How many total atoms are in one molecule of maltose?

Answer:

An increase in the concentration of the reactant in solution causes the reaction rate to increase exponentially - first order

The reaction rate increases in direct proportion to the concentration of the reactant in solution -second order

The reaction rate is constant regardless of the amount of reactant in solution - zero order

Explanation:

The Order of Reaction refers to the power dependence of the rate on the concentration of each reactant. The order of reaction is determined experimentally and not necessarily by inspection.

Typically, in a second order reaction, the rate of reaction increases in proportion to increase in concentration.

For a first order reaction, the rate of reaction increases exponentially as the increase in concentration.

For a zero order reaction, the rate of reaction is independent of the concentration of the reactant.

Answer: The mass of product, [tex]H_2O[/tex] is, 36.0 grams.

Explanation : Given,

Mass of [tex]H_2[/tex] = 4.0 g

Mass of [tex]O_2[/tex] = 32.0 g

Molar mass of [tex]H_2[/tex] = 2 g/mol

Molar mass of [tex]O_2[/tex] = 32 g/mol

First we have to calculate the moles of [tex]H_2[/tex] and [tex]O_2[/tex].

[tex]\text{Moles of }H_2=\frac{\text{Given mass }H_2}{\text{Molar mass }H_2}[/tex]

[tex]\text{Moles of }H_2=\frac{4.0g}{2g/mol}=2.0mol[/tex]

and,

[tex]\text{Moles of }O_2=\frac{\text{Given mass }O_2}{\text{Molar mass }O_2}[/tex]

[tex]\text{Moles of }O_2=\frac{32.0g}{32g/mol}=1.0mol[/tex]

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

[tex]2H_2+O_2\rightarrow 2H_2O[/tex]

From the balanced reaction we conclude that

2 mole of [tex]H_2[/tex] react with 1 mole of [tex]O_2[/tex]

From this we conclude that, there is no limiting and excess reagent.

Now we have to calculate the moles of [tex]H_2O[/tex]

From the reaction, we conclude that

2 moles of [tex]H_2[/tex] react to give 2 moles of [tex]H_2O[/tex]

Now we have to calculate the mass of [tex]H_2O[/tex]

[tex]\text{ Mass of }H_2O=\text{ Moles of }H_2O\times \text{ Molar mass of }H_2O[/tex]

Molar mass of [tex]H_2O[/tex] = 18 g/mole

[tex]\text{ Mass of }H_2O=(2.0moles)\times (18g/mole)=36.0g[/tex]

Therefore, the mass of product, [tex]H_2O[/tex] is, 36.0 grams.

Answer:

Explanation:

Given that:

P₅₀ = 20 torr in muscle

The partial pressure of O2 in lungs Po₂ = 100 torr

The hill coefficient [tex]n_h[/tex] = 3

According to the Hill coefficient;

[tex]\dfrac{\Upsilon}{1-\Upsilon}= (\dfrac{PO_2}{P_{50}})^n[/tex]

here;

[tex]\Upsilon[/tex] = fraction of haemoglobin monomers

[tex]\dfrac{\Upsilon}{1-\Upsilon}= (\dfrac{100}{20})^3[/tex]

[tex]\dfrac{\Upsilon}{1-\Upsilon}[/tex] = 125 θ lungs

However for θ muscle :

[tex](\dfrac{PO_2}{P_{50}})^n=( \dfrac{20}{20})^3[/tex]

= 125 (θ lungs) - 1 (θ muscle)

= 124

B.

if nh =1

[tex]\mathtt {\theta \ lungs} = \dfrac{\Upsilon}{1-\Upsilon}= (\dfrac{100}{20})^1[/tex]

[tex]\mathtt {\theta \ lungs} =5[/tex]

[tex]\mathtt {\theta \ muscle} = \dfrac{20}{20}^1[/tex]

(θ muscle) = 1

(θ lungs) - (θ muscle) = 5 - 1

(θ lungs) - (θ muscle) = 4

A) The efficiency of hemoglobin at O₂ delivery = 124

B) Efficiency of O₂ delivery will change by : 4  

Given data:

Partial pressure of O₂ in lungs ( PO₂ )  = 100 torr

Partial pressure of O₂ in muscle  = ( P₅₀ ) = 20 torr

Hill coefficient nh = 3

r = fraction of hemoglobin monomers

A) Determine the efficiency of hemoglobin at O₂ delivery

Given that Hill coefficient = [tex]\frac{r}{1-r} = (\frac{PO_{2} }{P_{50} } )^{n}[/tex]  

                                          = [tex]\frac{r}{1-r} = (\frac{100}{20})^{3}[/tex]  = 125 ∅ Lungs

For Muscle :

[tex](\frac{20}{20} )^{3}[/tex] =  1 ∅ muscle

Therefore the efficiency of hemoglobin at 0₂ delivery

= ( ∅ lungs - ∅ muscle )

=  ( 125 - 1 )  = 124

B )  Determine the change in efficiency of O2 delivery

when hill coefficient ( nh ) = 1

for lungs :

