Which of the following are properties of substances with matter? (2 points)
a
Mass and volume
b
Length and width
c
Shape and color
d
Size and texture
What do you notice about the relationship between the force strength and the size of the velocity change? HELP MEEEEE
Velocity change increases as the force increases.
Even though this question is incomplete, but we can approach it from the stand point of Newton's second law of motion.
According to this law, force is directly proportional to change in velocity.
F = m(v - u)/t
F = force applied
m = mass of the body
v = final velocity of the body
u = initial velocity of the body
t = time taken
This means that velocity change increases as force increases.
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(b) in the direct hydration method, ethene reacts with steam. The equation for this reaction is C2H4 + H2O = C2H5OH
State the temperature and pressure used in this reaction.
Answer:
20 degree and 4000000N
7. Baking soda is a common household chemical compound. The chemical formula
NaHCO3 represents the matter needed to produce baking soda. Baking soda is
considered a compound because. WILL GIVE BRAINLIST
What is the organism that kills and eats other organisms for food called?
Group of answer choices
Host
Parasite
Predator
Prey
Which of the following terms best reflects the process by which humans store memories ?
Answer:
there are no term
Explanation:
what are the term
In a chemistry laboratory, a student filled a 10.0 L container with two (2) different gases. The
gases are nitrogen gas taken from 24.0 L container at 2.00 atm and 12.0 L container of
oxygen at 2.00 atm. If the temperature of the gases is 273 K, calculate the partial pressure
of both gases in the resulting mixture and the total pressure.
Answer:
[tex]P_N=1.33atm\\\\P_O=0.67atm[/tex]
[tex]P_T=2.00 atm[/tex]
Explanation:
Hello.
In this case, the first step is to compute the moles of nitrogen and oxygen given their initial P, T and V conditions via the ideal gas equation:
[tex]n_{N}=\frac{P_{N}V_{N}}{RT} =\frac{2.00atm*24.0L}{0.082\frac{atm*L}{mol*K}*273K}\\ \\n_{N}=2.144molN\\\\n_{O}=\frac{P_{O}V_{O}}{RT} =\frac{2.00atm*12.0L}{0.082\frac{atm*L}{mol*K}*273K}\\ \\n_{O}=1.072molO[/tex]
After that, since the total volume now, once the mixture is formed is the addition between the initial volumes (12.0 L + 24.0 L) is 36.0 L, the partial pressure of each gas turns out:
[tex]P_N=\frac{2.144mol*0.082\frac{atm*L}{mol*K}*273K}{36.0L}\\\\P_N=1.33atm\\\\P_O=\frac{1.072mol*0.082\frac{atm*L}{mol*K}*273K}{36.0L}\\\\P_O=0.67atm[/tex]
Thus, the final total pressure is:
[tex]P_T= P_N+P_O=1.33atm+0.67atm\\\\P_T=2.00 atm[/tex]
Best regards.
(a) At what substrate concentration would an enzyme with a kcat of 30.0 s−1 and a Km of 0.0050 M operate at one-quarter of its maximum rate? (b) Determine the fraction of Vmax that would be obtained at the following substrate concentrations [S]: ½Km, 2Km, and 10Km. (c) An enzyme that catalyzes the reaction X ⇌ Y is isolated from two bacterial species. The enzymes have the same Vmax but different Km values for the substrate X. Enzyme A has a Km of 2.0 μM, and enzyme B has a Km of 0.5 μM. The plot below shows the kinetics of reactions carried out with the same concentration of each enzyme and with [X] = 1 μM. Which curve corresponds to which enzyme?
The missing graph is in the attachment.
Answer: (a) [S] = 0.0016M
(b) Vmax = 3V; Vmax = [tex]\frac{3V}{2}[/tex]; Vmax = [tex]\frac{11V}{10}[/tex]
(c) Enzyme A: black graph; Enzyme B = red graph
Explanation: Enzyme is a protein-based molecule that speed up the rate of a reaction. Enzyme Kinetics studies the reaction rates of it.
