Find the value of x, giving reasons for your answer:

Hey there!

Formula: πr^2

r = radius

pi = 3.1415926535898 (but we can say it approximately equals 3.14)

Your equation (3.14)(4.2)^2 = answer

4.2^2 = 4.2 × 4.2 = 17.64

New equation: 17.64 × 3.14 = 55.3896

We round our answer to the nearest tenth

Answer: 55.4 ☑️

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

Answer:

x>-2

on a number line you would put a circle on -2 and draw a line going to the right since x is greater than -2

Step-by-step explanation:

Answer:

V = 3 m/s

Step-by-step explanation:

V= wavelength (meters) x frequency (Hz)

9514 1404 393

Answer:

  (d)  ΔABC ~ ΔFED

Step-by-step explanation:

All of the answer choices start with ΔABC, so the first-named vertex is the one with no angle marking. In the smaller triangle, that is vertex F.

Only one answer choice matches vertex A with vertex F:

  ΔABC ~ ΔFED

Answer:

not similar

Step-by-step explanation:

Answer:

yeah! cool so you add then divied and boom yw

Step-by-step explanation:

add and divide like I said! hope this helPwdd

The apprοximate prοbability that Ankit will make all three shοts is 0.405 οr 40.5%. Thus, option a is correct.

A prοbability distributiοn knοwn as the binοmial distributiοn is used tο characterize the number οf successes in a certain number οf independent trials, where each trial has οnly οne οf twο pοtential οutcοmes (success οr failure) and the chance οf success is cοnstant acrοss all trials. Fοr determining the likelihοοd οf achieving a certain number οf successes in a set number οf trials, it is utilised.

Given, Ankit makes 74% οf the free thrοws.

Using binοmial distributiοn we have:

[tex]$\rm P(X=k)= (^nC_k) \times p^{k} \times (1-p)^{(n-k)}$[/tex]

Fοr k = 3 we have:

[tex]$ \rm P(X=3)=(^3C_3) \times 0.74^{3} \times (1-0.74)^{(3-3)}$[/tex]

[tex]$ \rm P(X=3)=0.74^{3}$[/tex]

P(X=3) ≈ 0.405

Hence, the apprοximate prοbability that Ankit will make all three shοts is 0.405 οr 40.5%.

Learn more about binomial distribution here:

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Answer:

0.75 mg

Step-by-step explanation:

From the question given above the following data were obtained:

Original amount (N₀) = 1.5 mg

Half-life (t₁/₂) = 6 years

Time (t) = 6 years

Amount remaining (N) =.?

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Half-life (t₁/₂) = 6 years

Time (t) = 6 years

Number of half-lives (n) =?

n = t / t₁/₂

n = 6/6

n = 1

Finally, we shall determine the amount of the sample remaining after 6 years (i.e 1 half-life) as follow:

Original amount (N₀) = 1.5 mg

Half-life (t₁/₂) = 6 years

Number of half-lives (n) = 1

Amount remaining (N) =.?

N = 1/2ⁿ × N₀

N = 1/2¹ × 1.5

N = 1/2 × 1.5

N = 0.5 × 1.5

N = 0.75 mg

Thus, 0.75 mg of the sample is remaining.

The duration of decay is the same as the half-life of radium, therefore,

half the mass  of radium will remain after 6 years.

Response:

The given mass of the sample of radium, N₀ = 1.5 mg

The half-life of radium = 6 years

Required:

The amount of the sample that will remain after 6 years

Solution:

Let N(t) represent the mass of the sample that remains after 6 years, we have;

[tex]N(t) = \mathbf{N_0 \cdot \left(\dfrac{1}{2} \right)^{\dfrac{t}{t_{1/2}} }}[/tex]

Which gives;

[tex]N(6) = \mathbf{1.5 \times \left(\dfrac{1}{2} \right)^{\dfrac{6}{6} }} = 0.75[/tex]

Learn more about half-life of radioactive substances here:

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Answer:

B

Step-by-step explanation:

all you need is to solve the first term

2x² - (-3x²) = 5x² ,

b is the only answer with 5x² in it

Answer:

A

Step-by-step explanation:

-3x2 + 5y - 4xy + y2 - (2x2 - 4y + 7xy - 6y2)

use - sign to open bracket by multiplying

-3x2 + 5y - 4xy + y2 - 2x2 + 4y - 7xy - 6y2

collect like terms

-3x2 - 2x2 + 5y +4y - 4xy - 7xy + y2 +6y2

-5x2 + 9y - 11xy + 7y2

Answer:

12.66 yards/hour

Step-by-step explanation:

38 feet/3 feet per yard=12.66 yards

Answer:

12 2/3 is the answer...

Step-by-step explanation:

Answer:

It's A and the answer is 4^x

Step-by-step explanation:

The exponential function that models the data is f(x) = [tex]4^x[/tex].

A mathematical phrase, rule, or law that establishes the link between an independent variable and a dependent variable (the dependent variable).

The characteristic that every input is associated to exactly one output defines a function as a relationship between a set of inputs and a set of allowable outputs.