[tex]\frac{r}{1-r} = (\frac{100}{20})^{1}[/tex]  = 5

for muscle :

[tex](\frac{20}{20} )^{1}[/tex]   = 1

Therefore change on efficiency =  ( 5 - 1 ) = 4

Hence we can conclude that The efficiency of hemoglobin at O₂ delivery = 124 and Efficiency of O₂ delivery will change by  4  

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Answer:

λ = 5.56 × 10⁻³ m

Explanation:

You have to use the formula c = λv to solve the problem.  Review what you are given.  You are given v and c, where v = 5.40 × 10¹⁰ Hz and c = 3.00 × 10⁸ m/s.  The value c is for the speed of light and is something you need to memorize.  You will use it often in physics and sometimes in chemistry.

Now that you figured out what you know, you can see that there is only one unknown, allowing you to solve.

c = λv

λ = c/v

λ = (3.00 × 10⁸ m/s)/(5.40 × 10¹⁰ Hz)

λ = 5.56 × 10⁻³ m

Answer:

electron

Explanation:

Answer:

A.endoplamic reticulum

Explanation:

The endoplamic reticulum  is an important organelle in protein synthesis. The nucleus contains DNA, which is the template for transcription of mRNA. mRNA acts as a message, which leaves the nucleus to become translated into proteins.

The endoplasmic reticulum is important in the synthesis, folding, and modification of proteins.  

According to the electronic configuration of boron, there are three electrons in the Bohr model of a boron atom.

Electronic configuration is defined as the distribution of electrons which are present in an atom or molecule in atomic or molecular orbitals.It describes how each electron moves independently in an orbital.

Knowledge of electronic configuration is necessary for understanding the structure of periodic table.It helps in understanding the chemical properties of elements.

Elements undergo chemical reactions in order to achieve stability. Main group elements obey the octet rule in their electronic configuration while the transition elements follow the 18 electron rule. Noble elements have valence shell complete in ground state and hence are said to be stable.

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Answer:

Sediment increases the cost of treating drinking water and can result in odor and taste problems. Sediment can clog fish gills, reducing resistence to disease, lowering growth rates, and affecting fish egg and larvae development.

Explanation:

Answer:

"Sediment increases the cost of treating drinking water and can result in odor and taste problems. Sediment can clog fish gills, reducing resistance to disease, lowering growth rates, and affecting fish egg and larvae development".

Explanation:

Answer:

Pressures and temperatures

Explanation:

In deciding the new substances that develop in a metamorphic stone, pressures and temperatures are major factors. Under various conditions of pressure and temperature, various minerals form.

Metamorphic rocks are classified that, extreme heat and strain, have altered shape. Metamorphic derives from the terms meta and morph in german. Meta means alteration and morph means shape. So, to alter shape, we get metamorphosed significance.

Answer:

Zinc weighs 65.38 grams per mole, so we’ve got 0.994 moles of zinc (I’ll worry about sig figs at the end). HCl weighs 36.46 grams per mile, so we’ve got 1.78 moles of HCl. However, two moles of HCl react with one mole of zinc. So only 1.78/2 = 0.890 moles of Zinc are going to react.

One mole of zinc produces one mole of hydrogen, which weigh 2.02 grams per mole. So 0.890 moles * 2.02 grams/mole means 1.90 grams of hydrogen will be produced.

Since we have 2 sig figs in the weights given, the answer should have 2 sig figs, thus 1.9 grams.

This is just an example

Answer:

alkali metals- Group 1

Explanation:

they have less valence electrons and therefore are more reactive

Answer:

268.3 m/sec

Explanation:

Answer:

Option C is correct = ₈₅At²²⁰

Explanation:

Given radioactive decay shows the beta emission.

²²⁰₈₄Po    ₈₅At²²⁰  +  ⁰₋₁e ⁻

Beta radiations are result from the beta decay in which electron is ejected. The neutron inside of the nucleus converted into the proton an thus emit the electron which is called β particle.

Properties of beta radiations:

1) They can travel in air in few meter distance.

2) These radiations can penetrate into the human skin.

3) The mass of beta particle is smaller than the alpha particles.

4) The sheet of aluminium is used to block the beta radiation

¹⁴₆C → ¹⁴₇N + ⁰₋₁e ⁻

The beta radiations are emitted in this reaction. The one electron is ejected and neutron is converted into proton.

Answer:

The nitrogen atom has 5 electrons in the outermost shell, so it can accept 3 electrons to fulfil the octet structure. Therefore the valency of nitrogen is 3.

Answer:

Volume of solution is 0.88 L.

Explanation:

Given data:

Molarity of solution = 0.750 M

Mass of KNO₃ = 67.0 g

Volume of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Now we will calculate the number of moles.

Number of moles = mass/molar mass

Number of moles = 67.0 g/ 101.1 g/mol

Number of moles = 0.66 mol

Now we will put the values in molarity formula.

0.750 M = 0.66 mol / L of solution

L of solution  = 0.66 mol / 0.750 M

L of solution  = 0.88 L

Volume of solution is 0.88 L.

