Friction between our feet and the surface we walk on is desirable. True False​

Answer:

Least count of vernier caliper=.1/50=.002 CM=.02 MM Least count and precision The least count is directly linked with precision. The smaller is the least count number, the more precise the instrument is.

Explanation:

Is a vernier scale accurate or precise? Every instrument has its accuracy defined as the least count of the instrument.As the least count of vernier callipers is 0.01mm,hence it is not accurate beyond the size measurement of 0.01mm.For which it may be called for vernier scale has presize measurement up to 0.01mm.Ans.. What is a vernier caliper?

Answer:

our acceleration is 0 because there is a constant speed..

a = final speed - initial speed / time

final speed = initial speed ( since speed is constant)

therefore acceleration is 0

Answer:

In scintillation detectors the material of the detector is excited to luminescence (emission of visible or near-visible light photons) by the absorbed photons or particles. The number of photons produced is proportional to the energy of the absorbed primary photon. The light pulses are collected by a photo- cathode.

Explanation:

Hope this helps :-)

Enjoy your day or night!

Have fun with your studies and assignments

ps. please don't give full credit to me I used references from other sites

<3 simplysun

A karate expert breaks a stack of bricks with his bare hand. If the force applied is 520 newtons and the impact time is [tex] \sf{5.0 \times 10^{-4}} [/tex] seconds, what is the value of impulse ?

So, the value of impulse is (A). 0.26 newton seconds.

Hi ! Here, I will help you about the impulse. Impulse is described as a quantity which expresses the integral of the amount force respect to time. The amount of impulse will be proportional to the amount of force or time (the greater  value of the force or the value of time, the value of impuls is greater too). The relationship between impulse, force, and time is expressed in this equation :

[tex] \boxed{sf{\bold{I = F \times \Delta t}}} [/tex]

With the following condition:

What was asked :

Step by step :

[tex] \sf{I = F \times \Delta t} [/tex]

[tex] \sf{I = 520 \times (5.0 \times 10^{-4}} [/tex]

[tex] \sf{I = 2,600 \times 10^{-4}} [/tex]

[tex] \sf{I = 2.60 \times 10^3 \times 10^{-4}} [/tex]

[tex] \sf{I = 2.60 \times 10^{3 + (-4)}} [/tex]

[tex] \sf{I = 2.60 \times 10^{-1} = \boxed{0.26 \: N.s}} [/tex]

So, the value of impulse is (A). 0.26 newton seconds

Answer:

0.568

Explanation:

velocity = -9.8 (t) + Vo

Vo= 0 so v= 9.8(t)

Momentum = mass x velocity

v * 0.14 kg = 0.78 kg m/s

v = 5.571 m/sec

v= 9.8(t) , so substituting v we get , 5.571 = 9.8 * t

t = 5.571/9.8 = 0.568 seconds

Answer:

Current(I)= charge(q)/time

I=15/22

I=0.680.68A

Explanation:

Current is flow of charge per unit time. Always make sure the time is in seconds. istthe

Answer:

They eat Himalayan blue sheep, boar, deers, wild mountain goats, pikas etc.

Explanation:

Answer:

The circuits that were made previously were large and bulky, consisting of circuit components like resistor, capacitor, inductor, transistor, diodes, etc., which were connected with copper wires.

Explanation:

I am in confusion with mono electronic circuit and I am not want to made u confused person.

I am really sorry brother.

:-befrank

Explanation:

Given: Required: solution:

k=25N/m PE ? PE= 1/2 × KX²

X= 5m 1/2 × (25)(5)²

= 312.5 J

The total mechanical energy is kinetic energy + potential energy, so we can look at the object's potential energy to determine the place where it has maximum and minimum kinetic energy.

Potential energy is determined by the equation PE = mgh, where the height is the only changing variable here. Therefore, we look at the height to answer these questions.

Which point on the graph would have the most kinetic energy?

Which point on the graph would have the least kinetic energy?

What point on the graph would have just a little less potential energy than point E?

What point on the graph would have just a little more potential energy than point F?

What point on the graph would have just a little less potential energy than point G?

For a system of four capacitors is connected across a 90-V voltage source, the potential difference across the plates of the 6.0-µF and 2uF capacitors  is mathematically given as

a) vd=30v

b) Q=119.7uc

Generally, the equation for the charge across 6uf  is mathematically given as

Q=C6Vd

Where

1/c36=1/3+1/6

c36=2

Q3=2*90

Q3=180

Therefore

vd=180/6

vd=30v

In conclusion

1/c24=1/2+1/4

C24=1.33uf

Q2=1.33*90

Q=119.7uc

Read more about Charge

https://brainly.com/question/9156412

Answer:

Mass.

Explanation:

I took the quiz and got the answer right

Answer:

100 mR

Explanation:

Answer:

49671.875

Explanation:

KE = [tex]\frac{1}{2}m[/tex][tex]v^{2}[/tex]

KE = 0.5(1375)(8.5)

= 49671.875 J

Answer:

Forces on the test (test is positive) charge

Σ Fx = 0       net result of x-compoment charges is zero

Σ Fy = 2 F sin θ      where F is the force due to the distance of the test charge from one of the charges and sin θ  is the component of that force that is perpendicular to the line separating the charges

The direction of the force is perpendicular to the line separating the two given charges

Answer:

The "new" moon phase is being shown because the moon shown is directly between the sun and earth and is not visible from the earth because of the brightess of the sun.

Hi ! I will help you to discuss about Proportionally Changes in Circular Motion. The analogy of proportionally changes in circular motion is same as the analogy of proportionally changes in direct motion. Here you will hear again the terms acceleration and change in speed, only expressed in the form of a certain angle coverage. Before that, in circular motion, it is necessary to know the following conditions:

The following equations apply to proportionally changes circular motion:

[tex] \boxed{\sf{\bold{\omega_t = \omega_0 + \alpha \times t}}}[/tex]

With the following conditions:

[tex] \boxed{\sf{\bold{\theta = \omega_0 \times t + \frac{1}{2} \times \alpha \times t^2}}}[/tex]

Or

[tex] \boxed{\sf{\bold{(\omega_t)^2= (\omega_0)^2 + 2 \times \alpha \times \theta}}}[/tex]

With the following condition :

We know that :

What was asked :

Step by step :

[tex] \sf{(\omega_t)^2= (\omega_0)^2 + 2 \times \alpha \times \theta} [/tex]

[tex] \sf{0^2= (11)^2 + 2 \times \alpha \times 80} [/tex]

[tex] \sf{0 = 121 + 160 \alpha} [/tex]

[tex] \sf{-160 \alpha = 121} [/tex]

[tex] \sf{\alpha = \frac{121}{-160}}[/tex]

[tex] \sf{\alpha = -0.75625 \: rad/s^2 \approx \boxed{-0.76 \: rad/s^2}}[/tex]

[tex] \sf{\alpha = \frac{\omega_0 - \omega_t}{t}}[/tex]

[tex] \sf{-0.76 = \frac{0 - 11}{t}}[/tex]

[tex] \sf{-0.76t = -11}[/tex]

[tex] \sf{t = \frac{- 11}{-0.76}}[/tex]

[tex] \boxed{\sf{t \approx 14.474 \: s}}[/tex]

So :

Answer:

What i got was A. An unbalanced force.

Hope This Helps

it is called groups or families.

Answer:

groups or families

Explanation:

The vertical column of the periodic table are called groups or famileis because of their similar chemical behavior.

Answer:

a water is heating up

Explanation:

the water's temperature is inceasing

For a total charge of Q coulomb is uniformly distributed along a rod 40cm in length,  the electric field intensity 20cm away from the rod is mathematically given as

E1=1.598*10^11v/m

Generally, the equation for the  initial electric field intensity   is mathematically given as

[tex]dEp=\int{kd/r}cosd\theta[/tex]

Therefore

[tex]e1=kd/r{sin\theta2+sinR1}[/tex]

Hence

[tex]E1=(9*10^9/20*10^{-2})({sin45+sin45})*B/40*10^-2[/tex]

E1=B*9*10^{13})/(10*110)*[tex]\sqrt{2}[/tex]

E1=1.598*10^11v/m

In conclusion, the electric field intensity

E1=1.598*10^11v/m

Read more about Electric field

https://brainly.com/question/9383604

Answer:

1.55 x 10⁷ m²

Explanation:

Unit conversion

Solving

Answer:

20 or 12

Explanation:

if it is 20 u will have to multiple 6 by 4 and the answer u will multiple it by2 and when it is 12 u will have to add 6 +4 and the answer u will add it to 2

For a rock is suspended from the lower end of a light string,  the weight of the rock is mathematically given as

W = 3.10 N

Generally, the equation for the W = Fh1+  is mathematically given as

W = Fh+T1

Where

PiVg+T1 = P2V9+T

(1000) V(9.8) + 1.2 = (790) V(9.8) + 1.6

V = 1.944* 10^-4 m3

In conclusion

W = Fh+T1

W = (1000) (1.944 * 10-4) (9.8) + 1.2

W = 3.10 N

Read more about Weight

https://brainly.com/question/11408596

Explanation:

Newton’s second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.

Potential energy:-

Now

So

Power:-