Step-by-step explanation:
3/4 ÷ 3
recall that the inverse of division is multiplication
=3/4 x 1/3
=1/4
Pippa had 35 stickers.
She gave an equal number of stickers to 8 friends.
She gave each friend as many stickers as possible and kept the rest for herself.
How many stickers did Pippa keep for herself?
What is the misconception if a student selects D) 27?
A)3
B)4
C)11
D) 27
Answer:
A) 3
Pippa kept 3 stickers for herself
Answer to question 2:
The misconception of if a student selects D) 27 is that instead of dividing to find out how many stickers Pippa kept for herself, the student subtracted. They subtracted instead of dividing.
Step-by-step explanation:
It said that Pippa gave each of her friends an EQUAL number of stickers and AS MANY STICKERS AS POSSIBLE. This tells us that to find our answer we need to divide and what ever the remainder is, is how many stickers Pippa kept for herself.
(You will kind of need to do long division for this)
35 ÷ 8 = 4
8 x 4 = 32
35 - 32 = 3
Pippa will give each of her friends 4 stickers and will keep 3 for herself.
Step-by-step explanation for question 2:
35 stickers - 8 friends = 27
D) 27 is the wrong answer to question 1/part 1
I hope this helped! c:
The Image of a point under Do3, is (7,2).
Its preimage is
A. (7/3, 7/2)
B. (21, 6)
C. (4, -1)
Answer:
B
Step-by-step explanation:
9514 1404 393
Answer:
B. (21, 6)
Step-by-step explanation:
The preimage coordinates are multiplied by the dilation factor to obtain the image coordinates. If P is the preimage point and the dilation factor is 1/3, you have ...
(1/3)P = (7, 2)
P = 3(7, 2) = (3·7, 3·2)
P = (21, 6)
The preimage point is (21, 6).
1. Which of these sentences are propositions? What are the
truth values of those that are propositions?
a) Boston is the capital of Massachusetts.
b) Miami is the capital of Florida.
c) 2 + 3 = 5. d) 5 + 7 = 10.
e) x + 2 = 11. 1) Answer this question.
Answer:I have the same problem
Step-by-step explanation
The number of basic trigonometric ratios is....
A.3
B.4
C.5
D.6
Answer:
There are three basic trigonometric ratios: sine , cosine , and tangent .
Step-by-step explanation:
The Barnes store manager prefers that customers use the Barnes preferred
customer credit card for most purchases. In which case, would the manager prefer
customers use their MCVS credit card?
A. When the purchase is less than $100.00
B. When the purchase is less than $150.00
C. When the purchase is greater than $300.00
D. When the purchase is greater than $350.00
Answer:
D. When the purchase is greater than $350.
Step-by-step explanation:
Stores prefer to use credit card for customer whose purchase are worth high. The Barnes store manager prefer that customers use credit card for most purchases. When customers buy more than worth of $350, the store manager will prefer to use credit card.
Answer:
B
Step-by-step explanation:
Find u(n):
u(0)=1, u(1)=16, u(n+2)=8*u(n+1)-16u(n)
I don't know what methods are available to you, so I'll just use one that I'm comfortable with: generating functions. It's a bit tedious, but it works! If you don't know it, there's no harm in learning about it.
Let U(x) be the generating function for the sequence u(n), i.e.
[tex]\displaystyle U(x) = \sum_{n=0}^\infty u(n)x^n[/tex]
In the recurrence equation, we multiply both sides by xⁿ (where |x| < 1, which will come into play later), then take the sums on both sides from n = 0 to ∞, thus recasting the equation as
[tex]\displaystyle \sum_{n=0}^\infty u(n+2) x^n = 8 \sum_{n=0}^\infty u(n+1) x^n - 16 \sum_{n=0}^\infty u(n) x^n[/tex]
Next, we rewrite each sum in terms of U(x). For instance,
[tex]\displaystyle \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2} \sum_{n=0}^\infty u(n+2) x^{n+2} \\\\ \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2} \bigg(u(2)x^2 + u(3)x^3 + u(4)x^4 + \cdots \bigg) \\\\ \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2} \sum_{n=2}^\infty u(n) x^n \\\\ \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2} \left(\sum_{n=0}^\infty u(n) x^n - u(1)x - u(0)\right) \\\\ \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2}(U(x) - 16x - 1) \\\\ \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2}U(x) - \frac{16}x - \frac1{x^2}[/tex]
After rewriting each sum in a similar way, we end up with a linear equation in U(x),
[tex]\displaystyle \frac1{x^2}U(x) - \frac{16}x - \frac1{x^2} = \frac8x U(x) - \frac8x - 16 U(x)[/tex]
Solve for U(x) :
[tex]\displaystyle \left(\frac1{x^2}-\frac8x+16\right) U(x) = \frac1{x^2} + \frac8x \\\\ \left(1-8x+16x^2\right) U(x) = 1 + 8x \\\\ (1-4x)^2 U(x) = 1 + 8x \\\\ U(x) = \dfrac{1+8x}{(1-4x)^2}[/tex]
The next step is to get the power series expansion of U(x) so that we can easily identity u(n) as the coefficient of the n-th term in the expansion.