Answer:

I would place 0.5 M solution of the 6.0 stock solution to a 250 mL volumetric flask and then add 250 mL of water.

Explanation:

Answer:

batteries

Explanation:

bc they're powered by energy

Answer:

On a warm day, water absorbs from its warmer environment, lowering the air tempurature. On a cool night, heat is transferred from the water to its cooler environment, raising the air tempura

Explanation:

Answer:

110.91 g of CaCl2

Explanation:

11.9 grams of CaCl₂ is required to make 1 Liter of 0.1M solution.

We first need to calculate the molecular weight of calcium chloride CaCl₂.

The atomic weight of Ca = 40.01

and the atomic weight of Cl₂ = 2×35.45 = 70.90

So, the molecular weight of CaCl₂ = 40.01 + 70.90 = 110.91

This means that 110.91 g of CaCl₂ mixed with enough water will produce 1Liter of 1M solution.

Now, to calculate the amount of CaCl₂ required to make 1 Liter of 0.1M solution we use:

grams of chemical = (molarity of solution in mole/liter) x (MW of chemical in g/mole) x (ml of solution) ÷ 1000 ml/liter

= 0.1 × 110.91 × 1000 ÷ 1000

= 11.09 grams

So, 11.09 grams of CaCl₂ will be used.

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Answer:

v = 3.60Lmol⁻¹s⁻¹ [NH₄CNO]²

Explanation:

The reaction at 65°C of ammonium cyanate to produce urea is:

NH₄CNO → NH₂CONH₂

The general rate law is:

v = K  [NH₄CNO]ˣ

Where v is rate of the reaction, K is rate constant and x represents the order of reaction

Based on the units of the rate constant (Lmol⁻¹s⁻¹ = M⁻¹s⁻¹) the reaction must be order 2 and the rate law:

v = K  [NH₄CNO]²

Answer:

39270 J

Explanation:

The quantity of heat required to raise the temperature of a substance from its initial temperature to its final temperature is given by:

Q = mCΔT

m = mass of substance, C = specific heat capacity of substance, ΔT = temperature change = final temperature - initial temperature

Melting point = 0°C, boiling point = 100°C, m = 93.5 g = 0.0935 g, ΔT = boiling point - melting point = 100 - 0 = 100°C, C = 4200 J/kg°C

Q = mCΔT

Q = 0.0935 × 4200 × 100 = 39270 J

Answer:

Its A

Explanation:

Green, blue, indigo lists three parts of sunlight that make up some of the visible spectrum. Hence option with green, blue, indigo is correct.

Electromagnetic spectrum is nothing but the range of wavelengths or frequencies on which electromagnetic radiation extend. it is whole distribution of electromagnetic waves according to frequency or wavelength. Electromagnetic wave is nothing but a photon which carries energy. Photon has frequency, wavelength as well as amplitude.

Electromagnetic spectrum is show in figure.

Range from 4000 angstrom to 7000 angstrom from violet to red respectively shows the visible light

Infrared light is nothing but the heat we feel from the sun. and ultraviolet light is blacked by ozone layer. we can calculate exact value of temperature of the sun rom Stephan's forth power law.

Green, blue, indigo, red and oranges are the colors from visible light, therefore they are part of visible light.

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Answer:

46%

Explanation:

When solving this problem we have to note that the amount of salt (in grams) before isolation and after isolation are equal. If [tex]V_1[/tex] represents its volume before isolation and [tex]V_2[/tex] its volume after isolation then:

[tex]2.1 \frac{g}{L} *V_1=3.89\frac{g}{L} *V_2\\\\\frac{V_2}{V_1} =\frac{2.1}{3.89}\\\\\frac{V_2}{V_1} =0.54\\\\This\ means\ after \ isolation\ the\ volume\ of water\ is\ 54\%\ of\ its\ original\ value.\\\\The\ amount\ of\ evaporation=1-\frac{V_2}{V_1} =1-0.54=0.46=46\%\\\\The\ amount\ of\ evaporation=46\%[/tex]

Answer:

Explanation:

The density of a substance can be found by using the formula

[tex]density = \frac{mass}{volume} \\[/tex]

From the question

mass = 17.2 g

volume = 5 cm³

We have

[tex]density = \frac{17.2}{5} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

Method 1 - precision

Method 2 - accuracy

Method 3 - precision

Method 4 - accuracy

Explanation:

The accuracy of a method refers to how close the experimental result is to the accepted value. Accuracy could be checked by carrying out the required test on the standard and not on the sample or by adding a known amount of analyte to the sample so that the results obtained can be carefully compared.

Precision on the other hand, refers to how close the results of a replicate analysis are to each other. In testing for precision, the analysis must be carried out several times, in order to check how close the results are to each other.

Answer:

0.000305 km

Explanation:

1 foot = 0.000305 kilometers

Answer:

[\tex]\huge\bold\red{brainiest answer}[/tex]1 km =3,280.8398950131foot