Answer:
It is an identity, proved below.
Step-by-step explanation:
I assume you want to prove the identity. There are several ways to prove the identity but here I will prove using one of method.
First, we have to know what cot and cosec are. They both are the reciprocal of sin (cosec) and tan (cot).
[tex]\displaystyle \large{\cot x=\frac{1}{\tan x}}\\\displaystyle \large{\csc x=\frac{1}{\sin x}}[/tex]
csc is mostly written which is cosec, first we have to write in 1/tan and 1/sin form.
[tex]\displaystyle \large{1+(\frac{1}{\tan x})^2=(\frac{1}{\sin x})^2}\\\displaystyle \large{1+\frac{1}{\tan^2x}=\frac{1}{\sin^2x}}[/tex]
Another identity is:
[tex]\displaystyle \large{\tan x=\frac{\sin x}{\cos x}}[/tex]
Therefore:
[tex]\displaystyle \large{1+\frac{1}{(\frac{\sin x}{\cos x})^2}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{1}{\frac{\sin^2x}{\cos^2x}}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}[/tex]
Now this is easier to prove because of same denominator, next step is to multiply 1 by sin^2x with denominator and numerator.
[tex]\displaystyle \large{\frac{\sin^2x}{\sin^2x}+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}\\\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}[/tex]
Another identity:
[tex]\displaystyle \large{\sin^2x+\cos^2x=1}[/tex]
Therefore:
[tex]\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}\longrightarrow \boxed{ \frac{1}{\sin^2x}={\frac{1}{\sin^2x}}}[/tex]
Hence proved, this is proof by using identity helping to find the specific identity.
help me pls pls help
Answer:
third one is a required answer.
x =2y
or
1/x=y
Answer:
Option 3, where x = 6, y = 3; x = 10, y = 5; x = 14, y = 7
Step-by-step explanation:
Step 1: Define proportional relationship
According to Khan Academy, "proportional relationships are relationships between two variables where their ratios are equivalent. Another way to think about them is that, in a proportional relationship, one variable is always a constant value times the other."
Step 2: Find the proportional relationship
Looking at option 3, we see that x is always 2 times bigger than y. This means as y increases, x is twice that amount. So if y is 10, x would be 20 and so on. Therefore, Option 3 is the correct answer.
Answer: Option 3, where x = 6, y = 3; x = 10, y = 5; x = 14, y = 7
Chocolate beans are packed in 250 g and 750 g packages. The number of 250 g packages and 750 g packages are in the ratio 1 : 2. If two of the 750 g packages are replaced into 250 g packages, then the ratio becomes 5 : 3. Find
a) the original number of 250 g packages,
b) the total mass of the chocolate beans.
Answer:
a) 4 packages
b) 7000 g or 7 kg
Step-by-step explanation:
x is the number of 250g packages and y is the number of 750g packages.
2x = y
3(x + 2 x (750 : 250)) = 5(y - 2)
3(x + 6) = 5(y - 2)
3(x + 6) = 5(2x - 2)
3(x + 6) = 5(2(x - 1))
3(x + 6) = 5 * 2 * (x - 1)
3(x + 6) = 10(x - 1)
3x + 18 = 10x - 10
(3x + 18) + 10 = (10x - 10) + 10
3x + 28 = 10x
28 = 10x - 3x
28 = 7x
x = 28/7
x = 4
y = 2 * 4 = 8
(250 * 4) + (750 * 8) = 7000 g
One person can do a certain job in 10 minutes and another person to the same job and 15 minutes how many minutes will it take to do the job together
Answer:
6 minutes
Step-by-step explanation:
The equation for time together is
1/a+1/b = 1/c where a and b are the times alone and c is the time together
1/10 + 1/15 = 1/c
Multiply by the least common denominator to clear the fraction
30c(1/10 + 1/15 = 1/c)
3c+ 2c = 30
5c = 30
Divide by 5
5c/5 = 30/5
c = 6
Answer:
6 minutes
Step-by-step explanation:
Person A does 1 job in 10 minutes.
In 1 minute, person A does 1/10 of the job.
Person B does the same job in 15 minutes.
In 1 minute, person B does 1/15 of the job.
Working together, in 1 minute the do
1/10 + 1/15 of the job.
Working together, they take t minutes to do the job.
In 1 minute, they do 1/t of the job.
1/10 + 1/15 = 1/t
3/30 + 2/30 = 1/t
5/30 = 1/t
1/6 = 1/t
t = 6
The length of a rectangle is 9 inches more than half the width. Find the length if the perimeter is 60 inches.
Answer:
Length = 10.435 inches
Step-by-step explanation:
Let the length be l
Let the width be w
Since the length is 9 inches more than half the width.
Then;
L = 0.5w + 9
Perimeter of a rectangle is;
P = 2Lw
Thus;
P = 2w(0.5w + 9)
Since perimeter = 60
Then;
2w(0.5w + 9) = 60
w² + 18w = 60
w² + 18w - 60 = 0
From quadratic formula;
w ≈ 2.87 in
L = 0.5(2.87) + 9
L = 10.435 in
( 1,-2), gradient = -3
Answer:
if you are required to find the equation of a straight line use the formula y-y1= m (x-x1)
y+2=-3(x-1)
y+2=-3x+3
y= -3x+3-2
y -3x+1
hope this helps
Answer:
y = -3x + 1
Step-by-step explanation:
(y -(-2)) = -3(x-1)
y+ 2 = -3x+ 3
y = -3x + 1
Find derivative of 3x^2+4 using limits
The derivative of a function f(x) is defined as
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h[/tex]
For f(x) = 3x ² + 4, we have
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{(3(x+h)^2+4) - (3x^2+4)}h[/tex]
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{(3(x^2+2xh+h^2) - 3x^2}h[/tex]
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{6xh+3h^2}h[/tex]
[tex]f'(x)=\displaystyle\lim_{h\to0}(6x+3h) = \boxed{6x}[/tex]
Two similar triangle prisms have edge lengths in the ratio of 5:3. What is the ratio of the surface areas the two prisms?
Answer:
Since the ratio of the two corresponding sides is 3:5, this means that edge_prism_1%2Fedge_prism_2=3%2F5
So the ratio of the two surface areas is simply the square of the ratio of the two sides. This means that ratio of the two surface areas is simply
3%5E2%2F5%5E2=9%2F25
Consequently, this works with volume also. So ratio of the two volumes is:
3%5E3%2F5%5E3=27%2F125Step-by-step explanation:
The included side between
The included side between
The included side between
Answer:
what?????............. :O
(15×4)6÷6[{32÷4(7x2-15+5)}+3]
(15×4)6÷6[{32÷4(7x2-15+5)}+3]
= -2
[ use BODMAS rule]
express the following shaded area using a definite integral. use geometry to calculate the area. please show work too
Answer:
Integrate( sqrt(9-x^2) from x=-3 to x=3)
Step-by-step explanation:
The equation for a full circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is center and radius is r.
Your center, your (h,k) is (0,0). Your radius, your r, is 3.
So your equation is (x-0)^2+(y-0)^2=3^2 or more simply x^2+y^2=9.
We also must consider we don't have full circle.
Solving for y will give us the circle in terms of top half if we take positive values and bottom half if we take negative values. Since y is positive in the picture, you only see top half, we will only take the positive cases for y.
Subtracting x^2 on both sides gives: y^2=9-x^2
Square root both sides: y= sqrt(9-x^2)
(I did not choose -sqrt(9-x^2) because again y is positive).
So the x's in the picture range from -3 to 3.
The integral is therefore,
Integrate( sqrt(9-x^2) from x=-3 to x=3)
THE LOGO SHOWN BELOW HAS A TOTAL AREA OF 125cm² AND THE SQUARE HAS SIDE LENGTH 5cm.CALCULATR THE WIDTH OF THE LOGO.
Answer:
Please show an image
How many times is the value of the digit 5 in 65.1748 lesser than the value of
the digit 5 in 3526.987?
100
1/100
1000
10
Answer:
3 times
Step-by-step explanation:
The 5 in "65.1748" is in the ones place. 5 is less than 10, 100, and 1000. 5 is greater than 1/100.
