find the slope of a line perpendicular to y=-2/3x+4/5

Answer:

Answer:

safe speed for the larger radius track u= √2 v

Explanation:

The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.

Also given that r_1= smaller radius

r_2= larger radius curve

r_2= 2r_1..............i

let u be the speed of larger radius curve

now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=

r

1

mv

2

=

r

2

mu

2

................ii

form i and ii we can write

v^2= \frac{1}{2} u^2v

2

=

2

1

u

2

⇒u= √2 v

therefore, safe speed for the larger radius track u= √2 v

Answer:

[tex]12[/tex]

Step-by-step explanation:

[tex]\sqrt{12} \times\sqrt{12}[/tex]

[tex]\mathrm{Apply\:radical\:rule}:\quad \sqrt{a}\sqrt{a}=a,\:\quad \:a\ge 0[/tex]

[tex]\sqrt{12}\sqrt{12}=12[/tex]

[tex]=12[/tex]

The value of [tex]\sqrt{12} * \sqrt{12}[/tex] is equal to 12

To solve this problem, we have to convert the surds to radicals and then use the law of indices on this.

[tex]\sqrt{12} * \sqrt{12}= 12^\frac{1}{2} * 12^\frac{1}{2}[/tex]

This law is given as

[tex]a^m+a^n = a^(^m^+^n^)[/tex]

let's substitute the values in this question.

[tex]12^\frac{1}{2}*12^\frac{1}{2}[/tex]

Let's apply the law and solve the radical

[tex]12^\frac{1}{2}*12^\frac{1}{2} = 12^(^\frac{1}{2}^+^\frac{1}{2}^)\\[/tex]

Solve the fractions

[tex]\frac{1}{2}+\frac{1}{2}=1[/tex]

substitute the values and solve

[tex]12^\frac{1}{1}=12[/tex]

from the calculations above, the value of the radical is 12.

Learn more on laws of indices here;

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Answer:

39.2m

Step-by-step explanation:

The ratio would be 14/20 which is 0.7. So, you would take 56 and multipy it by 0.7 to get 39.2.

Answer:

39.2

Step-by-step explanation:

ok so you are given 2 triangles that are proportional

the 20 m side and the 56 m side go together

so this leaves 14 and L

so the ration is 2.8

multiply 14 by 2.8 and you get 39.2

Answer:

the answer is

7

Step-by-step explanation:

why is it 7 it is cause -10+7=3

Answer:

7

the answer is 7 because -10+7=-3

Answer:

x intercept= (-3,0)  y intercept= (0,3)

Step-by-step explanation:

for x intercepts, y should equal zero

for y intercepts, x should equal zero

x intercept: -x+0=3

-x=3

x=-3  (x,y)--> (-3,0)

y intercept: 0+y=3

y=3 (x,y)--> (0,3)

Answer:

Answer:x - intercept (0, -3)

3)y - intercept (3, 0)

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

y = [tex]\frac{3}{2}[/tex]x-3 ; Graph C

2x + 6y = -6 ; Graph A

y = [tex]\frac{1}{2}[/tex]x + 2; Graph B

Answer:

The second one. 30 minutes ÷ 6 miles.

Step-by-step explanation:

You want to find how long it took Jamaal to run one mile.

30 minutes ÷ 6 miles = 5 minutes.

So Jamaal can run one mile in 5 minutes.

Option B, 30mins/6miles

Answer:

see explanation

Step-by-step explanation:

(1)

Using the sine ratio in the right triangle

sin x = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{4}{6}[/tex] , then

x = [tex]sin^{-1}[/tex] ([tex]\frac{4}{6}[/tex] ) ≈ 41.8° ( to the nearest tenth )

(2)

Using the tangent ratio in the right triangle

tan x = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{29}{14}[/tex] , then

x = [tex]tan^{-1}[/tex] ([tex]\frac{29}{14}[/tex] ) ≈ 64.2° ( to the nearest tenth )

(3)

Using the cosine ratio in the right triangle

cos x = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{25}{40}[/tex] , then

x = [tex]cos^{-1}[/tex] ([tex]\frac{25}{40}[/tex] ) ≈ 51.3° ( to the nearest tenth )

Answer:

15%

Step-by-step explanation:

[tex]\frac{138}{120}[/tex]×100=

1.15

115%

Increase in 15%

Answer:

[tex]\frac{59}{5}[/tex] or 11 [tex]\frac{4}{5}[/tex]

Step-by-step explanation:

hope this helps :)

Answer:

220 calories

Step-by-step explanation:

Cross multiply and then divide:

[tex]\frac{14}{22}= \frac{140}{x}[/tex]

140 x 22 = 3080

3080 / 14 = 220

Answer:

$2.50

Step-by-step explanation:

1h + 2w = 9

3h + 4w = 22

Multiply the first expression x 3

3h + 6w = 27

Subtract the 2 equations

3h + 6w = 27

3h + 4w = 22

2w = 5, w = 2.5

Answer: JGI

Step-by-step explanation:

An adjacent angle are angles that share a vertex and side. FGI and JGI share the vertex G and the segment GI

Have a good day!

Answer:

The apothem, rounded to the nearest tenth, is

2.9 units.

The perimeter of the equilateral triangle is

30 units.

Therefore, the area of the equilateral triangle is

1/2(2.9)(30), or approximately 43.5 units2.

The calculated areas are

the same, despite using different formulas.

Step-by-step explanation:

Edge

Answer:

See answer below

Step-by-step explanation:

R3:  If parallel lines, then alternate interior angles is congruent

S4:  AC ≅ AC

R5:   ASA

Answer:

y-intercept is -2 slope is up 2 right 1(2/1)

Step-by-step explanation:

The expression that can be used to approximate the expression below is[tex]log_a x = \frac{log_{b}a}{log_{b}x}[/tex]

[tex]log_a x = \frac{log_{10}a}{log_{10}x}[/tex]

This is similar to the option c where the base of "b" was used as [tex]log_a x = \frac{log_{b}a}{log_{b}x}[/tex]

Learn more on law of logarithms here: https://brainly.com/question/11587706

Answer: C

Step-by-step explanation:

If you don't want to read it all

Answer: All of the them except for the last relation.

Step-by-step explanation: For a relation to be a function, it can have y-values repeat but not x-values. In the last relation, you have (6,-6,), (-3,12), (6,-1), (-8,13). Notice that the x-value of 6 repeats 2 times in this relation. You can graph this relation and use the vertical line test  and you will notice that it will touch the graph more than one time. Therefore, relations 1-4 represents functions and relation 5 does not.

Hope this explanation helps.

Answer:

10 or 10/1

Step-by-step explanation:

1/1000 * 10= 0.01 = 1/100

Answer:

7?

Step-by-step explanation:

The programs cost the same for 7 classes.

Given, no. of classes is represented by c, no. of dogs is represented by d, no. of hours is represented by h, the no. of programs is represented by p and the total cost is represented by t.

The first program charges $35 membership fee and $5 for each class.

The second program charges only $10 for each class.

Now the total cost say [tex]t_{1}[/tex], for first program can be written in equation form as,

[tex]t_{1} =35+5c[/tex],  here c is the no. of classes.

Similarly, the total cost say [tex]t_{2}[/tex] , for second program can be written in equation form as,

[tex]t_{2} =10c[/tex].

We have to find out the no. of classes for which the two programs cost the same.

according to the question,

[tex]t_{1} =t_{2}[/tex]

[tex]35+5c=10c\\10c-5c=35\\5c=35\\c=7[/tex]

Hence for 7 of classes the programs cost the same.

For more details follow the link:

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