Answer:
When the object is placed between centre of curvature and principal focus of a concave mirror the image formed is beyond C as shown in the figure and it is real, inverted and magnified.
solution
Which two statements are true of electromagnetic waves?
DA. They do not need a medium to transfer energy.
DB. They travel by causing particles of matter to vibrate.
C. They need a medium to transfer energy.
DD. They transfer energy by disturbing electric and magnetic felds.
Answer:
AD
Explanation:
electromagnetic waves do not need a medium to travel, examples are ultraviolet radiation and infrared radiation.
Answer:
A and D
Explanation:
Just did it
Ifa truck starts from rest and it has acceleration of 4 m/s for 5 second
calculate its final velocity. What will be the distance travelled by the track
during the time interval?
Answer:
Distance 50m
final velocity 20ms^-1
[tex]s = ut + \frac{1}{2} a {t}^{2} \\ = 0 \times t + \frac{1}{2} \times 4 \times {5}^{2} = 50m[/tex]
[tex]v = u + at \\ v = 0 + 4 \times 5 \\ v = 20ms^{ - 1} [/tex]
A 68-kg skydiver has a speed of 52 m/s at an altitude of 670 m above the
ground. Determine the kinetic energy possessed by the skydiver, KE =
1/2mv^2*
Answer:
91936J
Explanation:
We know that kinetic energy= 1/2 mv^2
M= mass = 68 Kg
v= velocity= 52 m/s
KE=1/2 × 68 × (52)^2
KE= 1/2 × 68 × 2704
KE= 91936J
Many people experiment with a gateway drug.
A. before they try other drugs.
B. after they've tried other drugs.
C. only once.
Answer:B
Explanation:onec thwy tried others
base your answer to this question on the information below and on your knowledge of physics. A toy launcher that is used to launch small plastic spheres horizontally contains a spring with a spring constant of 50. Newtons per meter. The spring is compressed a distance of 0.10 meter when the launcher is ready to launch a plastic sphere. The spring is released and a 0.10-kilogram plastic sphere is fired from the launcher. Calculate the maximum speed with which the plastic sphere will be launched.
Answer: v = 2.24 m/s
Explanation: The Law of Conservation of Energy states that total energy is constant in any process and, it cannot be created nor destroyed, only transformed.
So, in the toy launcher, the energy of the compressed spring, called Elastic Potential Energy (PE), transforms into the movement of the plastic sphere, called Kinetic Energy (KE). Since total energy must be constant:
[tex]KE_{i}+PE_{i}=KE_{f}+PE_{f}[/tex]
where the terms with subscript i are related to the initial of the process and the terms with subscript f relates to the final process.
The equation is calculated as:
[tex]\frac{1}{2}kx^{2}+0=0+\frac{1}{2}mv^{2}[/tex]
[tex]\frac{1}{2}kx^{2}=\frac{1}{2}mv^{2}[/tex]
[tex]\frac{1}{2}50(0.1)^{2}=\frac{1}{2}(0.1)v^{2}[/tex]
[tex]v^{2}=\frac{50(0.1)^{2}}{0.1}[/tex]
[tex]v=\sqrt{50(0.1)}[/tex]
[tex]v=\sqrt{5}[/tex]
v = 2.24
The maximum speed the plastic sphere will be launched is 2.24 m/s.
The maximum speed of plastic sphere is 2.236 m/s, when sphere is launched.
The maximum velocity of sphere can be calculated by,
[tex]V_{max}= x \sqrt {\dfrac km}[/tex]
Where,
[tex]V_{max}[/tex] - maximum velocity of the sphere
[tex]x[/tex] - length of stretch = 0.10 m
[tex]k[/tex]- spring constant = 50 N
[tex]m[/tex]- mass of sphere = 0.10 kg
Put the values in the equation,
[tex]V_{max}= 0.1\sqrt {\dfrac {50}{0.1}}\\\\V_{max}= 0.1\times {22.36}\\\\V_{max}= 2.236\\[/tex]
Therefore, the maximum speed of plastic sphere is 2.236 m/s, when sphere is launched.
To know more about maximum velocity of in spring,
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ccording to Newton's Second Law, what effect will doubling the mass of an object have?
Use the table of electric force between objects in two different interactions to answer the question. Interaction Charge on Object 1 (C) Charge on Object 2 (C) Amount of Force A +1 -2 weak B +1 +2 strong Which conclusion about the interactions is correct? (1 point) O The objects in interaction A are farther apart than in interaction B. O The objects in interaction A are smaller than in interaction B O Positive charges are stronger than negative charges. O Repulsive forces are stronger than attractive forces. Type here to search
Answer:
The objects in interaction A are farther apart than in interaction B.
The objects in interaction A are farther apart than in interaction B.
What is coulomb's law?According to Coulomb's law: The magnitude of each of the electric forces with which two point-at-rest charges interact is directly proportional to the product of the magnitude of both charges.
And inversely proportional to the square of the distance that separates them and has the direction of the line that joins them.
The formula will be given as:
] [tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
Intersaction A is having weak force since the magnitude of the force is same in both interaction A and B from the formula of force the force is also dependent on the distance between the charge.
Thus the weak force in the interaction A is due to the higher distance between the two charges.
To know more about the coulomb's law, follow
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If a device uses mains electricity at 230v and has a 13a fuse in the plug wht is the maximmum power it can safley use?
Answer:
2990W
Explanation:
Given parameters:
Voltage = 230V
Current = 13A
Unknown:
Maximum power it can safely use = ?
Solution:
To solve this problem;
Power = Current x Voltage
Power = 230 x 13 = 2990W
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A 64 kg swimmer jumps, with a velocity of 4.2 m/s, off the front of a 25 kg kayak when the kayak is moving forward at a velocity of 3.2 m/s. What is the velocity of the kayak after the swimmer jumps off
Answer:
3.88m/s
Explanation:
Using the law of conservation of momentum
m1u1+m2u2 = (m1+m2)v
m1 and m2 are the masses
u1 and 2 are the initial velocities
v is the final velocity
Given
m1 = 64kg
u1 = 4.2m/s
m2 = 25kg
u2 = 3.2m/s
Required
Final velocity v
Substitute the given values into the formula
64(4.2)+25(3.2) = (65+25)v
268.8+80 = 90v
348.8 = 90v
v = 348.8/90
v = 3.88m/s
Hence the velocity of the kayak after the swimmer jumps off is 3.88m/s
Which factor should change when comparing the boiling times of the liquids?
A. The surface area of the boiling vessel
B. The type of liquid inside the boiling vessel
C. The original temperature of the boiling vessel
D. The volume of liquid inside the boiling vessel
Answer:
B
Explanation:
cause it be like that
B. The type of liquid inside the boiling vessel.
Which liquid is used in boiling point?
Paraffin oil is used for boiling factor willpower as it has a very excessive boiling factor and so it could be used to hold a high temperature within the boiling factor and melting factor equipment without lack of the substance.
Boiling is the process by which a liquid will become a vapor whilst it's miles heated to its boiling point. The alternative from a liquid segment to a gaseous segment occurs while the vapor pressure of the liquid is identical to the atmospheric stress exerted on the liquid.
Learn more about a boiling point here: https://brainly.com/question/40140
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Which example provides a complete scientific description of an object in motion?
A .5kg ball is tied to a 1 meter long string and swung in a vertical circle at a velocity of 4 m/s. Find the tension in the string at:
A-Top of the Circle
B-Bottom of the Circle
Answer:
A-Top of the Circle
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Mechanical engineers generally work in all of the following EXCEPT
•marine biology.
•aerospace products.
•automotive industry.
•computers and electronics.
Answer:
•marine biology.
Explanation:
A mechanical engineer is a professional individual who ensures the design of a mechanical assembly as well as the monitoring of its realization. His role involves the manufacturing of a prototype and developing new products for the company. Responsible for manufacturing, he advises the company and customers and assesses the risks and techniques used for its development. Finally, he supervises the installation and the market penetration of the product, as well as its maintenance.
A mechanical engineer can collaborate with many useful and complementary professions such as designers or marketers, it ensures the appearance and technical operation of the product. It is a job under high responsibility with projects that can be large.
Finally, he can also work in the construction sector, in the automotive industry, biomechanics, shipbuilding, aerospace production and aeronautics, railways, mechanics and metallurgy, robotics, textile machinery, etc.
When a car is going at a constant velocity down the freeway, is the net force zero or not zero assuming no friction?
Answer:
Zero
Explanation:
The net force acting on an object moving with constant velocity is zero. This is an accordance with the Newton's first law of motion.
Newton's first law of motion states that a body will continue in its state of rest or constant motion unless it is acted upon by an external force.
Since this body is moving with uniform motion, it is not accelerating. When a body is acceleration, the net force on it is not zero.
But this one is moving with uniform motion. The net force on the body is balanced and zero.
The capacitance of each capacitor is 1μF. Find the total capacitance
A sound wave traveling through dry air has a frequency of 16 Hz, a wavelength of 22 m, and a speed of 350 m/s. When the sound wave passes through a cloud of nitrous oxide, its wavelength changes to 16 m, while its frequency remains the same. What is its new speed? (The equation for the speed of a wave is v= f x 1.)
A. 350 m/s
B. 16 m/s
C. 5,600 m/s
D. 256 m/s
It's D
Answer:
D. 256 m/s
Explanation:
[tex]f[/tex] = Frequency of the wave = [tex]16\ \text{Hz}[/tex]
[tex]\lambda[/tex] = Wavelength = [tex]16\ \text{m}[/tex]
Speed of a wave is given by
[tex]v=f\lambda[/tex]
[tex]\Rightarrow v=16\times 16[/tex]
[tex]\Rightarrow v=256\ \text{m/s}[/tex]
The speed of the wave as it passes through the cloud of nitrous oxide is [tex]256\ \text{m/s}[/tex].
Answer:
D. 256 m/s
Explanation:
d. d as in dog
Jen is conducting an experiment involving a device known as a pith-ball electroscope, shown below.
The plastic ball of the electroscope hangs in midair and is uncharged. Charges cannot move along the silk thread that holds the ball in the air.
Jen completes the following steps in her experiment:
1- She collects three identical, uncharged rubber tubes.
2-She holds a magnet to the first tube for 5 minutes.
3-She submerges the second tube in a tank of water for 5 minutes.
4- She rubs the third tube with animal fur for 5 minutes.
Jen's teacher tells her that she can use the pith-ball electroscope to see if any of the rubber tubes are surrounded by an electric field. What should Jen do to test for an electric field surrounding each tube?
Answer:
bring each tube close to the plastic ball and note any movement of the ball
Explanation:
study island
just took the test!!!!!
Answer:
bring each tube close to the plastic ball and note any movement of the ball
Explanation:
Electric fields can exert forces on objects, even if the objects involved are not touching. One way to demonstrate that electric fields exist around charged objects is to observe the effects of their forces at a distance.
Since the plastic ball of the electroscope is made of insulating plastic and is uncharged, it will be attracted to any charged object brought near it. So Jen can observe the effects of the tube's electric fields by bringing each tube close to the plastic ball and noting any movement of the ball. If the ball moves toward a tube, then the process that Jen used on the tube generated an electric field.
What group of the periodic table is this atom in?
Answer:
Group 3
Explanation:
In groups moving from top to bottom in a group, valency remains same because number of valence electron remains same.
eg . valency of first group elements = 1
valency of second group = 2
valency of third group = 3
Hope it is useful
Explain the answer for the below Question
Pleaseeeee help me with b, c, and d. There are no angles.
Answer:
a. 150 J
b. 150 J
c. 0 J
d. 0 J
Explanation:
The given parameters are;
The horizontal force with which the man pulls the canister, F = 50 N
The distance he moves the vacuum cleaner, d = 3.0 m
a. Work done, W = Force applied, F × Distance moved by the force, d
Therefore, for the work done by the 50 N force on the canister, we have;
W = 50 N × 3.0 m = 150 N·m = 150 J
b. Given that he pulls the canister at a constant speed, we have;
The acceleration of the canister, a = 0 m/s²
Therefore, the net force on the canister, [tex]F_{NET}[/tex] = F - [tex]F_{Friction}[/tex] = m × a
Where;
m = The mass of the canister
a = The acceleration of the canister
F = The applied force = 50 N
[tex]F_{Friction}[/tex] = The force of friction
∴ [tex]F_{NET}[/tex] = m × a = m × 0 m/s² = 0 N
Therefore;
[tex]F_{NET}[/tex] = F - [tex]F_{Friction}[/tex] = 0 N
From which we have;
F = [tex]F_{Friction}[/tex] = 50 N (The applied force, F is equal to the force of friction,
The work done by friction = The force of friction × The distance in which the force of friction acts
∴ The work done by friction = [tex]F_{Friction}[/tex] × d - 50 N × 3.0 m = 150 J
The work done by friction = 150 J
c. The normal force, N acts perpendicular to the force of friction
The distance the canister moves in the perpendicular direction, [tex]d_p[/tex] = 0 m
∴ The work done by the normal direction = N × [tex]d_p[/tex] = N × 0 m = 0 J
The work done by the normal direction = 0 J
d. The vacuum weight, W, acts on the same line as the normal force but in the opposite direction to the normal force, N
Therefore, the weight, W, acts perpendicular to the line of motion of canister
The distance the canister moves in the direction of the weight, [tex]d_{wieght}[/tex] = 0 m
Therefore, the work done by the weight = W × [tex]d_{wieght}[/tex] = W × 0 m = 0 J
The work done by the weight = 0 J
A car traveling at a speed of 25 m/s increases its speed to 30 m/s in 10 sec. What is the acceleration of the car?