The relationship between substrate and rate of reaction is determined by the Michaelis-Menten Equation:
[tex]V=\frac{V_{max}[S]}{K_{M}+[S]}[/tex]
in which:
V is initial velocity of reaction
Vmax is maximum rate of reaction when enzyme's active sites are saturated;
[S] is substrate concentration;
Km is measure of affinity between enzyme and its substrate;
(a) To determine concentration:
[tex]0.25V_{max}=\frac{V_{max}[S]}{0.005+[S]}[/tex]
[tex]0.25V_{max}(0.005+[S])=V_{max}[S][/tex]
[tex]0.00125+0.25[S]=[S][/tex]
0.75[S] = 0.00125
[S] = 0.0016M
For a Km of 0.005M, substrate's concentration is 0.0016M.
(b) Still using Michaelis-Menten:
[tex]V=\frac{V_{max}[S]}{K_{M}+[S]}[/tex]
Rearraging for Vmax:
[tex]V_{max}=\frac{V(K_{M}+[S])}{[S]}[/tex]
(b-I) for [S] = 1/2Km
[tex]V_{max}=\frac{V(K_{M}+0.5K_{M})}{0.5K_{M}}[/tex]
[tex]V_{max}=\frac{V(1.5K_{M})}{0.5K_{M}}[/tex]
[tex]V_{max}=[/tex] 3V
(b-II) for [S] = 2Km
[tex]V_{max}=\frac{V(K_{M}+2K_{M})}{2K_{M}}[/tex]
[tex]V_{max}=\frac{V(3K_M)}{2K_M}[/tex]
[tex]V_{max}=\frac{3V}{2}[/tex]
(b-III) for [S] = 10Km
[tex]V_{max}=\frac{V(K_{M}+10K_M)}{10K_M}[/tex]
[tex]V_{max}=\frac{V(11K_{M})}{10K_{M}}[/tex]
[tex]V_{max}=\frac{11V}{10}[/tex]
(c) Being the affinity between enzyme and substrate, the lower Km is the less substrate is needed to reach half of maximum velocity.
Km of enzyme A is 2μM and of enzyme B is 0.5μM.
Enzyme B has lower Km than enzyme A, which means the first will need a lower concnetration of substrate to reach half of Vmax.
Analyzing each plot, notice that the red-coloured graph reaches half at a lower concentration, therefore, red-coloured plot is for enzyme B, while black-coloured plot is for enzyme A
Which of the following always combines in definite proportions?
a. compound
b. homogeneous mixture
c. element
d. heterogeneous mixture
Answer:
The answer is heterogeneous mixture
g The free energy change of the reaction A (g) ---> B(g) is zero under certain conditions. The STANDARD Free energy change of the reaction is -42.5 kJ. Which of the following statements must be true about the reaction described here? A) The concentration of the product is greater than the concentration of the reactant. B) The reaction is at equilibrium. C) The concentration of the reactant is greater than the concentration of the product.
Answer:
The reaction is at equilibrium.
Explanation:
In thermodynamics, the Gibbs free energy is a term used traditionally to refer to the available or useful work that can be obtained from a thermodynamic system.
Gibbs free energy is a measure of the chemical potential that a reaction has left to do work. Hence, if the free energy is zero, then the reaction has attained equilibrium, and there is no more work to be done
The statement that should be true related to the reaction should be that it should be at equilibrium.
What is Gibbs free energy?In terms of thermodynamics, this energy should be applied for the availability or the useful work that should be obtained via the system of thermodynamics.
Also, it determined the chemical potential where the reaction has left for doing the work. Also in the case when the free energy should be zero so here the reaction should be attained the equilibrium.
hence, the option b is correct.
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Soil is an essential component of the earth's crust. It enabled life to exist and
provides the services necessary for human survival. What is the effect of soil
erosion? What will you do to protect the community?
Answer:
The consequences of soil erosion go beyond the loss of fertile land. It has contributed to increased runoff and sedimentation in streams and rivers, clogging these waters and causing declines in fish and other animals.
We can protect the community from soil erosion by -:
Maintaining a good, perennial cover for plants. From mulching. Planting a crop for coverExplanation:
SOIL EROSION -: The soil erosion mechanism is both natural and man-made. In nature, this refers to the removal of the top layer of soil caused by wind and water, while human activity may increase exposure to these elements.