Which of the following values are in the range of the function graphed below? Check all that apply
Answer:
B, C, D
Step-by-step explanation:
In this problem, the range is what the output, or y, can be. The origin, or the middie of the graph, is when x=0 and y=0. From the 10s on the screen, we can gather that 5 lines = a distance of 10 on the graph. Using this information, we can say
5 lines = distance of 10
divide both sides by 5 to find the distance for each line
1 line = distance of 2
The function goes from y=0 to three lines down, for a distance of 6. The range is therefore [-6,0] as all values from -6 to 0 on the y axis are included on the graph, including 0 and -6. In this range, -6, -2, and -1 are all included.
U is the centroid of ∆SRT. What is the length of segment UV if length of UT = 3 cm?
Answer:
1.5 cm
Step-by-step explanation:
Since U us the centroid, the ratio between UV and UT is 1:2, UT = 3
so UV = 3/2 = 1.5 cm
1. Find(x) + g(x)
4 options to pick from
Find the measure of the indicated angle to the nearest degree
[tex] \cos(θ) = \frac{6}{32} \\ θ = 79.19[/tex]
What is the greatest common factor of 15n^5, 30n^3, and 45n^2
Answer:
15n^2 as it the highest expression that is common among these three.
can someone help me out
Can SOMEONE PLEASE HELP ME? I really need to get this work done by tonight. PLEASE
Are the triangle below similar
Answer:
Yes ,because of SAS similarity theorem
Step-by-step explanation:
In ΔYOM , ΔTON
∠YOM = ∠TON
[tex]\frac{OY}{OT}=\frac{96}{84}=\frac{8}{7}\\\\\frac{OM}{ON}=\frac{104}{91}=\frac{8}{7}[/tex]
SAS similarity theorem
Answer:
Hello,
Answer C
Step-by-step explanation:
[tex]\dfrac{96}{104}=? \dfrac{84}{91} \\\\Calculating\ crossed\ products\\96*91=8736\\104*84=8736\\they\ are\ equals\\\\\\\dfrac{YO}{MO} =\dfrac{OT}{ON} \\\\\\Triangles\ are\ similar\ because \ SAS \theorem\\\\[/tex]
What is the volume of this figure?
Answer:
156.25
Step-by-step explanation:
1/2 × b ×h =12.5
12.5 ×9 =156.25 hope you ace it
last one for similarity transformations:)
1. 1/2
2. Across Y axis
3. 3 rights and 2 ups (3, 2)
I need the answer ASAP
1. Add Area (Split the shape up to two or more known
shapes first)
12.5 ft
11.6 ft
19.2 ft
16.7 ft
Answer:
Step-by-step explanation:
The shape cam be split into a triangle and a trapezoid
✔️Area of the trapezoid = ½(a + b)h
Where,
a = 12.5 ft
b = 16.7 ft
h = 11.6 ft
Plug in the values
Area of the trapezoid = ½(12.5 + 16.7)*11.6
Area of trapezoid = 169.36 ft²
✔️Area of the triangle = ½*b*h
b = 16.7 ft
h = 19.2 - 11.6 = 7.6 ft
Area of the triangle = ½*16.7*7.6
= 63.46 ft²
✔️Area of the shape = 169.36 + 63.46
= 232.82 ft²
Help pls will give brainliest
Answer:
[(12+24)*7]/2=126. + area of circle. πr²/2= 72*3=216
Step-by-step explanation:
the answer is 342 if we assume valume of π to 3
SOMEONE HELP ME PLEASE
name least to greatest
3780
3.78
0.378
378
0.0378
Answer:
0.0378
0.378
3.78
378
3780
Answer: 0.0378, 0.378, 3.78, 378, 3780
Step-by-step explanation:
A sinusoidal graph has a maximum at the point (–40, 3) and a midline of y = – 12. Determine the amplitude of the graph.
Answer:
15
Step-by-step explanation:
The amplitude of y=sin(x) is 1 with a maximum of y=1 and a minimum of y=-1. It's amplitude is 1 because that is the distance the max( y=1 )is from the mid line (y=0) or the distance the min( y=-1 ) is from the mid line (y=0).
So we just need to find the distance the mid line, y=-12, and the max,y= 3, is from each other.
3--12=3+12=15
75% students out of 80 are present in a test , the students absent are :
Answer:
20 students are absent
Step-by-step explanation:
75/100 × 80 = 60
If 60 were present out of the 80
80 - 60 = 20
Have a great day :)
A company determines that its weekly online sales, Upper S (t ), in hundreds of dollars, t weeks after online sales began can be estimated by the equation below. Find the average weekly sales for the first 3 weeks after online sales began. Upper S (t )equals2 e Superscript t
Answer:
$1272.36 ( average weekly sales for first 3 weeks )
Step-by-step explanation:
weekly online sales = S(t)
Determine average weekly sales for first 3 weeks
S(t) = 2e^t
total sales = ∫ S(t) dt
∴ Average weekly sales for first 3 weeks ( note : S(t) = 2e^t )
= [tex]\int\limits^3_0 {2e^t \, dt / ( 3 - 0 )[/tex]
= 2 [ e^t ] ³₀ / 3 = 2 ( e^3 - e^0 ) / 3 = 2 ( 6.3618 ) = 12.7236 hundreds
= $1272.36 ( average weekly sales for first 3 weeks )
Iliana rotated trapezoid WXYZ 180° about the origin.
On a coordinate plane, trapezoid W X Y Z has points (negative 4, 2), (negative 3, 4), (negative 1, 4), (0, 2).
What is the correct set of image points for trapezoid W’X’Y’Z’?
W’(4, –2), X’(3, –4), Y’(1, –4), Z’(0, –2)
W’(4, 2), X’(3, 4), Y’(1, 4), Z’(0, 2)
W’(–2, –4), X’(–4, –3), Y’(–4, –1), Z’(–2, 0)
W’(2, 4), X’(4, 3), Y’(4, 1), Z’(2, 0)
Answer:
The answer is A. W’(4, –2), X’(3, –4), Y’(1, –4), Z’(0, –2)
Step-by-step explanation:
Answer:
The answer is A i got A 100 on the test here or the rest of the anwers for the test
Tanya’s rotation maps point K(24, –15) to K’(–15, –24). Which describes the rotation?
90 degrees clockwise rotation ✔
270 degrees clockwise rotation
180 degrees rotation
90 degrees counterclockwise rotation
Triangle XYZ is rotated 90° clockwise about the origin.
On a coordinate plane, triangle X Y Z has points (negative 3, 1), (4, 4), (4, 1).
What are the coordinates of point X’?
(1, 3) ✔
(3, –1)
(3, 1)
(–1, –3)
Triangle XYZ has vertices X(1, –1), Y(3, 4), and Z(5, –1). Nikko rotated the triangle 90° counterclockwise about the origin. What is the correct set of image points for triangle X’Y’Z’?
X’(1, 1), Y’(-4, 3), Z’(1, 5) ✔
X’(1, 1), Y’(–3, –4), Z’(–1, –5)
X’(–1, 1), Y’(–3, –4), Z’(–5, 1)
X’(–1, –1),Y’(4, –3), Z’(–1, –5)
Angie’s rotation maps triangle XYZ to triangle X’Y’Z’.
X(3, –6) maps to X’(–3, 6)
Y(1, –2) maps to Y’(–1, 2)
Z(–1, –5) maps to Z’(1, 5)
Which describes the rotation?
180 degrees rotation ✔
270 degrees clockwise rotation
90 degrees counterclockwise rotation
90 degrees clockwise rotation
A rotation maps point A to A’.
On a coordinate plane, point A prime is (negative 3, 4) and A is (3, negative 4).
Which statement describes the rotation?
270° counterclockwise rotation
90° clockwise rotation
180° rotation ✔
90° counterclockwise rotation
Rectangle PQRS is rotated 90° counterclockwise about the origin.
On a coordinate plane, rectangle P Q R S has points (2, 3), (5, 3), (5, 1), (2, 1).
What are the coordinates of point Q’?
Q’( –3, 5) ✔
Q’(3, –5)
Q’(5, –3)
Q’(–5, –3)