We have a table.

The given function is not a linear because the difference of two consecutive term is not constant.

Now, the ratio

1/(1/12)= 12

12/1= 12

144/12= 12

1728/ 144= 12

If the ratio is same then the function is Exponential.

So, the exponential function is

f(x) = [tex]4^x[/tex]

Learn more about Function here:

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Answer:

y= [tex]\frac{25}{11}[/tex]x

coordinates: (11,25)  (22,50) (33,75)

Step-by-step explanation:

I dont really understand this question but I input the equation into desmos (a graphing website) and that is the equation I got

Answer:

The answer to the question provided is letter b:

[tex] \frac{7}{9} \: and \: \frac{28}{36} [/tex]

Answer:

I think it's 0.083

Step-by-step explanation:

Answer:

0.0833333 (3 is repeating)

Step-by-step explanation:

it seems that is wrong.sorry for that.

Answer:

3)b

4)A

Step-by-step explanation:

Answer:

73

Step-by-step explanation:

the answer is 73 because a parallelogram has to add up to 180.

180-107= 73  

Answer: 486 in

Just did this on edge

The enlargement transformation applied to the rectangular figure gives

a rectangle that is enlarged and similar to the figure.

Correct response:

The given dimensions of the picture are;

Height, [tex]\overline{MN}[/tex] = 6 in.

Width, [tex]\overline{LP}[/tex] = 4 in.

The length of QL' = 12  + 42 = 54

By similar triangles, we have;

[tex]\dfrac{\overline{L'P'}}{\overline{LP}} = \mathbf{ \dfrac{\overline{QL'}}{\overline{QL}}}[/tex]

Which gives;

[tex]\dfrac{\overline{L'P'}}{6} = \mathbf{ \dfrac{54}{12}}[/tex]

[tex]\overline{L'P'} = \dfrac{54 }{12} \times 6 = \mathbf{27}[/tex]

Given that an enlargement gives similar figures, we have;

[tex]\dfrac{\overline{L'P'}}{\overline{LP}} = \mathbf{\dfrac{\overline{L'M'}}{\overline{LM}}} = Scale \, factor \ of \ the \ enlargement[/tex]

Therefore;

[tex]\dfrac{27}{6} = \dfrac{\overline{L'M'}}{4}[/tex]

Which gives;

[tex]\overline{L'M'} = \dfrac{27}{6} \times 4 = \mathbf{ 18}[/tex]

The area of the enlarged picture is, A = [tex]\overline{L'M'}[/tex] × [tex]\overline{L'P'}[/tex]

Which gives;

A = 27 × 18 = 486

Learn more about scale factors and enlargement transformation here:

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Answer:

y=25.5°

Step-by-step explanation:

because there's an isosceles triangle, 180-51 = 129

so 129/2 = 64.5, which is X

there is also a right angle so 90-64.5 = 25.5, which is y

Answer: 50% increase

Step-by-step explanation:

Answer:

C=S/1+R ( The + is a ___  so 1+R is under S)

Step-by-step explanation:

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

Answer: 10

Step-by-step explanation:

add 2.75 to 0

Answer:

$3.49 for 15oz is best buy

Step-by-step explanation:

3.49 divided by 15 = about 0.23

$0.23 for 1 oz

2.75 divided by 11 = 0.25

$0.25 for 1 oz

So $3.49 for 15oz is best buy

Answer:

1/1

Step-by-step explanation:

Add: 7/10+3/2

11/5-x       =      6/5

Rearrange: 11/5-x to -x+11/5

Subtract 11/5 of both sides

-x=6/5-11/5

to

-x=-1

x=1

1/1 is the fraction form

Answer:

1) 6+4x and 5+3x. 2) 3+6x and 10+2x. 3) 15+4x and 2+3x

Step-by-step explanation:

finding area is just multiplying the sides so find numbers that multiply to make 30 and 12

Answer:

2,7 Good Luck make sure to mark brainliest

Answer:

Wala po line jan♥️

Answer: y = 7- 5x

Step-by Step Explanation: The variable x is multiplied by a larger value here; it's multiplied by 5. So I should expect that my y-values will grow fairly quickly. This means that I should expect a fairly "tall" graph.

First I'll do the T-chart.

T-chart

This equation is an example of a situation in which you will probably want to be particular about the x-values you pick. Because the x is multiplied by a relatively large value, the y-values grow quickly. For instance, you probably wouldn't want to use x = 10 or x = –7 as inputs. You could pick larger x-values if you wished, but your graph would very quickly get awfully tall.

I can see, from my T-chart, that my y-values are getting pretty big on either end (that is, in the positive numbers above the horizontal axis, and in the negative numbers below). I don't want to waste time computing points that will only serve to make my graph ridiculously large, so I'll quit with what I've got so far. But I'm glad I plotted more than just two points, because lines that start edging close to vertical can easily go wrong, if I'm not neat in my work.

Here's my graph:

y = 7 - 5x

Answer:

30+y

Step-by-step explanation:

Answer:

He didn't include a parenthesis around 5+y

Step-by-step explanation: