Answer:
m^2/n
Step-by-step explanation:
The following laws of exponent are useful to this problem:
[tex] \displaystyle \large{ {(mn)}^{b} = {m}^{b} {n}^{b} } \\ \displaystyle \large{ {n}^{ - b} = \frac{1}{ {n}^{b} } }[/tex]
We are given the expression:
[tex] \displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } }[/tex]
Use the first law of exponent above.
[tex] \displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{(8)( \frac{1}{4}) } {n}^{ ( - 4)( \frac{1}{4}) } } \\ \displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{2 } {n}^{ - 1} }[/tex]
Make sure to recall the important necesscary fundamental math such as operation with negative numbers/integers, basic division, fraction, etc.
From the expression, apply the second law of exponent to n^-1.
[tex] \displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{2 } ( \frac{1}{ {n}^{1} } )} \\ \displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{2 } ( \frac{1}{ {n} } )} \\ [/tex]
Multiply m in.
[tex] \displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = \frac{ {m}^{2} }{ {n} } }[/tex]
Thus the answer is m^2/n.
find T1 and T2, if a 60 N load is hanged and in equilibrium position.
Answers:
T1 = 59.5677879151077 N
T2 = 45.7583538175564 N
The values are approximate. Round the values however you need to.
=========================================================
Explanation:
Refer to the diagram below. I have added red and blue lines to break up each tension vector into the x and y components. For tension T1 in red, we have x1 and y1 as the horizontal and vertical components respectively. Note that x1 points to the left and y1 points upward.
For T2 in blue, we have x2 point to the right and y2 point upward. The horizontal components x1 and x2 must be equal, and point in opposite directions, so that we have horizontal balance. Otherwise, the object would accelerate to one side rather than be stationary.
Applying a bit of trig, we can say
cos(angle) = adjacent/hypotenuse
cos(45) = (x1)/(T1)
x1 = T1*cos(45)
and also
sin(angle) = opposite/hypotenuse
sin(67) = (x2)/(T2)
x2 = T2*sin(67)
----------------------
Again, the x1 and x2 vectors must be equal in magnitude, allowing us to say this
x1 = x2
T1*cos(45) = T2*sin(67)
T1 = T2*sin(67)/cos(45)
which we'll use later.
----------------------
Doing a bit more trig set up, we know that
sin(45) = (y1)/(T1)
y1 = T1*sin(45)
and
cos(67) = (y2)/(T2)
y2 = T2*cos(67)
Adding those two y components together will yield the total upward force that the ropes apply
y1+y2 = T1*sin(45)+T2*cos(67)
y1+y2 = (T2*sin(67)/cos(45))*sin(45)+T2*cos(67)
y1+y2 = T2*( sin(67)*sin(45)/cos(45) + cos(67) )
y1+y2 = T2*( sin(67)*tan(45) + cos(67) )
y1+y2 = T2*( sin(67)*1 + cos(67) )
y1+y2 = T2*( sin(67) + cos(67) )
This combined upward pull must be equal to 60 newtons or else we wouldn't have vertical equilibrium. If the upward pull was smaller than the downward pull, then the object would be falling. If the other way around, then the object would be pulled upward at some accelerated speed (think of a spring action).
So we'll set y1+y2 equal to 60 and solve for T2
y1+y2 = 60
T2*( sin(67) + cos(67) ) = 60
T2 = 60/( sin(67) + cos(67) )
T2 = 45.7583538175564
That value is approximate. The units for T2 are in newtons. This is the amount of pull or force along the T2 line in the upper right direction.
Side note: make sure your calculator is in degree mode.
----------------------
The last thing to do is to compute T1
T1 = T2*sin(67)/cos(45)
T1 = 45.7583538175564*sin(67)/cos(45)
T1 = 59.5677879151077
That value is approximate as well. The units are also newtons here. This represents the amount of pull in the upper left direction as the diagram shows.
----------------------
Finding such values for T1 and T2 is useful to determine if a rope can handle a certain stress load. Let's say we had a rope that was rated for only 40 newtons. Anything beyond 40 N for this hypothetical rope would mean the rope breaks. We found T1 and T2 beyond this threshold which would indicate that such a rope isn't up to the task of holding this object up (at least not with the angles shown in the diagram).
The diagram shows a plan for a wheelchair ramp in a shopping Mall. The distance AC is 4 m. calculate the distance AB when BC= 300cm
Answer:500 cm.
Step-by-step explanation:in the picture.
Please give me a brainliest
Please help, I’ll mark your answer as brainliest!
