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The answer choice which represents the quotient of the polynomials given is; 2x² +x -3.

According to the task content, the quotient of the polynomial division; (2x4 – 3x3 – 3x2 7x – 3) ÷ (x2 – 2x 1) is required;

Hence, it follows from long division of polynomials that the required quotient is; 2x² +x -3.

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Answer:

D: 2x² +x -3

Step-by-step explanation:

Answer:

[tex]0 < x < 6[/tex]

Step-by-step explanation:

This question asks to solve an inequality which can be written as:

[tex]\sqrt{x^2-6x+9} < 3[/tex]

Solve for x:

[tex]\sqrt{x^2-6x+9} < 3\\x^2-6x+9 < 9\\x^2-6x < 0\\x(x-6) < 0[/tex]

From here we can deduce that the inequality is [tex]0[/tex] when:

[tex]x = 0[/tex] or [tex]x = 6[/tex]

We can write the solution as:

[tex]0 < x < 6[/tex]

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's evaluate ~

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 6x + 9 } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 3x - 3x+ 9 } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{}(x - 3) - 3(x - 3) } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ (x - 3)(x - 3) } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ (x - 3) {}^{2} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: { (x - 3) {}^{} } [/tex]

Now, we have been given that value of x :

[tex]\qquad \sf  \dashrightarrow \:x < 3[/tex]

So, let's plug the value of x as 3 in the given expression ~

[tex]\qquad \sf  \dashrightarrow \:3 - 3[/tex]

[tex]\qquad \sf  \dashrightarrow \:0[/tex]

Therefore, we can conclude that :

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 6x + 9 } < 0[/tex]

Value of the expression should be less than 0

The length of arc JL is 24.46 units see attachment for diagram.

An arc is a part of the circumference of a circle that meets two radii of a circle to form a sector.

Analysis:

From bigger triangle, if we bisect 144, the line meets JL at 90°.

To find AL,

sin 72 = AL/6

AL = 6 sin 72 = 5.71

To find the angle at O

∠O = 2∠K ( twice angle at circumference is equal to angle at center)

∠O = 2 (144) = 288°

For smaller right-angled triangle,

sin 144 = AL/OL

sin 144 = 5.71/OL

OL = radius of circle =  5.71/0.587 = 9.73 unit

length of arc JL = ∅/360 x 2πr

= 144/360 x 2 x 3.142 x 9.73 = 24.46 units

In conclusion, the length of arc JL is 24.46 units

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Answer:

The reflection over the y-axis means that we just multiply the x-value of the coordinates by -1.  So we take (4, 0) and get the x-value of 4 and multiply it by -1 which gives us (-4, 0) which is option C.

The correct student is Marcus because the power of the polynomial decreases till  0

The polynomial expressions are given as:

Marcus: 3x³ - 4x²y + y³ + 2

Ariel: y³ - 4x²y + 3x³ + 2

The standard form of a polynomial with the variable x is:

P(x) = ax³ + bx² + cx + d

This means that the power of the polynomial decreases till it gets to 0

Using the above form as a guide, the correct student is Marcus.

Marcus is correct because the power of the polynomial decreases till it gets to 0

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Answer:

720

Step-by-step explanation:

A polygon with 6 angles is called a hexagon

To find the sum of interior angles, we use the following formula:

(n-2)*180 (n is the number of angles)

4*180 = 720

Answer:

A = 81π units²

Step-by-step explanation:

the area (A) of a circle is calculated as

A = πr² ( r is the radius ) , then

A = π × 9² = 81π units²

Answer:

you can approximate it to 61°

Answer:

D

Step-by-step explanation:

Start by plugging in all the domain values (domain means input) into the function.

f(-1) = 4(-1) + 6 =-4+6=2

f(0) = 4(0) +6=0+6= 6

f(2) = 4(2) +6 = 8+6=14

Compute the sum to simplify C :

[tex]C = \begin{bmatrix}16-0.5 & 9+0 \\ -3+5 & 0 + 8 \\ 4-3 & -10+14\end{bmatrix} = \begin{bmatrix}15.5 & 9 \\ 2 & 8 \\ 1 & 4\end{bmatrix}[/tex]

Now, [tex]c_{ij}[/tex] is the entry of the matrix in row i and column j, so

[tex]C = \begin{bmatrix}15.5 & \boxed{9} \\ 2 & 8 \\ 1 & 4\end{bmatrix} \implies c_{12} = 9[/tex]

[tex]C = \begin{bmatrix}15.5 & 9 \\ 2 & 8 \\ \boxed{1} & 4\end{bmatrix} \implies c_{31} = 1[/tex]

[tex]C = \begin{bmatrix}15.5 & 9 \\ 2 & \boxed{8} \\ 1 & 4\end{bmatrix} \implies c_{22} = 8[/tex]

Answer: 6, 6, 9 and 25

Step-by-step explanation:

bbringingbbringingout the data's from the graph and arrangementsarrangingarrangingarrangementsarrangingarranging them serially that's from smallest to biggest biggest, then selecting the middle number if the number of entire entries is an odd number but if it's an even number you take the average of the two middle number

Answer: 48 feet

Step-by-step explanation:

Answer:

12 feet

Step-by-step explanation:

Containers are generally in the shape of a rectangular prism.