Answer:
.5m/s/s
Explanation:
V + at
What is the momentum of a 31.2 kg object traveling at a velocity of 2.1 m/s?
Answer:
p = 65.52 kg m/s
Explanation:
p = m × v
p = 31.2 × 2.1
p = 65.52 kg m/s
Petter performed an experiment to test which of the three compounds his teacher game him was an ionic compound. Which compound (A, B, or C) is most likely an ionic compound?
A major league pitcher can throw a baseball with a kinetic energy of 150 J. How much work must the pitcher do to the ball to give it that much KE?
A.) 150 J
B.) 0 J
C.) can't tell without knowing the mass of the ball
D.) 75 J
Answer:
A= 150 J
Explanation:
Kinetic energy is the energy of an object in motion.
The formula for kinetic energy is ;
K.E = 1/2 * m *v² where m is mass and v is velocity
Work done is equal to change in kinetic energy
W= Δ K.E
Given that K.E = 150 J
Taking that the ball was stationary before it was thrown, this makes its initial kinetic energy to be 0 J so the work done will be
W= Δ K.E
W= 150 - 0
W= 150 J
A mover pushes a 46.0kg crate 10.3m across a rough floor without acceleration. How much work did the mover do (horizontally) pushing the crate if the effective coefficient of friction was 0.50
Answer:
2,321.62JoulesExplanation:
The formula for calculating workdone is expressed as;
Workdone = Force * Distance
Get the force
F = nR
n is the coefficient of friction = 0.5
R is the reaction = mg
R = 46 ( 9.8)
R = 450.8N
F = 0.5 * 450.8
F = 225.4N
Distance = 10.3m
Get the workdone
Workdone = 225.4 * 10.3
Workdone = 2,321.62Joules
Hence the amount of work done is 2,321.62Joules
the gravitational potential energy of an object is due to
a .its mass
b .its acceleration due to gravity
c. its height above the earth' s surface
d .all of these
d. all of these
look at the picture to know from where we get this law with application on it
the weight of an object on the earths surface is 300N. when it is lifted to 3 times the height, its weight will become
Answer:
The weight of the object when it is lifted to 3 times the height is 33.[tex]\overline 3[/tex] N
Explanation:
The given parameters are;
The weight of the object on Earth, W = 300 N
The initial position of the object = On the surface of the Earth
Therefore;
The distance with which the weight is measured = The radius of the Earth, R
By Newton's Law of Gravitation, we have;
[tex]W = G \times \dfrac{M \times m}{R^2}[/tex]
Where;
W = 200 N
G = The universal gravitational constant
M = The mass of the Earth
m = The mass of the object
When the height of the object = 3 × R, the weight of the object, W₂, is given as follows;
[tex]W_2 = G \times \dfrac{M \times m}{(3 \times R)^2} = \dfrac{1}{9} \times G \times \dfrac{M \times m}{ R^2} = \dfrac{1}{9} \times W = \dfrac{1}{9} \times 300 N = 33.\overline 3 \ N[/tex]
Therefore, the weight of the object at 3 times the height, W₂ = 33.[tex]\overline 3[/tex] N
A car is stopped at a stop light. When the light turns green, it travels south 55 m/s in 5s. What is its acceleration? *
Answer:
11m/s^2
Explanation:
Acceleration can be calculated by diving speed by time. Since we know speed and time, acceleration can be calculated.
55/5 = 11m/s^2
What is the main idea of this text of "Phillis Wheatley"
Answer:
The main idea of the text is to tell you how Phillis wheatley grew up and what the person life was like