Recall that for |x| < 1, we have
[tex]\displaystyle \frac1{1-x} = \sum_{n=0}^\infty x^n[/tex]
By differentiating both sides, we get
[tex]\displaystyle \frac1{(1-x)^2} = \sum_{n=0}^\infty nx^{n-1} = \sum_{n=1}^\infty nx^{n-1} = \sum_{n=0}^\infty (n+1)x^n[/tex]
It follows that
[tex]\displaystyle \frac1{(1-4x)^2} = \sum_{n=0}^\infty (n+1)(4x)^n[/tex]
and so
[tex]\displaystyle \frac{1+8x}{(1-4x)^2} = \sum_{n=0}^\infty (n+1)(4x)^n + 8x\sum_{n=0}^\infty (n+1)(4x)^n \\\\ \frac{1+8x}{(1-4x)^2} = \sum_{n=0}^\infty 4^n(n+1)x^n + 2\sum_{n=0}^\infty 4^{n+1}(n+1)x^{n+1} \\\\ \frac{1+8x}{(1-4x)^2} = \sum_{n=0}^\infty 4^n(n+1)x^n + 2\sum_{n=1}^\infty 4^nnx^n \\\\ \frac{1+8x}{(1-4x)^2} = \sum_{n=0}^\infty 4^n(n+1)x^n + 2\sum_{n=0}^\infty 4^nnx^n \\\\ \frac{1+8x}{(1-4x)^2} = \sum_{n=0}^\infty 4^n(3n+1)x^n[/tex]
which means
[tex]u(n) = \boxed{4^n(3n+1)}[/tex]
The rate of change for yyy as a function of xxx is
, therefore the function is
.
For all values of xxx, the function value y\:yy
\:000.
The yyy-intercept of the graph is the function value y=\:y=y, equals
.
When x=1x=1x, equals, 1, the function value y=\:y=y, equals
.
everything seems to be correctly filled.
if you wanted confidence by confirmation: here, take some
It is an exponentially decaying function.
What is an exponential function ?An exponential function is where the independent variable is in the exponent. Generally the the independent variable is in the power of a constant term e.
Exponential functions are of two types one is exponentially growing function and exponentially decaying function.
when the we have a positive exponent the function is exponentially growing and when we have a negative exponent the function is exponentially decaying.
In the given question f(x) = 8e⁻ˣ
when, x = 0 f(x) = 8
f(x) = 8e⁻ˣ
f(0) = 8e⁰
f(0) = 8
Learn more about Exponential functions here :
https://brainly.com/question/15352175
#SPJ5
which expressions are equivalent to the given expression?
Answer: Choice C. [tex]\frac{1}{x^{2}y^{5} }[/tex]and Choice E. [tex]x^{-2} y^{-5}[/tex]
Step-by-step explanation:
Algebraic exponents.
(y^-8)(y^3)(x^0)(x^-2)
(y^-8)(y^3)(x^-2)
(y^-5)(x^-2)
(1) / (y^5)(x^2)
Options 3 and 5 are correct
Hope this helps!
El valor de "x" que es solución de la ecuación 5x + 22 = 2x + 29 es:
Answer:
x =7/ 3
Step-by-step explanation:
5x+ 22= 2x+ 29
⇔5x - 2x= 29 - 22
⇔3x = 7
⇔x = 7/3
can somebody help with this please
Answer:
"D"
Step-by-step explanation:
just add the two functions
5x^2 - 8x^2 = -3x^2 etc
A motorboat travels 104 kilometers in 4 hours going upstream. It travels 200 kilometers going downstream in the same amount of time. What is the rate of the boat in still water and what is the rate of the current?
