I really need help with this Helpppp please

Answer:

-33

Step-by-step explanation:

The sequence is descending so the nth term would be -10n and the 0 term would be 27 so the nth term for the sequence would be -10n +27.

The question asks you to find the 6th term so (-10 x 6) + 27 = -60 + 27 = -33

Answer:

D

Step-by-step explanation:

Whatever angle you pick the three possibilities must add to 180.

a) adds to 150

b) 32 + 59 + 79  =  170. Close but not close enough

c) c has three 5s. The total will end in 5. Not the answer.

d) d does add to 180. It's the answer.

Which set of measures could be the measures of the interior angles of a triangle?

a.30°, 90°, 30°

b.32°, 59°, 79°

c.35°, 65°, 75°

d.22°, 37°, 121°

In this question we are asked to find out which one could be the measures of the interior angles of a triangle. Add the three measure angles given if you get 180° then those angles can be the interior angles of a triangle.

We know that,

[tex] \bull \: \small\boxed{ \rm{ Sum \: of \: all \: interior \: angles \: of \: a \: triangle = 180°}}[/tex]

a) 30°, 90°, 30°

→ 30° + 90° + 30° = 180°

→ 150° ≠ 180°

Option a) is not the correct answer.

b) 32° , 59° , 79°

→ 32° + 59° + 79° = 180°

→ 170° ≠ 180°

Option b) is not the correct answer.

c) 35° , 65° , 75°

→ 35° + 65° + 75° = 180°

→ 175° ≠ 180°

Option c) is not the correct answer.

d) 22° , 37° , 121°

→ 22° + 37° + 121° = 180°

→ 180° = 180°

Hence, opition d) is the correct answer

Answer:  Around 10 days.  The real answer is 10 2/3.

Answer:

10 and 2-third days.

Convert mixed number to improper fraction

Initial equation

[tex]\frac{176}{9} / \frac{11}{6}[/tex]

Next, multiply the numerators by the numerators, and do the same for the denominators. Flip the second number to 6/11

[tex]\frac{176 * 6}{9 * 11}[/tex]

[tex]= \frac{1056}{99}[/tex]

Simplify.

[tex]\frac{1056}{99} -- > 10\frac{2}{3}[/tex]

Explanation:

Perimeter of the base = 8+10+15+7+23+17 = 80 meters

The 23 is from 8+15 = 23 and it is the length along the back wall, while the 10+7 = 17 is the length along the left side wall. Both the sides of 23 and 17 are hidden from view. The height of 5 meters is not part of the perimeter of the base.

Multiply the perimeter of the base by the height of the building to find the lateral area, aka wall area.

80*5 = 400 square meters

Answer:

√10z^3(z - 1)(z + 1).

Step-by-step explanation:

The GCF is √10z* z^2

= √10z^3

So factoring we get

√10z^3(z^2 - 1)           The expression in brackets is difference of 2 squares so:

= √10z^3(z - 1)(z + 1)

Answer: 2/sqrt6

Step-by-step explanation:

tan theta=perpendicular/base so

cot theta =base /perependicular=sqrt2/2

while sin theta=perpendicular/hypotenous=2/x

here x is unkown to find it we will use pythagoras theorem

(hypoteneous)^2=(Base)^2+(perependicular)^2

                            =(sqrt 2)^2+(2)^2

                            =2+4

  (hypoteneous)^2=6

  hypotenous   =sqrt6

so

sin theta=2/sqrt6

Since f(x) is a cubic polynomial, it has at most 3 distinct roots. If f(x) has 3 real roots, then f(x) = 0 for more than one instance of x.

But if f(x) is one-to-one, then there must be only one real root and the other two are non-real. Let a + bi and a - bi be these non-real roots and c the single real root; then we can factorize f(x) as

[tex]f(x) = x^3 - kx^2 + 12x + 7 = (x - (a + bi)) (x - (a - bi)) (x - c)[/tex]

Expand the right side to get

[tex]f(x) = x^3 - kx^2 + 12x + 7 = (x^2 - 2ax + a^2+b^2) (x - c)[/tex]

[tex]f(x) = x^3 - kx^2 + 12x + 7 = x^3 - (2a + c) x^2 + (a^2 + 2ac + b^2) x - (a^2c + b^2c)[/tex]

from which it follows that

[tex]\begin{cases}k = 2a + c \\ 12 = a^2+2ac+b^2 \\ 7 = -a^2c-b^2c\end{cases}[/tex]

Since f(x) has only one root, its graph will have no turning points/extrema. If f(x) has a critical point, it must be a saddle point. Differentiating f(x) yields

[tex]f'(x) = 3x^2 - 2kx + 12[/tex]

Solve for the critical point:

[tex]f'(x) = 3x^2 - 2kx + 12 = 0[/tex]

[tex]x^2 - \dfrac{2k}3 x = -4[/tex]

[tex]x^2 - \dfrac{2k}3 x + \dfrac{k^2}9 = \dfrac{k^2}9-4[/tex]

[tex]\left(x - \dfrac k3\right)^2 = \dfrac{k^2}9-4[/tex]

[tex]x = \dfrac k3 \pm \sqrt{\dfrac{k^2}9-4}[/tex]

There is at most one real critical point, so either the square root term vanishes or it produces a non-real number. This happens for

[tex]\dfrac{k^2}9 - 4 \le 0 \implies k^2 \le 36 \implies -6 \le k \le 6[/tex]

So, if f(x) is one-to-one, then

[tex]k \in \left\{\kappa \in \Bbb R \mid -6 \le \kappa \le 6\right\}[/tex]

Answer:

594

Step-by-step explanation:

A=πrl+πr²

(22/7×9×12)+(22/7×9²)

=594

Answer:

4387.63

Step-by-step explanation:

Answer:

A. 44 (if unanswered questions do not deduct 1 point)

B. 40

Step-by-step explanation:

22 x 2 = 44

25 x 2 - 10 = 40

The function that has the same minimum value as fx= 3x³ is f(x) = x + 3.

It should be noted that a function simply means a relation or expression that involves two or more variables.

In this case, the function that has the same minimum value as the expression of 3x³ is f = x + 3.

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Answer:b

Step-by-step explanation:

Answer:

30

Step-by-step explanation:

Answer:

To get f⁻¹(x), write f(x) = y = x^(1/3)/3, exchange x and y, so x = y^(1/3)/3, then y = (3x)³, this is just the f⁻¹(x) = (3x)³.

Step-by-step explanation:

Answer:

Your answers are below ↓

Step-by-step explanation:

Given ↓

A) 2x-3y = 5 and 3x+4y = 6  ( The method this has to be solved in is the elimination method. )

Now using these,

(1)×3 - (2)×2 = 6x + 9y - 6x - 8y = 15 - 12

therefore,

y = 3

putting the value of y in eqn. (1)

2x + 6 = 5

therefore,

x = -1/2

B)  y=x^2 - 2x and y = 2x -3  ( The method this has to be solved in is the substitution method. )

Reduce the greatest common factor on both sides of the equation:
[tex]\left \{ {{4x-y=9} \atop {xy=-2}} \right.[/tex]

Rearrange like terms to the same side of the equation:

[tex]\left \{ {{-y=9-4x} \atop {xy=-2}} \right.[/tex]

Divide both sides of the equation by the coefficient of the variable:

[tex]\left \{ {{y=-9+4x} \atop {xy=-2}} \right.[/tex]

Substitute the unknown quantity into the elimination:

[tex]x(-9+4x)=-2[/tex]

Apply Multiplication Distribution Law:

[tex]-9x+4x^2=-2[/tex]

Reorder the equation:

[tex]4x^2-9x=-2[/tex]

Divide the equation by the coefficient of the quadratic term:

[tex]\frac{1}{4}(4x^2)+\frac{1}{4}(-9x)=\frac{1}{4}*(-2)\\[/tex]

Calculate:

[tex]x^2-\frac{9x}{4}=-\frac{1}{2}[/tex]

Add one term in order to complete the square:

