I throw a thin uniform circular disc (think of a frisbee) into the air so that it spins with angular velocity ω about an axis which makes an angle α with the axis of the disc. Show that the magnitude of ω is constant.

Answer:

v = 108 m/s.

Explanation:

Given that,

The position of a particle moving on a straight line is given by :

[tex]X =12 + 18t + 9t^2[/tex]

We need to find the instantaneous velocity at  t=5s.

Velocity, [tex]v=\dfrac{dX}{dt}[/tex]

So,

[tex]v=\dfrac{d(12 + 18t + 9t^2)}{dt}\\\\=18+18t[/tex]

Instantaneous velocity at t = 5 s will be :

v = 18+18t

v = 18+18(5)

= 18 + 90

= 108 m/s

So, the instantaneous veloctiy at  t=5s is 108 m/s.

Answer:

8 m/s

Explanation:

KE Formula: KE = 1/2mv^2

Kinetic Energy is equal to energy, J.

6400 = 1/2 * 200 * V^2

1/2 * 200 = 100

6400 = 100 * V^2

6400/100 =  V^2

64 = V^2

Square root both sides

Speed is  8 m/s

Answer:

The increase in the internal energy is  1.840 x 10⁶ J.

Explanation:

Given;

mass of the water, m = 1000 g = 1 kg

temperature of the boiling water, t = 212 ° F  = 100 ° C

latent heat of vaporization, L = 2.260 MJ/kg = 2.260 x 10⁶ J/kg

The internal energy of the boiling water is calculated as;

Q₁ = mcΔθ

where;

c is specific heat capacity of water, = 4200 J/kg.⁰C

Δθ is change in temperature = 100 ° C

Q₁ = 1 x 4200 x 100

Q₁ = 420,000 J

The internal energy of the vaporized steam is calculated as;

Q₂ = mL

Q₂ = 1 x 2.260 x 10⁶

Q₂ = 2,260,000 J

The increase in the internal energy is calculated as;

ΔQ = Q₂ - Q₁

ΔQ = 2,260,000 J - 420,000 J

ΔQ = 1,840,000 J

ΔQ = 1.840 x 10⁶ J

Therefore, the increase in the internal energy is  1.840 x 10⁶ J.

Answer:

id say D

Explanation:

because its the only answer that has to do with colors and visable light

but A and B also have to do with eachother so i feel like it could be with one of those but it def isnt C

I am sorry if i am wrong, let me know tho!

Answer:

A.

Explanation:

Answer:

1.52m/s

Explanation:

Using the law of conservation of momentum

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the masses

u1 and u2 are the initial velocities

v is the final velocity

Substitute the given values into the formula

0.013(270)+2(130) = (270+130)v

3.51+260 = 400v

263.51 = 400v

v = 400/263.51

v = 1.52m/s

Hence the velocity after the bullet emerges is 1.52m/s

Answer:

7 m/s approx

Explanation:

Step one:

Given data

Mass m= 42kg

distance covered= 100m

time taken = 14.2 seconds

Required

The speed of the athlete

Step two:

We know that speed= distance/time

Substitute

Speed= 100/14.2

Speed= 7.04 m/s

Speed= 7 m/s approx

Answer:

B

Explanation:

The ray diagram demonstrated the phenomenon of absorption in B. Hence, option B is correct.

Absorption is the phenomenon of electromagnetic radiation taking up the energy of photons and it also transfers the electromagnetic energy to the internal energy of the absorber.  

Absorption refers to the transfer of the energy of a wave to matter as the wave passes through it. The process in which the light waves get converted into energy. Absorption causes attenuation of the waves and the intensity decreases gradually when the light waves propagate through the medium.

From the given, the first diagram represents the light passes through the slit, it gets diffracted and forms alternate bright and dark fringes in the screen. The third diagram represents that the light ray strikes the surface it gets reflected and the path of light gets changed.

Thus, the absorption is the ray diagram given in the second image. Hence, option B is correct.