[tex] \Large \mathbb{SOLUTION:} [/tex]
[tex] \begin{array}{l} \text{Let }r\text{ be the rate of the boat in still water and} \\ c\text{ be the rate of the current.} \\ \\ \text{So } \\ \begin{aligned} \quad&\bullet\:\text{Rate Upstream}= r - c \\ &\bullet\:\text{Rate Downstream}= r - c\end{aligned} \\ \\ \text{We know that }\text{Rate} = \dfrac{\text{Distance}}{\text{Time}}. \end{array} [/tex]
[tex] \begin{array}{l} \bold{Equations:} \\ \\ \begin{aligned} &\quad\quad \quad r - c = \dfrac{104}{4} = 26\quad (1) \\ \\ & \quad \quad \quad r + c = \dfrac{200}{4} = 50\quad (2)\\ \\ & \text{Adding (1) and (2), we get} \\ \\ &\quad\quad 2r = 76 \implies \boxed{r = 38\ \text{kph}} \\ \\ &\text{Using (2), it follows that} \\ \\ & \quad \quad c = 50 - r \implies \boxed{c = 12\ \text{kph}} \end{aligned} \end{array} [/tex]
To win at LOTTO in one state, one must correctly select numbers from a collection of numbers (1 through ). The order in which the selection is made does not matter. How many different selections are possible?
Answer: If order does not matter then we can use following formula to find different combinations of 6 numbers out of 46 numbers
Step-by-step explanation: Use following Combination formula
nCr = n! / r!(n-r)!
n=46
r=6
=46!/6!(46-6)!
=46!/[6!(40)!]
=(46*45*44*43*42*41*40!)/(6*5*4*3*2*1)(40!)
Cancel out 40!
=46*45*44*43*42*41/(6*5*4*3*2*1)
=6744109680/720
=9366819
What is the approximate volume of the
pyramid if the base area is 625 square
feet and the height is 50 feet?
Answer:
10417 cubic units (to nearest unit)
Step-by-step explanation:
A formula for the volume of pyramids (and cones--"pointy" things) is one-third times the area of the base times the height.
[tex]V=\frac{1}{3}Bh[/tex] where B is the area of the base.
[tex]V=\frac{1}{3}(625)(50) \approx 10417[/tex] cubic units (rounded)
What is the x-coordinate of the point of intersection for the two lines below?
-6 + 8y = -6
7x -10y = 9
Answer choices
1.) -6
2.) -3
3.) 3
4.) 7
Answer:
c.
Step-by-step explanation:
In remodeling a house an architect finds that by adding the same amount to each dimension of a 15ft by 19ft rectangular room, the area would be increased by 98 ft^2. How
much must be added to each dimension?
Let x be the amount that is added to each dimension. After writing an equation in standard form with a > 0, a= ? b= ? and c= ?
(Simplify your answers.)
Answer:
Step-by-step explanation:
new length=15+x
width=19+x
then area=(15+x)×(19+x)=285+15x+19x+x²=x²+34x+285 ft²
original area=15×19=285 ft²
then 285+98=x²+34x+285
or
x²+34x-98=0
x²+34x+17²=98+17²
(x+17)²=98+289=387
x+17=√387=3√43
x=3√43-17 ft
Question two
The lengths of the sides of a triangle are in the ratio 2:3:4. The shortest side is 14cm long.
Find the lengths of the other two sides
Answer:
14 and 21 and 28
Step-by-step explanation:
2:3:4.
The shortest side is 14
14/2 = 7
Multiply each side by 7
2*7:3*7:4*7
14 : 21 : 28
please help me out asap:)
Based on the information, the triangles share two sides but have one different side. one included angle is bigger than the other.
This means that the triangle with side 2x-4 must be smaller than the triangle with the side 10.
Let first, find it minimum amount. A triangle side must be greater than zero so
[tex]2x - 4 > 0[/tex]
[tex]2x > 4[/tex]
[tex]x > 2[/tex]
The triangle side must be smaller than 10.
[tex]2x - 4 < 10[/tex]
[tex]2x < 14[/tex]
[tex]x < 7[/tex]
So x must be greater than 2 but must be smaller than 7.
A recipe asks that the following three ingredients be mixed together as follows: add 1/2 of a cup of flour for every 1/2 of a teaspoon of baking soda, and every 1/4 of a teaspoon of salt.
