Mathematics High School

find the base of an isosceles triangle whose area is 12 cm square and one of the equal sides is 5cm.
​

Answers

Answer 1
b≈6cm
or
8cm

Hope that helps!!! Good luck

Related Questions

Two sides of an equilateral triangle are labeled 12 inches and 3x - 6 inches. Find x.

Answers

Answer:

6

Step-by-step explanation:

In equilateral triangle, all the sides are congruent.

3x - 6 = 12

Add 6 to both sides

3x = 12 + 6

3x = 18

Divide both sides by 3

x = 18/3

x = 6

what is the sum of the first 30 even numbers i added them all up and got 300 but lots of people are getting diffrent answers some how?

Answers

the horses name was friday

Freddy bought 3 bags of pebbles to put in his fish tank. Each bag contains 295 pebbles. After he put the right amount of pebbles in his fish tank, he had 104 pebbles left over. How many pebbles did he put in his fish tank?

Answers

295 x 3 = 885

885-104 = 781

781 pebbles

You are buying bottles of a sports drink mix for a softball team. Each bottle costs $1.19. What function rule models the total cost of a purchase? Evaluate the function for 15 bottles​

Answers

Answer: f(x) = 1.19x, where f(x) is the total cost, and x is the cost per bottle

Cost of 15 bottles: $17.85

Step-by-step explanation:

This question describes a straightforward relation between cost per bottle, and cost for all the bottles.  As such, simply equate one variable to the value of one bottle, and f(x) as the value of every bottle.

Hope it helps :) and let me know if you want me to elaborate.

P.S. f(x) can simply be substituted for "y"

Cost of each bottle=1.19$

Let

no of bottles be x

.The function is given by

[tex]\\ \sf\longmapsto f(x)=1.19x[/tex]

Now

Bottles=15

Cost:-

[tex]\\ \sf\longmapsto f(15)[/tex]

[tex]\\ \sf\longmapsto 1.19(15)[/tex]

[tex]\\ \sf\longmapsto 17.89[/tex]

Use the Pythagorean Theorem to find the distance between the point (1,4) and (-5,-4) on the coordinate plane? (FREE RESPONSE)

PLZ I NEED IT RIGHT NOW

Answers

Answer:

hope this helps

The answer is 10.

x^2 + y^ = c^2

The horizontal distance of the triangle is just the distance between their x values:
x = 1 - -5 = 6

The vertical distance of the triangle is just the difference between their y values:
y = 4 - -4 = 8

6^2 + 8^2= c^2
36 + 64 = c ^2
100 = c^2
10 = c

Find the slope of the line that passes through (1, 2) and (10, 10).

Answers

Slope m = 8 / 9 = 0.88889

Hope it helps!

Please mark Brainliest if you want to :)

A box is pulled to the right with a force of 65 N at an angle of 58 degrees to the horizontal. The surface is frictionless. The free body diagram is shown.

A free body diagram with 3 force vectors. The first vector is pointing north, labeled F Subscript N Baseline, the second vector is pointing south labeled F Subscript g Baseline = 30 N, and the third pointing 58 degrees north of east labeled F Subscript g Baseline = 65 N.
What is the net force in the x-direction?

30 N
34 N
55 N
65 N

Answers

Answer:

34 N.

Step-by-step explanation:

Net force in x direction = 65 cos 58

= 34 N.

Answer:

34N is the answer :)

Step-by-step explanation:

HELP PLS MARKING BRAINLEIST

Answers

Answer:

1

Step-by-step explanation:

5/5=1

Answer:

4/5

Step-by-step explanation:

You move up four on the y-axis and over 5 on the x-axis and it would meet the next point

Hope this Helps

(6d+5)−(2−3d) find the difference

Answers

9d+3 that’s the answer I think though try it

Answer:

10d

Step-by-step explanation:

6d+5 =11d

2-3d = -1d

11d-1d= 10d

neeeeeeed heeeeeelp pleaseeeeeeeee

Answers

Answer:

D

Step-by-step explanation:

Hope this is correct and helps

Answer:

D

Step-by-step explanation:

I'm not completely sure but A is constant cuz it don't move B is increasing C is same as A and D Is decreased

can someone pls help me

Answers

Answer:10 & 12

Step-by-step explanation:

Answer:

The 5th step will need 32 blocks, and the 6th step will need 64 blocks.

