Answer:
58.9 N [W24.8°N]
Explanation:
The vectors are at right angles, so the magnitude of their sum is ...
√(38² +45²) ≈ 58.9 . . . . newtons
The angle Fc makes with Fa can be found using the arctangent:
angle between Fa and Fc = arctan(45/38) ≈ 49.8°
The direction required for the sum of the vectors to be zero is the opposite of [E(49.8° -25°)S], so is [W24.8°N]
The vector that makes the sum zero is 58.9 N [W24.8°N].
What is periodic motion?
Answer:
Periodic Motion :–
This is a type of motion where the object repeats its motion after a fixed interval of time.
Examples: pendulum of a clock, motion of child on a swing etc.
Answer:
Periodic motion is a type of motion that is being performed. You can take a rocking chair, bouncing ball, and a swing as an example of periodic motion.
Periodic motion is just another word for the motion because it describes any type of object performing movements even an object vibrating is another great example of periodic motion. If you want to talk about the motion of the universe take Earth and the moon orbiting around the sun it is an object performing.
Hope this helped :)
I need help with science
Answer:
Ca = 2
Cl = 2
O = 6
Explanation:
Element given from the question above include = 2CaClO₃
NOTE: The 2 in front of CaClO₃ is affecting Ca, Cl and O.
Thus, the number of each atom of element present in 2CaClO₃ can be obtained as follow:
Ca = 1 × 2 = 2
Cl = 1 × 2 = 2
O = 3 × 2 = 6
Thus,
Ca = 2
Cl = 2
O = 6
Need help ASAPPPPP plssssss giving big points
Answer:
average
Explanation:
What determines whether a real or a virtual image is formed from a concave mirror?
Answer:
The distance of the object from the concave mirror determines if it is a virtual or real image
Explanation:
Concave mirrors form both real and virtual images. When the concave mirror is placed very close to the object, a virtual and magnified image is obtained and if we increase the distance between the object and the mirror, the size of the image reduces and real images are formed.
If the wrench is initially displaced 0.400 rad from its equilibrium position, what is the angular speed of the wrench as it passes through the equilibrium position
This question is incomplete, the complete question is;
1.80 kg monkey wrench is pivoted 0.250 m from its center of mass and allowed to swing as a physical pendulum. the period for small angle oscillations is 0.940 s.
a) what is the moment of inertia of the wrench about an axis through the pivot?
b) If the wrench is initially displaced 0.400 rad from its equilibrium position, what is the angular speed of the wrench as it passes through the equilibrium position
Answer:
a) the moment of inertia of the wrench about an axis through the pivot is 0.0987 Kg.m²
b) the angular speed of the wrench as it passes through the equilibrium position is 2.6559 rad/s
Explanation:
Given that
mass m = 1.80 kg
L or d = 0.250 m
period T = 0.940 sec
g = 9.8
a)
we take a look at the expression for the moment of inertia
I = T²mgL / 4π²
we substitute
I = ((0.940)² × 1.80 × 9.8 × 0.250) / 4 × π²
I = 3.896676 / 4 × π²
I = 0.0987 Kg.m²
Therefore the moment of inertia of the wrench about an axis through the pivot is 0.0987 Kg.m²
b)
If the wrench is initially displaced 0.400 rad from its equilibrium position,
the angular speed of the wrench as it passes through the equilibrium position = ?
Using conservation of energy;
mg × d × ( 1 - cos∅) = 1/2×I×w²
we substitute
1.80 × 9.8 × 0.250 × ( 1 - cos(0.400 rad)) = 1/2 × 0.0987 × w²
4.41 × ( 1 - 0.921060994 ) = 0.04935 × w²
0.000441 = 0.04935w²
w² = 0.3481 / 0.04935
w² = 7.0536
w = √7.0536
w = 2.6559 rad/s
Therefore, the angular speed of the wrench as it passes through the equilibrium position is 2.6559 rad/s
Different between rarer medium and denser medium at least 5 point each?? can anyone help me to solve this question
Answer:
A medium in which speed of light is more is known as optically rarer medium and a medium in which speed of light is less is said to be optically denser medium. For example in air and water, air is raer and water is a denser medium.