Which of the following rates is a unit rate equivalent to the ratios shown above?
A. 2 teaspoons of salt per 1 cup of flour
B. 1/2 teaspoon of salt per 1 teaspoon of baking soda
C .2 teaspoons of salt per 1 teaspoon of baking soda
D. 1 teaspoon of baking soda per 2 teaspoons of salt
Answer:
all of the above
Step-by-step explanation:
the ratio between the flour, the baking soda, and the salt would = 1:1:2 (disregarding tsp or cup measurements, since all the units stay the same in the choices)
so really, all the answers are correct
hope this helps!
Answer:
B. 1/2 teaspoon of salt per 1 teaspoon of baking soda.
Step-by-step explanation:
The ratio of cups of flour to tsp. of baking soda to tsp. of salt shown above is:
1/2 : 1/2 : 1/4
An equivalent rate to the ratio of tsp. of salt to tsp. of baking soda is 1/2 : 1 because:
Ratio of tsp. of salt to tsp. of baking soda is:
1/4 : 1/2
If we were to find an equivalent rate to this, it would be 1/2 teaspoon of salt per 1 teaspoon of baking soda for:
Multiply 2 to both terms in the ratio 1/4 : 1/2:
1/4 x 2 = 1/2 (simplified)
1/2 x 2 = 1 (simplified)
The new ratio is 1/2 : 1, which also represents the rate 1/2 teaspoon of salt per 1 teaspoon of baking soda.
Hope this helps!
Please comment back if this was correct.
Find the measure of each angle in the problem. RE contains point P.
Answer:
∠3z = 108 degrees
∠2z = 72 degrees
Step-by-step explanation:
First, we need to create an equation.
3z + 2z = 180
5z = 180
Divide both sides by 5:
z = 36
Now, substitute z for five for both angles.
3 x 36 = 108 degrees
2 x 36 = 72 degrees
Hope this helps!
If there is something wrong, please let me know.
A company producing a standard line and a deluxe line of dishwashers has the following time requirements (in minutes) in departments where either model can be processed.
STANDARD DELUXE
STAMPING 3 6
Motor installation 10 10
Wiring 10 15
The standard models contribute $20 each and the deluxe $30 each to profits. Because the Company produces other items that share resources used to make the dishwashers, the Stamping machine is available only 30 minutes per hour, on average. The motor installation Production line has 60 minutes available each hour. There are two lines for wiring, so the time Availability is 90 minutes per hour. Let x = number of standard dishwashers produced per hour y = number of deluxe dishwashers produced per hour.
Required:
a. Write the formulation for this linear program and then solve.
b. What is the value of the optimal profit ?
Complete Question
Complete Question is attached below
Answer:
[tex]M=160[/tex]
Step-by-step explanation:
From the question we are told that:
Standard models contribute $20
Deluxe models contribute $30
Availability Average :
Stamping machine S= 30 minutes per hour
Motor installation Production M=60 minutes
Wiring is W=90 minutes per hour
Generally the formulation of the linear program is given as
[tex]Maximium (M)=20x + 30 y[/tex]
Where
For Stamping machine
[tex]S= 3x + 6y \leq 30.....Equ 1[/tex]
For Motor installation Production
[tex]10x + 10y \leq 60....Equ 2[/tex]
For Wiring
[tex]10x + 15y \leq 90....Equ3[/tex]
Therefore
Solving Equ...(1,2,3) simultaneously we have
[tex]x=2\\\\y=4[/tex]
Therefore
[tex]Maximium\ (M)=20x + 30 y[/tex]
[tex]M=20(2)+30(4)[/tex]
[tex]M=160[/tex]
Find the greatest common factor of the
following monomials:
39c^2
9c^3'
Answer:
3c^2
Step-by-step explanation:
You measure 49 turtles' weights, and find they have a mean weight of 80 ounces. Assume the population standard deviation is 6.1 ounces. Based on this, construct a 99% confidence interval for the true population mean turtle weight. Round your answers to 2 decimal places.
Answer:
The 99% confidence interval for the true population mean turtle weight is between 77.76 and 82.24 ounces.
Step-by-step explanation:
We have to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1 - 0.99}{2} = 0.005[/tex]
Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].
That is z with a p-value of [tex]1 - 0.005 = 0.995[/tex], so Z = 2.575.