[tex]x^2-\frac{9x}{4}+(\frac{9}{4}*\frac{1}{2})^2=-\frac{1}{2}+(\frac{9}{4}*\frac{1}{2})^2[/tex]

Calculate:

[tex]x^2-\frac{9x}{4}+(\frac{9}{8} )^2=-\frac{1}{2} +(\frac{9}{8} )^2[/tex]

Factor the expression using [tex]a^2$\pm$2ab+b^2=(a$\pm$b)^2[/tex]:

[tex](x-\frac{9}{8} )^2=-\frac{1}{2} +(\frac{9}{8} )^2[/tex]

Simplify using exponent rule with the same exponent rule: [tex](ab)^n=a^n*b^n[/tex]

[tex](x-\frac{9}{8} )^2=-\frac{1}{2} +\frac{9^2}{8^2}[/tex]

Calculate the power:

[tex](x-\frac{9}{8} )^2=-\frac{1}{2}+\frac{81}{64}[/tex]

Find common denominator and write the numerators above the denominator:

[tex](x-\frac{9}{8} )^2=\frac{-32+81}{64}[/tex]

Calculate the first two terms:

[tex](x-\frac{9}{8} )^2=\frac{49}{64}[/tex]

Rewrite as a system of equations:

[tex]x-\frac{9}{8} =\sqrt{\frac{49}{64} }[/tex] or [tex]x-\frac{9}{8} =-\sqrt{\frac{49}{64} }[/tex]

Rearrange unknown terms to the left side of the equation:

[tex]x=\sqrt{\frac{49}{64} } +\frac{9}{8}[/tex]

Rewrite the expression using [tex]\sqrt[n]{ab} =\sqrt[n]{a} *\sqrt[n]{b}[/tex]:

[tex]x=\frac{\sqrt{49} }{\sqrt{64} } +\frac{9}{8}[/tex]

Factor and rewrite the radicand in exponential form:

[tex]x=\frac{\sqrt{7^2} }{\sqrt{8^2} } +\frac{9}{8}[/tex]

Simplify the radical expression:

[tex]x=\frac{7}{8} +\frac{9}{8}[/tex]

Write the numerators over the common denominator:

[tex]x=\frac{7+9}{8}[/tex]

Calculate the first two terms:
[tex]x=\frac{16}{8}[/tex]

Reduce fraction to the lowest term by canceling the greatest common factor:

[tex]x=2[/tex]

Rearrange unknown terms to the left side of the equation:

[tex]x=-\sqrt{\frac{49}{64} } +\frac{9}{8}[/tex]

Rewrite the expression using [tex]\sqrt[n]{a} =\sqrt[n]{a} *\sqrt[n]{b}[/tex]:

[tex]x=-\frac{\sqrt{49} }{\sqrt{64} }+\frac{9}{8}[/tex]

Factor and rewrite the radicand in exponential form:
[tex]x=-\frac{\sqrt{7^2} }{\sqrt{8^2} } +\frac{9}{8}[/tex]

Simplify the radical expression:

[tex]x=-\frac{7}{8} +\frac{9}{8}[/tex]

Write the numerators over common denominator:

[tex]x=\frac{-7+9}{8}[/tex]

Calculate the first two terms:

[tex]x=\frac{2}{8}[/tex]

Reduce fraction to the lowest term by canceling the greatest common factor:

[tex]x=\frac{1}{4}[/tex]

Find the union of solutions:

[tex]x=2[/tex] or [tex]x=\frac{1}{4}[/tex]

Substitute the unknown quantity into the elimination:

[tex]y=-9+4*2[/tex]

Calculate the first two terms:

[tex]y=-9+8[/tex]

Calculate the first two terms:

[tex]y=-1[/tex]

Substitute the unknown quantity into the elimination:

[tex]y=-9+4*\frac{1}{4 }[/tex]

Reduce the expression to the lowest term:

[tex]y=-9+1[/tex]

Calculate the first two terms:

[tex]y=-8[/tex]

Write the solution set of equations:
[tex]\left \{ {{x=2} \atop {y=-1}} \right.[/tex] or [tex]\left \{ {{x=\frac{1}{4} } \atop {y=-8}} \right.[/tex]   -------> Answer

