Given the following equation: NaOH + HCl -> NaCl + H2O. Calculate the mass of water produced when 80.0 g of NaOH react with excess HCl.

Let's see the balanced equation

[tex]\\ \rm\Rrightarrow 2Ca+O_2\longrightarrow 2CaO[/tex]

Hence

As moles are equal given

Answer:

1. Boron B 13 2 Non-Metal

2. Aluminium Al 13 3 Metal

3. Tin Sn 14 5 Metal

4. Helium He 18 1 Non- Metal

5. Neon Ne 18 2 Non- Metal

6. Calcium Ca 2 4 Metal

7. Francium Fr 1 7 Metal

8. Gold Au 11 6 Metal

Answer:

a. C (s)+ 02(g)---->C02(g)

b. CO2(g) +C(s)--->2CO(g)

Explanation:

This reaction is the method of purification of some precious metals such a iron(Fe) in it's ore. a.The carbon(coke) is oxidized to carbon (IV) oxide

b. the carbon dioxide gas is reduced with the same carbon to produce carbon(II) oxide.

Answer:

Fatty acids and glycerol.

Explanation:

I hope this helps! :)
(The process is called lipolysis by the way)

The property of mixture which describes a mixture are it can be separated by physical methods, it can appear different from different sources and it cannot be described by a chemical symbol or formula.

Mixtures are the compounds which are formed by the addition or combination of one or two elements or compounds.

As in the mixtures many states of matters are present and it will be filtered by using various physical methods, and it is not chemically shown by single chemical symbol or formula. Mixtures are also of two types:

Hence options (1), (3) and (4) are correct.

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Answer:

2H2 + O2 —-> 2H2O

The mole ratio of H2 to H2O is 2 : 2 = 1:1

4 moles of H2 = 4 moles of H2O

Moles of H20 = 4mol

Molar mass of H2O = 18g/mol

Mass = moles X Molar mass

= 4mol x 18g/mol

= 72g

Mass of H2O is 72g

Answer:

Total flow: = 1000 cfm = 4.7 x 10 ml/sec. Stack Ht.: 2.7m (9 ft) ... 1.2x10-8. 6.4x10 7. C-14. 4.3x10 7. 1.0x10 5. 2.0x10 8. 1.1x10-8. Na-22. 1.3x1i dont know how to explain it

Answer:

Write the name of high quatity of coal​

Explanation:

That should be 5mols of solute

Now

Let that volume be V

Answer:

1) because of heating

2) because of hammering

Answer:

[tex]\displaystyle K_a = \frac{[\text{H$_3$O}^+][\text{F}^-]}{[\text{HF}]}[/tex]

Explanation:

Write the reaction of HF (a weak acid) with water:
[tex]\displaystyle \text{HF}_\text{(aq)} + \text{H$_2$O}_\text{($\ell$)} \rightleftharpoons \text{H$_3$O}^+_\text{(aq)} + \text{F}^-_\text{(aq)}[/tex]

Recall that the equilibrium constant expression for an equilibrium reaction is the product of the concentration of the products over the product of the concentration of the reactants raised to their respective coefficients.

The equilibrium constant expression for this equation will hence be:

[tex]\displaystyle K_a = \frac{[\text{H$_3$O}^+][\text{F}^-]}{[\text{HF}]}[/tex]

Note that pure solids and liquids are not included in the equilibrium expression.

In conclusion:

[tex]\displaystyle K_a = \frac{[\text{H$_3$O}^+][\text{F}^-]}{[\text{HF}]}[/tex]

Answer:

It's b

Explanation:

Answer:

When matter interact with EMR then spectrum is obtained. We can understand both spectra using Bohr's hydrogen spectrum. let's have a look on Bohr's hydrogen spectrum what does it say. It says when a electron gains energy it moves from one energy level to other(lower to higher) which is Absorption phenomenon. When the electrons returns from excited state to ground state they emits several spectral lines. this spectrum is called as emission spectrum. inshort the

Emission spectrum is spectrum of electromagnetic radiations that were emitted from the higher energy state(Excited state) to lower energy state(Ground state). and study of emission spectrum is known as AES (Atomic Emission spectroscopy).

When an atom or ion is subjected to EMR, it absorbs certain level of radiations, and when this absorbed energies are studied under spectroscopy they are plotted as absorption spectrum, and study of Absorption spectrum is known as AAS (Atomic Absorption spectroscopy).

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Answer:

because in the different countries it is distributed unevenly.

Explanation:

hope this helps

Answer:

Fluorine needs two more electrons on the outermost shell.

Explanation:

I'm in K12 too.

Given that the mixture of the three gases has a pressure of 2.6 atm, the partial pressure of O₂ is 1.924 atm

This law states that at contact temperature, the total pressure of a mixture of gases is equal to the sum of the partial pressure exerted by each gas. Mathematically, it is expressed as

Total pressure = partial pressure of A + partial pressure of B

Partial pressure of O₂ = (percentage of O₂) × total pressure

Partial pressure of O₂ = 74% × 2.6

Partial pressure of O₂ = 0.74 × 2.6

Partial pressure of O₂ = 1.924 atm

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Answer:

.47

Explanation:

I just took a test that asked this exact same question and I got it right.