Now, find the margin of error M as such
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
[tex]M = 2.575\frac{6.1}{\sqrt{49}} = 2.24[/tex]
The lower end of the interval is the sample mean subtracted by M. So it is 80 - 2.24 = 77.76 ounces.
The upper end of the interval is the sample mean added to M. So it is 80 + 2.24 = 82.24 ounces.
The 99% confidence interval for the true population mean turtle weight is between 77.76 and 82.24 ounces.
Write the equation in vertex form of the parabola with the vertex (-4,-4) that goes through the point (-2,-16)
Answer:
[tex] - 3(x + 4) {}^{2} - 4[/tex]
Step-by-step explanation:
Vertex form is
[tex]a(x - h) {}^{2} + k = f(x)[/tex]
We know that h and k are both -4. Let x be -2 and y be -16.
[tex]a( - 2 + 4) {}^{2} - 4 = - 16[/tex]
[tex]a(2) {}^{2} - 4 = - 16[/tex]
[tex]4a - 4 = - 16[/tex]
[tex]4a = - 12[/tex]
[tex]a = - 3[/tex]
So the equation in vertex form is
[tex] - 3(x + 4) {}^{2} - 4[/tex]
find the equation for the parabola that has its vertex at the origin and has directrix at x =1/34
Answer:
Focus is at the origin, so (0,0)
directrix at x=1/34
the equation of the parabola is,
[tex]x = \frac{1}{68} - 17 {y}^{2} [/tex]
anybody willing to help me?
Answer:
The answer is a. [tex] \frac{ \sqrt{w} }{ \sqrt[3]{w} }[/tex]y = 60x + 20
y = 65x
Answer:
4=x y=325
Step-by-step explanation:
60x + 20 = 65x
group the variables
20=5x
because you subtracted 60x from both
4=x
because you divided 5 from both
now substitute 5 for x
65×5 is 325
y=325
Determine the value of k so that the following system has an infinite number of solutions
10x+ky= -8
-15x-6y= 12
Please help.
Answer:
k=4
Step-by-step explanation:
remove x:
10x.(-3) + ky.(-3)=-8.(-3) (1)
-15x.2 - 6y.2 = 12.2 (2)
(1) - (2) => -3ky+12y = 0
<=> (12-3k)y = 0
so that y has infinitely many solutions then
12-3k = 0 => k=4
Three friends go grocery shopping together, and each buys the same kind of
strawberries. Akio buys 2 pounds (lb) and pays $3,50. Gordon buys 3 pounds
and pays $5.25. Maria buys 4 pounds and pays $7.00,
Identify the graph and unit price that represent the strawberry costs.
Unit Price
A. $1.75
1lb
b. $3.00
1lb
the bottom two are the same but with more space between the lines and they go up to 24
c $3.00
1lb
d. $1.75
1lb
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Answer:
A.
Step-by-step explanation:
If you can find the given points (pounds, dollars) = (2, 3.50), (3, 5.25), and (4, 7.00) on the graph, then it is an appropriate graph. If the graph label matches the value it shows for 1 pound, then that graph and label are the one you want.
Graph A meets these requirements. It shows the cost of 1 lb to be $1.75, as the label says.
Find the line integral with respect to arc length ∫C(9x+5y)ds, where C is the line segment in the xy-plane with endpoints P=(2,0) and Q=(0,7).
(a) Find a vector parametric equation r⃗ (t) for the line segment C so that points P and Q correspond to t=0 and t=1, respectively
(b) Rewrite integral using parametrization found in part a
(c) Evaluate the line integral with respect to arc length in part b
(a) You can parameterize C by the vector function
r(t) = (x(t), y(t) ) = P (1 - t ) + Q t = (2 - 2t, 7t )
where 0 ≤ t ≤ 1.
(b) From the above parameterization, we have
r'(t) = (-2, 7) ==> ||r'(t)|| = √((-2)² + 7²) = √53
Then
ds = √53 dt
and the line integral is
[tex]\displaystyle\int_C(9x(t)+5y(t))\,\mathrm ds = \boxed{\sqrt{53}\int_0^1(17t+18)\,\mathrm dt}[/tex]
(c) The remaining integral is pretty simple,
[tex]\displaystyle\sqrt{53}\int_0^1(17t+18)\,\mathrm dt = \sqrt{53}\left(\frac{17}2t^2+18t\right)\bigg|_{t=0}^{t=1} = \boxed{\frac{53^{3/2}}2}[/tex]
Geometry workkkk I need help it’s due tonightttt
