find the measures of m and n

Answer:

N/a^3/2

Step-by-step explanation:

loga(N/X)=3/2

N/X= a^3/2

X= N/a^3/2

Step-by-step explanation:

When subtracting logarithms with the same base, it is equivalent to combining them into one logarithm, then dividing the arguments inside:

[tex] log_{a}(n) - log_{a}(x) = log_{a}( \frac{n}{x} ) [/tex]

Then use the formula:

[tex] log_{a}( \frac{n}{x} ) = \frac{3}{2} [/tex]

[tex]{a}^{ \frac{3}{2} } = \frac{n}{x} [/tex]

[tex]x = n {a}^{ - \frac{3}{2} } [/tex]

Answer:

-1/3

Step-by-step explanation:

Multiply by root 3 on the top and bottom. Root 3 times root 3 is 3. 2-3 is -1.

Applying the Pythagorean theorem, the measure of the other leg, to the nearest tenth, is: 2.6 cm.

In a right triangle, where the lengths of its two legs are a and b, and the hypotenuse length is c, the Pythagorean theorem states that: c² = a² + b².

Given the following parameters of the right triangle:

Apply the Pythagorean theorem:

b = √(4² - 3²)

b = 2.6 cm (nearest tenth)

Thus, applying the Pythagorean theorem, the measure of the other leg, to the nearest tenth, is: 2.6 cm.

Learn more about Pythagorean theorem on:

https://brainly.com/question/654982

Answer:

It depends on the question! You should look at the other values of the data and see what they are rounded to and apply it for the mean too. If not, I normally round it to 3 significant figures.

Answer:

8

Step-by-step explanation:

Answer:

it will be 8

Step-by-step explanation:

Answer:

J(0,6)

K(-1,3)

L(-3,4)

Step-by-step explanation:

Answer:

D.

Step-by-step explanation:

1) if the points (1;-1) and (4;0) belong to the line, then

2) the equation of this line is 3y-x=-4;

3) the inequality is 3y-x≤-4.

Answer:

You would multiply 160 by 32 and get an answer of 5120 centimeters cubed.

Step-by-step explanation:You would multiply 160 by 32 and get an answer of 5120 centimeters cubed.

The volume of the cylinder with the same radius and height as the cone is: 135 cm³.

Relating both volumes, we would have:

Volume of a cylinder = 3(volume of a cone), if they both have equal height and radius.

Given that a cone and a cylinder have the same radius (r) and the same height (h), and the cone has a volume of 45 cm³, therefore:

Volume of the Cylinder = 3(45)

Volume of the Cylinder = 135 cm³.

Learn more about volume of cylinder on:

https://brainly.com/question/9554871

Answer:

x=15

Step-by-step explanation:

1. Solve

4x-6=54

4x-6+6=54+6 <=== Add 6 to both sides

4x=60

4x÷4=60÷4 <=== divide by 4 on both sides

x=15

2. Check

4x15-6=54 <=== Replace x with 15 to check

60-6=54 <=== 4x15 equals 60

54=54 <=== 60-6 equals 54 and 54=54

so it is correct!!

Answer:

1,080

Step-by-step explanation:

Multiply the different amounts of customizations to get all the possibilities 3 sizes × 4 choices of crust is 12 possibilities,
12 possibilities × 3 choices of sauce is 36 possibilities,
36 possibilities × 3 choices of cheese is 108 possibilities,
108 possibilities × 10 different toppings is 1,080 possibilities.    

now, this is assuming there are 365 days in 1 year, so

[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill &\$3000\\ P=\textit{original amount deposited}\dotfill &\$2500\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{daily, thus 365} \end{array}\dotfill &365\\ t=years \end{cases}[/tex]

[tex]3000=2500\left(1+\frac{0.035}{365}\right)^{365\cdot t}\implies \cfrac{3000}{2500}=\left(1+\frac{0.035}{365}\right)^{365t} \\\\\\ \cfrac{6}{5}=\left(1+\frac{0.035}{365}\right)^{365t}\implies \cfrac{6}{5}=\left(\cfrac{73007}{73000}\right)^{365t}[/tex]

[tex]\log\left( \cfrac{6}{5} \right)=\log\left[ \left(\cfrac{73007}{73000}\right)^{365t} \right]\implies \log\left( \cfrac{6}{5} \right)=t\log\left[ \left(\cfrac{73007}{73000}\right)^{365} \right] \\\\\\ \cfrac{~~ \log\left( \frac{6}{5} \right)~~}{\log\left[ \left(\frac{73007}{73000}\right)^{365} \right]}=t\implies 5.21\approx t\qquad \textit{about 5 years, 2 months and a half}[/tex]

Answer:

1. [tex]x^2-6x+8=0[/tex]

2. [tex](x-4)(x-2)=0[/tex]

3. [tex]x=4 \text{ and } x=2[/tex]

4. [tex]x=4 \text{ and } x=2[/tex]

Step-by-step explanation:

1. When using substitution all we do would be is substituse the y for a 3.

This leaves us with the equation:

[tex]3=-x^2+6x-5[/tex]

Rewriting it we get:
[tex]0=-x^2+6x-8[/tex]

or if we shift the 0 to the other side:

[tex]x^2-6x+8=0[/tex]

2. In order to factor the equation we can use the butterfly method:

[tex]\left[\begin{array}{ccc}1&-4\\1&-2\end{array}\right][/tex]
So it factors out to:

[tex](x-4)(x-2)=0[/tex]
You can also use the quadratic formula.

