HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Answer:

Step-by-step explanation:

Area of figure I = length * width

                        = 8 *16

                         = 128 cm²

Area of figure II = length * width

                          = 4 * 3

                          = 12 cm²

Trianlge:

base = b =  7 cm

height = 4 + 4 + 6 = 14 cm

[tex]\text{area of triangle =$\dfrac{1}{2}*b*h$}[/tex]

                         [tex]= \dfrac{1}{2} * 7 * 14[/tex]

                        = 7 * 7

                        = 49 cm²

Area of the figure = area of figure  I + area of figure II + area of figure II

                               =  128 + 12 + 49

                                = 189 cm²[tex]\text{area of figure III = \dfrac{1}{2}*b*h}[/tex]

Answer:

189 cm²

area of triangle:

1/2 * base * height

1/2 * 7 * (6+4+4)

49 cm²

area of rectangle:

Length * Width

8 * 10

80 cm²

area of rectangle 2:

Length * Width

6 * 8

48 cm²

area of small rectangle:

Length * Width

4 * 3

12 cm²

total area:

49 + 48 + 12 + 80

189 cm²

Answer:

i believe its 150

Step-by-step explanation:

Answer:

630

Step-by-step explanation:

1st = 3

2nd = 6

3rd = 9 ...

20th = 60

Súmalos todos juntos para encontrar la suma.

3 + 6 + 9 + 12 + 15 + 18 + 21 + 24 + 27 + 30 + 33 + 36 + 39 + 42 + 45 + 48 + 51 + 54 + 57 + 60 = 630

La suma de los primeros 20 múltiplos de 3 es 630

¡Espero que esto ayude!

Answer:

G

Step-by-step explanation:

Volume of a triangular prism = area of the base x height

(where the "bases" are the triangles)

Area of a triangle = 1/2 x base x height

Given:

⇒ area of base of prism = 1/2 x 3.1 cm x 4.8 cm = 7.44 cm²

Given:

⇒ Volume of the prism = 7.44 cm² x 2.6 cm = 19.344 cm³

Answer: So, the average temperature dropping is 2 degrees per hour.

Step-by-step explanation:

The expression that will make the algebraic equation true for all values of x is: A. 3x - 3.

An algebraic equation is an equation where for a value of x, the right side and the left side of the equation must be balanced.

Given the algebraic equation, 15x - 15 = 5(?)

The missing expression, is 3x - 3, because:

15x - 15 = 5(3x - 3)

Open the bracket

15x - 15 = 15x - 15

Both sides are equal.

Therefore, the expression that will make the algebraic equation true for all values of x is: A. 3x - 3.

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Answer:

the one where it say it takes height

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

I got 100%

Answer:

64   <====  I don't see the correct answer listed

Step-by-step explanation:

Max will occur in month x given by  - b/2a =  - 32/ (2 * -16) = 1

  plug this 'x'  month in to find the max value v

=  64

Answer:

0.19, 0.23, 0.28...............

Answer: Since −3x does not contain the variable to solve for, move it to the right-hand side of the equation by adding 3x to both sides.

y=5x−7

−2y=3x−12

Divide each term in the equation by −2.

y=5x−7

y=−3x/2+6

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

(2,3)

Answer:

B

Step-by-step explanation:

5 × pi ÷12 = 75 degrees

this is essentially cos75

= cos(30 + 45)

then we use the identities to solve.

the answer will = to 0.2588

Answer:

The third option.

[tex]cos(Q)=\frac{RQ}{PQ}[/tex]  

Step-by-step explanation:

SIN is opposite over hypotenuse.

COS is adjacent over hypotenuse

Therefore

[tex]sin(P)=\frac{RQ}{PQ}[/tex]

Then we have 4 options.

It is not the first option beacause we can't determine which side is adjacent to the angle.

The second option

[tex]sin(Q)=\frac{RP}{QP}[/tex]

The third option

[tex]cos(Q)=\frac{RQ}{PQ}[/tex]

It is not the fourth option beacause we can't determine which side is opposite to the angle.

Finally we see that

[tex]cos(Q)=\frac{RQ}{PQ}[/tex]  

and

[tex]sin(P)=\frac{RQ}{PQ}[/tex]

are equivalent.

Answer:

504

Step-by-step explanation:

14x18x2=

(14x18)x2=

252x2=

504

Answer:

2.6 inches

Step-by-step explanation:

As shown in the title if length is x,

x * 1/x = 8/3  * x

8 * 1 = 3x

x = 8/3 in

= 2.6 in

The new length of the rectangular print will be 2.68 feet.

A rectangle is a geometrical figure in which opposite sides are equal.

The angle between any two consecutive sides will be 90 degrees.

Area of rectangle = length × width.

Perimeter of rectangle = 2( length + width).

Given a rectangular print with dimensions,

Length = 1 foot = 12 inches

Width = 8 inches.

Area = 12(8) = 96 square inches

Now,

The area of the new print should be the same

So,

96 = Length × 3

Length = 32 inches = 2.67 feet.

Hence "The new length of the rectangular print will be 2.68 feet".

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Answer:

Step-by-step explanation:

Answer:

57°

Step-by-step explanation:

Using the Law of sines,

Answer:

see image

Step-by-step explanation:

See image. It all on the paper in the picture. Hope this helps! Please mark Brainliest if possible! tysm!

(You should take the full screenshot)

Since no percentages were provided (at least not in the ss), we have to approximate?

The space that parrots and sparrows take up is almost half the circle (we'll say 48-49%)

So, we can convert that to fraction : 48/100 or 49/100

There is 1/2 of the birds seen were either parrots or sparrows.

A number which can be written in the form of fraction p / q , where q is non zero, are called Rational numbers.

Given that;

Figure shows the birds seen.

Now, We have;

By figure the half of circle is shown either parrots or sparrows.

Hence, The value of fraction of the birds seen were either parrots or sparrows is,

⇒ 1/2 of 100%

⇒ 1/2 × 100/100

⇒ 1/2

Therefore,  The value of fraction of the birds seen were either parrots or sparrows is, 1/2

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Answer:

2 1/3

Step-by-step explanation:

if joshua has enough juice than  this is how much he needs

Given Information :-

⠀

⠀

To Find :-

⠀

⠀

Formula Used :-

⠀

[tex] \qquad \diamond \: \underline{ \boxed{ \pink{ \sf Exterior ~angle = \dfrac {360^\circ}{no. ~of~sides}}}} \: \star[/tex]

⠀

Solution :-

⠀

Putting the given values, we get,

⠀

[tex]\sf \dashrightarrow Exterior ~angle = \dfrac{360 ^\circ}{10} \: \: \\ \\ \\ \sf \dashrightarrow Exterior ~angle = \frac{36 \cancel{0}^\circ}{ \cancel{10}} \: \: \\ \\ \\ \sf \dashrightarrow Exterior ~angle = \underline{ \boxed{ \frak{ \red{36^\circ}}}} \: \star \\ \\ [/tex]

Thus, the value of the exterior angles of a Decagon is 36°.

⠀

[tex] \underline{ \rule{227pt}{2pt}} \\ \\ [/tex]

Answer:

⠀

Explanation :

⠀

For a regular polygon of n sides, we have

[tex]{ \longrightarrow \qquad \pmb{ \it{Each \: exterior \: angle = { \bigg( {\dfrac{360}{n} } \bigg)^{ \circ} }}}}[/tex]

⠀

Here, We are to find the measure of each exterior angle of a regular decagon.