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Answer:

vt3bryhtevy4g24vu5hy4

Answer:

the point about which an unconstrained rotation occurs

the mass-weighted center of the object

Explanation:

The center of mass of an object can be described to be a a position that is defined relative to the object

The center of mass is the average position of every parts of the object. At this point we can assume that all of the mass of this object is concentrated

When weighted according to their masses, the center of mass is the average position of all the parts of the object. While other points in this object are rotating around it, the center of mass would not rotate (fixed).

So the correct options are:

1. the point about which an unconstrained rotation occurs

2. the mass-weighted center of the object

Answer: The correct option is

the point about which an unconstrained rotation occurs

Explanation:

The CENTER OF MASS is the average position of the different parts of the the object system which are weighted base on their masses

When it comes to phase shifts or phase change the greater the intermolecular interactions are the closer the molecules are to one another.

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Answer:

Power = 2.5 [W]

Explanation:

To be able to solve this problem we must remember that power is defined as the relationship of the work done in a given time interval.

[tex]P=W/t[/tex]

where:

P = power [W] (units of watts)

W = work = 50 [J]

t = time = 20 [s]

Now replacing:

[tex]P=50/20\\P=2.5[W][/tex]

Answer:

2.5

Explanation:

Answer:

The force exerted by each string is 25 N

Explanation:

Net Force

The net force is the vector sum of forces acting on a body. The net force is a single force that represents the effect of the original forces on the body's motion. It gives the particle the same acceleration as all those actual forces together as described by Newton's second law of motion.

The picture described in the problem is hanging at rest supported by two vertical strings. This means that the net force acting on it is zero.

Assume the magnitude of each of these equal forces is F, and the picture has a weight of W=50 N, thus the net force is:

F + F - W

The positive signs indicate an upwards direction and the negative sign means a downwards direction. Since the net force is zero:

F + F - W = 0

2F = W

F = W/2 = 50 N/2

F = 25 N

The force exerted by each string is 25 N

Answer:

a)[tex]t=59.817652833125294s \approx 59.8s[/tex]

b)[tex]D_1=894.01m[/tex]

Explanation:

From the question we are told that

Speed of opposing player [tex]V_2=4.0m/s[/tex]

First player chase his opponent after[tex]t=2.80t[/tex]

Acceleration of  first player [tex]a=0.14 m/s2[/tex]

Let time of catch be  [tex]t_c[/tex]

a)Generally the Equation for distance covered is mathematically given as follows

Distance to catch First opponent

[tex]D_1=\frac{1}{2}(0.14)t^2[/tex]

[tex]D_1=0.07t^2[/tex]

Distance to covered Second opponent

[tex]D_2=(2.8+t)*4[/tex]

Generally when first opponent catch the second opponent it is represented mathematically as

[tex]D_2=D_1[/tex]

[tex]0.07t^2=(2.8+t)*4[/tex]

[tex]0.07t^2=11.2+4t[/tex]

[tex]0.07t^2-4t-11.2[/tex]

[tex]t=59.817652833125294s \approx 59.8s[/tex]

b)Generally the the total time traveled by the first opponent is mathematically given as

[tex]D_1=\frac{t^2}{4}[/tex]

[tex]D_1=\frac{59.8^2}{4}[/tex]

[tex]D_1=894.01m[/tex]

Answer:

C

Explanation:

You stand on the bathroom scale and then decide to jump off and observe the

change in the reading.

Answer:

b

Explanation:

Answer:

2.72*10-3 Joules

Explanation:

From Newton's second law of motion

F=ma

[tex]\tau=I*\alpha[/tex]

given

[tex]\tau= 0.11Nm\\\\I=0.034kgm^2\\\\t= 8s\\\\\alpha=?[/tex]

[tex]\alpha =0.11/0.034\\\\\alpha=3.23 rad/s^2[/tex]

the angular velocity is

[tex]\omega = \alpha/t\\\\\omega =3.23/8\\\\\omega =0.4 rad/s[/tex]

[tex]KE= 1/2*I* \omega^2[/tex]

[tex]KE=1/2*0.034*0.4^2\\\\KE=1/2*0.034*0.16\\\\KE=0.00272\\\\KE=2.72*10^-3J[/tex]

Answer:

a) F=ma

F=13.2×10

F=132

b) I=P/V

I=75/15

I=5

Explanation:

Remember Newton's Second law

[tex]F = ma[/tex]

We can use this to solve for the force exerted by the tree on the car when it stops the car.