Explanation:
Answer:Rarer medium is less dense
Explanation:
Rarer medium is less dense than dense medium because rarer medium doesn't have a very high amount of particles packing it together. It's easier to see through a rarer medium, so you're able to get a clearer picture of what's on the other side of it. Denser medium is, simply put, more dense.
Plz help its due in in 15 mins
Answer:
Alpha radiation is a kinda massive type of radiation, this would mean that alpha radiation is weakly penetrating. Because of this:
a) When we have particles of smoke in the path of the alpha radiation, the smoke will "stop" a big part of the radiation, and when the detector stops detecting the radiation, it will let the alarm go off.
b) The radiation of alpha particles can be harmful, yes, but the smoke detector is shielded (Again, alpha radiation is weakly penetrating, then shielding the smoke detector is an easy task), this means that the radiation can not get out of the smoke detector, then it is not a problem for the people living near it.
Henry is researching the efficacy of a new drug for treating agoraphobia (fear of public places). His assistant, who is unaware of the study’s purpose, randomly assigns half of his 200 subjects a 30 day supply of the drug (Fearnot) and the other half a 30 day supply of a placebo (i.e., sugar pill). A month later the subjects are given a questionnaire to rate their fear of being in public. Henry finds that there is no difference between the two groups in their level of fear. How many subjects participated in this study?
You are sitting on the beach and notice that a seagull floating on the water moves up and down 5 times in I minute. What is the frequency of the water waves
Answer:
f = 0.0833 Hz
Explanation:
Frequency is defined as the no. of cycles per unit time. The frequency of water waves can be given by the following formula:
[tex]Frequency\ of\ waves = f = \frac{No.\ of\ Waves}{time}\\[/tex]
here,
No. of Waves = No. of times seagull moves up and down = 5
Time = 1 minute = 60 sec
Therefore, using these values in the formula, we get:
[tex]f = \frac{5}{60\ sec}[/tex]
f = 0.0833 Hz
PLEASE HELP PHYSICS QUIZ DUE TODAY!
WILL GIVE BRAINLIEST TO THE CORRECT ANSWER
A block of mass 4kg is pushed up against a wall by a force (P) that makes the 50 degree angle with the horizontal.
A. Calculate the force P needed if the coefficient of static friction between the block and the wall is 0.
B. Calculate the the force or forces needed if the coefficient 0.25.
Please answer in Newton’s with two 2 significant figures.
I suppose you mean to say that the wall is frictionless in the first scenario? Also, I assume the block is to held in place. Construct a free body diagram for the block. There are 3 (in part A) or 4 (in part B) forces acting on it.
• its weight w, pulling it downward
• the normal force (magnitude n), pushing outward from the wall to the left
• the push as described, with magnitude p
• static friction (mag. f ), opposing the upward net force and thus pointing downward.
The static friction force has a magnitude proportional to that of the normal force. If the coefficient of static friction is µ, then
f = µ n
so if the wall is frictionless with µ = 0, then f = 0 and does not need to be considered.
(A) If µ = 0, then by Newton's second law we have
• net vertical force:
∑ F = p sin(50°) - w = 0
and we don't need to consider the net horizontal force to determine p from here. We get
p = w / sin(50°) = (4 kg) (9.8 m/s²) / sin(50°) ≈ 51 N
(B) If µ = 0.25, then Newton's second law gives
• net vertical force:
∑ F = p sin(50°) - w - f = 0
p sin(50°) - f = (4 kg) (9.8 m/s²)
p sin(50°) - f = 39.2 N
• net horizontal force:
∑ F = p cos(50°) - n = 0
p cos(50°) - f /0.25 = 0
[since f = 0.25 n]
p cos(50°) - 4f = 0
Multiply the first equation by -4, then add it to the second equation to eliminate f and solve for p :
-4(p sin(50°) - f ) + (p cos(50°) - 4f ) = -4 (39.2 N) + 0
p (cos(50°) - 4 sin(50°)) = -156.8 N
p = (156.8 N) / (4 sin(50°) - cos(50°)) ≈ 65 N
The electric field at a distance of 5cm from the center of a charged dome is 3 * 10 ^ 4 * N * C ^ - 1 . Calculate the charge (Q) on the dome.
Explanation:
Q is the charge, 9×10^9×3×10^4 is the magnitude ,d = 5 cm therefore q=3×10^4÷5^2=2.7×10^14÷25=1.08×10^13 c
58) Two balls, A and B are simultaneously projected from the top
of a building at 10 mis upwards & 20 m/s downwards respectively. Find
out the separation btwn them 3 sec after projection.
Answer:
90 m
Explanation:
For ball A::
The equation of a ball moving upwards is given by the formula:
s = ut - (1/2)gt²
where u is the initial velocity, t is the time covered, g is the acceleration due to gravity = 10 m/s² and s is the distance travelled.
Given that:
u = 10 m/s, t = 3 sec, g = 10 m/s², hence:
s = (10 * 3) - (1/2) * 10 * 3²
s = 30 - 45
s = -15 m
The negative sign means the object travels in the opposite direction. Hence s = 15 m
For ball B::
The equation of a ball falling downwards is given by the formula:
s = ut + (1/2)gt²
Given that:
u = 10 m/s, t = 3 sec, g = 10 m/s², hence:
s = (10 * 3) + (1/2) * 10 * 3²
s = 30 + 45
s = 75 m
Hence the separation between the two balls after 3 sec of projection = 15 m + 75 m = 90 m
The potential difference between points A and B in an electric
field is 25.0 volts. How much work is required to transfer 10.0
coulombs of charge from A to B?
Answer:
Work = 250 Joules.
Explanation:
Given the following data;
Potential difference, V = 25V
Charge, C = 10 Coulombs
To find the work required;
Work = Charge * potential difference
Substituting into the equation, we have
Work = 10*25
Work = 250 Joules.
Therefore, the amount of work required to move the charge from A to B is 250 Joules.
Nancy walks 100 m west and then 60 m east. What is Nancy's displacement?
Answer:
40m to the East
Explanation:
Displacement is the distance moved in a specific direction. When writing the displacement value of a moving body, the direction must be put in the description.
Displacement takes into account the start and finish position of a body.
100m
Start -------------------------------------------------------------- →
60m
Final ←----------------------------------
Displacement = 100m - 60m = 40m
Therefore, the displacement is 40m due east
According to Coulomb's Law, how does distance affect the electric force?
A. The electric force only acts on objects that are in contact with
each other.
B. Only in charging by induction can the electric force act at a
distance.
C. Electric force gets stronger as charges get closer together and
gets weaker as charges move farther apart.
D. The electric force is zero if the objects are more than several
centimeters apart.
Answer:
C option is right.
Explanation:
According to columb's law
F ∝ 1/r²
so as r means distance between charges decrease force F increase and vice versa.
Suppose that a single guitar player makes noise at 70 dB. If two guitar players play at the same time, the noise level will be approximately 73 dB. How many guitar players will it take for the sound intensity level to be 100 dB
Answer: it will take 1000 guitar players for sound intensity level to be 100 dB
Explanation:
Given that;
noise level of a single player = 70 dB
Intensity of one guitar will be;
SL= 10 × log(I/I₀)
where I₀ is hum threshold intensity = 10⁻¹² W/m²
I is intensity of sound produced by 1 guitar
SL is intensity level of one guitar
so we substitute
70 = 10 × log(I/10⁻¹²)
70/10 = log (I/10⁻¹²)
I = 10⁻¹² × 10⁷
I = 10⁻⁵ W/m²
now Suppose n guitars produce sound intensity of 100 dB, then intensity of n guitars (In) will be;
100 = 10 × log(In/10⁻¹²)
log(In/10⁻¹²) = 100/10
In = 10⁻¹² × 10¹⁰ = 10⁻² Wm²
we know that Now intensity of 1 guitar I = 10⁻⁵ W/m²
so Intensity of n guitars will be;
n × I = In
n = In / I
we substitute
n = 10⁻² Wm² / 10⁻⁵ W/m²
n = 1000
Therefore, it will take 1000 guitar players for sound intensity level to be 100 dB
A small glass bead has been charged to 8.0 nC (nano-Coulombs). What is the magnitude of the electric field 2.0 m from the center of the bead
Given :
Charge on glass bead, Q = 8 nC .