MAJOR EFFECTS OF SOIL EROSION -:
Pollution and Low Water Quality -: Sedimentation is created by gradual soil erosion, a process by which rocks and minerals in the soil are separated from the soil and deposited elsewhere, often in streams and rivers. Soil contaminants, such as fertilizers and pest control agents, often settle in the streams and rivers to protect crops. Water contaminants contribute to low water quality, including drinking water quality, if the contaminants are not removed prior to ingestion. As sunlight can get through the sediment, sedimentation also leads to the excessive growth of algae. According to the World Wildlife Fund, high levels of algae drain too much oxygen from the water, resulting in the mortality of marine species and reduced fish stocks.Structural Issues and Mudslides -: Soil erosion contributes to mudslides, impacting the stability of buildings and roadways and their structural integrity. Mudslides affect not only soil-supported structures, but also buildings and roads that are in the path of slides. Mudslides occur when, as a result of the intensity and energy of heavy rainfall, fine sand , clay, silt, organic matter and soil spill off the sides of hills and slopes. According to Envirothon, a program of the National Conservation Foundation and North America's largest high school environmental education competition, this runoff happens rapidly, because there is not enough time for the surface to reabsorb or catch the eroding soil.Flooding and Deforestation -: Deforestation erodes soil — the removal of trees to create space for towns and agriculture. Trees help to maintain soil in place, so winds and rains drive the loose soil and rocks to streams and rivers when they are uprooted, resulting again in unnecessary sedimentation. The thick layers of sediment keep streams and rivers from flowing smoothly, ultimately contributing to flooding. Excess water, especially during rainy seasons and when the snow melts, gets trapped by the sediment and has nowhere to go except back on land.The Deterioration of Soil -: Soil nutrient depletion is often the result of poorly performed cultivation and cultivation practices that contribute to soil erosion. For natural vegetation and agricultural purposes, excessive irrigation and obsolete tilling practices decrease the amount of nutrients in the soil and make it less fertile.PROTECTION OF COMMUNITY FROM SOIL EROSION -
Maintaining a good, perennial cover for plants -: Your perennial garden's care and upkeep need not be difficult or overwhelming. A blend of certain simple horticultural values with common sense and a good eye is a great part of good gardening.MULCHING -: The amount of water that evaporates from your soil will be reduced by mulch, greatly reducing the need to water the plants. By breaking up clay and permitting better movement of water and air through the soil. Mulch supplements sandy soil with nutrients and enhances its ability to retain water. PLANTING A CROP FOR COVER -: Winter rye in vegetable gardens, for instance. This includes annual grasses, small grains , legumes and other forms of vegetation that have been planted to provide temporary vegetative cover. Cover crops are also often tilled as a 'green manure' crop under serving.Some of the effects of erosion on the environment includes :
Washing away of soil nutrients Pollution of the waterways Blockage of drainages degradation of soilWays to protect the earth from soil erosion includes
planting of cover crops Mulching use of crush rocks on certain areasSoli erosion is the washing away of the top soil of the earth's crust which can be caused by the movement of wind , water or ice over the surface of the earth crust. this action leads to the degradation of the soil
Soli erosion leads to the washing away of soil nutrients and the pollution of waterways because of the deposition of soil particles into the waterways. the washed away soil can also block the drainages leading to a bigger problem ( flooding ).
Some of the steps that would help protect the soil from the effects of soil erosion are planting of cover crops , mulching and use of crush rocks on areas that are used most frequently to prevent the washing away of the soil.
Hence we can conclude that the effects of soil erosion are Washing away of soil nutrients , Pollution of the waterways, Blockage of drainages while ways to protect the earth from erosion are ;planting of cover crops, Mulching, use of crush rocks on certain areas
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Without SALT or SUGAR, does the water conduct electricity?
A ________________ causes a __________________ heat transfer rate.
Answer:
A smaller temperature difference causes a smaller heat transfer
Explanation:
The greater the temperature difference, the greater the rate at which heat transfers.
Which of the following is least like the others on the list?
a. Estrogen
b. Cholesterol
c. Glycogen
d. Triglyceride
Answer:
Glycogen
Explanation:
a,b,d are lipidic and glycogen is glucide
1) Consider the dissolution of CaCO3 compound in aqueous medium.
a) Write down the equation of the chemical reaction that represents this dissolution.
b) Write the expression of the equilibrium constant for this reaction.
c) Explain how the addition of a certain amount of sodium carbonate to
water would affect this balance
2) The equilibrium constant for the reaction 2 SO2(g) + O2(g) 2 SO3(g) has a Kc value = 2.5x10^10 to 500 K. Find the kc value for each of the following reactions at the same temperature
(a) SO2(g) +1/2 O2 SO3(g).