Formula

The value of uv to the nearest tenth or as an integer is 3.1 units

uv is the adjacent side of the right triangle.

uv can be found using trigonometric ratios as follows:

Therefore,

tan 63 = opposite / adjacent

Hence,

tan 63 = 6 / adjacent

cross multiply

uv tan 63 = 6

divide both sides by tan 63

uv = 6 / tan 63

uv = 6 / 1.96261050551

uv  = 3.05716906145

uv = 3.1 units

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Answer:

yo whats your name i think that we are from the same class

Step-by-step explanation:

Answer:

x = 8

z = 65

Step-by-step explanation:

Through various rules, we are able to assert: (6x + 67)° = 115°.

Now, we want to solve for x:

6x + 67 = 115

6x = 48

x = 8

We know that z° is equal to the complement of (6x + 67)°, and together these must sum to 180°. Therefore, we can simply take 180° - 115° to find that z° = 65°.

Answer:

Step-by-step explanation:

Answer: Choice D

y-4 = -3(x+1)

========================================================

Explanation:

Let's first find the slope of the line through (-1,4) and (1,-2)

[tex](x_1,y_1) = (-1,4) \text{ and } (x_2,y_2) = (1,-2)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{-2 - 4}{1 - (-1)}\\\\m = \frac{-2 - 4}{1 + 1}\\\\m = \frac{-6}{2}\\\\m = -3\\\\[/tex]

The slope is -3, which tells us that the answer must be choice D.

Choices A,B, & C can be eliminated because choices A and B have a slope of -13, while choice C has a slope of 3.

Refer to the point-slope format [tex]y-y_1 = m(x - x_1)[/tex] where m is the slope and [tex](x_1,y_1)[/tex] is a point the line goes through.

Answer: x = 0, x = -3, x = 2

Step-by-step explanation:

f(x) = x^3 + x^2 - 6x

f(x) = 0

x^3 + x^2 - 6x = 0

x(x^2 + x - 6) = 0

x = 0 or

x^2 + x - 6 = 0

D = b^2 - 4ac = 1 - 4*(-6) = 25

x = (-b - sqrt(D))/(2a) = (-1 - 5)/2 = -3 or

x = (-b + sqrt(D))/(2a) = (-1 + 5)/2 = 2

The coordinates of the fourth vertex, H is; (-6.056, 7.302)

A kite has 4 sides and we know that a pair of diagonally opposite angles of a kite are said to be congruent.

We are given the coordinates of its' vertices as;

E(1,6), F(3,5), and G(4,-3).

The two diagonals are perpendicular;

Slope of EG = (-3 - 6)/(4 - 1)

Slope of EG = -9/5

Equation of line passing through G is;

y = mx + c

-3 = -9/5(4) + c

-15 = -36 + 15c

c = 51/15 = 17/5

y = (-9/5)x + 17/5    ------(1)

Equation of line passing through F is;

y = mx + c

6 = (5/9)(1) + c

54 = -9 + 9c

c = 7

y = (5/9)x + 7   -----(2)

Solving eq 1 and eq 2 simultaneously gives;

x = -1.528 and y = 6.151

If (a, b) are coordinates of vertex H, then;

(a + 3)/2 = -1.528 and (b + 5)/2 = 6.151

Thus;

a = -6.056 and b = 7.302

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Add 12 and 5 to get 17.

Multiply 32 and 10 to get 320.

Add 17 and 320 to get 337.

Subtract 5 from 337 to get 332.

332 ===> Answer

Add 12 and 5 to get 17

Subtract 5 from 10 to get 5.

Multiply 32 and 5 to get 160.

Add 17 and 160 to get 177.

177 ===> Answer

Answer:

Output: 3

Step-by-step explanation:

(x, y)

(Input, Output)

(2, 3)

Answer:

In quadrant I, the answer is A. sin(x) ≈ 0.97

Answer:

0.2165 to the nearest ten thousandth.

Step-by-step explanation:

Sin(15) × cos(15) × cos(30)​

= 0.258819 * 0.965926 * 0.866025

= 0.216506

The height of the given triangular prism.

[tex]h = \frac{V}{ A_{B}}[/tex]

[tex]h = \frac{310}{31} [/tex]

[tex]\large\boxed{\sf{h=10 \: units}}[/tex]

Therefore, the height of the given triangular prism is 10 units.

h= 310/31

h= 10 units

hope this helps

Answer:

h=3

Step-by-step explanation:

Here's the explanation

Move 10 to the other side

5h=25-10

5h=15

h=15/5

h=3

10+5h=25

10+5h-10=25-10

5h=15

[tex]\frac{5h}{5}=\frac{15}{5}[/tex]

h=3

the answer is 3

======================================================

Explanation:

Draw out a right triangle as you see below.

Let's use the pythagorean theorem to find 'a'

[tex]a^2 + b^2 = c^2\\\\a = \sqrt{c^2 - b^2}\\\\a = \sqrt{(9.9)^2 - (7.3)^2}\\\\a = \sqrt{44.72}\\\\a \approx 6.6873\\\\a \approx 6.7\\\\[/tex]