Help me with this please

Answer:

700,000+ 8+20+ 40,000

Step-by-step explanation:

All you needed to do was line them up and find the missing value. Or add all of the given numbers and subract the answer. Quite simple actually

Answer:

700,000+40,000+ 20+8= 740,028

20 is the missing number

Answer:

y= [tex]\frac{25}{11}[/tex]x

coordinates: (11,25)  (22,50) (33,75)

Step-by-step explanation:

I dont really understand this question but I input the equation into desmos (a graphing website) and that is the equation I got

Answer:

26

Step-by-step explanation:

Fitst,  you substitute

f(2) = 3(2) + 20

f(2) = 6 + 20

f(2) = 26

your answer is 26

Answer:

c.)  26

Step-by-step explanation:

f(2) = 3(2) + 20

f(2) = 6 + 20

f(2) = 26

Answer:

a

Step-by-step explanation:

because it goes into negaative so its smaller

Answer:

B

Step-by-step explanation:

Look at the way the arrow points. It has a dot on the -3 meaning it could be equal as well. Since it’s going negative, that chooses the way the inequality faces.

it seems that is wrong.sorry for that.

Answer:

0.75 mg

Step-by-step explanation:

From the question given above the following data were obtained:

Original amount (N₀) = 1.5 mg

Half-life (t₁/₂) = 6 years

Time (t) = 6 years

Amount remaining (N) =.?

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Half-life (t₁/₂) = 6 years

Time (t) = 6 years

Number of half-lives (n) =?

n = t / t₁/₂

n = 6/6

n = 1

Finally, we shall determine the amount of the sample remaining after 6 years (i.e 1 half-life) as follow:

Original amount (N₀) = 1.5 mg

Half-life (t₁/₂) = 6 years

Number of half-lives (n) = 1

Amount remaining (N) =.?

N = 1/2ⁿ × N₀

N = 1/2¹ × 1.5

N = 1/2 × 1.5

N = 0.5 × 1.5

N = 0.75 mg

Thus, 0.75 mg of the sample is remaining.

The duration of decay is the same as the half-life of radium, therefore,

half the mass  of radium will remain after 6 years.

Response:

The given mass of the sample of radium, N₀ = 1.5 mg

The half-life of radium = 6 years

Required:

The amount of the sample that will remain after 6 years

Solution:

Let N(t) represent the mass of the sample that remains after 6 years, we have;

[tex]N(t) = \mathbf{N_0 \cdot \left(\dfrac{1}{2} \right)^{\dfrac{t}{t_{1/2}} }}[/tex]

Which gives;

[tex]N(6) = \mathbf{1.5 \times \left(\dfrac{1}{2} \right)^{\dfrac{6}{6} }} = 0.75[/tex]

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Answer:

not similar

Step-by-step explanation:

9514 1404 393

Answer:

  (d)  ΔABC ~ ΔFED

Step-by-step explanation:

All of the answer choices start with ΔABC, so the first-named vertex is the one with no angle marking. In the smaller triangle, that is vertex F.

Only one answer choice matches vertex A with vertex F:

  ΔABC ~ ΔFED

Answer:

x>-2

on a number line you would put a circle on -2 and draw a line going to the right since x is greater than -2

Step-by-step explanation:

Answer:

4 kilograms

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

b. 75°

Step-by-step explanation:

Draw a triangle. Write a person name and a point name (a letter) at each vertex: Sam A, Sonny B, and Sal C at the vertices.

Write the distances as AB = c = 153 ft; AC = b = 201 ft; BC = a = 175 ft.

We are looking for angle B.

Since we have a triangle with three side lengths and no angle measures, we use the Law of Cosines.

[tex] b^2 = a^2 + c^2 - 2ac \cos B [/tex]

[tex] 201^2 = 175^2 + 153^2 - 2(175)(153) \cos B [/tex]

[tex] 40401 = 30635 + 23409 - 53550 \cos B [/tex]

[tex] -53550 \cos B = -13643 [/tex]

[tex] \cos B = \dfrac{-13643}{-53550} [/tex]

[tex] \cos B = 0.254771242 [/tex]

[tex] B = \cos^{-1} 0.254771242 [/tex]

[tex] B = 75^\circ [/tex]

Answer: b. 75°

Answer:

Step-by-step explanation:

1). [tex]\frac{2}{3}n-\frac{3}{4}n+\frac{1}{6}n+2\frac{2}{9}n[/tex]

= [tex]\frac{2}{3}n-\frac{3}{4}n+\frac{1}{6}n+(2+\frac{2}{9})n[/tex]

= [tex](\frac{2}{3}-\frac{3}{4}+\frac{1}{6})n+(2+\frac{2}{9})n[/tex]

= [tex](\frac{8}{12}-\frac{9}{12}+\frac{2}{12})n+(2+\frac{2}{9})n[/tex]

= [tex]\frac{(8-9+2)}{12}n+(2+\frac{2}{9})n[/tex]

= [tex]\frac{1}{12}n+(2+\frac{2}{9})n[/tex]

= [tex](\frac{1}{12}+2+\frac{2}{9})n[/tex]

= [tex](\frac{3}{36}+\frac{72}{36}+\frac{8}{36})n[/tex]

= [tex]\frac{83}{36}n[/tex]

= [tex]2\frac{11}{36}n[/tex]

2). [tex]\frac{2}{5}g-\frac{1}{6}-g+\frac{3}{10}g-\frac{4}{5}[/tex]

