Mathematics College

GIVING BRAINLIEST AND 5 STARS TO BEST ANSWER!!! I HAVE 1 HOUR LEFT!!!!!!

Answers

Answer 1

Answer:

The origin is where x,y lines meet. I put a cirlce there with no label there. Sorry it's messy

Step-by-step explanation:

I'm only a 6th grader. No hate, please. I only did what I learned from my teacher.

Related Questions

Dried rose petals can be used to make rose water. Fatima buys 0.454 kilogram
of rose petals.
• She uses 0.02 kilogram of the rose petals to make rose water.
• Then, she buys an additional 0.056 kilogram of rose petals.
• Finally, she uses 0.095 kilogram of the rose petals to make more rose water.
Fatima completes the steps below and says she has 0.413 kilogram of rose
petals left. What mistake did Fatima make?
Use the drop-down menus to explain her mistake and to find the number of
kilograms of rose petals left.
First Step
Second Step
Third Step
0.454
0.452
0.508
0.02
+0.056
- 0.095
0.452
0.508
0.413
Click the arrows to choose an answer from each menu.
Fatima made her first mistake at the Choose...
step.
She incorrectly Choose...
Fatima has Choose...
Y
kilogram of rose petals left.

Answers

Fatima's claim that she has 0.413 kilogram of rose petals left is wrong

How to determine the amount of rose petals left?

The given parameters are:

Amount purchased = 0.454 kg and 0.056 kgUsed amounts = 0.02kg and 0.095 kg

The amount left is the difference between the amount purchased and the amount used.

So, we have:

Remaining = 0.454 + 0.056 - 0.02 - 0.095

Evaluate

Remaining = 0.395

This means that the remaining amount is 0.395kg, not 0.413 kg

Hence, Fatima's claim that she has 0.413 kilogram of rose petals left is wrong

Read more about sum and difference at:

https://brainly.com/question/2560921

#SPJ1

Answer: she is left with 0.395 kilogram of rose pedals

Step-by-step explanation: she misalinged the first step,

0.454 - 0.02 = 0.434 + 0.056 = 0.490 - 0.095 = 0.395

There was a population of 160 beavers in a National Park. After a year, the population increased by 45%. How many beavers are there in the park now?

Answers

Answer:

232

Step-by-step explanation:

→ Find the percentage multipier

( 100 + 45 )÷ 100 = 1.45

→ Multiply this by the original amount

1.45 × 160 = 232

Please help me do this mathematics question experts

Answers

[tex]\textbf{(i)}\\\\~~~~~~~y= e^{3x} \sin 2x\\\\\\\implies \dfrac{dy}{dx} = \dfrac{d}{dx} \left( e^{3x} \sin 2x \right)\\\\\\~~~~~~~~~~~~=e^{3x} \dfrac{d}{dx} \sin 2x + \sin 2x \dfrac{d}{dx} e^{3x}\\\\\\~~~~~~~~~~~~=2e^{3x} \cos 2x + 3e^{3x}\sin 2x \\\\\\[/tex]

[tex]\textbf{(ii)}\\\\~~~~~~~~y = \dfrac{e^{3x}}{\cos 2x}\\\\\\\implies \dfrac{dy}{dx} = \dfrac d{dx} \left(\dfrac{e^{3x}}{\cos 2x} \right)\\\\\\~~~~~~~~~~~=\dfrac{\cos 2x \dfrac{d}{dx}\left(e^{3x} \right) -e^{3x} \dfrac{d}{dx}( \cos 2x) }{\cos^2 (2x)}\\\\\\~~~~~~~~~~~=\dfrac{3e^{3x} \cos 2x+2e^{3x}\sin2x }{\cos^2(2x)}\\\\\\~~~~~~~~~~~=\dfrac{3e^{3x} \cos 2x}{ \cos^2(2x)} + \dfrac{2e^{3x} \sin 2x}{\cos^2(2x)}\\\\\\~~~~~~~~~~~=3e^{3x}\sec (2x) + 2e^{3x}\sec (2x) \tan (2x)[/tex]

[tex]\textbf{(iii)}\\\\~~~~~~~~~y=( 3x+2)^3\\\\\\\implies \dfrac{dy}{dx} = \dfrac{d}{dx}(3x+2)^3\\\\\\~~~~~~~~~~~=3(3x+2)^2 \dfrac{d}{dx} (3x+2)\\\\\\~~~~~~~~~~~=3(3x+2)^2 \cdot 3\\\\\\~~~~~~~~~~~=9(3x+2)^2[/tex]

[tex]\textbf{(iv)}\\\\~~~~~~~~~x^2 +y^2 = 5xy\\\\\\\implies \dfrac{d}{dx}(x^2 +y^2) = 5\dfrac{d}{dx} (xy)\\\\\\\implies 2x + 2y \dfrac{dy}{dx} = 5\left(x \dfrac{dy}{dx} +y\right)\\ \\\\\implies 2x +2y \dfrac{dy}{dx} = 5x \dfrac{dy}{dx} +5y\\\\\\\implies 2y \dfrac{dy}{dx} - 5x \dfrac{dy}{dx} = 5y-2x\\\\\\\implies (2y-5x) \dfrac{dy}{dx} = 5y-2x\\\\\\\implies \dfrac{dy}{dx} = \dfrac{5y-2x}{2y-5x}[/tex]

rewrite! Write an new and equivalent equation that is easier to solve

Answers

[tex]{\huge{\fcolorbox{yellow}{red}{\orange{\boxed{\boxed{\boxed{\boxed{\underbrace{\overbrace{\mathfrak{\pink{\fcolorbox{green}{blue}{Answer}}}}}}}}}}}}}[/tex]

[tex] \sf 7( \sqrt{m + 1} - 3) = 21[/tex]

we will multiply 7 with bracket

[tex] \sf 7 \sqrt{m + 1} - 21 = 21[/tex]

Now we will take (-21) on LHS to RHS

[tex] \sf 7 \sqrt{m + 1} = 21 + 21 \\ \\ \sf7 \sqrt{m + 1 } = 42 \\ \\ \sf \sqrt{m + 1} = \frac{42}{7} \\ \\ \sf \sqrt{m + 1} = 6[/tex]

Now we will do squaring both sides

[tex] \sf {( \sqrt{m + 1}) }^{2} = {(6)}^{2} \\ \\ \sf \red {m + 1 = 36}[/tex]

[tex]\sf{ 7( \sqrt{m+1} - 3)=21}[/tex]