To Find :
The magnitude of the electric field 2.0 m from the center of the bead.
Solution :
Electric field at position r is given by :
[tex]E = \dfrac{kQ}{r^2}\\\\E = \dfrac{9\times 10^9\times 8\times 10^{-9}}{2^2}\\\\E = 18\ N/C[/tex]
Therefore, the magnitude of the electric field 2.0 m from the center of the bead is 18 N/C .
When you mix two substances, the heat gained by one substance is equalto the heat lost by the other substance. Suppose you place 125 g of aluminum ina calorimeter with 1,000 g of water. The water changes temperature by 2 °C andthe aluminum changes temperature by â74.95 °C.
Required:
a. Water has a known specific heat capacity of 4.184 J/g °C. Usethe specific heat equation to find out how much heat energy the watergained (q).
b. Assume that the heat energy gained by the water is equal to the heat energy lost by the aluminum. Use the specific heat equation to solve for the specific heat of aluminum. (Hint: Because heat energy is lost, the value of q is negative.)
Answer:
A) 8,368 J
B) 0.893 J/gºC
Explanation:
A)
The heat gained by the water can be obtained solving the following equation:[tex]q_{g} = c_{w} * m * \Delta T (1)[/tex]
where cw = specific heat of water = 4.184 J/gºCm= mass of water = 1,000 gΔT = 2ºC Replacing these values in (1) we get:[tex]q_{g} = c_{w} * m * \Delta T = 4.184 J/gºC*1,000 g* 2ºC = 8,368 J (2)[/tex]
B)
Assuming that the heat energy gained by the water is equal to the one lost by the aluminum, we can use the same equation, taking into account that the energy is lost by the aluminum, so the sign is negative: -8,368 J.Replacing by the mass of aluminum (125 g), and the change in temperature (-74.95ºC), in (1), we can solve for the specific heat of aluminum, as follows:[tex]q_{l} = c_{Al} * m_{Al} * \Delta T (3)[/tex]
⇒ [tex]-8,368 J = c_{Al}* 125 g * (-74.95ºC) (4)[/tex]
[tex]c_{Al} = \frac{-8,368J}{125g*(-74.95ºC} = 0.893 J/gºC (5)[/tex]
Answer:
A: the heat gained is 8368 J (8.368 KJ)
B: 0.893 J/g°C
Explanation:
A:
q = ?
m = 1000 g
C = 4.184 J/g°C
△T = 2°C
q = mc△T
q = (1000g) (4.184 J/g °C) (2 °C)
q = 8368 J
B:
q = mc△T
---------------
△T △T
c = q / m△T
c = - 8368 J / (125 g) (-74.95 °C)
c = 0.893 J/g°C
Objects 1 and 2 attract each other with a gravitational force
of 72.0 units. If the distance separating Objects 1 and 2 is
changed to four times the original value (i.e., quadrupled),
then the new gravitational force will be units.
Answer:
The new gravitational force will be of 4.5 units
Explanation:
Recall that the formula for the gravitational force between two objects of masses m1 and m2 separated by a distance d is given by:
[tex]F_g=G\,\frac{m1*m2}{d^2}[/tex]
in our case, we are told that such gives 72 units of force:
[tex]F_g=G\,\frac{m1*m2}{d^2} =72[/tex]
Then we change the distance between the objects to 4 times the original (4 * d), such will produce a new gravitational force Fg':
[tex]F_g'=G\,\frac{m1*m2}{(4*d)^2} =G\,\frac{m1*m2}{16*d^2} = \frac{1}{16} *G\,\frac{m1*m2}{d^2}=\frac{1}{16} *\,72=4.5[/tex]
Therefore the new gravitational force would be of 4.5 units
How much power does it take to lift a box with 350 newtons of force, 25 meters high, in 5 seconds? 70 watts 43,750 watts 2.8 watts 0 Points / 100
Answer:70 watts
Explanation: I took the test and got it correct
A car is traveling due north at 23.6 m>s. Find the velocity of the car after 7.10 s if its acceleration is (a) 1.30 m>s2 due north, or (b) 1.15 m>s2 due south.