Answer:

1.5 mol/L

Explanation:

molarity = moles/litres

NaOH = 23 + 16 + 1 = 40 g/mol

[tex] ? \: mol \: naoh \: = 30 \: g \: naoh \: \times \\ \\ \frac{1 \: mol \: naoh}{40 \: g \: naoh} = 0.75 \: mol \: naoh[/tex]

molarity = 0.75 mol NaOH ÷ 0.5 L = 1.5 mol/L NaOH

Answer:

1.837 atm

Explanation:

According to Boyle's Law:

[tex]V_{1} P_{1} = V_{2}P_{2}[/tex]

(22.6L) (3.6atm) = (44.3L) (x)

x = 81.36 /44.3

x = 1.837 atm

This is because Volume and Pressure are inversely proportional. If one increases the other has to decrease.

Answer:

Cassiterite is an ore of Sn.It is also called tinstone and has molecular formula of SnO

2 . It is heavy, metallic, hard tin dioxide that is the major ore of tin. It is colourless when pure, but brown or black when iron impurities are present.

Inhibition of protein synthesis is the mode of action done by most antifungal drugs.

Antifungals drugs inhibit the synthesis of ergosterol the main fungal sterol, polyenes which interact with fungal membrane sterols and 5-fluorocytosine inhibits macromolecular synthesis.

So we can conclude that inhibition of protein synthesis is the mode of action done by most antifungal drugs.

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Answer:

food , push , gas , pop

Explanation:

sorry i know this:

4. 2 methyl 2 heptene

Answer:

D

Explanation:

Explanation:

distance = speed x time

distance = 10 x 2

distance = 20miles

hope that helps :)

If a cross country runner travels at a speed of 10 mph and he runs for 2 hours, 20miles he will have run at the end of the 2 hours.

Distance is a description of how far apart two things or points are, either numerically or occasionally qualitatively. Distance can be used to describe a length in physics or to an estimate based on other factors in common usage.

The phrase is widely used metaphorically to refer to a measurement of the degree of distinction between two similar items since spatial intelligence is a rich source of implicatures in human understanding.

distance = speed x time

distance = 10 x 2

distance = 20miles

Therefore,  20miles is the distance.

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V1= 19.229L

Explanation:

V1/T1 = k

V1/836.06=14.509/625.06

V1/836.06= 0.023

V1 = 19.229L

The temperature of CI₂ is changed from 836.06K to 625.06K. If it's new volume is 14.509L then its original volume in liters was 19.4 L.

The combined gas law is the law of of gaseous state which is made by combination of Boyle's law, Charle's law, Avogadro's law and Gay Lussac's law.

It is a mathematical expression that relates Pressure, Volume and Temperature.

(P1 × V1)÷T1 = (P2 × V2)÷T2

We can also use the following relation-

PV = nRT

According to the question, Pressure is constant and we can write the formula as-

V1÷T1 = V2÷T2

T1 = 836.06 K

T2 = 625.06 K

V1 = ?

V2 = 14.509 L

V1 = 19.4 L

Therefore, The temperature of CI₂ is changed from 836.06K to 625.06K. If it's new volume is 14.509L then its original volume in liters was 19.4 L.

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Answer:

Approximately [tex]1.7\; {\rm L}[/tex].

Explanation:

Nitrogen [tex]{\rm N_{2}}\, (g)[/tex] reacts with hydrogen [tex]{\rm H_{2}}\, (g)[/tex] at a [tex]1:3[/tex] ratio to produce ammonia [tex]{\rm NH_3}\, (g)[/tex]:

[tex]{\rm N_{2}}\, (g) + 3\; {\rm H_{2}}\, (g) \to 2\; {\rm NH_{3}}\, (g)[/tex].

The ratio between the coefficient of [tex]{\rm N_{2}}\, (g)[/tex] and the coefficient of [tex]{\rm H_{2}}\, (g)[/tex] is:

[tex]\begin{aligned}\frac{n({\rm N_{2}})}{n({\rm H_{2}})} = \frac{1}{3}\end{aligned}[/tex].

Under the ideal gas assumptions, the same ratio would apply to the volume of [tex]{\rm N_{2}}\, (g)[/tex] and [tex]{\rm H_{2}}\, (g)[/tex] in this reaction:

[tex]\begin{aligned}\frac{V({\rm N_{2}})}{V({\rm H_{2}})} = \frac{n({\rm N_{2}})}{n({\rm H_{2}})} = \frac{1}{3}\end{aligned}[/tex].

[tex]\begin{aligned}V({\rm N_{2}})= \frac{1}{3}\, V({\rm H_{2}})\end{aligned}[/tex].

Given that [tex]V({\rm H_{2}}) = 5.0\; {\rm L}[/tex]:

[tex]\begin{aligned}V({\rm N_{2}}) &= \frac{1}{3}\, V({\rm H_{2}}) \\ &= \frac{1}{3}\times 5.0\; {\rm L} \\ &\approx 1.7\; {\rm L}\end{aligned}[/tex].

(Rounded to [tex]2[/tex] significant figures.)

Answer:

a 63.428gm

b 41.5 gm

Explanation:

a

70 gm CaCOH2=111gm of CaCl2

40 gm =(111*40)/70

=63.428gm

b

107 gm of NH4Cl =111 gm of CaCl2

40 gm gives =(111*40)/107

=41.5 gm