9, y = -1 4/9.
Define
Rough calculating
Answer:
A rough calculation or guess is approximately correct, but not exact. roughly adverb.
Step-by-step explanation:
The diagonal of a rectangle big-screen TV screen measures 152cm. The length measures 132cm. What is the height if the screen?
Answer:
75.36cm
Step-by-step explanation:
We use the pithagorean theorem: height^2 = 152^2 - 132^2 = 5680;
height = [tex]\sqrt{5680} = 75..36 cm[/tex]
A recipe calls for 3/4 of a cup of flour to make 5/8 of a pound of bread
dough. How many cups of flour are needed to make 1 pound of dough?
Show your work and write your answer in simplest form.
Answer:
[tex]\huge\boxed{\sf 1 \ pound \ of \ dough = 1\frac{1}{5} \ cup \ of \ flour}[/tex]
Step-by-step explanation:
[tex]\displaystyle \underline{Given \ that:}\\\\\frac{5}{8} \ pound \ of \ dough = \frac{3}{4} \ cup\ of \ flour\\\\Multiply \ 8 \ to \ both \ sides\\\\5 \ pounds \ of \ dough = \frac{3}{4} \times 8 \ cup \ of \ flour\\\\5 \ pounds \ of \ dough = 3 \times 2 \ cup \ of \ flour\\\\5 \ pounds \ of \ dough = 6 \ cups \ of \ flour\\\\Divide \ both \ sides \ by \ 5\\\\1 \ pound \ of \ dough = \frac{6}{5} \ cup \ of \ flour\\\\\boxed{1 \ pound \ of \ dough = 1\frac{1}{5} \ cup \ of \ flour}\\\\[/tex]
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807An angle measures 136°. What is the measure of its supplement?
Answer:
44⁰.
Step-by-step explanation:
Its supplement = 180 - 136
= 44 degrees.
Write the equation to the line parallel to y= 3x – 5 that goes through the point (-2, -7) using any form.
Thank you!
Answer:
y = 3x - 1
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = 3x - 5 ← is in slope- intercept form
with slope m = 3
Parallel lines have equal slopes , then
y = 3x + c ← is the partial equation
To find c substitute (- 2, - 7 ) into the partial equation
- 7 = - 6 + c ⇒ c = - 7 + 6 = - 1
y = 3x - 1 ← equation of parallel line
What is the equation of the line: * parallel to the line y = -¼x + 5 and * passing through the point (2, -1)
y = -¼x - 1/2
y = ¼x + 2
y = -¼x + 4
y = ¼x - 1
Answer:
last one
Step-by-step explanation:
Charles wants to buy an anime book that is on sale for $14.99. Her sister kyra wants to buy a novel book for $17.99. Both of them has to pay a 7% tax. Kyra has a coupon for 15% discount. Whats the difference between the amount that each siblings has to pay?
Answer:
The difference between their total amounts is .34 cents
also it didnt look like i was supposed to count a discount for charles so i didnt :)
Step-by-step explanation:
Charles14.99 times .07 = 1.04
14.99 + 1.04 = 16.03
Kyra17.99 times .15 = 2.69
17.99 -2.69 = 15.30
15.30 times .7 = 1.07
15.30 + 1.07 = 16.37
16.37 - 16.03 = .34
3] What is - 2y + 10 + 2y - 8 simplified?
a) – 4y + 18
C) 18
b) 4y + 2
d) 2
Expressions
Answer:
d. 2
Step-by-step explanation:
-2y +10+2y-8
10-8. ( -2y+2y = 0)
2
Answer:
d) 2
Step-by-step explanation:
We can first combine like terms
-2y + 2y = 0
Now, our expression is simply 10 - 8, which is 2
So, the answer is
d) 2
can't believe that you got me in a suit and tie I had to take a pull so I wouldn't cry
You got a line out the church door sayin' goodbye
Yeah, I believe 'em when they say you're in a better place
NAME THE SONG AND THE SINGER 50 POINTS!!!!!
Answer:
give heaven some hell by Hardy
Step-by-step explanation:
How is the series 9 + 13+ 17+ ... + 149 represented in summation notation?
Notice that
13 - 9 = 4
17 - 13 = 4
so it's likely that each pair of consecutive terms in the sum differ by 4. This means the last term, 149, is equal to 9 plus some multiple of 4 :
149 = 9 + 4k
140 = 4k
k = 140/4
k = 35
This tells you there are 35 + 1 = 36 terms in the sum (since the first term is 9 plus 0 times 4, and the last term is 9 plus 35 times 4). Among the given options, only the first choice contains the same amount of terms.
Put another way, we have
[tex]\displaystyle 9 + 13 + 17 + \cdots + 149 = \sum_{k=0}^{35} (9 + 4k)[/tex]
but if we make the sum start at k = 1, we need to replace every instance of k with k - 1, and accordingly adjust the upper limit in the sum.
[tex]\displaystyle 9 + 13 + 17 + \cdots + 149 = \sum_{k-1=0}^{35+1} (9 + 4(k-1))[/tex]
[tex]\displaystyle 9 + 13 + 17 + \cdots + 149 = \sum_{k=1}^{36} (5 + 4k)[/tex]