Answer:
a) v = 32.8 m/s
b) v= 15.4 m/s
Explanation:
a)
Applying the definition of acceleration (assumed to be constant), we can write the following expression for the velocity v:[tex]v = v_{o} + a*t (1)[/tex]
where v₀ is the initial velocity and a is the acceleration, being t the
time elapsed.
In the case a) the acceleration and the velocity vectors have both the same direction (due north), so both have the same sign, which means that the car is speeding up.Replacing by the givens v₀ and t in (1), we get:[tex]v = 23.6 m/s + (1.30 m/s2 * 7.10 s) = 32. 8 m/s (2)[/tex]
b)
In this case, the acceleration vector and the velocity vector have opposite directions, so the car slows down, due to both vectors have opposite signs.Replacing by the givens in (1) and taking into account the signs, we get:[tex]v = 23.6 m/s + ((-1.15 m/s2) * 7.10 s)) = 15. 4 m/s (3)[/tex]
1. Each of four boys were given
some marbles.
have
day.
punc
exan
class
Joe: sixth multiple of eight
Khal: quarter of a gross
mar
Tate: 4 dozen
Tevin: one score plus a dozen
Which two boys r3eceived the same
number of marbles?
A. Joe and Tate
B. Joe and Khal
C. Tate and Tevin
D. Joe and Tevin
Answer:
the answer is A because
from tate 4 dozen is 48 and from joe the sixth multiple of eight is 48
A subway train is brought to a stop from a speed of 0.500 m/s in 0.400 m by a large spring bumper at the end of its track. What is the force constant of the s
Complete question is;
A 5 × 10^(5) kg subway train is brought to a stop from a speed of 0.5 m/s in 0.4 m by a large spring bumper at the end of its track. what is the force constant k of the spring
Answer:
781250 N/m
Explanation:
From conservation of energy, potential energy is equal to kinetic energy.
Thus;
½mv² = ½kx²
where;
m = mass of train
v = velocity of train
k = force constant of spring
x = the distance the train went while being stopped
We are given;
Mass; m = 5 × 10^(5) kg
Velocity; v = 0.5 m/s
Distance; x = 0.4 m
Thus, from ½mv² = ½kx²
Divide both sides by ½ to get;
mv² = kx²
k = mv²/x²
k = [(5 × 10^(5)) × 0.5²]/0.4²
k = 781250 N/m
A football player who weighs 550 N stands indoors wearing her football boots. The boot’s ‘blades’ (long studs) have a total area of 30 cm 2 . Only her blades are in contact with the floor.
Calculate the player’s pressure on the floor. Give the units.
Explanation:
Since Pressure = Force / Area,
We have 550N / (0.003m²) = 180k Pa. (2s.f.)
When Pluto was classified as a planet it was known as a oddball planet why? Why is it less if an oddball now?
Answer:
a strange world that has baffled scientists ever since it was discovered in 1930. It is not the large gas giant that one might expect to find in the outer reaches of the solar system.
Explanation:
Explanation
can i eat air? im hungry
Answer:
Yes
Explanation:
which terms correctly represent a vector quantity and its respective unit
Answer:
Explanation:
The best terms that represent vector quantity are magnitude and direction. Magnitude and direction are both qualities in vector quantity. The basic measurement of vector quantity is the meter all others would best be described as scalars. So to best describe vector quantity use the meter uni
What is my name?:
I am a god
I am a guardian of the sun
I am used to measure heat.
Answer:
Apllo?
Explanation:
importance of choke coil?
Answer:The choke coil works because it can act as an inductor. When the current pass through will change as AC currents creates a magnetic field in the coil that works against that current. This is known as inductance and blocks most of the AC current from passing through.
Explanation:
Which of the following changes would lead to an increase in the efficiency of
a heat engine?
O A. Increasing the amount of work done while absorbing the same
amount of heat
B. Doing the same amount of work while increasing the amount of
heat released
C. Decreasing the amount of work done while absorbing the same
amount of heat
D. Doing the same amount of work while increasing the amount of
heat absorbed
Answer:
b
Explanation:
doing same amount of work while increase in amount of heat released