help please!! i don’t understand this one!

Answer:

Step-by-step explanation:

bro im out n can come scoop

Problem 5

Domain = [tex]-4 \le x \le 3[/tex]

This is because the smallest x value allowed is x = -4 as shown by the left-most point. The right most point has x coordinate x = 3, so this is the largest value in the domain.

The domain in interval notation is [-4, 3]. The square brackets include the endpoint.

--------------

Range = [tex]-4 \le y \le 5[/tex]

We're now looking at the possible y values. The lowest point happens when y = -4 and the highest point is when y = 5. We can have any y value between those endpoints.

The range in interval notation is [-4, 5]

=============================================================

Problem 6

Domain = [tex]-2 \le x < 2[/tex]

Same idea as the previous problem. This time the left most point has x = -2 and the right most point has x coordinate x = 2.

The big difference here is that the open hole says to not include the endpoint. The domain in interval notation is [-2, 2) where we use a parenthesis to not include the endpoint.

-------------

Range = [tex]-4 \le y < 4[/tex]

The smallest possible y value is y = -4. The ceiling for the y values is y = 4, but we can't actually reach this value due to the open hole.

The range in interval notation is [-4, 4)

=============================================================

Problem 7

Domain = [tex]-4 < x \le 2[/tex]

Same idea as earlier. Now the open hole is at the left endpoint. The right most point occurs not at an endpoint this time.

The domain in interval notation is (-4, 2]

-------------

Range: [tex]-4 < y < 4[/tex]

Both endpoints are open holes, so we exclude both endpoints.

The range in interval notation is (-4, 4). Unfortunately in this case, interval notation looks identical to ordered pair notation.

=============================================================

Problem 8

Domain = [tex]-5 < x < 3[/tex]

Domain in interval notation = (-5, 3)

The graph is too blurry to be able to determine the range.

Answer:

the answer is                                                 b

Step-by-step explanation:

Answer:

Step-by-step explanation:(F)=1/F+6

We move all terms to the left:

(F)-(1/F+6)=0

Domain of the equation: F+6)!=0

F∈R

We get rid of parentheses

F-1/F-6=0

We multiply all the terms by the denominator

F*F-6*F-1=0

We add all the numbers together, and all the variables

-6F+F*F-1=0

Wy multiply elements

F^2-6F-1=0

a = 1; b = -6; c = -1;

Δ = b2-4ac

Δ = -62-4·1·(-1)

Δ = 40

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

F1=−b−Δ√2aF2=−b+Δ√2a

The end solution:

Δ‾‾√=40‾‾‾√=4∗10‾‾‾‾‾‾√=4√∗10‾‾‾√=210‾‾‾√

F1=−b−Δ√2a=−(−6)−210√2∗1=6−210√2

F2=−b+Δ√2a=−(−6)+210√2∗1=6+210√2

Answer:

a

[tex]E[(3X+1)^2]= 8.5  [/tex]

b

[tex]P(1 <  X < 2)=0.1170 [/tex]

Step-by-step explanation:

From the question we are told that

   The parameter of  X  is  [tex]\lambda  =  2[/tex]

Generally the expected value of  X is  

    [tex]E(X) =  \frac{1}{\lambda }[/tex]

     [tex]E(X) =  \frac{1}{2}[/tex]

=>  [tex]E(X) =  0.50 [/tex]

Generally we have that

     [tex]E(X^2) =  E(X)^2 + E(X)^2[/tex]

=>  [tex]E(X^2) =  [\frac{1}{2}] ^2 + [\frac{1}{2} ]^2[/tex]

=>  [tex]E(X^2) =  0.5 [/tex]

Generally

    [tex]E[(3X+1)^2]= E(9x^2 + 1 + 6x)[/tex]

=>  [tex]E[(3X+1)^2]= 9E[X^2] + 1 + 6 E[X])[/tex]

=>    [tex]E[(3X+1)^2]= 9* 0.5  + 1 + 6 * 0.5 [/tex]

=>   [tex]E[(3X+1)^2]= 8.5  [/tex]

Generally  

   [tex]P(1 <  X < 2)=  P(X < 2) - P(X < 1)[/tex]

Here  [tex]P(X <  2 ) =  e^{- 2 * \lambda }[/tex]

=>      [tex]P(X <  2 ) =   e^{- 2 * 2 }[/tex]

=>       [tex]P(X <  2 ) =   e^{- 4}[/tex]

and  

    [tex]P(X <  1 ) =   e^{- 1 * \lambda }[/tex]

    [tex]P(X <  1 ) =   e^{- 1 * 2 }[/tex]

    [tex]P(X <  1 ) =   e^{-2 }[/tex]

So

   [tex]P(1 <  X < 2)= e^{-2 } -  e^{- 4} [/tex]

  [tex]P(1 <  X < 2)=0.1170 [/tex]

Answer:

$26.05

Step-by-step explanation:

$8.99(2) + $19.99 + $11.99(3) = $73.95 - $100

Hope this helped :)

Answer:

[tex] f(-2) = 13 [/tex]

[tex] f(0) = 9 [/tex]

[tex] f(5) = -1 [/tex]

Step-by-step explanation:

Given:

[tex] f(x) = -2x + 9 [/tex]

Required:

Find,

h(-2); h(0), and h(5)

SOLUTION:

Plug in the value of x into [tex] f(x) = -2x + 9 [/tex] in each case as follows:

[tex] f(-2) = -2(-2) + 9 [/tex]

[tex] f(-2) = 4 + 9 [/tex]

[tex] f(-2) = 13 [/tex]

[tex] f(0) = -2(0) + 9 [/tex]

[tex] f(0) = 0 + 9 [/tex]

[tex] f(0) = 9 [/tex]

[tex] f(5) = -2(5) + 9 [/tex]

[tex] f(5) = -10 + 9 [/tex]

[tex] f(5) = -1 [/tex]

The value of h(x) when x= -2,0, and 5 is; 13, 9 and -1 respectively.

The function, h(x) given is; h(x) = -2x +9 .

As such, evaluation of h(x) when x = 2,0, and 5 is as follows;

For x = -2

For x = 0

For x = 5

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Answer:

300,000

Step-by-step explanation:

Answer:

2/5 is bigger

Step-by-step explanation:

2/5 is 0.40

Answer:

9 < x < 0

Step-by-step explanation:

from 0 to 9 i think

Answer:

0 and 0

Step-by-step explanation:

it stays the same 7 to 17 is 7

14 to 21 is 7 etc...

The amplitude of the function is 48 units.

The period of the function is 28 units.

The graph has a vertical shift of 48 unit.

To determine the amplitude and period of the cosine function that describes the relationship between the day (d) and the illuminated percentage of the moon (%), we can analyze the given data:

d     %

0   48

14   96

21  48

28   0

Amplitude:

The amplitude of a cosine function represents half the difference between the maximum and minimum values of the function.

So, (96 - 0) / 2

= 48 units.

Period:

The period of a cosine function is the length of one complete cycle.

Therefore, the period of the function is 28 units.

Vertical shift:

The vertical shift represents the displacement of the graph vertically.

The graph has a vertical shift of 48 unit.

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When you indicate triangle congruency, the order of the letters matter. As you see these statements, look at how the side length names correspond to how the letters are written in its order, ΔABC ≅ ΔDEF. (By the way, triangles aren't equal with an = sign. It's a ≅ congruency sign.)

AB is congruent or the same length as DE.

BC is congruent or the same length as EF.

AC is congruent or the same length as DF.

In the same way, all of the angles in the corresponding order are ALSO congruent. By the way, we say that angles are congruent and angle MEASURES (like 30 degrees) are equal.

m∠A = m∠D

m∠B = m∠E

m∠C = m∠F

In the same way, we can try to find m∠C, or measure C!

1. Let's find the missing angle!

So, we know that m∠A is 50 degrees and m∠E is 30 degrees. Since we know that m∠E = m∠B because of the order of the triangles, now we know two of the angles in triangle ABC.

m∠A = 50 degrees

m∠B = 30 degrees

m∠C = 180 degrees - (50 + 30) = 100 degrees

(We minus from 180 degrees because 180 degrees is the sum of the angles in a triangle!)

And that's it! If you have any questions, please feel free to ask questions. I'm not here to judge, and I'm only here to help. Again, ask questions if you need help. It's crucial that you know the basics of geometry!