(b) SO3(g) SO2(g)+1/2 O2(g)
(c) 3SO3(g)+ 3/2 O2(g) 3SO3(g)
3) A reaction mixture consisting of 0.400 mol H 2 and 1.60 mol I 2 was prepared in a 3.00 L flask and heated. In balance, 60.0% of the hydrogen gas reacted. What is the equilibrium constant for the reaction H 2(g) + I 2(g) 2 HI(g) at this temperature?
Explanation:
1a) CaCO₃(s) → Ca²⁺(aq) + CO₃²⁻(aq)
1b) Remember, solids are not included in the equilibrium equation.
K = [Ca²⁺] [CO₃²⁻]
1c) Adding CO₃²⁻ ions will shift the reaction to the left, producing CaCO₃(s) until equilibrium is restored.
2) 2 SO₂(g) + O₂(g) → 2 SO₃(g)
Kc = 2.5×10¹⁰ = [SO₃]² / ([SO₂]² [O₂])
2a) SO₂(g) + ½ O₂(g) → SO₃(g)
Kc = [SO₃] / ([SO₂] [O₂]^½)
Kc² = [SO₃]² / ([SO₂]² [O₂])
Kc² = 2.5×10¹⁰
Kc ≈ 1.58×10⁵
2b) SO₃(g) → SO₂(g) + ½ O₂(g)
Kc = [SO₂] [O₂]^½ / [SO₃]
Kc = 1 / (1.58×10⁵)
Kc ≈ 6.33×10⁻⁶
2c) 3 SO₂(g) + ³/₂ O₂(g) → 3 SO₃(g)
Kc = [SO₃]³ / ([SO₂]³ [O₂]^³/₂)
Kc = ([SO₃] / ([SO₂] [O₂]^½))³
Kc = (1.58×10⁵)³
Kc ≈ 3.95×10¹⁵
3) H₂(g) + I₂(g) → 2 HI(g)
K = [HI]² / ([H₂] [I₂])
Make an ICE table.
[tex]\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\H_{2}&0.400&-0.240&0.160\\I_{2}&1.60&-0.240&1.360\\HI&0&+0.480&0.480\end{array}\right][/tex]
K = (0.480)² / (0.160 × 1.360)
K = 1.06
What is the main limitation of flame tests? Check all that apply.
1. It takes a long time to perform
2.Inability to determine the identity of mixtures
3.Some metals have similar flame test results
4.Color is subjective
Answer:
All of the above are correct.
Explanation:
The Flame Test Shortcomings
Small quantities of most molecules can not be measured by the examination.
The signal's intensity ranges from one test to the next.
The test findings are impaired by impurities or toxins.
The test is not capable of differentiating between all components.
. Give two everyday examples of the thermal energy of a substance being increased.
Answer:
• the warmth from the sun
• the heat from another a heater
• A cup of hot chocolate
•baking in an oven
Two everyday example that we say for the thermal energy of a substance being increased are, faster movement of the substances and boiling if liquids as well light absorption.
What is thermal energy?Thermal energy is a form of energy generated by heating up a substance. It can also be generated by the movement of its particles.
Vibrating molecules increases the thermal energy of a substance. Similarly, when we heat a substance it acquires more thermal energy.
Another way of increasing thermal energy is light absorption by the substance. Thermal energy associated with light increases the temperature of of the system which is absorbed the light.
Hence, the two ways by which thermal energy of a substance is increased are heating or boiling and faster movement.
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What is the frequency of a photon with an energy
Answer:
option b is correct option = (6.76×10¹⁴ Hz)
Explanation:
Given data:
Wavelength of photon = 4.42×10⁻⁷ m
Speed of light = 2.99×10⁸ m/s
Frequency of radiation = ?
Solution:
Formula:
Speed of wave = frequency × wavelength
Now we will rearrange this formula.
frequency = Speed of wave / wavelength
f = c/ λ
f = 2.99×10⁸ m/s / 4.42×10⁻⁷ m
f = 0.676×10¹⁵ Hz (s⁻¹ = Hz)
f = 6.76×10¹⁴ Hz
Thus option b is correct option.