PLEASE PLEASE PLEASEEEEEEE HELP RNNN xddddddd
Lets find the slope of the graph for Jennifer's record. THe slope represents her rate.
Slope = (y2 - y1) / (x2 - x1)
Lets use the first two points.
Slope = (8 - 5) / 64 - 40)
= 3 / 24
= 1 / 8
Use the second and third points.
Slope = (10 - 8) / (80 - 64)
= 2 / 16
= 1 / 8
Last points.
Slope = (12 - 10) / (96 - 80)
= 2 / 16
= 1 / 8
The slopes are constant.
Now we compare the slopes. Use the LCD to compare fractions.
1 / 9 = 8 / 72
1 / 8 = 9 / 72
9 / 72 > 8 / 72
Jennifer has the faster training rate. She can cover more distance in less time than Patrick can.
Will give brainliest for best answer
Answer:
The answer is A
Step-by-step explanation:
X represents the numbers of cones which is 50
Anyone willing to help? I have to submit it tmr
Answer:
here's your answer
hope it helps
(look at attachment)
The Moon is about 240,000, or x _____ 10 miles from earth
Step-by-step explanation:
240,000 = 24 x 10^4
24 followed by 4 zeros = 24 x 104
Just make the number of zeroes be the exponent for 10
24 = 24 x 10^0
240 = 24 x 10^1
2400 = 24 x 10^2
24000 = 24 x 10^3
240,000 = 24 x 10^4 miles
if x=1 and y =-2 what's 3(2-x)+4(3-y)
explanation please
Answer:
23
Step-by-step explanation:
When using empirical data (data and information collected by scientists in an experiment), sometimes, that data will not form a perfect line on a graph. When this happens, the line that is created using a linear regression is known as the “Line of Best Fit.” The following speed data was collected from a car moving with a constant acceleration.
Time (s) Velocity (m/s)
2 13.1
4 19.8
6 28.1
8 34.6
What is the Line of Best Fit for this data? Perform a linear Regression on this table to find the equation.
Based on your equation, what was the car’s approximate initial velocity (at time=0)?
If the car continued at the same acceleration (meaning the slope of the line does not change), how fast would it be going in 15 seconds?
Answer:
98.25
Step-by-step explanation:
sorry to ask this late on Friday but stuck at home without a calculator Plllleeeaaassseee Hep me!!!!!!!!!!!!!!!!!!!!!!
5+842+6666+7432+84 x 4
Answer:(:
Step-by-step explanation:
15281
The pyramid of Khafre measured 143.5 meters high. The pyramid of Menkaure measured 65.5 meters high. Write and solve an equation to find d, the difference in the heights of these two pyramid.
Answer:
See belowStep-by-step explanation:
The pyramid of Khafre measured 143.5 meters high.The pyramid of Menkaure measured 65.5 meters high.The difference in the heights of the two pyramids:
d = 143.5 m - 65.5 md = 78 mLets see
d is difference between the heights
143.565.5So
d=143.5-65.5d=78mWhat type of property is 3x•2y=3•2•x•y
Multiply 5x(6x−4)
A- 11x^2+x
B- 30x^2 - 4
C - 30x^2 + 20x
D - 30x^2 - 20x
What is the rhyme scheme of this poem?
I wanted to use the mat
but couldn't remove my cat
who always sat
directly at
the place I needed to pose.
A. abccb
B. ababa
C. aaaab
D. abbab
Answer:
c
Step-by-step explanation:
because all of the lines except for the last one is the same. so its aaaab
Write 3/6/7 in an improper fraction in the lowest term
Answer:
27/7
the mixed number 3 6/7 can be written as 27/7.
The value of an improper fraction in the lowest term is,
⇒ 27/7
We have to give that,
A mixed fraction is,
⇒ 3 6/7
Now, We can change the fraction into an improper fraction as,
⇒ 3 6/7
⇒ (3×7 + 6)/7
⇒ (21 + 6)/7
⇒ 27/7
Therefore, an improper fraction in the lowest term is,
⇒ 27/7
To learn more about the fraction visit:
https://brainly.com/question/5454147
#SPJ6
A metal strip is being installed around a rectangular workbench that is 8 feet long and 4 feet wide. If the stripping costs $4 per foot, find the total cost of the stripping.
Answer:
$144
Step-by-step explanation:
Length*Width*Price
12*3 = 36
36*4 = 144
$144
Using the quadratic formula, which of the following are the zeros of the quadratic equation below?
y=x²-x-5
Answer: The answer is the option A.
x=(5±)/4
Step-by-step explanation: The quadratic formula has the following form for a quadratic equation ax²+bx+c:
x=(-b±))/(2a)
We apply the quadratic formula and we obtain:
x=(-(-5)±))/(2(2))
x=(-(-5)±))/(4)
x=(-(-5)±))/(4)
Solve: (x - y)/(sqrt(x) + 1) = 2 + (sqrt(x) - 5)/3
Given the endpoint (-4,5) and midpoint (-8, 8), what is the other endpoint?