= [tex](\frac{2}{5}-1+\frac{3}{10})g-(\frac{1}{6}+\frac{4}{5})[/tex]

= [tex](\frac{4}{10}-\frac{10}{10}+\frac{3}{10})g-(\frac{5}{30}+ \frac{24}{30})[/tex]

= [tex](\frac{4-10+3}{10})g-(\frac{5+24}{30})[/tex]

= [tex]\frac{-3}{10}g-\frac{29}{30}[/tex]

= [tex]-\frac{3}{10}g-\frac{29}{30}[/tex]

3). [tex]i+6i-\frac{3}{7}i+\frac{1}{3}h+\frac{1}{2}i-h+\frac{1}{4}h[/tex]

= [tex]7i-\frac{3}{7}i+\frac{1}{2}i+\frac{1}{3}h-h+\frac{1}{4}h[/tex]

= [tex](7-\frac{3}{7}+\frac{1}{2})i+(\frac{1}{3}-1+\frac{1}{4})h[/tex]

= [tex](\frac{98}{14} -\frac{6}{14}+\frac{7}{14})i+(\frac{4}{12}-\frac{12}{12}+\frac{3}{12})h[/tex]

= [tex](\frac{98-6+7}{14})i+(\frac{4-12+3}{12})h[/tex]

= [tex]\frac{99}{14}i-\frac{5}{12}h[/tex]

Answer:

12.66 yards/hour

Step-by-step explanation:

38 feet/3 feet per yard=12.66 yards

Answer:

12 2/3 is the answer...

Step-by-step explanation:

Answer: 69.12

Step-by-step explanation: circumference=2*pi*radius

Answer:

The circumference of the circle is 69.12 m

Step-by-step explanation:

Circumference of a Circle

Given a circle of radius r, the circumference or perimeter of the circle is calculated by the formula:

[tex]C=2\pi\ r[/tex]

The circle shown in the image has a radius of r=11 m, thus the circumference is:

[tex]C=2\pi\ *11[/tex]

[tex]C=22\pi[/tex]

Calculating:

C = 69.12 m

Answer:

I think it's 0.083

Step-by-step explanation:

Answer:

0.0833333 (3 is repeating)

Step-by-step explanation:

Answer:

A. (3,4)

B  (4,2)

C (1/2,1/2)

D (1,2 1/2)

E (1 and 3/4, 4 and 1/4)

Step-by-step explanation: coordinates

Answer:

15.1 $

Step-by-step explanation:

Answer:

2.3478 x 10^6

Step-by-step explanation:

Answer:

Step-by-step explanation:

A

Answer:

b

Step-by-step explanation:

Answer:

The answer to the question provided is letter b:

[tex] \frac{7}{9} \: and \: \frac{28}{36} [/tex]

Answer:

Wala po line jan♥️

Answer:

y=25.5°

Step-by-step explanation:

because there's an isosceles triangle, 180-51 = 129

so 129/2 = 64.5, which is X

there is also a right angle so 90-64.5 = 25.5, which is y

Answer:

30+y

Step-by-step explanation:

Answer:

He didn't include a parenthesis around 5+y

Step-by-step explanation:

Answer: 486 in

Just did this on edge

The enlargement transformation applied to the rectangular figure gives

a rectangle that is enlarged and similar to the figure.

Correct response:

The given dimensions of the picture are;

Height, [tex]\overline{MN}[/tex] = 6 in.

Width, [tex]\overline{LP}[/tex] = 4 in.

The length of QL' = 12  + 42 = 54

By similar triangles, we have;

[tex]\dfrac{\overline{L'P'}}{\overline{LP}} = \mathbf{ \dfrac{\overline{QL'}}{\overline{QL}}}[/tex]

Which gives;

[tex]\dfrac{\overline{L'P'}}{6} = \mathbf{ \dfrac{54}{12}}[/tex]

[tex]\overline{L'P'} = \dfrac{54 }{12} \times 6 = \mathbf{27}[/tex]

Given that an enlargement gives similar figures, we have;

[tex]\dfrac{\overline{L'P'}}{\overline{LP}} = \mathbf{\dfrac{\overline{L'M'}}{\overline{LM}}} = Scale \, factor \ of \ the \ enlargement[/tex]

Therefore;

[tex]\dfrac{27}{6} = \dfrac{\overline{L'M'}}{4}[/tex]

Which gives;

[tex]\overline{L'M'} = \dfrac{27}{6} \times 4 = \mathbf{ 18}[/tex]

The area of the enlarged picture is, A = [tex]\overline{L'M'}[/tex] × [tex]\overline{L'P'}[/tex]

Which gives;

A = 27 × 18 = 486

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Answer: 50% increase

Step-by-step explanation:

Answer:

V = 3 m/s

Step-by-step explanation:

V= wavelength (meters) x frequency (Hz)

Answer:

It's A and the answer is 4^x

Step-by-step explanation:

The exponential function that models the data is f(x) = [tex]4^x[/tex].

A mathematical phrase, rule, or law that establishes the link between an independent variable and a dependent variable (the dependent variable).

The characteristic that every input is associated to exactly one output defines a function as a relationship between a set of inputs and a set of allowable outputs.

We have a table.

The given function is not a linear because the difference of two consecutive term is not constant.

Now, the ratio

1/(1/12)= 12

12/1= 12

144/12= 12

1728/ 144= 12

If the ratio is same then the function is Exponential.

So, the exponential function is

f(x) = [tex]4^x[/tex]

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