Step-by-step explanation:

Each step requires the blocks to be doubled. The first step has two, 2x2 is 4. There are 4 blocks in the next step. 4x2 is 8. There are 8 blocks in the next step, and so on and so forth. Just multiply by 2. Hope this helped!

01.01 LC)Look at the following numbers: −4, −5, 0, 5 Which pair of numbers has a sum of zero? 5, −5 −5, 0 −4, 5 −4, 0

Answers

Answer:

5, -5

hope this helps

Answer:

Train to BaDussy

Step-by-step explanation:

The domine of definition of the function
[tex]f(x) = \frac{1}{ \sqrt{ |\cos(x)| + \cos(x) }} \: is \\ [/tex]
​

Answers

[tex]\large\underline{\sf{Solution-}}[/tex]

Given function is

[tex]\rm \longmapsto\:f(x) = \dfrac{1}{ \sqrt{ |cosx| + cosx} } [/tex]

Now,

[tex]\rm \longmapsto\:f(x) \: is \: defined \: if \: |cosx| + cosx > 0[/tex]

We know,

[tex]\begin{gathered}\begin{gathered}\bf\: \rm \longmapsto\: |x| = \begin{cases} &\sf{ - x \: \: when \: x < 0} \\ \\ &\sf{ \: \: x \: \: when \: x \geqslant 0} \end{cases}\end{gathered}\end{gathered}[/tex]

So,

[tex]\begin{gathered}\begin{gathered}\bf\: \rm \longmapsto\: |cosx| + cosx = \begin{cases} &\sf{ \: \: 0 \: \: when \: cosx \leqslant 0} \\ \\ &\sf{ \: \: 2 \: cosx \: \: when \: cosx > 0} \end{cases}\end{gathered}\end{gathered}[/tex]

So,

[tex]\rm\implies \:f(x) \: is \: defined \: when \: cosx > 0[/tex]

So, from graph we concluded that cosx > 0 in the following intervals.

[tex]\begin{gathered}\boxed{\begin{array}{c|c} \bf cosx & \bf \: x \: \in \: \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf + ve & \sf \bigg( - \dfrac{\pi}{2} ,\dfrac{\pi}{2} \bigg) \\ \\ \sf + ve & \sf \bigg(\dfrac{3\pi}{2} ,\dfrac{5\pi}{2} \bigg) \\ \\ \sf + ve & \sf \bigg(\dfrac{7\pi}{2} ,\dfrac{9\pi}{2} \bigg) \end{array}} \\ \end{gathered}[/tex]

So, if we generalized this we get

[tex]\rm\implies \:cosx > 0 \: when \: x \: \in \: \bigg(\dfrac{(4n - 1)\pi}{2} ,\dfrac{(4n + 1)\pi}{2} \bigg) \: \forall \: n \in \: Z[/tex]

Hence,

Domain of the function is

[tex]\red{\rm\implies \boxed{\tt{ \: x \in \: \bigg(\dfrac{(4n - 1)\pi}{2} ,\dfrac{(4n + 1)\pi}{2} \bigg) \: \forall \: n \in \: Z}}}[/tex]

[tex]\textsf{More to know :-} \\[/tex]

[tex]\begin{gathered}\begin{gathered}\boxed{\begin{array}{c|c} \bf T-eq & \bf Solution \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf sinx = 0 & \sf x = n\pi \: \forall \: n \in \: Z\\ \\ \sf cosx = 0 & \sf x = (2n + 1)\dfrac{\pi}{2}\: \forall \: n \in \: Z\\ \\ \sf tanx = 0 & \sf x = n\pi\: \forall \: n \in \: Z\\ \\ \sf sinx = siny & \sf x = n\pi + {( - 1)}^{n}y \: \forall \: n \in \: Z\\ \\ \sf cosx = cosy & \sf x = 2n\pi \pm \: y\: \forall \: n \in \: Z\\ \\ \sf tanx = tany & \sf x = n\pi + y \: \forall \: n \in \: Z\end{array}} \\ \end{gathered}\end{gathered}[/tex]

find the sum of the first seven terms -3,3,-3,3.
Show your work.

Answers

-3 as there are 3(-3+3) -3 meaning 3(0) -3 so therefore just -3

What is the common difference in the sequence?

Answers

The common difference is the amount between each number in an arithmetic sequence.