C)   y=x^2 - 2x and y = 2x -3 ( This method this has to be solved in is the substitution method. )

Step 1: We start off by Isolating y in y = 2x - 3

y=2x-3 ----------> ( Simplify )

y+(-y)=2x-3+(-y)   ---- > ( Add (-y)on both sides)

0=-3+2x-y

y/1 = 2x-3/1 --------> (Divide through by 1)

y = 2x - 3

We substitute the resulting values of y = 2x - 3 and y = x^2 - 2x

(2 * x - 3) = x^2 - 2x ⇒ 2x -3 = x^2 - 2x ---->   ↓

                                               (Substituting 2x - 3 for y in y = x^2 -2x )

Next: Solve (2x - 3 = x^2 - 2x) for x using the quadratic formular method

2x - 3 = x^2 - 2x

x = -b±b^2-4ac/2a  Step 1: We use the quadratic formula with  ↓

                                                                                         a = -1,b=4,c= - 3

x = -4±(4)^2-4(-1)(-3)/2(-1) Step 2: Substitute the values into the Quadratic  Formular

x = -4± 4/ - 2         x = 1 or x = 3        Step 3: Simplify the Expression & Separate Roots

x = 1 or x = 3  ------- ANSWER

Substitute 1 in for x in y = 2x - 3 then solve for y

y = 2x - 3

y = 2 · (1)  - 3 (Substituting)

y = -1 (Simplify)

Substitute 3 for in y = 2x - 3 then solve for y

y = 2x - 3

y = 2 · (3) - 3 (Substituting)

y =  3   (Simplify)

Therefore, the final solutions for y = x^2 -2x; y = 2x - 3 are

x₁ = 1, y₁ = -1

x₂ = 3, y₂ = 3              

Answer:

[tex]\huge{\purple {r= 2\times\sqrt[3]3}}[/tex]

[tex]\huge 2\times \sqrt [3]3 = 2.88[/tex]

Step-by-step explanation:

Answer:

x = 8

Step-by-step explanation:

The sides are in proportion.

Answer:

621 i guess

Step-by-step explanation:

18x² + 2x² - 7

Tap on a clip to paste it in the text box.

Answer:

1st blank: $51.00.    3rd blank: 1.1   5th blank: 24.2

2nd blank: $67.00.  4th blank: 91.30.  6th blank: -57.4

Step-by-step explanation:

Answer:

3/20

Step-by-step explanation:

1.  Multiply the numerators

2. Multiply the denominators

3. Your answer, in this case, will be 6/40

4. Simplify fraction to its simplest form* which gives you 3/20

*I halved both numbers as they are both even

Hope this helped :)

Answer:

There are many ways to describe a data set using a single measure. Some common ways are to find the mean, median, or mode of the data set.

Step-by-step explanation:

A single measure can be used to describe a data set in the form of a statistic. This statistic can be used to measure the central tendency, dispersion, or shape of the data set. For example, the mean can be used to describe the central tendency of a data set, while the standard deviation can be used to describe the dispersion of a data set.

Answer:

86486400

Step-by-step explanation:

Answer:

10% failed the driving test

Step-by-step explanation:

27/30 = 90% and since 90% is what PASSED, 10% is what FAILED

this should be correct... if its not im sorry

Answer:

10% failed

27 / 30 is 90% so, 100% - 90% = 10%

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Answer:

20 square units

Step-by-step explanation:

Area of a parallelogram is calculated with the following formula:

b*h (b: base, h: height)

5*4 = 20 square units

The Gradient of the line PQ is -5/2.

Gradient the basically the ratio between the change in vertical coordinate to change in horizontal coordinates.

Here, P (2, 7) and Q (6, -3)

Now, Gradient = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

           m = [tex]\frac{-3 -7}{6 - 2}[/tex]

           m = -10/4

         m = -5/2

Thus, the Gradient of the line PQ is -5/2.

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Answer:

D (8, 11, 13, 13,17,20,23)

Step-by-step explanation:

I did this and got it correct.