⠀

⠀

Now, substituting the value :

⠀

[tex]\sf \longrightarrow \qquad Each \: exterior \: angle_{(Decagon)} = { \bigg( {\dfrac{360}{10} } \bigg)}^{ \circ} [/tex]

⠀

[tex]\sf \longrightarrow \qquad Each \: exterior \: angle _{(Decagon)}= { \bigg( {\dfrac{36 \cancel0}{1 \cancel0} } \bigg)}^{ \circ} [/tex]

⠀

[tex]\sf \longrightarrow \qquad Each \: exterior \: angle_{(Decagon)} = { \bigg( {\dfrac{36}{1} } \bigg)}^{ \circ} [/tex]

⠀

[tex]{\pmb{ \frak{ \longrightarrow \qquad Each \: exterior \: angle_{(Decagon)} = 36^{ \circ} }}}[/tex]

⠀

Therefore,

Answer:

13 players

Step-by-step explanation:

Money Raised=RentedBus+Meals

1319.25=776.50+41.75p (p is for the number of players)(Now we solve for x)

Subtract 776.50 from both sides:   542.75=41.75x

Divide both sides by 41.75:   13=x

Remember that x is for the number of players so there'll be 13 players going to the tournament.

Answer:

2 & 13

Step-by-step explanation:

The square of 2 plus the prime number 13 add up to 17

[tex]2^{2}+13=4+13 =17[/tex]

Hope this helps

Answer:

Square number = 4

Primer number = 13

Step-by-step explanation:

A square number is the result when a number has been multiplied by itself.

A prime number is a whole number greater than 1 that only has two factors, itself and 1.

List all the square numbers and prime numbers below 17:

Square numbers: 1, 4, 9, 16, ...

Prime numbers: 2, 3, 5, 7, 11, 13, ...

Therefore, the only combination of square number and prime number that sums to 17 is:  4 + 13 = 17

Solution

Square number = 4

Primer number = 13

Answer:

? = 49

Step-by-step explanation:

To solve this we just need to understand that when A=1, B=7. So when the side for a is 7 that is basically multiplying A by 7 so we have to do the same to the B side. So when the B side is multiplied by 7 it would be 7*7 =49 so the ? is equal to 49 when that similar side is equal to 7.

This is all based on the fact that the two triangles must be similar triangles.

The water of the cylinder cannot fill the container, since the cylinder has less volume. Lastly, there is no apparent mistakes.

The rectangular container ([tex]V_{R}[/tex]), in cubic inches, is full whether its volume is equal to the volume of the cylinder ([tex]V_{C}[/tex]), in cubic inches. The volume formulae for both containers are described below:

[tex]V_{R} = w\cdot l \cdot h[/tex]   (1)

Where:

[tex]V_{C} = \pi\cdot r^{2}\cdot h[/tex]   (2)

Where:

Now we proceed to determine the volume of each figure:

[tex]V_{R} = (3.6\,in)\cdot (3.6\,in)\cdot (5.3\,in)[/tex]

[tex]V_{R} = 68.688\,in^{3}[/tex]

[tex]V_{C} = \pi\cdot (1.8\,in)^{2}\cdot (5.3\,in)[/tex]

[tex]V_{C} \approx 53.947\,in^{3}[/tex]

The volume of the water in the cylinder is approximately 53.947 cubic inches. The water of the cylinder cannot fill the container, since the cylinder has less volume. Lastly, there is no apparent mistakes. [tex]\blacksquare[/tex]

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Answer:

115

Step-by-step explanation:

41+24=65.

180-65=115

Answer:

1/5

Step-by-step explanation:

It is easy to see a right triangle on each side of the original square with its hypotenuse on the side of the original square, each with an area of 2⋅A2=A. Thus the total area of the original square is 5A, or the ratio of the area of the shaded square to the original square is 1/5.

Answer:

yes! they're pretty skinny

Step-by-step explanation:

check the template in the picture below, thus

[tex]y = \stackrel{A}{\cfrac{3}{2}}cot\stackrel{B\qquad C}{\left( \cfrac{3}{5}x + 0 \right)}+\stackrel{D}{5}~\hfill \stackrel{\textit{\Large Period}}{\cfrac{\pi }{B}\implies \cfrac{\pi }{~~ \frac{3}{5}~~}\implies \cfrac{5\pi }{3}}[/tex]