For example, the sequence 4,7,10,13,... has a common difference of 3.

Questions linked below

Answers

Answer:

The blur of the photo I do not understand sorry

Step-by-step explanation:

ty for the points

the area of the floor of a cubical room is 49m .find the area of 4 walls of a room.​

Answers

Answer: [tex]196m^2[/tex]

Step-by-step explanation:

since it's a cube the floor is in square shape

area of one wall = [tex]a^2[/tex] area of 4 walls = = [tex]4[/tex]×[tex]49[/tex] = [tex]196[/tex]

Answer:

SINCE ITS A CUBE OF FLOOR SHAPE.

area of 1 wall=a²

=4

area of 4 wall=4x49

=169m²Ans.

I NEED HELP PLEASE!!!!

Answers

Answer:

the answer is x=15

Step-by-step explanation:

Answer:

15

Step-by-step explanation:

since angles 84 and 5x + 9 are alternate interior angles they both are equal

i.e

5x +9 = 84

5x = 84 -9

5x = 75

x = 75/5

therefore x = 15

keep smiling

If x = a sin α, cos β, y = b sin α.sin β and z = c cos α then (x²/a²) + (y²/b²) + (z²/c²) = ?​

Answers

[tex]\large\underline{\sf{Solution-}}[/tex]

Given:

[tex] \rm \longmapsto x = a \sin \alpha \cos \beta [/tex]

[tex] \rm \longmapsto y = b \sin \alpha \sin \beta [/tex]

[tex] \rm \longmapsto z = c\cos \alpha[/tex]

Therefore:

[tex] \rm \longmapsto \dfrac{x}{a} = \sin \alpha \cos \beta [/tex]

[tex] \rm \longmapsto \dfrac{y}{b} = \sin \alpha \sin \beta [/tex]

[tex] \rm \longmapsto \dfrac{z}{c} = \cos \alpha[/tex]

Now:

[tex] \rm = \dfrac{ {x}^{2} }{ {a}^{2}} + \dfrac{ {y}^{2} }{ {b}^{2} } + \dfrac{ {z}^{2} }{ {c}^{2} } [/tex]

[tex] \rm = { \sin}^{2} \alpha \cos^{2} \beta + { \sin}^{2} \alpha \sin^{2} \beta + { \cos}^{2} \alpha [/tex]

[tex] \rm = { \sin}^{2} \alpha (\cos^{2} \beta + \sin^{2} \beta )+ { \cos}^{2} \alpha [/tex]

[tex] \rm = { \sin}^{2} \alpha \cdot1+ { \cos}^{2} \alpha [/tex]

[tex] \rm = { \sin}^{2} \alpha + { \cos}^{2} \alpha [/tex]

[tex] \rm = 1[/tex]

Therefore:

[tex] \rm \longmapsto\dfrac{ {x}^{2} }{ {a}^{2}} + \dfrac{ {y}^{2} }{ {b}^{2} } + \dfrac{ {z}^{2} }{ {c}^{2} } = 1[/tex]

When converting from inches to feet, the measurement in inches, m, of an object varies directly with its measurement in feet, f, with the constant of variation being 12.

What is the equation relating these two quantities?



How many inches would a 3.5-foot object measure?


inches

How many feet would a 27-inch object measure?

Answers

Step-by-step explanation:

wow, how complicated can one phrase this ...

the point being :

1 ft = 12 in and vice versa (1 in = 1/12 ft)

so, any measurements given in feet but needed in inches need to be multiplied by 12.

and any measurements given in inches but needed in feet need to be divided by 12.

so,

3.5 ft = 3.5×12 = 7/2 × 12 = 7×6 = 42 in

27 in = 27/12 = 9/4 = 2 1/4 or 2.25 ft

Answer:When converting from inches to feet, the measurement in inches, m, of an object varies directly with its measurement in feet, f, with the constant of variation being 12.

What is the equation relating these two quantities?

✔ m = 12f

How many inches would a 3.5-foot object measure?

✔ 42

inches

How many feet would a 27-inch object measure?

✔ 2.25

feet

Step-by-step explanation:

Describe the translation of the point to its image. (-2,-3) to (-2,4)

Answers

Up 8 Units, Hope this helps :)

A flock of birds perched on a tree. In the morning, each bird perched 1 tree and 1 bird left. In the afternoon, 2 chicks perched, 1 tree left over. Ask how many birds, how many trees?

