How to calculate magnitude of tension if given an angle of 10°

Answer:

Concave lens

.............

Answer:

wait one second im about to go get some milk im thirsty

Explanation:

do you want any chicken on your salad

Answer:

See below

Explanation:

The units of the specific heat hint at how to solve these types of problems

.88 J/(g-C)   * 10 g  *  (100- 50 C) = 440 J  

                                  ( see how the g and the C 'cancel out' ?)

The concept of the centrifugal force is used for producing an effective imitation of gravity. It is an important concept in the mechanics.

when any body is executing circular motion about a fixed axis, an outward force act on that object to balance the body and to execute the circular motion. The outward force is known as the centrifugal force.

It is the pseudo force act in order to balance the centripetal force acting inward during the circular motion.

The centrifugal force is comes into the picture when any body executes circular motion about a fixed axis.

To simulate gravity for the inhabitants, the concept of the centrifugal force is used.

Hence, the concept of the centrifugal force is used for producing an effective imitation of gravity.

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The magnitude of the vertical force that a concrete support exerts on the bridge at the far end is 201.25 N.

The force is an action of push or pull which makes a body to move or stop.

Given is the weight of tourist W = 805 N and L is the length of the bridge.

Let the reaction force at both the ends of the bridge is R1 and R2.

Taking the moments about point A,

R1 x 0 - W x L/4 +R2 x L =0

R2 = W/4

R2 = 805 /4

R2 = 201.25 N

Thus, the magnitude of the vertical force that a concrete support exerts on the bridge at the far end is 201.25 N.

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Answer:

8 m/s

Explanation:

(16-0)/2 = 8 m/s

Answer:

2

Explanation:

there are two lonely pairs

2 hydrogens

Explanation:

oxygen has 3 lone pairs of electrons which do not take part in the bonding leaving two electrons in the outermost shell to be part of it, hydrogen has only one electron in it's outermost shell it needs one electron to be stable so two atoms of hydrogen bonds with one oxygen atom to to share there electrons to be stable.

Answer:

1. a

2. b (FALSE)

3. c (beryllium)

Explanation:

Answer:

the answer for number one is A. number 2 is B. and number 3 is C.

Explanation:

theys a Quizlet made on these three questions already so I just got it from there. they should be correct pls let me know if they are.

Answer:

The acceleration is

Explanation:

Acceleration = final velocity - initial velocity
                        ---------------------------------------
                                speed
Initial velocity = 10m/s
final velocity = 22m/s
speed = 2 secs
acceleration = 22 - 10
                       -----------
                           2
                    = 12/2
                     6 m/s^2

Answer:

290.4 joules

Explanation:

As the formula to find kinetic energy is 1/2 mv^2.

So if we put the given data in it,the answer comes 290.4 joules

Answer:

Clark Hull put the emphasis of his work on experimentation, an organized theory of learning, and the nature of habits, which he argued were associations between a stimulus and a response

Explanation:

Taking into account the definition of calorimetry, sensible heat and latent heat, the amount of heat required is 463.28 kJ.

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

In firts place, the melting point of water (temperature at which it changes state from solid to liquid) is 0°C.

So, first of all you must increase the temperature from -25 ° C (in solid state) to 0 ° C, in order to supply heat without changing state (sensible heat).

The amount of heat a body receives or transmits is determined by:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

Replacing:

Q1= 2050 [tex]\frac{J}{kgC}[/tex]  × 0.845 kg× 25 °C

Solving:

Q1= 43,306.25 = 43.3 kJ

The heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q = m×L

where L is called the latent heat of the substance and depends on the type of phase change.

In this case, you know:

Replacing:

Q2= 0.845 kg× 334[tex]\frac{kJ}{kg}[/tex]

Solving:

Q2= 282.23  KJ

Similar to sensible heat previously calculated, you know:

Replacing:

Q3= 4180 [tex]\frac{J}{kgC}[/tex] × 0.845 kg× 39 °C

Solving:

Q3= 137,751.9 J= 137.75 kJ

The total heat required is calculated as:  

Total heat required= 43.3 kJ + 282.23 kJ + 137.75 kJ

Total heat required= 463.28 kJ

In summary, the amount of heat required is 463.28 kJ.

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The amount of energy required if the final temperature of the system is to reach 39 °C is 463288.15 J

Q = MCΔT

Q₁ = 0.845 × 2050 × 25

Q₁ = 43306.25 J

Q = mL

Q₂ = 0.845 × 334000

Q₂ = 282230 J

Q = MCΔT

Q₃ = 0.845 × 4180 × 39

Q₃ = 137751.9 J

Qₜ = Q₁ + Q₂ + Q₃

Qₜ = 43306.25 + 282230 + 137751.9

Qₜ = 463288.15 J

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GPE = mgh

GPE = 57 x 9.8 x 381 = 2.12 x 10⁵ J

Answer:

529.2 joules

Explanation:

Work done = force x distance = mass x gravity x distance

= 36x9.8 x1.5 =529.2 joules

[tex]\huge{\boxed{{\colorbox{red}{1 N}}}}[/tex]

that's my answer

vf²=vi²-2ad (vf=0, stop)

vi²=2ad

200²=2.a.5

a = 200² : 10

F = ma

F = 25 x 200² : 10

F = 1 x 10⁵ dyne = 1 N

Answer:

0.315C

Explanation:

Force/Electric field

7520N/23900C

[tex]\Large{\green}\fcolorbox{blue}{cyan}{\bf{\underline{\red{\color{red}Answer}}}}[/tex]

2300 N upward

Explanation:

The force by weight of balloon = 1000 N

The atmospheric force experienced by balloon = 3300 N

While weight of balloon is attracted by gravity so the force of weight will act downward

And the atmospheric force gives upward lifting force to the balloon

Net force = atmospheric force - weight of balloon

= 3300 - 1000

= 2300 N

As the atmospheric force is more dominating the balloon will goes upward with 2300 N force

Answer:

C. The poster provides an emotional picture of a young, innocent girl with a slightly worried expression to make protective feelings.

Explanation:

The girl looks quite worried in the poster. Attached is the image:

Answer:

Staying single makes it a whole lot easier to focus on yourself, gain self love, and work on yourself!

Explanation:

Answer:

air does not have a modulus of rigidity.

Explanation:

Since air is completely elastic medium, that is, it does not have a modulus of rigidity, therefore sound waves in air are longitudinal.

Answer:

Because it is the standard operational range for measuring the body temperature of a living individual.

Explanation:

When making a measuring equipment like a thermometer, you attempt to keep the reading range (Span) as small as possible so that the reading is as accurate as feasible. Because sensors are often rated in percent of span (in this example, span = 45 C–32 C = 13 degrees Celsius), One percent of 13 equals 0.13 degrees Celsius, thus if your sensor has a usual accuracy of 1%, your temperature reading is accurate to roughly 0.1 degrees Celsius.

Your precision would be 0.2 degrees Celsius if you doubled the span. The reading accuracy is now becoming unsatisfactory. Readability is another advantage of analog and mercury clinical thermometers. The markings for 0.1 deg C would be ten times closer together if a mercury thermometer had ten times the range (span). There is a limit to the device's readability.

Answer:

I think the answer is B.

Explanation:

Answer:

true

Explanation:

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Here we go ~

Speed of the car is 75 miles per hour and it travels for 14 hours. so the distance travelled by it in the given period of time can be calculated using this formula ~

[tex]\qquad \sf  \dashrightarrow \: d = v \sdot t[/tex]

[tex]\qquad \sf  \dashrightarrow \: d = 75 \times 14[/tex]

[tex]\qquad \sf  \dashrightarrow \: d = 1050 \: \: miles[/tex]

so, it can travel 1050 miles in 14 hours

Answer:

1050 miles

Explanation:

Simply:

d =  75 m/hr   *  14 hr   =1050 miles

 ( see how the 'hr' cancels and you are left with miles ?)

Consider,

[tex]{:\implies \quad \displaystyle \sf \langle p\rangle =m\langle v(t)\rangle=m\int_{-\infty}^{\infty}x\bigg\{\dfrac{\partial \Psi^{*}(x,t)}{\partial t}\Psi (x,t)+\Psi^{*}(x,t)\dfrac{\partial \Psi (x,t)}{\partial t}\bigg\}dx}[/tex]

Multiply both sides by ih and simplification will yield

[tex]{:\implies \quad \displaystyle \sf ih\langle p\rangle =m\int_{-\infty}^{\infty}x\bigg[\Psi (x,t)\bigg\{\dfrac{h^2}{2m}\dfrac{\partial^{2}\Psi^{*}(x,t)}{\partial x^2}-V(x)\Psi^{*}(x,t)\bigg\}+\Psi^{*}(x,t)\bigg\{V(x)\Psi (x,t)-\dfrac{h^2}{2m}\dfrac{\partial^{2}\Psi (x,t)}{\partial x^2}\bigg\}\bigg]dx}[/tex]

Some simplification, Then Integrate by parts and then knowing the fact that the wave function vanishes for [tex]{\bf x\to \pm \infty}[/tex] will yield:

[tex]{:\implies \quad \displaystyle \sf \langle p\rangle =\dfrac{ih}{2}\int_{-\infty}^{\infty}\bigg\{\dfrac{\partial \Psi^{*}(x,t)}{\partial x}\Psi (x,t)-\Psi^{*}(x,t)\dfrac{\partial \Psi (x,t)}{\partial x}\bigg\}dx}[/tex]

Integrating by parts and knowing the same fact by some simplification will yield:

[tex]{:\implies \quad \displaystyle \sf \langle p\rangle =-ih\int_{-\infty}^{\infty}\Psi^{*}(x,t)\dfrac{\partial \Psi (x,t)}{\partial x}dx}[/tex]

The momentum is thus contained within the wave function, so we can then deduce that:

[tex]{:\implies \quad \sf p\rightarrow -ih\dfrac{\partial}{\partial x}}[/tex]

[tex]{:\implies \quad \sf p^{n}\rightarrow \bigg(-ih\dfrac{\partial}{\partial x}\bigg)^{n}}[/tex]

[tex]{:\implies \therefore \quad \displaystyle \sf \langle p^{2}\rangle =-h^{2}\int_{-\infty}^{\infty}\Psi^{*}(x,t)\dfrac{\partial^{2}\Psi (x,t)}{\partial x^2}dx}[/tex]

Now the kinetic energy

[tex]{:\implies \quad \displaystyle \sf \langle K\rangle =\dfrac{\langle p^{2}\rangle}{2m}=\dfrac{-h^2}{2m}\int_{-\infty}^{\infty}\Psi^{*}(x,t)\dfrac{\partial^{2}\Psi (x,t)}{\partial x^2}dx}[/tex]

The classical formula for the total energy

[tex]{:\implies \quad \sf \dfrac{p^2}{2m}+V(x)=E}[/tex]

Multiplying this equation by [tex]{\sf \Psi (x,t)=\psi (x)exp\bigg(\dfrac{-iEt}{h}\bigg)}[/tex] and use the above equations and simplify it we will be having

[tex]{:\implies \quad \boxed{\bf{\dfrac{-h^2}{2m}\dfrac{d^{2}\psi (x)}{dx^{2}}+V(x)\psi (x)=E\psi (x)}}}[/tex]

This is the Famous Time-Independent Schrödinger wave equation

Note:- If I write all the explanation then the Answer box willn't allow me to submit the answer

Answer: reference point

Explanation: A reference point could be a put or question utilized for comparison to decide in case something is in movement.