We aren't given the acceleration directly in the problem statement, but we can solve for acceleration.

Recall that acceleration is the change is velocity per unit time. [tex]a = \frac{\Delta v}{\Delta t}[/tex]

We know the original velocity as 21.1 m/s and the final velocity as 0.0 m/s. The time that it takes to stop the car is 0.22 seconds.

Now we can solve using the equation. [tex]F = \frac{21.1 - 0.0}{0.22} * 365[/tex]

A freely falling mass m will be pulled down toward the ground with downward acceleration +g while feeling upward drag D due to air resistance with acceleration -a such that D = - m a = - k v ². Hence the body's velocity v(t) changes with respect to time t according to the differential equation,

dv(t)/dt = m g - k v ²

Answer:(B)

Explanation:

No; the inertial mass of Earth is so large that the planet’s change in motion is imperceptible, therefore the correct answer is option A.

According to Newton's first law, until pushed to alter its condition by the intervention of an external force, every object will continue to be at rest or in uniform motion along a single direction.

As given in the problem suppose the entire population of the world gathers in one spot and, at the sound of a prearranged signal, everyone jumps up. While all the people are in the air, we have to find out if Earth gains momentum in the opposite direction,

The mass of the earth is very huge approximately 5.97 ×10²⁴ kilogram.

Even the combined mass of all the population combined would be negligible as compared to the mass of the earth.

Thus, the earth would not gain momentum in the opposite direction.

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Answer: wqcjn qefveqeqfbj qeib

Explanation:oiaer vgneiofrvn eiforbnewtjbioe

Answer:

the atmosphere would still be in motion with the Earth's original 1100 mile per hour rotation speed at the equator. ... This means rocks, topsoil, trees, buildings, your pet dog, and so on, would be swept away into the atmosphere.

Explanation:

to me, this means we would proabaly be sucked into outer space and could die if no astronaut gear is on

Answer:

765.625 m

Explanation:

When brakes are applied , work is done by frictional force to reduce the kinetic energy of the car . To stop the car , the work done by brake must equalize the kinetic energy of car .

1/2 m v² = F d

m is mass of the car , v its velocity , F is frictional force and d is displacement of car .

1/2 x 1000 x 35² = 800 x d

d = 765.625 m

Answer:

A. Weight

Explanation:

On Earth a gallon of milk has the same mass as a gallon of milk in space, but it has a different weight

Answer:

[tex]F=3.665 \times 10^{-7} N[/tex] acting along the line joining both the sphere and always attractive in nature.

Explanation:

The given radius of both the sphere, r= 65 mm = 0.065 m

So, the volume of the spheres, [tex]v= \frac 4 3 \pi r^3[/tex]

[tex]v= \frac 4 3 \pi (0.065)^3 = 1.150 \times 10^{-3} m^3[/tex]

The density of steel, [tex]\rho _s = 7850 kg/m^3[/tex]

and the density of copper, [tex]\rho_c= 8940 kg/m^3[/tex]

Let M be the mass of the copper ball and m  is the mass of the steel ball.

So, [tex]M=\rho_c v= 8940\times 1.150 \times 10^{-3} = 10.281[/tex] kg

[tex]m=\rho_s v= 7850\times 1.150 \times 10^{-3} = 9.0275[/tex] kg

The gravitational force, F, between the two objects having masses M and m and separated by distance d is

[tex]F=\frac{GMm}{d^2}[/tex]

Where [tex]G= 6.674 30 x 10^{-11} m^3 kg^{-1} s^{-2}[/tex] is the universal gravitational constant.

When both the sphere touches each other, d = 2r= 2 x 0.065 = 0.13 m

Hence, the gravitational force between both the sphere,

[tex]F= \frac {6.674 30 x 10^{-11}\times 10.281 \times 9.0275}{0.13^2} \\\\F=3.665 \times 10^{-7} N[/tex]

The nature of gravitational force is always attractive and acting along the line joining the center of both the sphere.

Answer:

The silicon used to make monocrystalline solar cells has a high level of purity. ... Because of the way light interacts with a monocrystalline silicon layer, monocrystalline solar panels appear black in color.