Answers

Answer:

2 birds 1 tree

Step-by-step explanation:

I think only not sure

Help pls and show your work!

Answers

1. Turn 1 1/3 into an improper fraction.
2. Now you have 4/3 + 5/6.
3. The LCD of 3 and 6 is 6. Convert 4/3 into 8/6. We multiplied 4/3 by 2 to get the denominator of 6.
4. 8/5 + 5/6 = 13/6

helpppppppp plzzzzzzzzzzzzzzzzz (ANSWER ONLY IF YOU KNOW)

Answers

Answer:

1/7 ( a+1 )

Step-by-step explanation:

1/7a + 1/7

1/7 ( a+1 )

Directions: Follow the instructions for the following inequalities. Will give brainlist!


1. 4<7 Multiply both sides by 7, then by 6, then by 3, then by 10

2. 11>-2 Add 5 to both sides, then add 3, then add (-4)

3. -4<-2 Subtract 6 from both sides, then 8, and then 2

4. -8<8 Divide both sides by -4, then by -2

5. Write a short explanation of the effects of the above operations. Did this affect the inequality sign? Was it still true? Why or why not?

Answers

1) 4<7

×7 ×7

28<49

×6 ×6

168<294

×3 ×3

504<882

×10 ×10

5040<8820

2) 11>-2

+5 +5

16> 3

+3 +3

19>6

+-4 +-4

15>2

3) -4<-2

-6 -6

-10<-8

-8 -8

-18<-16

-2 -2

-20<-18

4) -8<8

÷-4 ÷-4

2<-2

÷-2 ÷-2

-1< 1

5) ~The affect of the inequality sign didn't change. If you add or subtract the same positive or negative number to both sides of an inequality or an equation, the inequality stays the same. If you multiply or divide both sides of an inequality or an equation by the same positive number, the inequality stays the same. This is because when manipulating inequalities there are rules this if a < b then a + c < b + c so we get a new number that replaces a and b yet the inequality symbol stays the same so a still is smaller than b.

Hope this helped you- have a good day bro cya)

Please help!!

9.(05.02)
Solve the following system of equations: (5 points)
x - 2y = 5
2x - 4y = 10

Infinitely many solutions

No solutions

(0, 0)

(5, 10)

Answers

Answer:

Infinite solutions

Step-by-step explanation:

If you look at the equation, you will see that if you multiply everything by two (On the 1st equation), you get the 2nd equation. This means that the lines are the same, so infinite solutions.

Step-by-step explanation:

infinitely many solutions :)

write an inequality whose solutions are represented by the shaded part of the graph​

Answers

Answer:

x > 3

Step-by-step explanation:

Use the remainder theorem to determine whether x=-4 is a solution of x^6+5x^5+5^4+5^3+2x^2-10x-8.​​

Answers

Hello haohaoxNienie!

[tex] \huge \boxed{\mathbb{QUESTION} \downarrow}[/tex]

Use the remainder theorem to determine whether x = - 4 is a solution of x⁶ + 5x⁵ + 5x⁴ + 5x³ + 2x² - 10x - 8.

[tex] \large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}[/tex]

Refer to the attached picture.

Steps :-First find the divisor using the given information (x = - 4).Now, divide x⁶ + 5x⁵ + 5x⁴ + 5x³ + 2x² - 10x - 8 by x + 4.We'll get the remainder as 0.Using the remainder theorem & solving it, we'll get LHS & RHS as 0.Hence proved.

Answer :- Yes, x = - 4 is a solution of x⁶ + 5x⁵ + 5x⁴ + 5x³ + 2x² - 10x - 8.

__________________

Hope it'll help you!

ℓu¢αzz ッ

Find the area of this triangle.

Answers

Answer:

84 cm²

Step-by-step explanation:

Area triangle = 1/2(b x h)

Area = 1/2(21 x 8)

Area = 1/2(168)

Area = 84

84 cm²

-Chetan K

A car travels the first 50km of its journey at an average speed of 25m/s and the next 120km at an average speed of 80km /h . The car completes the last part of its journey at an average speed of 90Km/h in 35 minutes . Find the average speed for its entire journey , giving your answer in km/h
Step by step

Answers

Answer:

What do you need me to do

Step-by-step explanation:

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