All sound begins with a vibration. Sound travels through the air to your ears which our brains interpret as sound. How are guitar strings like the particles in matter?
1.They are gold
2.They vibrate
3.They are a liquid
Pick One.
10. Explain the relationship between the group number and the valence electrons
of MAIN GROUP elements (Groups 1, 2, 13-18). *
Valence electrons are electrons that are in the outermost orbitals of an atom. In the periodic table the elements are divided into groups. All elements of the first main group have one valence electron. All elements of the second main group have two valence electrons. And so on:
group 1 - 1 valence electrongroup 2 - 2 valence electronsgroup 13- 3 valence electronsgroup 14 - 4 valence electronsgroup 15 - 5 valence electronsgroup 16 - 6 valence electronsgroup 17 - 7 valence electronsgroup 18 - 8 valence electrons15.0 L of an ideal gas at 298 K and 3.36 bar are heated to 350 K with a new pressure of 4.40 atm. What is the new volume in litres?
Answer:
13.3 L
Explanation:
Step 1: Given data
Initial pressure (P₁): 3.36 barInitial volume (V₁): 15.0 LInitial temperature (T₁): 298 KFinal pressure (P₂): 4.40 atmFinal volume (V₂): ?Final temperature (T₂): 350 KStep 2: Convert P₁ to atm
We will use the conversion factor 1 atm = 1.01325 bar.
3.36 bar × (1 atm / 1.01325 bar) = 3.32 atm
Step 3: Calculate V₂
We will use the combined gas law.
P₁ × V₁/T₁ = P₂ × V₂/T₂
V₂ = P₁ × V₁ × T₂/T₁ × P₂
V₂ = 3.32 atm × 15.0 L × 350 K/298 K × 4.40 atm
V₂ = 13.3 L
Oxides of sulfur are important in atmospheric pollution, arising particularly from burning coal. Use the thermodynamic data at 25 C given in the appendix to answer the following questions. a. In air, the oxidation of SO2 can occur: 1 2O2(g) SO2(g) S SO3(g). Calculate rG 298
Answer:
-70.87 kJ
Explanation:
Let's consider the following balanced equation.
1/2 O₂(g) + SO₂(g) ⇄ SO₃(g)
We can calculate the standard Gibbs free energy of reaction (ΔG°r) from the standard Gibbs free energies of formation (ΔG°f) using the following expression.
ΔG°r = 1 mol × ΔG°f(SO₃(g)) - 1/2 mol × ΔG°f(O₂(g) - 1 mol × ΔG°f(SO₂(g))
ΔG°r = 1 mol × (-371.06 kJ/mol) - 1/2 mol × 0 kJ/mol - 1 mol × (-300.194 kJ/mol)
ΔG°r = -70.87 kJ
Which health issue is associated with exposure to indoor air pollution?
O stroke
O hair loss
diabetes
O skin cancer
Answer:
stroke
Explanation:
Problem PageQuestion Methanol and oxygen react to form carbon dioxide and water, like this: (l)(g)(g)(g) At a certain temperature, a chemist finds that a reaction vessel containing a mixture of methanol, oxygen, carbon dioxide, and water at equilibrium has the following composition: compoundamount Calculate the value of the equilibrium constant for this reaction. Round your answer to significant digits. Clears your work. Undoes your last action. Provides information about entering answers.
Answer:
[tex]Kc=3.8x10^{-7}[/tex]
Explanation:
Hello.