3. To find the solutions we just set each factor to 0
[tex]x-4=0\\\text{and}\\x-2=0[/tex]
So the x-values would be:
[tex]x=4 \text{ and } x=2[/tex]

4. To find the solution to the system we just plug in the values and it turns out to be the same numbers as before.

Answer:

b: y = 2x + 5

Step-by-step explanation:

you can find this out by first looking at what the slope is

the slope is rise over run which is 2

then you can see that the y intercept is 5

y = 2x + 5

Answer:

1. (-3) and (-4)

2. (-5) and 6; vise versa

Answer:

Step-by-step explanation:

hello :

1)Two numbers have a product of 12 but their sum is -7 :

means :  xy=12 ....(*)

              x+y = -7 ....(**)

solve this system : use (**) you have   x = -y-7 put this value in (*)

so : (-y-7)y = 12

-y²-7y-12 = 0

y² +7y+12=0       a=1 b=7   and  c= 12

the discriminant  delta =b²-4ac        delta = 7²-4(1)(12) = 1

y1 = (-7-1)/2  = -4      and y2 =  (-7+1)/2 =-3

but x= -7-y

if :y =  - 4   x= -7-(-4) =-3

if : y=-3   x = -7-(-3) =-4

2) same method : xy=-30

                             x+y=1

Answer:

C because he has to interview every student in his class to collect data

how many pieces of tape can be cutted.

[tex]5 \frac{1}{3} \div \frac{2}{3} [/tex]

[tex] = (5 + 0) + ( \frac{1}{3} + \frac{2}{3} )[/tex]

[tex] = 5 + \frac{1 + 2}{3} [/tex]

[tex] = 5 + \frac{3}{3} [/tex]

[tex] = 5 + \frac{3 \div 3}{3 \div 3} [/tex]

[tex] = 5 + \frac{1}{1} [/tex]

[tex] = 6[/tex]

therefore, 6 pieces of tape can be cutted.

Answer:

9330

Step-by-step explanation:

6x × 8y + 27x - 6y + 3 = 18 × 536 + 81 - 402 + 3 =

9330

Answer:

The answer is 9330

Hope it helps

✧GHOSTOFSPARTA✧

+ - makes a minus

+ + make a plus

-- makes a plus

7.0 - 2.9 = 4.1

Hope this helps!

Step-by-step explanation:

y=4x + 3

it should have another one

Answer:

The graph decreases from left to right.

Step-by-step explanation:

Answer:

The answer is

→ A.) Domain: {x | x is a real number}; range: {y | y > 5}; asymptote: y = 5

Step-by-step explanation:

For every real x, (1.4)x is always positive, therefore the range would be y > 0, but (1.4)x + 5 adds 5 to every integer in the original range. This suggests that the real range is y | y > 5, or all positive values bigger than 5.

This is the sole choice for the range that A has, therefore, it should. (The other two characteristics hold true, as can be any real integer and lim h(x) = 5 x, implying that y = 5 is a horizontal asymptote of h(x).)

Therefore, A.) Domain: {x | x is a real number}; range: {y | y > 5}; asymptote: y = 5 is your answer.

Hope this helped! :^)

⭐Brainliest will be appreciated!⭐

✉️Message me if you have any more questions!✉️

- ✨7272033Alt✨

Submitted on 4/20/2022 at 1:37 PM

(To avoid plagarism, by users whom decide to copy.)

Domain: {x | x is a real number}; range: {y | y > 5}; asymptote: y = 5. Option A is correct.

The given function is [tex]h(x)=1.4^x+5[/tex].

The domain of a function is the set of all valid inputs (x-values) for which the function is defined.

In this case, there are no restrictions on the base (1.4) raised to any real exponent, and thus, the domain includes all real numbers.

Therefore, Domain: {x | x is a real number}

The range of a function is the set of all possible output (y-values) that the function can produce.

In this case, the base (1.4) raised to any real exponent will always be positive, and when you add 5 to a positive number, you get values greater than 5.

Hence, the range consists of all real numbers greater than 5.

Therefore, Range: {y | y > 5}.

An asymptote is a line that a function approaches but never crosses.

For this exponential function, there are no vertical asymptotes since it is defined for all real numbers.

However, there is a horizontal asymptote. As the value of x approaches negative or positive infinity, the function h(x) will approach 5.

Therefore, Asymptote is y = 5.

Hence, option A is correct, domain: {x | x is a real number}; range: {y | y > 5}; asymptote: y = 5.

To learn more on Functions click:

https://brainly.com/question/30721594

#SPJ5

Answer:

F, 3^4+x

Step-by-step explanation:

You just have to add the powers together but not the actual base, you keep it as it is

The proportional relationship between (0,0) and (4,11) represents a direct variation

The equation that represents the graph is  y = 11x/4

The points on the graph are given as:

(x,y) = (0,0) and (4,11)

The equation of the graph is then calculated using:

y = (y₁/x₁) * x

This gives

y = (11/4) * x

Evaluate

y = 11x/4

Hence, the equation that represents the graph is  y = 11x/4

Read more about proportional relationships at:

https://brainly.com/question/12242745

As ray UW bisects ( divides the angles into two equal parts )

WUT = WUV

6x - 10° = 4x + 6°

6x - 4x = 6° + 10°

2x = 16°

x = 16° ÷ 2 = 8°

Putting the value of x in the Angle WUT

6 × 8° - 10° = 48° - 10° = 38°

Answer:

95 assuming this is one number

Step-by-step explanation:

3/5 of 160 is 96

04 - 12 x 4 + 23 is 79

it is greater than 79 and less than 96

79 < x < 96

now find numbers between these 2 numbers that have digits adding to 14.

8+6 and 9+5

The problem included that the number must be odd and so the answer is 95

Answer:

Step-by-step explanation: