Find the inequality represented by the graph.

Answer:

[tex]→ \sqrt[4]{81 {x}^{8} {y}^{4} } \\ = {81}^{( \frac{1}{4})} {x}^{ (\frac{8}{4})}{y}^{ (\frac{4}{4})}\\= \boxed{3 {x}^{2} y}✓[/tex]

Answer:

9 = x

Step-by-step explanation:

63 = 7x (Given)

9 = x (Divide 7 on both sides)

Answer:

9

Step-by-step explanation:

63 divided by 7 = 9

X=9

Answer:

-3/1 or just -3

Step-by-step explanation:

Answer:The family will use 792 gallons of water in the new washing machine

Step-by-step explanation:

1440 X 0.55=792

100-45=55

Answer:

1.  (8, 6)  2. (16/5, 16/5) = (3.2, 3.2)

Step-by-step explanation:

I have attached e graphs of the 2 triangles below respectively.

Answer:

Step-by-step explanation:

NO i think

Answer:I think its D

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

I did it.

Answer:

y=-3(x)

Step-by-step explanation:

If x and y represent input and output respectively

y=-3(x)

Answer:

8x + 4y

Step-by-step explanation:

6x + 2x + y + 3y

Combine like terms

(6x + 2x) + (y + 3y)

8x + 4y

Answer:

4(2x+y)

Step-by-step explanation:

Answer:

4th quadrant is the red point..

I guess the answer is 70°

Answer:

Step-by-step explanation:

In the first triangle, using Pythagorean's theorem, x^2+3^2=5^2, x = 4

In the second triangle, using Pythagorean's theorem, x^2+7^2=24^2, x = 25

In the third triangle, using Pythagorean's theorem, 8^2+15^2=x^2, x = 17

In the fourth triangle, using Pythagorean's theorem, x^2+8^2=10^2, x = 6

In the fifth triangle, using Pythagorean's theorem, 5^2+12^2=x^2, x = 13

Step-by-step explanation:

1 week = 7 days

Therefore 1 week = 60,000 letters

=> 7 days = 60,000 letters

=> 1 day = 60,000 / 7 = 8571.4... letters

Hence Obama receives around 8,571 letters per day.

Answer:

1386.66666667

Step-by-step explanation:

i beleive this is the correct answer

Answer:

median is 3.9

Step-by-step explanation:

You arrange them all from the smallest to the biggest, then cross out pairs from each side till you get the one in the middle

0.8, 2.6, 2.8, 3.5, 3.9, 4.6, 6.8, 8.5, 8.6

Answer:

1. 0, 2 π , π , 2 π/3 , 4 π/3

2. 7 π/6 , 11 π/6

Step-by-step explanation:

1. we want to find the value of theta

Let us represent theta by x for ease of documentation

So we have ;

sin 2x + sin x = 0

Mathematically;

sin 2x = 2sinxcosx

So;

2 sin x cos x + sin x = 0

sin x (2 cos x + 1) = 0

sin x = 0

or

2cos x + 1 = 0

x = arc sin (0)

within the given range;

x = theta = 0 , 2 π , π

For;

2 cos x + 1 = 0

2cos x = -1

cos x = -1/2

cos x = -0.5

x = arc cos (-0.5)

x = 2 π/3 , 4 π/3

2. cos 2 x = 1 + sin x

Mathematically;

cos 2 x = 1-2 sin^2x

let sin x = y

1-2y^2 = 1 + y

y = -2y^2

1 = -2y

y = -1/2

y = -0.5

sin x = y

sin x = -0.5

x = arc sin (-0.5)

x = 7 π/6 , 11 π/6

Answer:

3 5/9

Step-by-step explanation:

You make 4/9 a whole by adding 5/9 and you get 9/9 or 1 whole

you add the whole to 5 and get 6, then add 3 because 6+3=9

I hope this helps!!!!

Answer:

38 ft

Step-by-step explanation:

Answe

Step-by-step explanation:

Answer:

$110,50

Step-by-step explanation:

Okay so I have done the whole process in the picture and the part where I said check I wanted to confirm my answer and it is correct, I hope you understand. This is the method I personally use because it is easier and makes more sense to me‍♀️.

Answer:

900 + 12 x 30

Step-by-step explanation:

Answer:

-7/3

General Formulas and Concepts:

Algebra I

Slope-Intercept Form: y = mx + b

Step-by-step explanation:

Step 1: Define

y = -7/3x + 5

Step 2: Break Function

Identify Parts

Slope m = -7/3

y-intercept b = 5

Answer:

Step-by-step explanation:

1.

F=ma

89=68a

a=89/69 units/s²

2.F=ma

45=85 a

a=45/85=9/17 units/s²

Problem 1

Answer: Approximately 1.3 m/s^2

---------------

Work Shown:

We'll use the formula F = m*a, which is from Newton's second law.

The force applied is F = 89 newtons. The mass of the boulder is m = 69 kilograms. This means,

F = ma

89 = 69*a

a = 89/69

a = 1.28985507246377

a = 1.3

I rounded to 2 sig figs because the other given values (89 and 69) are to 2 sig figs as well.

=================================================

Problem 2

Answer: Approximately 0.53 m/s^2

---------------

Work Shown:

We'll follow the same idea as problem 1

This time we are given F = 45 and m = 85

So,

F = ma

45 = 85*a

85a = 45

a = 45/85

a = 0.52941176470589

a = 0.53

The acceleration is roughly 0.53 m/s^2, which means that for every second, the speed is increasing by roughly 0.53 m/s.

Answer:

x = 107

Step-by-step explanation:

The exterior angle and the interior angle make a supplementary angle.

This means it is 180°. Knowing this, we can solve for x:

73 + x = 180

x = 107

Therefore, x = 107.

Answer:

d / 2

Step-by-step explanation:

Hey there!

“2 (5x + 3)”

• FIRST and ONLY STEP: DISTRIBUTE 2 to ALL OF YOUR NUMBERS in the parentheses

2(5x) + 2(3)

2(5x) = 10x ⬅️ FRONT number

2(3) = 6 ⬅️ BACK number

BOTH OF YOUR NUMBERS ARE POSITIVE SO WE DON’T HAVE TO CHANGE ANYTHING

Answer: 10x + 6 ☑️

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

Answer:

10x+6

Step-by-step explanation:

you have to multiply 2 times 5 then 2 times 3 then multiply 10 times x and write 6 beside it.

3 batches of chocolate chip with 2 cups per batch is 6 cups total for the chocolate chip cookies.

Subtract the total needed for the chocolate chip from the total flour used, then divide the remaining amount by number of batches of oatmeal

Cookies.

The problem show 122 total cups, but I don’t think that is right... what is the actual total cups used?

[tex]\bold{Highest\ Common\ Factor\ \ HCF\ of\ 60\ \& \ 96 }[/tex]

[tex]\bold{Finding\ your\ Prime\ Factorization \ in\ your\ given\ numbers!}[/tex]

[tex]\bold{60:2\times2\times3\times5}[/tex]

[tex]\bold{96:2\times2\times2\times2\times2\times3}[/tex]

[tex]\bold{Your\ Greatest\ Common\ Factor(GCF): 2\times2\times3}[/tex]

[tex]\bold{2\times2\times3}\\ \bold{2\times2=4}\\ \bold{4\times3=12}[/tex]

[tex]\boxed{\boxed{\bold{Answer: HCF \rightarrow \bold{\underline{12}}}}}\checkmark[/tex]

~[tex]\frak{LoveYourselfFirst:)}[/tex]