Develop a program to sort a file consisting of bonks details in the alphabetical order of author names. The details of books include book id, author_name, price. no of pages, publisher, year of publishing
Please provide C++ program for above question.​

Answers

Answer 1

Use the knowledge in computational language in C++ to write the a code with alphabetical order of author name.

How to define an array in C++?

An Array is a set of values ​​arranged in lists and accessible through a positive numeric index. So, we have that each position of our Array is a variable of the type of our Array, so we have to have a way to initialize this set of variables.

#include <iostream>

#include <iomanip>

#include <fstream>

#include <string>

using namespace std;

struct Book {

   string title;

   string author;

};

const int ARRAY_SIZE = 1000;

Book books [ARRAY_SIZE];

string pathname;

ifstream library;

int LoadData();

void ShowAll(int count);

void ShowBooksByAuthor(int count, string name);

void ShowBooksByTitle(int count, string title);

void sortByTitle(int count, string title);

void sortByAuthor(int count, string author);

int main()

{  

   int count = 0;

   char selector = 'q', yesNoAnswer = 'n';

   string name;

   string title;

     cout << "Welcome to Forrest's Library Database." << endl;

   cout << "Please enter the name of the backup file: ";

   getline(cin, pathname);

   LoadData();

   count = LoadData();

   cout  << count << " records loaded successfully." << endl;

   do

   {

       cout << endl << "\t(S)how All, Search (A)uthor, Search (T)itle, (Q)uit: ";

       cin >> selector;

       selector = toupper(selector);

       switch(selector)

       {

           case 'S':

               sortByTitle(count, title);

               if (count <= 0)

                   cout << "No counts found!\n";

               else

                   ShowAll(count);

               break;

           case 'A':

               sortByAuthor(count, name);

               cout << "bookAuthor: ";

               cin.ignore();

               getline(cin, name);

               if (count <= 0)

                   cout << "No records found!\n";

               else

                   ShowBooksByAuthor(count, name);

               break;

           case 'T':

               sortByTitle(count, title);

               cout << "bookTitle: ";

               cin.ignore();

               getline(cin, title);

               if (count <= 0)

                   cout << "No records found!\n";

               else

                   ShowBooksByTitle(count, title);      

               break;

       }

   }

   while (selector != 'q' && selector != 'Q');

   return 0;

}

int LoadData()

{

   int count = 0;

   int i = 0;

   library.open(pathname);

   ifstream library(pathname);

   if (!library)

   {

       cout << "Cannot open backup file" << endl;

       return 0;

   }

   while (!library.eof())

   {

       getline(library, books[count].title);

       getline(library, books[count].author);

       count++;

   }

   return count;

}

void ShowAll(int count)

{

   for (int i = 0; i < count; i++)

   {

      cout << books[i].title << " " << "(" << books[i].author << ")" << endl;

   }

}

void ShowBooksByAuthor(int count, string name)

{

   int j = 0;

   for (int i = 0; i < count; i++)

   {

       if(books[i].author.find(name) < 100)

       {

           cout << books[i].title << " " << "(" << books[i].author << ")" << endl;

           j++;

       }

   }

   cout << j << " records found";}

void ShowBooksByTitle(int count, string title)

{

   int j = 0;

   for (int i = 0; i < count; i++)

   {

       if(books[i].title.find(title) < 100)

       {

           cout << books[i].title << " " << "(" << books[i].author << ")" << endl;

           j++;

       }

   }

   cout << j << " records found";

}

void sortByTitle(int count, string title) {

   string temp;

   for (int i = 0; i < count; i++) {

       for(int j = 0; j < count - i; j++) {

           if (books[j].title > books[j + 1].title) {

               temp = books[j].title;

               books[j].title = books[j + 1].title;

               books[j + 1].title = temp;

           }

       }

   }

}

void sortByAuthor(int count, string name) {

   string temp;

   for (int i = 0; i < count; i++) {

       for(int j = 0; j < count - i; j++) {

           if (books[j].author > books[j + 1].author) {

               temp = books[j].author;

               books[j].author = books[j + 1].author;

               books[j + 1].author = temp;

           }

       }

   }

}

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Develop A Program To Sort A File Consisting Of Bonks Details In The Alphabetical Order Of Author Names.
Develop A Program To Sort A File Consisting Of Bonks Details In The Alphabetical Order Of Author Names.
Develop A Program To Sort A File Consisting Of Bonks Details In The Alphabetical Order Of Author Names.

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Explanation:

Also i don't think this is coding related-

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Answers

Answer:

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Explanation:

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Option B

Answer:

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Explanation:

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Answer:

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Explanation:

Stay safe, stay healthy and blessed.

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Thank you

Answer ↓

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Explanation ↓

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hope helpful ~

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Answers

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Explanation:

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Write a program that allows two players (player X and player O) to play a game of tic-tac-toe. Use a two- dimensional char array with three rows and three columns as the game board. Each element of the array should be initialized with an asterisk (*). The players take turns making moves and the program keeps track of whose turn it is. Player X moves first. The program should run a loop that:

Answers

#include <iostream>

using namespace std;

//function prototypes

void showBoard(char[][3]);

bool checkWinner(char[][3], char);

void playerMove(char[][3], char);

int main()

{

  //declare variables needed

  //declare 2D array for the board

  //and initialize with all *

  char board[3][3] = {{'*', '*', '*'},

                      {'*', '*', '*'},

                      {'*', '*', '*'}};

  int moves = 0;  //variable to keep track

                  //of number of moves

                  //to determine tie

  cout << "TIC - TAC - TOE\n\n";

  //while loop to repeat until 9 moves are done

  while(true){

      //display board

      showBoard(board);

      cout << "Player 1 moves\n";

      //get player X move

      playerMove(board, 'X');

      //increment moves counter

      moves++;

      //if this is a winning move

      //store winner and terminate

      if(checkWinner(board, 'X')){

          showBoard(board);

          cout << "\nPlayer 1 (X) wins!\n";

          return 0;

      }

      //if 9 moves are done

      //break from loop

      if(moves == 9)

          break;

      //display board again

      showBoard(board);

      cout << "Player 2 moves\n";

      //do the same thing for player O

      playerMove(board, 'O');

      moves++;

      if(checkWinner(board, 'O')){

          showBoard(board);

          cout << "\nPlayer 2 (O) wins!\n";

          return 0;

      }

  }

  //if we have gone this far and program

  //still has not terminated (no winner)

  //it means this is a tie

  showBoard(board);

  cout << "This game is a tie!\n";

  //return 0 to mark successful completion of program

  return 0;

}

//this function is helpful because we need to show

//the board repetitively during the program

void showBoard(char board[][3]){

  cout << endl;

  //loop on the rows

  for(int row = 0; row < 3; row++){

      //loop on the columns

      for(int col = 0; col < 3; col++)

          cout << board[row][col] << "    ";

      //display newline after each row

      cout << endl << endl;

  }

  cout << endl;

}

//this function checks if second argument

//is a winning player

bool checkWinner(char board[][3], char player){

  //boolean variable to check

  //for winner later

  bool flag;

  //CHECK FOR WINNER IN ROWS

  for(int row = 0; row < 3; row++){

      //initialize flag to true

      flag = true;

      //loop within a row

      for(int col = 0; col < 3; col++){

          //Notice that the right part of the

          //assignment operator, is an expression

          //with a relational operator (==)

          //this expression will yield either

          //true (1) or false (0)

          //while flag is already true (1)

          //if multiplied by true (1) will result

          //in true(0), or multiplied by false (0)

          //will result in false (0)

          flag *= (board[row][col] == player);

      }

      //after checking within row, if the flag

      //is still true at this point, it means we have

      //three chars of the same kind within the row,

      //thus we have a winner

      if(flag)

          return true;

      else

          continue;

  }

  //CHECK FOR WINNER IN COLUMNS

  //using a similar logic

  for(int col = 0; col < 3; col++){

      flag = true;

      for(int row = 0; row < 3; row++){

          flag *= (board[row][col] == player);

      }

      if(flag)

          return true;

      else

          continue;

  }

  //CHECK FIRST DIAGONAL (row = col)

  //reset flag to true

  flag = true;

  //check diagonal

  for(int i = 0; i < 3; i++){

      flag *= (board[i][i] == player);

  }

  //check if there is winner

  if(flag)

      return true;

  //CHECK OTHER DIAGONAL (row = 2 - col)

  //reset flag to true

  flag = true;

  //check diagonal

  for(int col = 0; col < 3; col++){

      flag *= (board[2-col][col] == player);

  }

  //check if there is winner

  if(flag)

      return true;

  //if all of these have been checked

  //and function still has not returned,

  //it means there is no winner

  return false;

}

//this function gets a move from the player,

//checks if it is valid, and if yes it puts

//it on the board

void playerMove(char board[][3], char player){

  //variables to store user move

  int row, col;

  //get user move

  cout << "Row: ";

  cin >> row;

  cout << "Col: ";

  cin >> col;

  //check if this is valid move

  //you have to check if that tile has

  //already been marked, or if tile

  //of choice is out of bounds of board

  while(board[row-1][col-1] != '*' ||

        row > 3 || row < 0 ||

        col > 3 || row < 0)

          {

      cout << "Invalid move! Try again\n";

      cout << "Row: ";

      cin >> row;

      cout << "Col: ";

      cin >> col;

  }

  //after validation, mark new move

  board[row-1][col-1] = player;

}

Answer:

if on edgen. The answer is c

Explanation:

with the aid of your own example explain how memory,registers and secondary storage all work together​

Answers

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Craig's team can demonstrate this by creating a(n) {----------}
.

Answers

Answer:

A project scope

Explanation:

I just took this on plato

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Homework 8 Matlab Write a function called fibonacciMatrix. It should have three inputs, col1, col2, and n. col1 and col2 are vertical arrays of the same length, and n is an integer number greater than 2. It should return an output, fib, a matrix with n columns. The first two columns should be col1 and col2. For every subsequent column:

Answers

In this exercise we have to use the knowledge in computational language in python to write the following code:

We have the code can be found in the attached image.

So in an easier way we have that the code is:

function v = myfib(n,v)

if nargin==1

   v = myfib(n-1,[0,1]);

elseif n>1

   v = myfib(n-1,[v,v(end-1)+v(end)]);

end

end

function v = myfib(n,v)

if nargin==1

   v = myfib(n-1,[0,1]);

elseif n>1

   v = myfib(n-1,[v,v(end-1)+v(end)]);

elseif n<1

   v = 0;

end

function [n] = abcd(x)

if (x == 1 || x==0)

   n = x;

   return

else

   n = abcd(x-1) + abcd(x-2);

end

end

fibonacci = [0 1];

for i = 1:n-2

   fibonacci = [fibonacci fibonacci(end)+fibonacci(end-1)];

end

>> myfib(8)

ans =

   0    1    1    2    3    5    8   13

>> myfib(10)

ans =

   0    1    1    2    3    5    8   13   21   34

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Answers

Answer:

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Answers

Answer:

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Explanation:

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2.Thesaurus

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3.Risk assessment

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and last..........is four

4. Field

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FieldDifferent branches of cyber securityApplication security.Network and infrastructure security.

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FieldDifferent branches of cyber securityApplication security.Network and infrastructure security.Intrusion detection and penetration testing.Digital forensics and incident response.

FieldDifferent branches of cyber securityApplication security.Network and infrastructure security.Intrusion detection and penetration testing.Digital forensics and incident response.Endpoint protection and mobile security.

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Answers

Answer:

A real address is the physical address in main memory. Though a virtual address is the address of a storage location in virtual memory.

hopes this help (:`

Answer:

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Answers

The quiz program is an illustration of loops and conditional statements

Loops are used to perform repetitionConditional statements are used to make decisions

The quiz program

The quiz program written in C++, where comments are used to explain each action is as follows:

#include <iostream>

using namespace std;

int main(){

   //This prints the instruction

   cout<<"Enter T/t for True; F/f for False\n";

   //This initializes the question

   string questions[5] = { "Q1", "Q2", "Q3", "Q4", "Q5"};

   //This initializes the correct options

   char options[5] = { 'T','T','F','F','T'};

   //This declares the user response

   char opt;

   //This initializes the score to 0

   int score = 0;

   //This loop is repeated 5 times

   for (int i = 0; i < 5; i++){

       //This prints the current question

       cout << i + 1 <<". "<<questions[i]<<"\nAnswer: ";

       //This gets the user response

       cin>>opt;

       //If the user response is correct

       if(toupper(opt) == options[i]){

           //The score is incremented by 2

           score+=2;

       }

   }

   //This prints the total score

   cout<<"Score: "<<score;

   return 0;

}

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What should I do instead of listen to music?

Answers

You could watch a movie
Learn something new that you are interested in

what does the GPU do?

Answers

Answer:

With graphics processing units (GPU), many pieces of data can be processed simultaneously, which makes them useful for applications such as machine learning, editing, and gaming. It is an electronics circuit capable of accelerating the processing of images, animations, and videos.

Explanation:

Restarting a computer which is already on is referred as

Answers

Answer:

what is compute

Explanation:

computer is machine

Match the product to its function.

Answers

Answer:

MYSQL: Database

MONGO DB: Database

SVELTE: Framework

JS: Language

VUE: Framework

PHP: Language

POSTGRES: Database

React: Framework (a JS library actually)

Python: Language

9.11: Array Expander
Write a function that accepts an int array and the array’s size as arguments. The function should create a new array that is twice the size of the argument array. The function should copy the contents of the argument array to the new array, and initialize the unused elements of the second array with 0. The function should return a pointer to the new array. Demonstrate the function by using it in a main program that reads an integer N (that is not more than 50) from standard input and then reads N integers from a file named data into an array. The program then passes the array to your array expander function, and prints the values of the new expanded array on standard output, one value per line. You may assume that the file data has at least N values.

Prompts And Output Labels. There are no prompts for the integer and no labels for the reversed array that is printed out.

Input Validation. If the integer read in from standard input exceeds 50 or is less than 0 the program terminates silently.

Answers

The Array Expander is an illustration of arrays and functions.

Arrays are variables that stores multiple valuesFunctions are named statements that are executed when called

The Array Expander program

The Array Expander program written in C++, where comments are used to explain each action is as follows:

#include <iostream>

using namespace std;

//This declares the Array Expander function

int* ArrayExpander(int *oldArr, int size){

   //This declares the new array

   int *newArr = new int[size * 2];

//This iteration sets values into the new array

   for (int i = 0; i < size * 2; i++) {

       if(i < size){

           *(newArr+i) = *(oldArr+i);

       }

       else{

           *(newArr+i) = 0;

       }

   }

//This returns a pointer to the new array

   return newArr;

}

//The main method begins here

int main(){

//This declares the length of the array, N

   int N;    

//This gets input for N

   cin>>N;

   int initArr[N];

//If N is between 1 and 50

   if(N > 0 && N <=50){

//This iteration gets values for the array

       for(int i = 0; i<N; i++){

           cin>>initArr[i];

       }

//This calls the Array Expander function

   int *ptr = ArrayExpander(initArr, N);

//This iteration prints the elements of the new array

   for (int i = 0; i < N*2; i++) {

       cout << ptr[i] << " ";

   }

   }

  return 0;

}

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what is the important of hvac?

Answers

Answer:

Moreover, buildings need HVAC installed in them because:

HVAC systems are used for controlling the overall climate in a building. ...

HVAC fosters enhanced productivity in offices as they feel comfortable. ...

HVAC improves air quality in the building, helping make it appropriate for human breathing and comfort. ...

HVAC systems help you achieve more savings when it comes to energy bills

Explanation:

Answer:

Units larger than a terabyte include a petabyte, exabyte, zettabyte, yottabyte and brontobyte. A geopbyte is also larger than a terabyte and refers to 10 30 bytes, or 1,000 brontobytes. Additional units of measurement become necessary as the amount of data in the world increases.

Explanation:

Identify three (3) general-purpose computing devices and write a short (no more than one page) essay explaining in detail the computing process.

Answers

The three general-purpose computing devices are desktops, notebooks, smartphones. The computing process of these devices are further explained below.

What are general-purpose computers?

A general-purpose computer is a type of computer that has the ability to carry out many different tasks. The following tasks can be performed by the general purpose computing devices:

installation of softwares,

processing of data, and

storage of processed data.

The computing process of all the general-purpose computer are the same.

It involves preparation and inputting of data into the computer using the input devices.

The data is sent to the processing unit called the central processing unit (CPU) which has the electronic circuitry that manipulates input data into the information people want.

The information is then displayed in an output device example the monitor, for the user to view.

Therefore, the three general-purpose computing devices are desktops, notebooks, smartphones.

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How many categories of computer do we have?

Answers

Answer:

The 10 types of computers include personal computers, desktops, laptops, tablets, hand-held computers, servers, workstations, mainframes, wearable computers and supercomputers.

Which method adds 10 to the right end of the array?
myArray.
insert
(10)

Answers

JavaScript has a set of mutator functions that allow you to modify the contents of an array without referencing the individual elements.To add to to myArray we us the push() method

Adding Elements to an Array

To add to to myArray we us the push() method

(10)

myArray.push(10)

There are two mutator functions for adding elements to an array: push() and unshift(). The push() function adds an element to the end of an array:

var nums = [1,2,3,4,5]; print(nums); // 1,2,3,4,5 nums.push(6);

print(nums); // 1,2,3,4,5,6

var nums = [1,2,3,4,5]; print(nums); // 1,2,3,4,5 nums[nums.length] = 6; print(nums); // 1,2,3,4,5,6

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It would be Array.append(10), so append is the answer.

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