In this case, for the chemical reaction:
[tex]2CH_3OH(l)+3O_2(g)\rightarrow 2CO_2(g)+4H_2O(g)[/tex]
We write the equilibrium expression including the gaseous or aqueous species only, that is why the methanol is not included due to heterogeneous equilibrium:
[tex]Kc=\frac{[CO_2]^2[H_2O]^4}{[O_2]^3}[/tex]
Whereas each gaseous species is powered to its stoichiometric coefficient (number before the species). In such a way, considering the equilibrium masses of carbon dioxide (44 g/mol), water (18 g/mol) and oxygen (32 g/mol) to be 1.56 g, 2.28 g and 3.33 g respectively, we compute the moles as we need molar concentrations in the equilibrium constant calculation:
[tex]n_{CO_2}=1.56g/(44g/mol)=0.0355mol\\\\n_{H_2O}=2.28g/(18g/mol)=0.127mol\\\\n_{O_2}=3.33 g/(32g/mol)=0.104mol[/tex]
Thus, into the 9.3.L vessel, the equilibrium concentrations are:
[tex][CO_2]=\frac{0.0355mol}{9.3L}=0.00382M[/tex]
[tex][H_2O]=\frac{0.127mol}{9.3L}=0.0137M[/tex]
[tex][O_2]=\frac{0.104mol}{9.3L}=0.0112M[/tex]
Therefore, the equilibrium constant shown with two significant figures is:
[tex]Kc=\frac{(0.00382M)^2(0.0138M)^4}{(0.0112M)^3} \\\\Kc=3.8x10^{-7}[/tex]
Best regards.
The net ionic equation for the reaction between aqueous nitric acid and aqueous sodium hydroxide is ________. The net ionic equation for the reaction between aqueous nitric acid and aqueous sodium hydroxide is ________. H+ (aq) + Na+ (aq) + OH- (aq) → H2O (l) + Na+ (aq) HNO3 (aq) + OH- (aq) → NO3- (aq) + H2O (l) H+ (aq) + HNO3 (aq) + 2OH- (aq) → 2H2O (l) + NO3- (aq) H+ (aq) + OH- (aq) → H2O (l) HNO3 (aq) + NaOH (aq) → NaNO3 (aq) + H2O (l)
Answer:
H+ (aq) + OH- (aq) → H2O (l)
Explanation:
The net ionic equation is the main reaction going on in the system. The reaction between nitric acid and sodium hydroxide is a neutralization reaction.
In a neutralization reaction, the main reaction is the combination of hydrogen ions and hydroxide ions to form water. This reaction has been shown in the answer box.
"the tamil naducoast recives winter rainfall "why?
Answer:
GDSSHCVJDJD
Explanation:
3. True or False. A compound is formed when two or more elements are
False
True
Which of the following is the best description of matter?
Answer:
description of matter:
Matter is everything around you. Atoms and compounds are all made of very small parts of matter. Those atoms go on to build the things you see and touch every day. Matter is defined as anything that has mass and takes up space (it has volume).
please give me brainliest if I answered you question correctly
Which locations are likely to have subatomic particles that are constantly in motion:
A) 1 and 2
B) 2 and 3
C) 1 and 3
D) 2 and 4
The answer is "2 and 4"
Location 2 and 4 are likely to have subatomic particles that are constantly in motion,thus the correct option is D.
In physics, a subatomic particle is a particle smaller than an atom.According to the Standard Model of particle physics, a subatomic particle can be either a composite particle, which is composed of other particles (for example, a proton, neutron, or meson), or an elementary particle, which is not composed of other particles Particle physics and nuclear physics study these particles and how they interact.
Experiments show that light could behave like a stream of particles (called photons) as well as exhibiting wave-like properties. This led to the concept of wave–particle duality to reflect that quantum-scale particles behave like both particles and waves; they are sometimes called wavicles to reflect this.
Thus, the correct option is D.
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The early periodic table grouped elements based on similar properties. Which element would be grouped with sodium using this principle.
A. Magnesium
B. Zinc
C.Potassium
D. Sulfur
Answer:
C.Potassium
Explanation:
As we know that Potassium is a mineral also at the same time it is an electrolyte. It helps for muscles work involves the muscles so that the heartbeat and breathing could be controlled.
Now as per the periodic table on an early basis that depends upon the similar properties so the element that should be grouped with the sodium is Potassium
hence, the option c is correct
According to the early periodic table the element that has been grouped together with Na has been Potassium. Thus, option C is correct.
The early periodic table has been consisted of the elements that has been arranged based on the increasing order of the atomic mass. The grouping of the elements has been performed based on the similarities with the elements.
The sodium has been the electrolyte that has been responsible for maintaining the electrolyte balance in the human body. The sodium has been the smaller size element with being highly reactive.
The element that has also been small size with high reactive, and has been able to maintain the body electrolyte balance has been Potassium.
Thus, according to the early periodic table the element that has been grouped together with Na has been Potassium. Thus, option C is correct.
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