Answer:

x=40

Step-by-step explanation:

Answer:

A=43

B=32

C=105

Answer: 325

Step-by-step explanation:

All your doing is multiplying

Answer:

The answer is 325

Step-by-step explanation:

the problem directly tells me that c(x)= 50x is how many words i can type in x minutes. then proceeds to ask me how many words i can type in 6.5 minutes.

in this case, x=6.5.

substitute and solve!

c(6.5)= 50(6.5)

c(6.5)= 325

according to this function, i can type 325 words in 6.5 minutes.

hope this helps!!

Answer:240 seconds

Step-by-step explanation:

Answer:

The price that maximizes the revenue is $63.75

Step-by-step explanation:

Analyzing the statement one after the other.

[tex]Initial\ Quantity = 550[/tex]  ---- When ----- [tex]Initial\ Price = \$100[/tex]

When there's a reduction of $1, we have:

[tex]Quantity = 550 + 20x[/tex] and [tex]Price = 100 - x[/tex]

Where x represents the maximum reduction

At this point, we need to calculate the revenue (R)

[tex]R = Quantity * Price.[/tex]

[tex]R = (550 + 20x) * (100 - x)[/tex]

Open Brackets

[tex]R = 55000 - 550x + 2000x - 20x^2[/tex]

[tex]R = 55000 +1450x - 20x^2[/tex]

Differentiate both sides with respect to x

[tex]\frac{dR}{dx} = 0 + 1450 - 40x[/tex]

[tex]\frac{dR}{dx} = 1450 - 40x[/tex]

To maximize revenue;

[tex]\frac{dR}{dx} = 0[/tex]

So:

[tex]1450 - 40x = 0[/tex]

[tex]1450 =40x[/tex]

Solve for x

[tex]x = 1450/40[/tex]

[tex]x = 36.25[/tex]

Recall that:

[tex]Price = 100 - x[/tex]

Substitute [tex]x = 36.25[/tex]

[tex]Price = 100 - 36.25[/tex]

[tex]Price = 63.75[/tex]

Hence:

The price that maximizes the revenue is $63.75

Answer:

7

Step-by-step explanation:

g(x)=4x-5

g(3)= 4(3)-5

=12-5

=7

Answer:

g(3)=4x-3

Step-by-step explanation:

put 3 into x

know g(3)=4x-3=4×3-1=12-1=11

11 will be the answer

Answer:

jdjcnsixjkskzmdmdmxndm

Answer:

Step-by-step explanation:

Given

N(t) = 29t²-115t+52

T(t) = 6t+1.5

To get the composite function N(T(t)), we will follow the steps

N(T(t)) = N(6t+1.5)

To get N(6t+1.5), we will replace t in N(t) with 6t+1.5 as shown:

N(6t+1.5) = 29(6t+1.5)²-115(6t+1.5)+52

N(6t+1.5) = 29(36t²+18t+2.25)-690t-172.5+52

N(6t+1.5) = 1044t²+522t+65.25-690t-172.5+52

N(6t+1.5) = 1044t²+522t-690t+65.25-172.5+52

N(6t+1.5) = 1044t²-168t-55.35

Hence;

N(T(t)) = 1044t²-168t-55.35

To determine the time when the bacteria count reaches 500, we will equate the expression to 500 and find t

500 = 1044t²-168t-55.35

1044t²-168t-55.35-500= 0

1044t²-168t-555.35 = 0

Factorize

t =140±√1630115/1740

t = 0.81

Hence the time reached when the bacteria was 500 hours is 0.81hours

Answer:

y = 3x - 1

Step-by-step explanation:

Original line: y = 3x + 5

Parallel line has the same slope, so use the point-slope form.

y - (-13) = 3(x - (-4))

y + 13 = 3x +12

y = 3x -1

The equation of the line that is parallel to the line shown in the graph and passes through the point (-4,-13) is y = 2x - 5.

A straight line is a combination of endless points joined on both sides of the point.

The slope 'm' of any straight line is given by:

[tex]\rm m =\dfrac{y_2-y_1}{x_2-x_1}[/tex]

It is given the graph of the linear equation:

From the graph:

The line passes through (-3, -1) and (0, 5)

The slope of the line is shown in the graph:

m = (5+1)/(0+3)

m = 2

The equation of the line that has slope -2 and passes through (-4, -13):

[y - (-13)] = 2[(x - (-4)]

y + 13 = 2(x + 4)

y + 13 = 2x + 8

y = 2x + 8 - 13

y = 2x - 5

Thus, the equation of the line that is parallel to the line shown in the graph and passes through the point (-4,-13) is y = 2x - 5.

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Step-by-step explanation:

David earns $8 per hour. He works 40 hours each week. How much does he earn in 6 weeks? . After 6 weeks, who earned more money? How much more money?

he would earn 1,680 because if he works 40 hours per week when you divide by 7 cuz there a 7 days in a week he works 5 hours each day. then we multiply 5 with 8 and it's 40 so he earns 40 dollars per day then if week multiply 40 with 7 we get 280 and that's what he earns per week. then I came and tried to figure out how many days are in 6 weeks and I got 42 so then i came and multiplied the hours(5) which then gave me 210 then I multiped that (210) and 8 together and got 1,680

1.Michael earns $9 per hour. He works 28 hours each week. How much does he earn in 6 weeks?

so what i did was divide 28 by 7 the 7 was for the days and the 28 was for the hours so per day he works 4 hours and he earns 36 dollars per day .and then i came to know what the final answer was I came a figured out how many days are in 6 weeks and it's 42 so then I came and multiped the hours with the days which gave me 168  then I multiped that by the amount of money he earns per hour and it gave me 1,512 per 6 weeks

Answer:

[tex]y=\frac{1}{4}(x)+2[/tex]

you can write this as

[tex]f(x)=\frac{1}{4}x+2[/tex]

Step-by-step explanation:

2 points

(-4,1)(0,2)

[tex]y=\frac{1}{4}x+2[/tex] is the equaction of the line thats in the grapj

Why and How I got it?

you had 2 points, so you can using the slope equaction

Rise over run

why is slope important?

using the y incept equactions

y=mx+b, where slope is m

so you get slope you got m

Solve

rise over run

[tex]\frac{2-1}{0-(-4)}[/tex]

so you get

[tex]y=\frac{1}{4}x+b[/tex]

How do you get B?

you plug 1 points in

[tex]-4=\frac{1}{4}(1)+b[/tex]

Hoped this helped ya

<3

Answer: 673.98

Step-by-step explanation: The 8 is the hundredth place, and anything less than five you don't round up

Answer:

3i-1

Step-by-step explanation:

2+3i-3

3i-1

Answer:

-1 + 3i.

Step-by-step explanation:

Hope this helps!

Answer:

[tex]C(t)=5\cdot(0.9)^t[/tex]

Step-by-step explanation:

The exponential function is often used to model natural growing or decaying processes, where the change is proportional to the actual quantity.

An exponential decaying function is expressed as:

[tex]C(t)=C_o\cdot(1-r)^t[/tex]

Where:

C(t) is the actual value of the function at time t

Co is the initial value of C at t=0

r is the decaying rate, expressed in decimal

The concentration of the pollutants starts at Co=5 mg/lt. We also know the pollutant reduces its concentration by 10% each hour. This gives us a value of r = 10% / 100 = 0.1

Substituting into the general equation:

[tex]C(t)=5\cdot(1-0.1)^t[/tex]

Operating:

[tex]\boxed{C(t)=5\cdot(0.9)^t}[/tex]

y(n) = 5(0.9)ⁿ

y(n) = a(1 - b)ⁿ

where;

y is the final amount at time n,

a is the original amount

b is the decay factor

x is the amount of time that has passed.

Thus;

a = 5 mg/L.

We are told that the pollutant reduces its concentration by 10% each hour. Thus; b= 10%

b = 0.1

y(n) = 5(1 - 0.1)ⁿ

y(n) = 5(0.9)ⁿ

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Answer:

Linear

Step-by-step explanation:

y=x-5/4 is a linear equation.

Answer:

the direction of the road

Step-by-step explanation:

To calculate the net force, we need to know the direction through which the forces are acting.

Are the forces directed towards one another or against each other?

  Net force is a vector sum of forces that acts on a body. It is that single force that can replace two or more forces acting on a body.

So, without knowing the direction, we cannot calculate the net force.