Answer: the endpoint is going to be (-12,11)
Step-by-step explanation: sorry if it wrong
please i need help asap!
Answer:
3
Step-by-step explanation:
3
Shaheer takes 4 1/2 minutes to run ONE
PROPER LAP around the School
How many laps can he do in each time
a) 30 minutes
b) 20 minutes
c) 15 minutes
Answer:
Im not
sure but i think its (B) i really hope its right
Step-by-step explanation:
I need help with my math, please?
Answer:
Step-by-step explanation:
guys pls help me!!!!!
Answer:
12 degrees
Step-by-step explanation:
it would be about 30 or 210
List the first 4 terms of the sequence 3n² + 1
Answer:
4, 13, 28, 49
Step-by-step explanation:
1st term = 3 × (1)² + 1 = 4
2nd term = 3 × (2)² + 1 = 13
3rd term = 3 × (3)² + 1 = 28
4th term = 3 × (4)² + 1 = 49
The first for terms of the series can be found by substituting the n for the term it is:
= 3(1)² + 1 , 3(2)² + 1 , 3(3)² + 1 ,3(4)² + 1
= 4, 13, 28, 49
Please help me, I will be so thankful
Answer:
Step-by-step explanation:
g(-4) = 4 , x < -2
g(-2) = (x - 1)² ; -2≤x< 1
= (-2-1)²
= (-3)²
g(-2) = 9
g(0) = (x -1)² ; -2 ≤ x < 1
= (0 -1)²
= (-1)²
= 1
Translate the sentence into an equation or formula.
The perimeter P of a triangle is equal to the sum of the lengths of sides a, b, and c.
Answer:
P = a + b + c
Step-by-step explanation:
Please help me out! View the image below!
Answer:
y=-2x+1
Step-by-step explanation:
Look at the photo i think
How do you do this question?
Answer:
The answer is D) 12
There are two trips, but the distances are the same.
Trip #1: uphill, at 9 mph
Trip #2: downhill at 18 mph
Total round trip is 30 minutes.
Since he's going half the speed uphill, Trip #1 takes twice as long as Trip #2.
So if the time for Trip #2 is x, then the time for Trip #1 is 2x.
x + 2x = 30, so x=10
Trip #2 takes 10 minutes.
Trip #1 takes 20 minutes.
Trip #1: 20 minutes at 9 mph = 3 miles
Trip #2: 10 minutes at 18 mph = 3 miles
This means his school is 3 miles away.
If you want an equation to solve,
Let d = distance to school. We use d = r·t formula to set up that t = d/r
let t1 = time going to school and t2 = times going home
t1 + t2 = 30 and t1 = d/9 and t2 = d/18.
d/9 + d/18 = 0.5 (it's 0.5, because we need the time in hours)
mutiply both sides b 18
2d + d = 9
3d = 9
d = 3
I need help ASAP!!! (please look at the image and explain how you got the answer, please and thanks)
Answer:
114
Step-by-step explanation:
so lets call shelf 1 x
shelf 2 is twice size + 18 of shelf 1 so it is 2(x)+18
shelf 3 is 12 less than shelf 1 so x-12
shelf 4 is four more so x+4
Add them all together and it should be 5x+10= 2.5 m or 250 cm
Solve for x using cm
then plug into shelf 2 equation
Que. 19. In the equation x = 2y + 9, if x = 1, than y =
Answer: y = -4
Step-by-step explanation:
If x = 1
1 = 2y + 9
1 - 9 = 2y
-8 = 2y
y = -8/2
y = -4
please give me a brainliest answer
Answer:
[tex]y = ( - 4)[/tex]
Step-by-step explanation:
Given that,
[tex]x = 1[/tex]
Question :
[tex]x = 2y + 9[/tex]
You have to find the value of y. So, make the y as the Subject
[tex]x = 2y + 9 \\ x - 9 = 2y \\ \frac{x - 9}{2} = \frac{2y}{2} \\ \frac{x - 9}{2} = y[/tex]
Now replace 1 instead of x
[tex]y = \frac{x - 9}{2} \\ y = \frac{1 - 9}{2} \\ y = \frac{ - 8}{2} \\ y = - 4[/tex]
Hope this helps you.
Let me know if you have any other questions :-)