Expand to write an equivalent expression
-1/4 (-8x + 12y)

Answers

Answer 1

The equivalent expression on expanding -1/4 (-8x + 12y) is 2x - 3y

Expansion of expression

Expansion of expression can be carried out using the distributive rule a shown:

A(B + C) = AB + AC

Note that A is distributed over B and C
Given the expression

-1/4 (-8x + 12y)

-1/4(-8x) - 1/4(12y)

2x - 3y

Hence the equivalent expression on expanding -1/4 (-8x + 12y) is 2x - 3y

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Related Questions

For what values of x is x2-36=5x true? -9 and -4 -4 and 9 4 and -9 9 and 4.

Answers

Answer: -4 and 9

Step-by-step explanation:

Someone help please.its really important

Answers

Answer:  Angle Y is 90 degrees, angle X is 35.  

Answer:x=35 and y=35

Step-by-step explanation:

Angle on straight line =180

so 180/2=90

90-55=35

and x and y opposite angle so are eqaul

Please simplify this!

Answers

Answer:

May be the answer is 5 . I don't think it's the answer .

Find the area of a sector of a circle with a radius of 6 and angle of the sector is 40 degrees

Answers

Answer:

12.56 units²

Step-by-step explanation:

Area of sector :

πr² x θ/360π(6)² x 40/36036π x  1/93.14 x 412.56 units²

Simplify the expression.
-81 ÷ (-9)
Please help

Answers

Answer:

-81/-9

both minus will be cut so

81/9

9

Step-by-step explanation:

the answer is 9

#57 will give brainliest to the best answer. please explain

Answers

Answer:

(x+y)(z+1)

Step-by-step explanation:

trust me .......

Answer:

(x+y) (z+1)

Step-by-step explanation:

xz + x + yz + y

- group the first two terms and the last two terms.

(xz + x ) + yz + y

- factor out the greatest common factor (GCF) from each group.

x (z + 1) + y (z + 1)

- factor the polynomial by factoring out the greatest common factor, z + 1.

(x+y) (z+1)

A podcast is 180 minutes long. During the podcast there are more than 48 minutes of commercials.
There are 8 commercial-free segments in the podcast that are each the same length.
In which inequality does a represent the possible length, in minutes, of each commercial-free segment of
the podcast?

Answers

127-79/4(48)-56a
A=68


Solve for y y/8 = 4

Answers

Answer:

32

Step-by-step explanation:

Multiply both sides by 8.

y/8 = 4

y/8 × 8 = 4 × 8

y = 32

Combine the like terms to create an equivalent expression.
2q+2+92

Answers

Answer:

2q + 94

Step-by-step explanation:

2q + 2 + 92 ← collect like terms

= 2q + (2 + 92)

= 2q + 94

Answer:

2q + 94

Step-by-step explanation:

2q + 2 + 92

Reorder and group

2q + (2 + 92)

Caculate

2q + 94

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*ANSWER*

What is the value of x?
x =6

Answers

Answer;

10

Step-by-step explanation:

from the question we observed that the shape is a right angled triangle.

and according to Pythagoras theorem, In a right angled triangle the square of the hypothenus is equal to the square of the sum of the other two side

hypothenus = 10

10^2= 8^ + X^2

100= 64 +X^2

X^2 = 100-64

X^2 = 36

X = √36

X= 6

2 1/6 - (-8/3) + (-4 7/9) what does it eqaul i cant figure it out

Answers

Answer:

- 95/18

Step-by-step explanation:

1st you have to convert the mixed number to an improper fraction so 2 ×6 = 12 +1 = 13 and that together equals 13/6 same goes for the next take away the parentheses 13/6 - 8/3 - 4 7/9

then you have to do the same thing with the 1st fraction convert it 4 × 9 = 36 + 7 = 43 that equals together 43/9

lastly you have to calculate the difference 13/6 - 8/3 - 43/9 and that equals negative 95/18

by the way the 95 isnt a negative the fraction itself is

Prove the following tan^2 A/(tan A -1 )+ cot A/(1 - tan A)=1 +sec A cosec A



In Image, Question is No.4 (vi)

Answers

See below for the proof of the trigonometry identity [tex]\frac{\tan^2(A)}{\tan(A) - 1} + \frac{\cot(A)}{1 - \tan(A)} =1 + \sec(A)\csc(A)[/tex]

How to prove the trigonometry identity?

The trigonometry equation is given as:

[tex]\frac{\tan^2(A)}{\tan(A) - 1} + \frac{\cot(A)}{1 - \tan(A)} =1 + \sec(A)\csc(A)[/tex]

Rewrite the equation as:

[tex]\frac{\tan^2(A) }{\tan(A) - 1} - \frac{\cot(A)}{ \tan(A) - 1} =1 + \sec(A)\csc(A)[/tex]

Take LCM

[tex]\frac{\tan^2(A) - \cot(A)}{ \tan(A) - 1} =1 + \sec(A)\csc(A)[/tex]

Express cot(A) as 1/tan(A)

[tex]\frac{\tan^2(A) - \frac{1}{\tan(A)}}{ \tan(A) - 1} =1 + \sec(A)\csc(A)[/tex]

Take LCM

[tex]\frac{\tan^3(A) - 1}{\tan(A)(\tan(A) - 1)} =1 + \sec(A)\csc(A)[/tex]

Apply the difference of two cubes on the numerator

[tex]\frac{(\tan(A) - 1)(\tan^2(A) + \tan(A) + 1)}{\tan(A)(\tan(A) - 1)} =1 + \sec(A)\csc(A)[/tex]

Cancel out the common factors

[tex]\frac{\tan^2(A) + \tan(A) + 1}{\tan(A)} =1 + \sec(A)\csc(A)[/tex]

Rewrite as:

[tex]\frac{\tan(A) + \tan^2(A) + 1}{\tan(A)} =1 + \sec(A)\csc(A)[/tex]

Split the fraction

[tex]1 + \frac{\tan^2(A) + 1}{\tan(A)} =1 + \sec(A)\csc(A)[/tex]

Express [tex]\tan^2(A) + 1[/tex] as [tex]\sec^2(A)[/tex]

[tex]1 + \frac{sec^2(A)}{\tan(A)} =1 + \sec(A)\csc(A)[/tex]

Divide [tex]\sec^2(A)[/tex] by [tex]\tan(A)[/tex]

[tex]1 + \frac{1}{\sin(A)\cos(A)} = 1 + \sec(A)\csc(A)[/tex]

Take the inverse of sin and cosine

[tex]1 + \sec(A)\csc(A) = 1 + \sec(A)\csc(A)[/tex]

Both sides of the equation are the same.

Hence, the trigonometry identity [tex]\frac{\tan^2(A)}{\tan(A) - 1} + \frac{\cot(A)}{1 - \tan(A)} =1 + \sec(A)\csc(A)[/tex] has been proved

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Would somebody be willing to help me please! I really need to pass this lesson!!

Answers

Answer:

x= -2 y= 36 (-2. 36)

x = -1 y = 6 (-1, 6)

x = 1 y = [tex]\frac{1}{6}[/tex] (1, [tex]\frac{1}{6}[/tex])

Step-by-step explanation:

Our function is [tex]y = (\frac{1}{6})^x[/tex]

all we need to do is fill in our x (given in the table) to solve for y

[tex]y = (\frac{1}{6})^{-2}[/tex]

[tex]y = 36[/tex]

[tex]y = (\frac{1}{6})^{-1}[/tex]

[tex]y = 6[/tex]

[tex]y = (\frac{1}{6})^1 = \frac{1}{6}[/tex]

Elias was given a lock for his school locker. The lock contains numbers between
O and 59 (60 different numbers). If 3 numbers are used to unlock the lock, and
the numbers can't repeat, how many codes can his lock have?

Answers

Answer:

34,220

Step-by-step explanation:

Because order doesn't matter, but the numbers can't be repeated, we need to find the number of combinations where 3 individual numbers can be chosen out of 60 possible numbers using the binomial coefficient:

[tex]\binom{n}{k}=\frac{n!}{k!(n-k)!}\\ \\\binom{60}{3}=\frac{60!}{3!(60-3)!}\\\\\binom{60}{3}=\frac{60!}{3!(57)!}\\\\\binom{60}{3}=\frac{60*59*58}{3*2*1}\\ \\\binom{60}{3}=34220[/tex]

Thus, Elias can make 34,220 unique 3-number codes given 60 different numbers.

PLSSS HELP IF YOU TURLY KNOW THISS

Answers

E: when looking at the line it starts from 0-1 and we’re looking for 0.97 which is 0.03 away from 1 meaning it’s going to be the closest to one
The answers to that one is e

Alice’s backyard is a rectangular piece of property that is twice as long as it is wide. the total area of her yard is 1,000 m2. what is the approximate width of her backyard? a = lw 11.2 m 15.8 m 22.4 m 44.8 m

Answers

The approximate width of Alice's backyard is 22.36 in.

Choose the answer 22.4

Please, please help. Unit test is due. (K12 User)


​△ACB​ is bisected by CP←→. m∠PCB=65° and PB=11 ft.

What is the approximate area of each half of ​△ACB​ ?


28 ft²

56 ft²

67 ft²

143 ft²

Answers

The approximate area of each half of ​△ACB is 28 square feet

Area of a triangle

The formula for calculating the area of a triangle is expressed as:

A = 0.5absintheta

Given the following

PB =11ft

<PCB = 65degrees

Using the SOH CAH TOA identity

tan<PCB = 11/CP
CP = 11/tan65
CP = 5.13 ft

Determine the required area

Area = 0.5(11)(5.13)sin90

Area = 5.5 * 5.13

Area . = 28 square ft

Hence the approximate area of each half of ​△ACB is 28 square feet

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POINTS!!! Answer both 3 and 4 PLEASE

Answers

Answer:

yes not function because 1 is repeated

Number 3 is a function because for every INPUT there is has only one output.
Number 4 isn’t a function because the input 1 has two values as the output therefore it isn’t a function.

Problem 4.2
A textbook has 428 numbered pages, starting with 1.



A textbook has 428 numbered pages, starting with 1.

You are equally likely to stop on any of the pages if you flip through the book randomly.
What is the probability that you turn to an even-numbered page?

Answers

Answer:

50%

half of the numbers are even

Step-by-step explanation:

Consider two events such that P(A) = equals 3/5 , P(B) = 2/3 , and P(A ∩ B) = 1/5 . Are events A and B independent events?

Yes, they are independent because P(A) ⋅ P(B) = P(A ∩ B)
No, they are dependent because P(A) ⋅ P(B) ≠ P(A ∩ B)
Yes, they are independent because P(A) ⋅ P(B) ≠ P(A ∩ B)
No, they are dependent because P(A) ⋅ P(B) = P(A ∩ B)

Answers

Answer:

Option 2

Step-by-step explanation:

Checking whether P(A) × P(B) = P(A∩B) :

3/5 x 2/3 = 1/52/5 ≠ 1/5

Since this does not obey the Multiplication rule of probability, these events are not independent.

So, the answer is :

No, they are dependent because P(A) ⋅ P(B) ≠ P(A ∩ B)

Answer:

Option B

Step-by-step explanation:

Option A should be true if they are independent

P(A)P(B)3/5×2/32/5≠1/5

So

They are dependant

The half-life of a radioactive kind of praseodymium is 17 minutes. If you start with 56 grams of it, how much will be left after 34 minutes?
grams

Answers

Answer:

14 gm

Step-by-step explanation:

34 minutes is TWO half lives   1/2 * 1/2 = 1/4   will be left

   1/4 * 56 = 14 gm

what is area and circumference of the circle if diameter is 30​

Answers

Solution, Diameter = 30[tex]radius = \frac{diameter}{2} = \frac{30}{2} = 15 \\ [/tex]

Now, []area = \pi {r}^{2} [/tex][tex] = 3.14 \times 15 \times 15[/tex][tex] = 706.5 [/tex]Hence the area is 706.5now........[tex]circumference = 2 \: \pi\: r[/tex][tex] = 2 \times 3.14 \times 15[/tex][tex] = 94.2[/tex]hence the answer is 94.2...

Solution,

Diameter = 30

[tex]radius = \frac{diameter}{2} = \frac{30}{2} = 15 \\ [/tex]

Now,

[tex]area = \pi {r}^{2} [/tex]

[tex] = 3.14 \times 15 \times 15[/tex]

[tex] = 706.5 [/tex]

Hence the area is 706.5

now........

[tex]=Circumference = 2 \: \pi\: r[/tex]

[tex] = 2 \times 3.14 \times 15[/tex]

[tex] = 94.2[/tex]

hence the answer is 94.2...

please help i dont understand how to find c i know about theorems but

Answers

Ok so firstly, you need to remember that when a radius is touching a tangent, the angle is always equal to 90°. So x + 57° = 90°. That means your angle is 33°. You have drawn a right angle which is correct so the left triangle's angle is 90° - 33° = 57°. Now because both sides of the triangle is radius, that means c and 57° are equal. That means c = 57°.

Answer:

c = 57 degrees.

Step-by-step explanation:

This is the Alternate Segment theorem:

The angle between a chord of a circle and a tangent to the circle = the angle subtended by the chord in the alternate segment.

So c = 57 degrees.

Interior and Exterior Triangle Angles (0/5)
Please full explanation
I will mark brainlist to whoever answers first

Answers

Answer:

     ∠R = 69

Step-by-step explanation:

Angle sum property

Sum of all angles of triangle = 180

     5x - 11 + 3x - 3 + 3x + 18 = 180

      5x + 3x + 3x  -11 - 3 + 18 = 180

Combine like terms

                             11x  + 4 = 180

                                   11x = 180 - 4

                                   11x = 176

                                      x = 176/11

                                       x = 16

∠R = 5x - 11

   = 5*16 - 11

   = 80 - 11

    = 69

Apply angle sum property

5x-11+3x-3+3x+18=18011x+4=18011x=176x=16

m<R

5(16)-1180-1169°

QUESTION ON THE IMAGE

Answers

Answer:

660 cubic cm

Step-by-step explanation:

Volume= bhl/2

Find the gradient of the line joining (-1,9) and (3,5)

Answers

[tex]\rule{300}{1}\\\dashrightarrow\large\blue\textsf{\textbf{\underline{Given question:-}}}[/tex]

   Find the gradient of the line joining (-1,9) and (3,5)

[tex]\dashrightarrow\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}[/tex]

Use the slope formula:-

[tex]\boxed{\frac{y_2-y_1}{x_2-x_1}}[/tex]

Replace the letters with the numbers:-

[tex]\boxed{\frac{5-9}{3-(-1)}}[/tex]

[tex]\circ[/tex] On simplification,

[tex]\boxed{\frac{-4}{3+1}}[/tex]

[tex]\circ[/tex] On further simplification,

[tex]\boxed{\frac{-4}{4}}[/tex]

[tex]\circ\sf{SLOPE=-1}[/tex]

Good luck with your studies.

[tex]\rule{300}{1}[/tex]

Bob is throwing a party. He has 22 pints of soda. At the end of the party, there are 8
pints of soda.
How many cups of soda were drank during the party?

Answers

Answer:

14

Step-by-step explanation:

If Bob has 22 pints, and one glass is one pint, the 22-8 = 14

Answer:

14

Step-by-step explanation:

you would subtract 8 pints of soda left from the total pints which is 22 to get 14 pints used during the party

22-8=14

does anyone know proof without words ?

Answers

Step-by-step explanation:

it shows that all the small triangles that together make the complete square (c²) under the Hypotenuse consist of exactly all the composing triangles of the squares above the legs (a² and b²).

we find the 2 purple, the 2 orange, the 2 yellow and the 2 blue triangles there.

so, the area of c² must be the same as the sum of the areas of a² and b².

How many different trains can you make of length three?

Answers

Using the combination formula, and supposing that you have n parts, it is found that the number of trains you can make is of:

[tex]N = C_{n,3} = \frac{n!}{3!(n - 3)!} = \frac{n!}{6(n-3)!}[/tex]

The order in which the parts are taken is not important, hence the combination formula is used to solve this question.

What is the combination formula?

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this problem, 3 parts are taken from a set of n, hence the total number of trains is given by:

[tex]N = C_{n,3} = \frac{n!}{3!(n - 3)!} = \frac{n!}{6(n-3)!}[/tex]

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Can someone please answer this, ill give you brainliest Would be very appreciated.

Answers

Explanation:

f(x) = (x-4)(x+2)

1) For x-intercept, y will be 0

(x-4)(x+2) = 0(x-4) =0, (x+2) = 0x = 4, x = -2

x-intercept: (4, 0), (-2, 0)

2) For vertex: x = -b/2a where ax² + bx + c

Quadratic function:

(x-4)(x+2)x² +2x-4x -8x² -2x -8

vertex:

x = -(-2)/2(1)x = 1

y: (x-4)(x+2) = (1-4)(1+2) = -9

ordered pair of vertex: (1, -9)

3) For y-intercept, x will be 0

(x-4)(x+2)(0-4)(0+2)-8

y-intercept: (0, -8)

Answer:

(4, 0) and (-2, 0)(1, -9)(0, -8)

Step-by-step explanation:

Q1 : Finding x-intercepts

Take f(x) to be 0, because the intercepts lie on the x-axis0 = (x - 4)(x + 2)x = 4 and x = -2The x-intercepts are : (4, 0) and (-2, 0)

Q2

Coordinates of vertex are : (h, k)Expand the polynomialx² - 2x - 8h = -b/2a = 2/2 = 1k = -D/4aD = b² - 4ac = 4 - 4(1)(-8) = 4 + 32 = 36k = -36/4 = -9The vertex is : (1, -9)

Q3

Take x = 0y = 0² - 2(0) - 8y = -8y-intercept is : (0, -8)
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